SlideShare a Scribd company logo
Section 4-1
Operations with Polynomials
Essential Questions
• How do you multiply, divide, and simplify monomials
and expressions involving powers?

• How do you add, subtract, and multiply polynomials?
Vocabulary
1. Simplify:
2. Degree of a Polynomial:
Vocabulary
1. Simplify: To eliminate all powers by applying all
rules so that there are no parentheses or
negative exponents remaining
2. Degree of a Polynomial:
Vocabulary
1. Simplify: To eliminate all powers by applying all
rules so that there are no parentheses or
negative exponents remaining
2. Degree of a Polynomial: The sum of all of the
powers of the term with the highest degree
Properties of Powers
Property Rule Example 1 Example 2
Product of
Powers
Power of a
Power
Power of a
Product
Quotient of
Powers
Properties of Powers
Property Rule Example 1 Example 2
Product of
Powers
Power of a
Power
Power of a
Product
Quotient of
Powers
xm
i xn
= xm+n
Properties of Powers
Property Rule Example 1 Example 2
Product of
Powers
Power of a
Power
Power of a
Product
Quotient of
Powers
xm
i xn
= xm+n x3
i x2
Properties of Powers
Property Rule Example 1 Example 2
Product of
Powers
Power of a
Power
Power of a
Product
Quotient of
Powers
xm
i xn
= xm+n x3
i x2
x5
Properties of Powers
Property Rule Example 1 Example 2
Product of
Powers
Power of a
Power
Power of a
Product
Quotient of
Powers
xm
i xn
= xm+n x3
i x2
24
i 25
x5
Properties of Powers
Property Rule Example 1 Example 2
Product of
Powers
Power of a
Power
Power of a
Product
Quotient of
Powers
xm
i xn
= xm+n x3
i x2
24
i 25
x5
29
Properties of Powers
Property Rule Example 1 Example 2
Product of
Powers
Power of a
Power
Power of a
Product
Quotient of
Powers
xm
i xn
= xm+n x3
i x2
24
i 25
x5
29
512
Properties of Powers
Property Rule Example 1 Example 2
Product of
Powers
Power of a
Power
Power of a
Product
Quotient of
Powers
xm
i xn
= xm+n x3
i x2
24
i 25
x5
29
512
(xm
)n
= xmn
Properties of Powers
Property Rule Example 1 Example 2
Product of
Powers
Power of a
Power
Power of a
Product
Quotient of
Powers
xm
i xn
= xm+n x3
i x2
24
i 25
x5
29
512
(xm
)n
= xmn (x7
)3
Properties of Powers
Property Rule Example 1 Example 2
Product of
Powers
Power of a
Power
Power of a
Product
Quotient of
Powers
xm
i xn
= xm+n x3
i x2
24
i 25
x5
29
512
(xm
)n
= xmn (x7
)3
x21
Properties of Powers
Property Rule Example 1 Example 2
Product of
Powers
Power of a
Power
Power of a
Product
Quotient of
Powers
xm
i xn
= xm+n x3
i x2
24
i 25
x5
29
512
(xm
)n
= xmn (x7
)3
x21
(32
)4
Properties of Powers
Property Rule Example 1 Example 2
Product of
Powers
Power of a
Power
Power of a
Product
Quotient of
Powers
xm
i xn
= xm+n x3
i x2
