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Chemical kinetics
(Dr.) Mirza Salman Baig
Assistant Professor (Pharmaceutics)
AIKTC, School of Pharmacy,New Panvel
Affiliated to University of Mumbai (INDIA)
Rate of reaction
• Rate of reaction is defined as the
change in concentration of any of
reactant or product per unit time.
• Rate= dA/dt
• Unit is Mole/liter
Rate Law
• The rate of reaction is directly
proportional to the reactant
concentration, each concentration
being raised to some power.
• 2A + B --> Product
• Rate =k[A]m[B]n
(k = specific rate constant)
The Equation shows how rate is related to concentration
Order of reaction
• Order of reaction is defined as sum of
powers of concentration in rate law.
• Rate =k[A]m[B]n
• Order of reaction in above case is
(m+n)
• It is the number of concentration
terms on which the rate of reaction
depends.
Molecularity of reaction
Number of molecules that react to give the
product. It is number (intiger) not a
fraction.
Types
• Unimolecular
cis to trans
• Bimolecular
A+B ---> C
• Termolecular
A+B+C --> D
Reaction
Order
• Sum of powers of
concentration
terms in rate law
• Experimentally
determined
• It can have
fractional value
• It can assume zero
value
Molecularity
• Number of
reacting species
in a reaction
• Theriotical
concept
• It is always a
whole number
• It cannot have zero
value
Zero Order reaction
• Rate of reaction is independent of
concentration of reactant/product
• Reaction A--> Product
• Initial conc a 0
• Final conc a-x x
Zero Order reaction
• Rate of reaction = -d[A]/dt= k0[A]0
• dx/dt= k0 (a-x)0=k0
• x=k0t
• k0 is rate constant (or specific rate
constant) of zero order reaction
• Rate constant is the rate of reaction
at all concentrations x/t
First Order Reaction
• A--> Product
• At time t=0 concentration of A is a
mole/lit, If at time t, x mole of A have
changed, the final concentration
after time t will be (a-x)
• For first order reaction dx/dt is
directly proportional to concentration
of reactant...
• dx/dt= k(a-x)
• dx/(a-x)= kdt
First Order Reaction
• dx/(a-x)= kdt
• Integrating above equation..
• ∫dx/(a-x)= ∫kdt
• -ln (a-x) = kt + I
• If t=0, x=0 then I= -ln a
• substuting for I
• ln a/(a-x)= kt or k = (1/t) ln a/(a-x)
• changing in common log
• k= 2.303/t . log a/(a-x)
First Order Reaction
• k= 2.303/(t2-t1) . log (a-x1)/(a-x2)
• t1 and t2 are time interval at which x1
and x2 amount of reactant changed
respectively
• Example
• N2O5--> 2NO2 + 1/2 O2
Second Order Reaction
• Reaction A--> Product
• Initial conc a 0
• Final conc a-x x
• For second order reaction rate of
reaction is proportional to square of
concentration of reactants
• dx/dt= k (a-x)2
Second Order Reaction
• dx/dt= k (a-x)2
• dx/(a-x)2=k dt
• On integration ∫dx/(a-x)2= ∫k dt
• 1/(a-x) = kt +I
• At t=0, x=0.... I = 1/a
Second Order Reaction
• Substituting value of I in above
equation
• 1/(a-x) = kt + 1/a
• kt = 1/(a-x) - 1/a
• k = 1/t . x/a(a-x)
Pseudo order reaction
• Experimental order of reaction which
is not actual is known as pseudo
order
• Reaction A+B --> Product
• If B is in excesses, its concentration
will practically constant and only
concentration of A will affect rate of
reaction hence rate law will be..
• Rate = k' [A]...
