This document summarizes key concepts in chemical kinetics including:
1) Kinetics is the study of reaction rates and how the molecular mechanism influences the rate. Factors like temperature, concentration, and catalysts affect the reaction rate.
2) The rate of a reaction is defined as the change in concentration of a reactant or product over time. Rate laws relate the reaction rate to concentrations of reactants.
3) Integrated rate laws allow calculation of reactant/product concentration as a function of time for different reaction orders (zero, first, second order). Graphical methods using these relations can determine the reaction order and rate constant.
The branch of chemistry, which deals with the study of reaction rates and their mechanisms, called chemical kinetics.
Thermodynamics tells only about the feasibility of a reaction whereas chemical kinetics tells about the rate of a reaction.
For example, thermodynamic data indicate that diamond shall convert to graphite but in reality the conversion rate is so slow that the change is not perceptible at all.
Introduction to redox reactions
References
Tindale, Ritchie et al, 2014, Chemistry for CSEC 2nd Edition, Nelson Thornes. p156-159
Electron Transfer in Redox Reactions Todayhttps://www.sewanhakaschools.org
Soluion and colligative propertries 2017nysa tutorial
it is based on CBSE, ICSE, HSC ,JEE, NEET, AIPMT, MTCET.
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Discusses the chemical of slightly soluble compounds. Ksp and factors affecting solubility are included as well as solved problems.
**More good stuff available at:
www.wsautter.com
and
http://www.youtube.com/results?search_query=wnsautter&aq=f
A complete introduction to all things chemical kinetics designed specifically for non-chemists to understand. Fair warning: The presentation is very rigorous in its mathematical treatment, which is makes it a useful reference for looking up equations, but this can unfortunately make it less polished and flowing then a typical presentation. I tried my best to spell everything out clearly, but despite my best efforts it's still pretty dense.
The branch of chemistry, which deals with the study of reaction rates and their mechanisms, called chemical kinetics.
Thermodynamics tells only about the feasibility of a reaction whereas chemical kinetics tells about the rate of a reaction.
For example, thermodynamic data indicate that diamond shall convert to graphite but in reality the conversion rate is so slow that the change is not perceptible at all.
Introduction to redox reactions
References
Tindale, Ritchie et al, 2014, Chemistry for CSEC 2nd Edition, Nelson Thornes. p156-159
Electron Transfer in Redox Reactions Todayhttps://www.sewanhakaschools.org
Soluion and colligative propertries 2017nysa tutorial
it is based on CBSE, ICSE, HSC ,JEE, NEET, AIPMT, MTCET.
class 12 chemistry.
for buy ppt pay by paytm acount- 8879919898. price-Rs99 only/-
for more detail go my site
www.akchem.blogspot.com
Discusses the chemical of slightly soluble compounds. Ksp and factors affecting solubility are included as well as solved problems.
**More good stuff available at:
www.wsautter.com
and
http://www.youtube.com/results?search_query=wnsautter&aq=f
A complete introduction to all things chemical kinetics designed specifically for non-chemists to understand. Fair warning: The presentation is very rigorous in its mathematical treatment, which is makes it a useful reference for looking up equations, but this can unfortunately make it less polished and flowing then a typical presentation. I tried my best to spell everything out clearly, but despite my best efforts it's still pretty dense.
This is a lecture is a series on combustion chemical kinetics for engineers. The course topics are selections from thermodynamics and kinetics especially geared to the interests of engineers involved in combusition
Chemical kinetics: the study of how fast chemical reactions occur.Specifically:
Rates of consumption of reactants and formation of products.
Response of chemical rates to changes in rxn conditions.
Identification of steps through which rxn takes place.
Reasons for study
Prediction of how quickly a rxn approaches equilibrium.
Understanding or elucidation of rxn mechanisms.
a detailed description of the chapter chemical kinetics (physical chemistry) including different problems by Dr. Satyabrata Si from KIIT school of biotechnology
June 3, 2024 Anti-Semitism Letter Sent to MIT President Kornbluth and MIT Cor...Levi Shapiro
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• The Committee on Education and the Workforce has been investigating your institution since December 7, 2023. The Committee has broad jurisdiction over postsecondary education, including its compliance with Title VI of the Civil Rights Act, campus safety concerns over disruptions to the learning environment, and the awarding of federal student aid under the Higher Education Act.