24
i 25
x5
29
512
(xm
)n
= xmn (x7
)3
x21
(32
)4
38
Properties of Powers
Property Rule Example 1 Example 2
Product of
Powers
Power of a
Power
Power of a
Product
Quotient of
Powers
xm
i xn
= xm+n x3
i x2
24
i 25
x5
29
512
(xm
)n
= xmn (x7
)3
x21
(32
)4
38
6561
Properties of Powers
Property Rule Example 1 Example 2
Product of
Powers
Power of a
Power
Power of a
Product
Quotient of
Powers
xm
i xn
= xm+n x3
i x2
24
i 25
x5
29
512
(xm
)n
= xmn (x7
)3
x21
(32
)4
38
6561
(ax)m
= am
xm
Properties of Powers
Property Rule Example 1 Example 2
Product of
Powers
Power of a
Power
Power of a
Product
Quotient of
Powers
xm
i xn
= xm+n x3
i x2
24
i 25
x5
29
512
(xm
)n
= xmn (x7
)3
x21
(32
)4
38
6561
(ax)m
= am
xm (2x)3
Properties of Powers
Property Rule Example 1 Example 2
Product of
Powers
Power of a
Power
Power of a
Product
Quotient of
Powers
xm
i xn
= xm+n x3
i x2
24
i 25
x5
29
512
(xm
)n
= xmn (x7
)3
x21
(32
)4
38
6561
(ax)m
= am
xm (2x)3
23
x3
Properties of Powers
Property Rule Example 1 Example 2
Product of
Powers
Power of a
Power
Power of a
Product
Quotient of
Powers
xm
i xn
= xm+n x3
i x2
24
i 25
x5
29
512
(xm
)n
= xmn (x7
)3
x21
(32
)4
38
6561
(ax)m
= am
xm (2x)3
23
x3
8x3
Properties of Powers
Property Rule Example 1 Example 2
Product of
Powers
Power of a
Power
Power of a
Product
Quotient of
Powers
xm
i xn
= xm+n x3
i x2
24
i 25
x5
29
512
(xm
)n
= xmn (x7
)3
x21
(32
)4
38
6561
(ax)m
= am
xm (2x)3
23
x3
8x3
(3x4
)2
Properties of Powers
Property Rule Example 1 Example 2
Product of
Powers
Power of a
Power
Power of a
Product
Quotient of
Powers
xm
i xn
= xm+n x3
i x2
24
i 25
x5
29
512
(xm
)n
= xmn (x7
)3
x21
(32
)4
38
6561
(ax)m
= am
xm (2x)3
23
x3
8x3
(3x4
)2
9x8
Properties of Powers
Property Rule Example 1 Example 2
Product of
Powers
Power of a
Power
Power of a
Product
Quotient of
Powers
xm
i xn
= xm+n x3
i x2
24
i 25
x5
29
512
(xm
)n
= xmn (x7
)3
x21
(32
)4
38
6561
(ax)m
= am
xm (2x)3
23
x3
8x3
(3x4
)2
9x8
xm
xn
= xm−n
Properties of Powers
Property Rule Example 1 Example 2
Product of
Powers
Power of a
Power
Power of a
Product
Quotient of
Powers
xm
i xn
= xm+n x3
i x2
24
i 25
x5
29
512
(xm
)n
= xmn (x7
)3
x21
(32
)4
38
6561
(ax)m
= am
xm (2x)3
23
x3
8x3
(3x4
)2
9x8
xm
xn
= xm−n x5
x2
= x3
Properties of Powers
Property Rule Example 1 Example 2
Product of
Powers
Power of a
Power
Power of a
Product
Quotient of
Powers
xm
i xn
= xm+n x3
i x2
24
i 25
x5
29
512
(xm
)n
= xmn (x7
)3
x21
(32
)4
38
6561
(ax)m
= am
xm (2x)3
23
x3
8x3
(3x4
)2
9x8
xm
xn
= xm−n x5
x2
= x3 6x12
y4
8x5
y
=
3x7
y3
4
Properties of Powers
Property Rule Example 1 Example 2
Power of a
Quotient
Zero
Power
Negative
Exponent
Properties of Powers
Property Rule Example 1 Example 2