Pseudo order reaction
(Example)
• Ethyle acetate+ Water (excesses) -->
Acetic acid + EtOH
Units of rate constant
• Units of rate constant for different
order reaction are different
• For Zero order
• k= d[A]/dt
• k= mol/lit . 1/time
• k= mol lit-1 time-1
Units of rate constant
• For first order
• k= 2.303/t . log a/(a-x)
• k= 2.303/t . log [A]0/[A]t
• k= 1/time
• k= time-1
Units of rate constant
• For second order reaction
• k= 1/t . x/a(a-x)
• k= 1/t . x/[A]0([A]0-x)
• k= 1/time . concentration/concentration2
• k= 1/time . 1/concentration
• k= 1/time . 1/(mol/lit)
• k= mol-1 lit time-1
How to determine order of
reaction
• Using integrated rate equations
• Graphical Method
• Using half life period
• Oswald isolation method
Using integrated rate
equations
• Perform the reaction using different
initial concentration of of reactant (a)
and note the concentration (a-x) at
regular time interwals (t)
• These values are then substituted in
integrated rate equations (first order,
second order, zero order)
• The rate equation which yield
constant value for k corrospond to
the correct order of reaction.
Graphical Method
• For straight line y=mx+c
• Fig A: If the plot of log (a-x) vs t is a straight
line, the reaction follows first-order .
• Fig B: If the plot of 1/(a-x) vs t is a straight
line, the reaction follows second order.
log(a-x)
t
t
1/(a-x)
Fig A Fig B
Half life reaction
• It is defined as the time required as
for the decrease in concentration of
reactant to half of its initial value.
• When x=a/2, then t=t1/2
• We can substitute this value in
equation of reaction
Using Half life method
• Seperate experiments should be
performed using different initial
concentration
• Half life for nth order reaction is
• t1/2= 1/ [A] n-1
Order of
reaction
Equation t1/2 (Half life)
0 k0= x/t OR x=k0t t1/2= a/2k0
1 k= 2.303/t . log a/(a-x) t1/2= 0.693/k
2 k = 1/t . x/a(a-x) t1/2= 1/ak
Using Half life method
• Zero order: Half life is directly
proportional to initial concentration of
the reactants
• First order: Half life is independent
of the initial concentration of
reactants
• Second order: Half life is inversly
proportional to initial cincentration
of reactants
Collision Theory of Reaction Rate
• According to this theory, chemical
reaction take place only when there
is collision between reacting
molecules.
• Colliding molecules must posses
sufficient kinetic energy
• A-A + B-B --> 2 A-B
• Molecules must collide with correct
orientation
Energy of activation Ea
• Minimum amount
of energy (Ea)
necessary to
cause reaction
between two.
• Only molecules
that collide with
kinetic energy
higher than Ea
are able to react.
Physical and chemical factors
influencing the chemical
degradation of pharmaceutical
product:
• Temperature
• Solvent & Dielectric constant
• Ionic strength
• Specific acid base catalysis
• General acid base catalysis
Effect of Temperature
(Arrhenius equation)
• Rate of reaction increace 3-folds by increase in
temperature of about 10oC
• Relation between rate constant, temperature and
Ea .....Arrhenius equation
• k= Ae-Ea/RT
• R= gas constant
• T = Temperature in Kelvin
• A= Factor related to frequency of collision
• Ea= Energy of activation
• log k2/k1 = Ea/2.303R . (T2 - T1)/T2T1
• k2 and k1 are rate of reaction at temperature T2 and
T1 respectively
Effect of solvent
(dielectric constant)
• Reactions involving ions of opposit charge
are accelerated by solvents with low
dielectric constant (ability of a substance to
store electrical energy in an electric field)
• Ex. Rate of hydrolysis of sulphate ester is
greater in low dielectric constant solvent like
methylene chloride than in water.
• Reaction between similar charged ions is
favoured by high dielectric constant
solvents
• Reaction between neutral molecules which
produce highly polar transition state is
favoured by high dielectric constant
solvents
Effect of Ionic strength
• Ionic strength may affect inter-ionic
attraction
• Increase ionic strength expected to
decrease the rate of reaction
between oppositely charged ions
and increase in rate of reaction
between similar charged ions... as
per Debye-Hukel equation
Catalyst
• It is a substance that influence speed
of reaction without itself being
altered chemically.