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• The Committee on Ways and Means has been investigating several universities since November 15, 2023, when the Committee held a hearing entitled From Ivory Towers to Dark Corners: Investigating the Nexus Between Antisemitism, Tax-Exempt Universities, and Terror Financing. The Committee followed the hearing with letters to those institutions on January 10, 202
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2. Goals/Objectives Rates of reaction & conditions affecting rates Rate eqn, rate constant, and order of a rxn Calcns involving integrated rate laws Collision theory and activation energy Link between rxn mechanism and the rate law
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7. Figure shows change in concentration (decreases exponentially) with time. The initial rate = the change in dye conc with time — can be determined from the slope. Initial Rate (rate at the start)
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9. H 2 ( g ) + I 2 ( g ) 2 HI( g ) Using [H 2 ], the instantaneous rate at 50 s is (30, 0.50); ( 70, 0.22) from y/ x : Using [HI], the instantaneous rate at 50 s is: [H 2 ] [HI]
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11. Tro, Chemistry: A Molecular Approach the average rate for the first 10 s is 0.0181 M/s the average rate for the first 40 s is 0.0150 M/s the average rate for the first 80 s is 0.0108 M/s HI H 2
12. Consider: 2N 2 O 5 4NO 2 + O 2 The rate of a reaction is measured w.r.t [product] or [reactant] per unit time. Rate of a Chemical Reaction
13. To equate rates , divide by stoichiometric coefficients in the balanced equation ( relative rates ). 2N 2 O 5 4NO 2 + O 2 The rate of reaction must reflect the stoichiometric coefficients in the reaction NB: coefficients written as fractions…
14. For the reaction, [I ] changes from 1.000 M to 0.868 M in the first 10 s. Calculate the average rate in the first 10 s. H 2 O 2 ( aq ) + 3 I ( aq ) + 2 H + ( aq ) I 3 ( aq ) + 2 H 2 O ( l )
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16. Rate of disappearance of H 2 = 4 .5 10 - 4 mol L -1 min -1 . N 2 (g) + 3H 2 (g) 2NH 3 (g) Rate of consumption N 2 = ? Rate of formation of NH 3 = ? SOLUTION -rate of consumptn H 2 4.5 10 -4 mol L -1 min -1 , -rate of consumption N 2 rate of formation NH 3
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18. - the order of a reaction w.r.t a reactant, is the exponent of its concentration term in the rate expression, (n is the order w.r.t B) Reaction Order (m is the order w.r.t A) can be 0, 1, 2 or fractions,-ve order must be determined by experiment!!!
19. Rate = k [A] m [B] n [C] p Total order = m + n + p - the total reaction order is the sum of all exponents on all concentration terms; Reaction Order
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21. k, rate constant The rate constant is a proportionality constant that relates rate of rxn and conc’n at a given temp. Rate constants have units consistent with the units for other terms in the rate equation. Rate = k [A] m 0 order: k = mol/L· time (M s -1 ) 1 st order: k = time -1 ( s -1 ) 2 nd order: k = L/mol · time (M -1 s -1 ) General: M 1-n time -1
22. Determine the rate law and rate constant for the reaction NO 2( g ) + CO ( g ) NO ( g ) + CO 2( g ) given the experimental data below. Comparing Expt #1 and Expt #2, the [NO 2 ] changes but the [CO] does not; -the rate of rxn also changes! Write a general rate law including all reactants Examine the data and find two experiments in which the concentration of one reactant changes , but the other concentrations are the same Expt. Number Initial [NO 2 ], (M) Initial [CO], (M) Initial Rate (M/s) 1. 0.10 0.10 0.0021 2. 0.20 0.10 0.0082 3. 0.20 0.20 0.0083 4. 0.40 0.10 0.033 Expt. Number Initial [NO 2 ], (M) Initial [CO], (M) Initial Rate (M/s) 1. 0.10 0.10 0.0021 2. 0.20 0.10 0.0082 3. 0.20 0.20 0.0083 4. 0.40 0.10 0.033
23. Determine the rate law and rate constant for the reaction NO 2( g ) + CO ( g ) NO ( g ) + CO 2( g ) given the data below. Determine by what factor the concentrations and rates change in these two experiments. Expt. Number Initial [NO 2 ], (M) Initial [CO], (M) Initial Rate (M/s) 1. 0.10 0.10 0.0021 2. 0.20 0.10 0.0082 3. 0.20 0.20 0.0083 4. 0.40 0.10 0.033
24. Determine the rate law and rate constant for the reaction NO 2( g ) + CO ( g ) NO ( g ) + CO 2( g ) given the data below. Determine to what power the concentration factor must be raised to equal the rate factor. Expt. Number Initial [NO 2 ], (M) Initial [CO], (M) Initial Rate (M/s) 1. 0.10 0.10 0.0021 2. 0.20 0.10 0.0082 3. 0.20 0.20 0.0083 4. 0.40 0.10 0.033