Power of a
Quotient
Zero
Power
Negative
Exponent
x
y
⎛
⎝
⎜
⎞
⎠
⎟
m
=
xm
ym
Properties of Powers
Property Rule Example 1 Example 2
Power of a
Quotient
Zero
Power
Negative
Exponent
x
y
⎛
⎝
⎜
⎞
⎠
⎟
m
=
xm
ym
x3
y2
⎛
⎝
⎜
⎞
⎠
⎟
4
=
x12
y8
Properties of Powers
Property Rule Example 1 Example 2
Power of a
Quotient
Zero
Power
Negative
Exponent
x
y
⎛
⎝
⎜
⎞
⎠
⎟
m
=
xm
ym
x3
y2
⎛
⎝
⎜
⎞
⎠
⎟
4
=
x12
y8
2x4
3y2
⎛
⎝
⎜
⎞
⎠
⎟
5
=
32x20
243y10
Properties of Powers
Property Rule Example 1 Example 2
Power of a
Quotient
Zero
Power
Negative
Exponent
x
y
⎛
⎝
⎜
⎞
⎠
⎟
m
=
xm
ym
x3
y2
⎛
⎝
⎜
⎞
⎠
⎟
4
=
x12
y8
2x4
3y2
⎛
⎝
⎜
⎞
⎠
⎟
5
=
32x20
243y10
x0
= 1
Properties of Powers
Property Rule Example 1 Example 2
Power of a
Quotient
Zero
Power
Negative
Exponent
x
y
⎛
⎝
⎜
⎞
⎠
⎟
m
=
xm
ym
x3
y2
⎛
⎝
⎜
⎞
⎠
⎟
4
=
x12
y8
2x4
3y2
⎛
⎝
⎜
⎞
⎠
⎟
5
=
32x20
243y10
x0
= 1 (x7
)0
= 1
Properties of Powers
Property Rule Example 1 Example 2
Power of a
Quotient
Zero
Power
Negative
Exponent
x
y
⎛
⎝
⎜
⎞
⎠
⎟
m
=
xm
ym
x3
y2
⎛
⎝
⎜
⎞
⎠
⎟
4
=
x12
y8
2x4
3y2
⎛
⎝
⎜
⎞
⎠
⎟
5
=
32x20
243y10
x0
= 1 (x7
)0
= 1 3x12
y4
z11
5x4
yz9
⎛
⎝
⎜
⎞
⎠
⎟
0
= 1
Properties of Powers
Property Rule Example 1 Example 2
Power of a
Quotient
Zero
Power
Negative
Exponent
x
y
⎛
⎝
⎜
⎞
⎠
⎟
m
=
xm
ym
x3
y2
⎛
⎝
⎜
⎞
⎠
⎟
4
=
x12
y8
2x4
3y2
⎛
⎝
⎜
⎞
⎠
⎟
5
=
32x20
243y10
x0
= 1 (x7
)0
= 1 3x12
y4
z11
5x4
yz9
⎛
⎝
⎜
⎞
⎠
⎟
0
= 1
x−n
=
1
xn
Properties of Powers
Property Rule Example 1 Example 2
Power of a
Quotient
Zero
Power
Negative
Exponent
x
y
⎛
⎝
⎜
⎞
⎠
⎟
m
=
xm
ym
x3
y2
⎛
⎝
⎜
⎞
⎠
⎟
4
=
x12
y8
2x4
3y2
⎛
⎝
⎜
⎞
⎠
⎟
5
=
32x20
243y10
x0
= 1 (x7
)0
= 1 3x12
y4
z11
5x4
yz9
⎛
⎝
⎜
⎞
⎠
⎟
0
= 1
x−n
=
1
xn
1
x−n
= xn
Properties of Powers
Property Rule Example 1 Example 2
Power of a
Quotient
Zero
Power
Negative
Exponent
x
y
⎛
⎝
⎜
⎞
⎠
⎟
m
=
xm
ym
x3
y2
⎛
⎝
⎜
⎞
⎠
⎟
4
=
x12
y8
2x4
3y2
⎛
⎝
⎜
⎞
⎠
⎟
5
=
32x20
243y10
x0
= 1 (x7
)0
= 1 3x12
y4
z11
5x4
yz9
⎛
⎝
⎜
⎞
⎠
⎟
0
= 1
x−n
=
1
xn
1
x−n
= xn x−4
y
z−5
=
yz5
x4
Example 1
Simplify.
a. (a−3
)(a2
b4
)(c−1
) b.
n2
n10
c.
3a2
b4
⎛
⎝⎜
⎞
⎠⎟
2
Example 1
Simplify.
a. (a−3
)(a2
b4
)(c−1
) b.
n2
n10
a−1
b4
c−1
c.
3a2
b4
⎛
⎝⎜
⎞
⎠⎟
2
Example 1
Simplify.
a. (a−3
)(a2
b4
)(c−1
) b.
n2
n10
a−1
b4
c−1
b4
ac
c.
3a2
b4
⎛
⎝⎜
⎞
⎠⎟
2
Example 1
Simplify.
a. (a−3
)(a2
b4
)(c−1
) b.
n2
n10
a−1
b4
c−1
b4
ac
1
n8
c.
3a2
b4
⎛
⎝⎜
⎞
⎠⎟
2
Example 1
Simplify.
a. (a−3
)(a2
b4
)(c−1
) b.
n2
n10
a−1
b4
c−1
b4
ac
1
n8
c.
3a2
b4
⎛
⎝⎜
⎞
⎠⎟
2
9a4
b8
Example 2
Determine whether each expression is a polynomial.
If is is, state the degree of the polynomial.
a. c4
− 4 c +18 b. −16p5
+
3
4
p2
t7
c. x 2
− 3x −1
+ 7
Example 2
Determine whether each expression is a polynomial.
If is is, state the degree of the polynomial.