Specific acid base catalysis
• Specific acid base catalysis refer to
catalysis by hydrogen ion (H+) or Hydroxyl
Ion (OH-)
• Ex. Rate of hydrolysis of ester ethylacetate
• CH3-COOC2H5 --> CH3COOH + C2H5-OH
• is studeid at constant pH (buffered soln),
rate of disappearance of ethyl acetate
(ester) will apperantly First order.
• If reaction is studied at different pH (in
acidic range) then different first order rate
conatant k is observed at different pH.
Specific acid base catalysis
• Observed rate depend on
concentration of ester and [H+],
therefore it is actually second order
reaction.
• Observed rate constant (kobs) is
proportional to [H+]
• kobs = kacid [H+]
• logkobs = log kacid + log [H+]
• logkobs = log kacid - pH
Specific acid base catalysis
• Log kobs = log kacid - pH
• It suggest kobs vs pH is straight line
with slop -1 and y-intercept log kacid
• If we study same reaction in alkaline
pH then we observe different rate
constant at different pH
• log kobs = log kbase + log [OH-]
• kobs = kacid[H+] + kbase [OH-]
1 st order Hydrolysis of atropin
General acid base catalysis
• Acid or base catalysis is not
restricted to effect of [H+] or [OH-]
• Undissociated acid and base can
often produce catalytic effect
• Metal can also serve as catalyst
• Ex. Mutarotation of glucose in
acetate buffer is catalysed by [H+],
[OH-], Acetate ion [CH3COO-],
undissociated acid [CH3COOH]
undissociated acetic acid.
Problem
Q. Solution of drug contained
500unit/ml of drug when prepared. It
was analyzed after 40 days and
found to contain 300 unit/ml. Assume
decomposition is first order, at what
time will the drug have decomposed
to one half of its original
concentration?
• a= 500 unit/ml
• (a-x) = 300 unit/ml
• t= 40 days
• k= 2.303/t . log a/(a-X)
• k= 2.303/40 . log 500/300
• k= 0.0576 × log 1.667
• k= 0.0576 × 0.222
• k= 0.01278 day-1
• t1/2 = 0.693/k .... for first order
• t1/2 = 0.693/ 0.01278
• t1/2 = 54.23 Days
Problem
• Rate constant for first order
reaction is 1.54 × 10-3
Thank You

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Chemical kinetics

  • 1. Chemical kinetics (Dr.) Mirza Salman Baig Assistant Professor (Pharmaceutics) AIKTC, School of Pharmacy,New Panvel Affiliated to University of Mumbai (INDIA)
  • 2. Rate of reaction • Rate of reaction is defined as the change in concentration of any of reactant or product per unit time. • Rate= dA/dt • Unit is Mole/liter
  • 3. Rate Law • The rate of reaction is directly proportional to the reactant concentration, each concentration being raised to some power. • 2A + B --> Product • Rate =k[A]m[B]n (k = specific rate constant) The Equation shows how rate is related to concentration
  • 4. Order of reaction • Order of reaction is defined as sum of powers of concentration in rate law. • Rate =k[A]m[B]n • Order of reaction in above case is (m+n) • It is the number of concentration terms on which the rate of reaction depends.