25. Determine the rate law and rate constant for the reaction NO 2( g ) + CO ( g ) NO ( g ) + CO 2( g ) given the data below. Repeat for the other reactant(s): CO Expt. Number Initial [NO 2 ], (M) Initial [CO], (M) Initial Rate (M/s) 1. 0.10 0.10 0.0021 2. 0.20 0.10 0.0082 3. 0.20 0.20 0.0083 4. 0.40 0.10 0.033
26. Determine the rate law and rate constant for the reaction NO 2( g ) + CO ( g ) NO ( g ) + CO 2( g ) given the data below. n = 2, m = 0 Substitute the exponents into the general rate law to get the rate law for the reaction Expt. Number Initial [NO 2 ], (M) Initial [CO], (M) Initial Rate (M/s) 1. 0.10 0.10 0.0021 2. 0.20 0.10 0.0082 3. 0.20 0.20 0.0083 4. 0.40 0.10 0.033
27. Determine the rate law and rate constant for the reaction NO 2( g ) + CO ( g ) NO ( g ) + CO 2( g ) given the data below. Substitute the concentrations and rate for any experiment into the rate law and solve for k Expt. Number Initial [NO 2 ], (M) Initial [CO], (M) Initial Rate (M/s) 1. 0.10 0.10 0.0021 2. 0.20 0.10 0.0082 3. 0.20 0.20 0.0083 4. 0.40 0.10 0.033
28. 2NO(g) + 2H 2 (g) N 2 (g) + 2H 2 O(g) Expt [NO], M [H 2 ], M Rate, mol/L s 1. 0.420 0.122 0.136 2. 0.210 0.122 0.0339 3. 0.210 0.244 0.0678 - order of the reaction for NO & H 2 ? - rate law (rate equation)? - value of k (units)? #2. Deriving Rate Laws
29. SOLUTION 4 = 2 n 2 2 = 2 n (n = 2 for [NO]) 2 = 2 m 2 1 = 2 m (m = 1 for [H 2 ]) rate concn rate concn concn
30. Rate Law = k[NO] 2 [H 2 ] Use exp 1 data + rate law - value of k (units)? k [NO] 2 [H 2 ]= 0.136 mol/L s k [0.420 mol/L] 2 [0.122 mol/L] = 0.136 mol/L s or, k = 6.32 M -2 s -1 Rate Law = 6.32 M -2 s -1 [NO] 2 [H 2 ]
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35. Q2. The reaction SO 2 Cl 2( g ) SO 2( g ) + Cl 2( g ) is first order with a rate constant of 2.90 10 -4 s -1 at a given set of conditions. Find the [SO 2 Cl 2 ] at 865 s when [SO 2 Cl 2 ] 0 = 0.0225 M the new concentration is less than the original, as expected [SO 2 Cl 2 ] 0 = 0.0225 M, t = 865, k = 2.90 10 -4 s -1 [SO 2 Cl 2 ] Check: Solution: Concept Plan: Relationships: Given: Find: SAME [SO 2 Cl 2 ] [SO 2 Cl 2 ] 0 , t, k
36. First order: ln[A] = - k t + ln[A] 0 Plot of ln[A] vs. time gives straight line with slope = - k and y-intercept = ln[A] 0 Using the Integrated Rate Laws: k, order The integrated rate law suggests a way to tell the order (& rate constant, k) based on experiment (graphical method). ln[A] 0 ln[A] time slope = − k
37. l/[A] 0 1/[A] time slope = k Second order: 1/[A] = k t +1/[A] 0 Plot of 1/[A] vs. time gives straight line with slope = + k and y-intercept = 1/[A] 0
38. Plot of [A] vs. time is straight line with slope = - k and y-intercept = [A] 0 Zero order: [A] = - k t + [A] 0 See summary in Table 13.2 [A] 0 [A] time slope = - k
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48. Half-Life Radioactive decay is a first order process. Tritium electron + helium 3 H 0 -1 e 3 He t 1/2 = 12.3 years If you have 1.50 mg of tritium, how much is left after 49.2 years?
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54. Energy Profile for the Isomerization of Methyl Isonitrile Product more stable (lower E); (exothermic rxn)
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57. More on Activation Energy Arrhenius equation — Frequency factor is related to frequency of collisions with correct geometry. Plot ln k vs. 1/T straight line, slope = -E a /R Rate constant Temp (K) 8.31 10 -3 kJ/K•mol Activation energy Frequency factor
58. The E a can also be evaluated mathematically if 2 rate constants are known at 2 diff temps: 2-point form R = 8.3145 J/(mol K)
59. The reaction NO 2( g ) + CO ( g ) CO 2( g ) + NO ( g ) has a rate constant of 2.57 M -1 ∙ s -1 at 701 K and 567 M -1 ∙ s -1 at 895 K. Find the activation energy in kJ/mol most activation energies are tens to hundreds of kJ/mol – so the answer is reasonable T 1 = 701 K, k 1 = 2.57 M -1 ∙s -1 , T 2 = 895 K, k 2 = 567 M -1 ∙s -1 E a , kJ/mol Check: Solution: Concept Plan: Relationships: Given: Find: E a T 1 , k 1 , T 2 , k 2
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71. Rate Laws and Mechanisms More than one possible mechanisms! 2 O 3 (g) 3 O 2 (g) things to do…. Derive rate laws (not mechanisms) Deduce eqn for an elementary step Determine overall eqn from elementary steps
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73. rate = k 2 [O 3 ][O] O is an intermediate (the rate of an elementary step must be written w.r.t the reactants only) Rate of formation of O = k 1 [O 3 ] Rate of conversion to O 3 = k -1 [O 2 ][O] k 1 [O 3 ] = k -1 [O 2 ][O] @ equilibrium