a. c4
− 4 c +18 b. −16p5
+
3
4
p2
t7
c. x 2
− 3x −1
+ 7
No
Example 2
Determine whether each expression is a polynomial.
If is is, state the degree of the polynomial.
a. c4
− 4 c +18 b. −16p5
+
3
4
p2
t7
c. x 2
− 3x −1
+ 7
No Yes
Example 2
Determine whether each expression is a polynomial.
If is is, state the degree of the polynomial.
a. c4
− 4 c +18 b. −16p5
+
3
4
p2
t7
c. x 2
− 3x −1
+ 7
No Yes
Degree: 9
Example 2
Determine whether each expression is a polynomial.
If is is, state the degree of the polynomial.
a. c4
− 4 c +18 b. −16p5
+
3
4
p2
t7
c. x 2
− 3x −1
+ 7
No Yes
Degree: 9
No
Example 3
Simplify each expression.
a. (2a3
+ 5a − 7)− (a3
− 3a + 2)
b. (4x 2
− 9x + 3)+ (−2x 2
− 5x − 6)
Example 3
Simplify each expression.
a. (2a3
+ 5a − 7)− (a3
− 3a + 2)
2a3
+ 5a − 7 − a3
+ 3a − 2
b. (4x 2
− 9x + 3)+ (−2x 2
− 5x − 6)
Example 3
Simplify each expression.
a. (2a3
+ 5a − 7)− (a3
− 3a + 2)
2a3
+ 5a − 7 − a3
+ 3a − 2
a3
+ 8a − 9
b. (4x 2
− 9x + 3)+ (−2x 2
− 5x − 6)
Example 3
Simplify each expression.
a. (2a3
+ 5a − 7)− (a3
− 3a + 2)
2a3
+ 5a − 7 − a3
+ 3a − 2
a3
+ 8a − 9
b. (4x 2
− 9x + 3)+ (−2x 2
− 5x − 6)
4x 2
− 9x + 3 − 2x 2
− 5x − 6
Example 3
Simplify each expression.
a. (2a3
+ 5a − 7)− (a3
− 3a + 2)
2a3
+ 5a − 7 − a3
+ 3a − 2
a3
+ 8a − 9
b. (4x 2
− 9x + 3)+ (−2x 2
− 5x − 6)
4x 2
− 9x + 3 − 2x 2
− 5x − 6
2x 2
−14x − 3
Example 4
Find − y (4y 2
+ 2y − 3).
Example 4
Find − y (4y 2
+ 2y − 3).
−4y 3
− 2y 2
+ 3y
Example 5
0.001x 2
+ 5x + 500
Matt Mitarnowski estimates that the cost in dollars
associated with selling x units Shecky’s Shoe Shine
is given by the expression . The
revenue from selling x units is given by 10x. Write a
polynomial to represent the profits generated by the
product if profit = revenue − cost.
x
Example 5
0.001x 2
+ 5x + 500
Matt Mitarnowski estimates that the cost in dollars
associated with selling x units Shecky’s Shoe Shine
is given by the expression . The
revenue from selling x units is given by 10x. Write a
polynomial to represent the profits generated by the
product if profit = revenue − cost.
x
profit = 10x − (0.001x 2
+ 5x + 500)
Example 5
0.001x 2
+ 5x + 500
Matt Mitarnowski estimates that the cost in dollars
associated with selling x units Shecky’s Shoe Shine
is given by the expression . The
revenue from selling x units is given by 10x. Write a
polynomial to represent the profits generated by the
product if profit = revenue − cost.
x
profit = 10x − (0.001x 2
+ 5x + 500)
profit = −0.001x 2
+ 5x − 500
Example 6
Find (a2
+ 3a − 4)(a + 2)
Example 6
Find (a2
+ 3a − 4)(a + 2)
a3
+ 2a2
+ 3a2
+ 6a − 4a − 8
Example 6
Find (a2
+ 3a − 4)(a + 2)
a3
+ 2a2
+ 3a2
+ 6a − 4a − 8
a3
+ 5a2
+ 2a − 8