  • 5. Molecularity of reaction Number of molecules that react to give the product. It is number (intiger) not a fraction. Types • Unimolecular cis to trans • Bimolecular A+B ---> C • Termolecular A+B+C --> D
  • 6. Reaction Order • Sum of powers of concentration terms in rate law • Experimentally determined • It can have fractional value • It can assume zero value Molecularity • Number of reacting species in a reaction • Theriotical concept • It is always a whole number • It cannot have zero value
  • 7. Zero Order reaction • Rate of reaction is independent of concentration of reactant/product • Reaction A--> Product • Initial conc a 0 • Final conc a-x x
  • 8. Zero Order reaction • Rate of reaction = -d[A]/dt= k0[A]0 • dx/dt= k0 (a-x)0=k0 • x=k0t • k0 is rate constant (or specific rate constant) of zero order reaction • Rate constant is the rate of reaction at all concentrations x/t
  • 9. First Order Reaction • A--> Product • At time t=0 concentration of A is a mole/lit, If at time t, x mole of A have changed, the final concentration after time t will be (a-x) • For first order reaction dx/dt is directly proportional to concentration of reactant... • dx/dt= k(a-x) • dx/(a-x)= kdt
  • 10. First Order Reaction • dx/(a-x)= kdt • Integrating above equation.. • ∫dx/(a-x)= ∫kdt • -ln (a-x) = kt + I • If t=0, x=0 then I= -ln a • substuting for I • ln a/(a-x)= kt or k = (1/t) ln a/(a-x) • changing in common log • k= 2.303/t . log a/(a-x)
  • 11. First Order Reaction • k= 2.303/(t2-t1) . log (a-x1)/(a-x2) • t1 and t2 are time interval at which x1 and x2 amount of reactant changed respectively • Example • N2O5--> 2NO2 + 1/2 O2
  • 12. Second Order Reaction • Reaction A--> Product • Initial conc a 0 • Final conc a-x x • For second order reaction rate of reaction is proportional to square of concentration of reactants • dx/dt= k (a-x)2
  • 13. Second Order Reaction • dx/dt= k (a-x)2 • dx/(a-x)2=k dt • On integration ∫dx/(a-x)2= ∫k dt • 1/(a-x) = kt +I • At t=0, x=0.... I = 1/a
  • 14. Second Order Reaction • Substituting value of I in above equation • 1/(a-x) = kt + 1/a • kt = 1/(a-x) - 1/a • k = 1/t . x/a(a-x)
  • 15. Pseudo order reaction • Experimental order of reaction which is not actual is known as pseudo order • Reaction A+B --> Product • If B is in excesses, its concentration will practically constant and only concentration of A will affect rate of reaction hence rate law will be.. • Rate = k' [A]...
  • 16. Pseudo order reaction (Example) • Ethyle acetate+ Water (excesses) --> Acetic acid + EtOH
  • 17. Units of rate constant • Units of rate constant for different order reaction are different • For Zero order • k= d[A]/dt • k= mol/lit . 1/time • k= mol lit-1 time-1
  • 18. Units of rate constant • For first order • k= 2.303/t . log a/(a-x) • k= 2.303/t . log [A]0/[A]t • k= 1/time • k= time-1
  • 19. Units of rate constant • For second order reaction • k= 1/t . x/a(a-x) • k= 1/t . x/[A]0([A]0-x) • k= 1/time . concentration/concentration2 • k= 1/time . 1/concentration • k= 1/time . 1/(mol/lit) • k= mol-1 lit time-1
  • 20. How to determine order of reaction • Using integrated rate equations • Graphical Method • Using half life period • Oswald isolation method
  • 21. Using integrated rate equations • Perform the reaction using different initial concentration of of reactant (a) and note the concentration (a-x) at regular time interwals (t) • These values are then substituted in integrated rate equations (first order, second order, zero order) • The rate equation which yield constant value for k corrospond to the correct order of reaction.
  • 22. Graphical Method • For straight line y=mx+c • Fig A: If the plot of log (a-x) vs t is a straight line, the reaction follows first-order . • Fig B: If the plot of 1/(a-x) vs t is a straight line, the reaction follows second order. log(a-x) t t 1/(a-x) Fig A Fig B
  • 23. Half life reaction • It is defined as the time required as for the decrease in concentration of reactant to half of its initial value. • When x=a/2, then t=t1/2 • We can substitute this value in equation of reaction
  • 24. Using Half life method • Seperate experiments should be performed using different initial concentration • Half life for nth order reaction is • t1/2= 1/ [A] n-1
  • 25. Order of reaction Equation t1/2 (Half life) 0 k0= x/t OR x=k0t t1/2= a/2k0 1 k= 2.303/t . log a/(a-x) t1/2= 0.693/k 2 k = 1/t . x/a(a-x) t1/2= 1/ak
  • 26. Using Half life method • Zero order: Half life is directly proportional to initial concentration of the reactants • First order: Half life is independent of the initial concentration of reactants • Second order: Half life is inversly proportional to initial cincentration of reactants
  • 27. Collision Theory of Reaction Rate • According to this theory, chemical reaction take place only when there is collision between reacting molecules. • Colliding molecules must posses sufficient kinetic energy • A-A + B-B --> 2 A-B • Molecules must collide with correct orientation
  • 28. Energy of activation Ea • Minimum amount of energy (Ea) necessary to cause reaction between two. • Only molecules that collide with kinetic energy higher than Ea are able to react.