More Related Content

What's hot

Chain rule
Chain ruleChain rule
Chain rule
Sabin Tiger
 
4.1 the chain rule
4.1 the chain rule4.1 the chain rule
4.1 the chain rule
Aron Dotson
 
Rules of derivatives 2.2
Rules of derivatives 2.2Rules of derivatives 2.2
Rules of derivatives 2.2Lorie Blickhan
 
redes neuronais
redes neuronaisredes neuronais
redes neuronais
Roland Silvestre
 
Lesson 11: The Chain Rule
Lesson 11: The Chain RuleLesson 11: The Chain Rule
Lesson 11: The Chain Rule
Matthew Leingang
 
solucionario de purcell 1
solucionario de purcell 1solucionario de purcell 1
solucionario de purcell 1
José Encalada
 
Engineering Mathematics - Total derivatives, chain rule and derivative of imp...
Engineering Mathematics - Total derivatives, chain rule and derivative of imp...Engineering Mathematics - Total derivatives, chain rule and derivative of imp...
Engineering Mathematics - Total derivatives, chain rule and derivative of imp...
Jayanshu Gundaniya
 
Common derivatives integrals
Common derivatives integralsCommon derivatives integrals
Common derivatives integrals
Kavin Ruk
 
19 trig substitutions-x
19 trig substitutions-x19 trig substitutions-x
19 trig substitutions-x
math266
 
Chain Rule
Chain RuleChain Rule
Chain Rule
Nishant Patel
 
Engg. math 1 question bank by mohammad imran
Engg. math  1 question bank by mohammad imran Engg. math  1 question bank by mohammad imran
Engg. math 1 question bank by mohammad imran
Mohammad Imran
 
Lesson 27: Integration by Substitution (Section 041 slides)
Lesson 27: Integration by Substitution (Section 041 slides)Lesson 27: Integration by Substitution (Section 041 slides)
Lesson 27: Integration by Substitution (Section 041 slides)
Matthew Leingang
 
5.2 the substitution methods
5.2 the substitution methods5.2 the substitution methods
5.2 the substitution methodsmath265
 
MA8353 TPDE
MA8353 TPDEMA8353 TPDE
MA8353 TPDE
rmkceteee
 
1520 differentiation-l1
1520 differentiation-l11520 differentiation-l1
1520 differentiation-l1
Dr Fereidoun Dejahang
 

What's hot (20)

Chain rule
Chain ruleChain rule
Chain rule
 
4.1 the chain rule
4.1 the chain rule4.1 the chain rule
4.1 the chain rule
 
Rules of derivatives 2.2
Rules of derivatives 2.2Rules of derivatives 2.2
Rules of derivatives 2.2
 
Chain Rule
Chain RuleChain Rule
Chain Rule
 
redes neuronais
redes neuronaisredes neuronais
redes neuronais
 
Lesson 11: The Chain Rule
Lesson 11: The Chain RuleLesson 11: The Chain Rule
Lesson 11: The Chain Rule
 
solucionario de purcell 1
solucionario de purcell 1solucionario de purcell 1
solucionario de purcell 1
 
11365.integral 2
11365.integral 211365.integral 2
11365.integral 2
 
Engineering Mathematics - Total derivatives, chain rule and derivative of imp...
Engineering Mathematics - Total derivatives, chain rule and derivative of imp...Engineering Mathematics - Total derivatives, chain rule and derivative of imp...
Engineering Mathematics - Total derivatives, chain rule and derivative of imp...
 
Common derivatives integrals
Common derivatives integralsCommon derivatives integrals
Common derivatives integrals
 
19 trig substitutions-x
19 trig substitutions-x19 trig substitutions-x
19 trig substitutions-x
 
Chain Rule
Chain RuleChain Rule
Chain Rule
 
Mech MA6351 tpde_notes
Mech MA6351 tpde_notes Mech MA6351 tpde_notes
Mech MA6351 tpde_notes
 
Alg2 lesson 3-2
Alg2 lesson 3-2Alg2 lesson 3-2
Alg2 lesson 3-2
 
Engg. math 1 question bank by mohammad imran
Engg. math  1 question bank by mohammad imran Engg. math  1 question bank by mohammad imran
Engg. math 1 question bank by mohammad imran
 
Lesson 27: Integration by Substitution (Section 041 slides)
Lesson 27: Integration by Substitution (Section 041 slides)Lesson 27: Integration by Substitution (Section 041 slides)
Lesson 27: Integration by Substitution (Section 041 slides)
 
Chapter 1 (maths 3)
Chapter 1 (maths 3)Chapter 1 (maths 3)
Chapter 1 (maths 3)
 
5.2 the substitution methods
5.2 the substitution methods5.2 the substitution methods
5.2 the substitution methods
 
MA8353 TPDE
MA8353 TPDEMA8353 TPDE
MA8353 TPDE
 
1520 differentiation-l1
1520 differentiation-l11520 differentiation-l1
1520 differentiation-l1
 

Similar to Algebra 2 Section 4-1

Special Products and Factors.pptx
Special Products and Factors.pptxSpecial Products and Factors.pptx
Special Products and Factors.pptx
JanineCaleon
 