  • 29. Physical and chemical factors influencing the chemical degradation of pharmaceutical product: • Temperature • Solvent & Dielectric constant • Ionic strength • Specific acid base catalysis • General acid base catalysis
  • 30. Effect of Temperature (Arrhenius equation) • Rate of reaction increace 3-folds by increase in temperature of about 10oC • Relation between rate constant, temperature and Ea .....Arrhenius equation • k= Ae-Ea/RT • R= gas constant • T = Temperature in Kelvin • A= Factor related to frequency of collision • Ea= Energy of activation • log k2/k1 = Ea/2.303R . (T2 - T1)/T2T1 • k2 and k1 are rate of reaction at temperature T2 and T1 respectively
  • 31. Effect of solvent (dielectric constant) • Reactions involving ions of opposit charge are accelerated by solvents with low dielectric constant (ability of a substance to store electrical energy in an electric field) • Ex. Rate of hydrolysis of sulphate ester is greater in low dielectric constant solvent like methylene chloride than in water. • Reaction between similar charged ions is favoured by high dielectric constant solvents • Reaction between neutral molecules which produce highly polar transition state is favoured by high dielectric constant solvents
  • 32. Effect of Ionic strength • Ionic strength may affect inter-ionic attraction • Increase ionic strength expected to decrease the rate of reaction between oppositely charged ions and increase in rate of reaction between similar charged ions... as per Debye-Hukel equation
  • 33. Catalyst • It is a substance that influence speed of reaction without itself being altered chemically.
  • 34. Specific acid base catalysis • Specific acid base catalysis refer to catalysis by hydrogen ion (H+) or Hydroxyl Ion (OH-) • Ex. Rate of hydrolysis of ester ethylacetate • CH3-COOC2H5 --> CH3COOH + C2H5-OH • is studeid at constant pH (buffered soln), rate of disappearance of ethyl acetate (ester) will apperantly First order. • If reaction is studied at different pH (in acidic range) then different first order rate conatant k is observed at different pH.
  • 35. Specific acid base catalysis • Observed rate depend on concentration of ester and [H+], therefore it is actually second order reaction. • Observed rate constant (kobs) is proportional to [H+] • kobs = kacid [H+] • logkobs = log kacid + log [H+] • logkobs = log kacid - pH
  • 36. Specific acid base catalysis • Log kobs = log kacid - pH • It suggest kobs vs pH is straight line with slop -1 and y-intercept log kacid • If we study same reaction in alkaline pH then we observe different rate constant at different pH • log kobs = log kbase + log [OH-] • kobs = kacid[H+] + kbase [OH-]
  • 37. 1 st order Hydrolysis of atropin
  • 38. General acid base catalysis • Acid or base catalysis is not restricted to effect of [H+] or [OH-] • Undissociated acid and base can often produce catalytic effect • Metal can also serve as catalyst • Ex. Mutarotation of glucose in acetate buffer is catalysed by [H+], [OH-], Acetate ion [CH3COO-], undissociated acid [CH3COOH] undissociated acetic acid.
  • 39. Problem Q. Solution of drug contained 500unit/ml of drug when prepared. It was analyzed after 40 days and found to contain 300 unit/ml. Assume decomposition is first order, at what time will the drug have decomposed to one half of its original concentration?
  • 40. • a= 500 unit/ml • (a-x) = 300 unit/ml • t= 40 days • k= 2.303/t . log a/(a-X) • k= 2.303/40 . log 500/300 • k= 0.0576 × log 1.667 • k= 0.0576 × 0.222 • k= 0.01278 day-1
  • 41. • t1/2 = 0.693/k .... for first order • t1/2 = 0.693/ 0.01278 • t1/2 = 54.23 Days
  • 42. Problem • Rate constant for first order reaction is 1.54 × 10-3