G8 Math Q1- Week 1-2 Special Products and Factors (1).pptx
G8 Math Q1- Week 1-2 Special Products and Factors (1).pptxG8 Math Q1- Week 1-2 Special Products and Factors (1).pptx
G8 Math Q1- Week 1-2 Special Products and Factors (1).pptx
CatherineGanLabaro
 
Business Math Chapter 2
Business Math Chapter 2Business Math Chapter 2
Business Math Chapter 2
Nazrin Nazdri
 
Properties Of Exponents
Properties Of ExponentsProperties Of Exponents
Properties Of Exponentsnina
 
New Properties
New PropertiesNew Properties
New Propertiesnina
 
Module 2 exponential functions
Module 2   exponential functionsModule 2   exponential functions
Module 2 exponential functions
dionesioable
 
Sifat Limit Fungsi Aljabar dan Contoh Soal
Sifat Limit Fungsi Aljabar dan Contoh SoalSifat Limit Fungsi Aljabar dan Contoh Soal
Sifat Limit Fungsi Aljabar dan Contoh Soal
Asrifida Juwita Tanjung
 
Algebra 2 Section 1-8
Algebra 2 Section 1-8Algebra 2 Section 1-8
Algebra 2 Section 1-8
Jimbo Lamb
 
exponen dan logaritma
exponen dan logaritmaexponen dan logaritma
exponen dan logaritma
Hanifa Zulfitri
 
Polynomial operations (1)
Polynomial operations (1)Polynomial operations (1)
Polynomial operations (1)swartzje
 
Laws of Exponent
Laws of ExponentLaws of Exponent
Laws of Exponent
JonathanSantos232
 
Lesson 10 derivative of exponential functions
Lesson 10 derivative of exponential functionsLesson 10 derivative of exponential functions
Lesson 10 derivative of exponential functions
Rnold Wilson
 
Chapter 6 taylor and maclaurin series
Chapter 6 taylor and maclaurin seriesChapter 6 taylor and maclaurin series
Chapter 6 taylor and maclaurin series
Irfaan Bahadoor
 
Algebra 2 Section 4-6
Algebra 2 Section 4-6Algebra 2 Section 4-6
Algebra 2 Section 4-6
Jimbo Lamb
 
Ah unit 1 differentiation
Ah unit 1 differentiationAh unit 1 differentiation
Ah unit 1 differentiation
sjamaths
 
Integration_of_Rational_Functions_by_Partial_Fraction.ppt
Integration_of_Rational_Functions_by_Partial_Fraction.pptIntegration_of_Rational_Functions_by_Partial_Fraction.ppt
Integration_of_Rational_Functions_by_Partial_Fraction.ppt
silva765736
 
Module 3 quadratic functions
Module 3   quadratic functionsModule 3   quadratic functions
Module 3 quadratic functions
dionesioable
 
Transforming Quadratic functions from General Form to Standard Form
Transforming Quadratic functions from General Form to Standard FormTransforming Quadratic functions from General Form to Standard Form
Transforming Quadratic functions from General Form to Standard Form
Ivy Estrella
 
Review
ReviewReview

Similar to Algebra 2 Section 4-1 (20)

Special Products and Factors.pptx
Special Products and Factors.pptxSpecial Products and Factors.pptx
Special Products and Factors.pptx
 
G8 Math Q1- Week 1-2 Special Products and Factors (1).pptx
G8 Math Q1- Week 1-2 Special Products and Factors (1).pptxG8 Math Q1- Week 1-2 Special Products and Factors (1).pptx
G8 Math Q1- Week 1-2 Special Products and Factors (1).pptx
 
Business Math Chapter 2
Business Math Chapter 2Business Math Chapter 2
Business Math Chapter 2
 
Properties Of Exponents
Properties Of ExponentsProperties Of Exponents
Properties Of Exponents
 
New Properties
New PropertiesNew Properties
New Properties
 
Module 2 exponential functions
Module 2   exponential functionsModule 2   exponential functions
Module 2 exponential functions
 
Sifat Limit Fungsi Aljabar dan Contoh Soal
Sifat Limit Fungsi Aljabar dan Contoh SoalSifat Limit Fungsi Aljabar dan Contoh Soal
Sifat Limit Fungsi Aljabar dan Contoh Soal
 
Algebra 2 Section 1-8
Algebra 2 Section 1-8Algebra 2 Section 1-8
Algebra 2 Section 1-8
 
exponen dan logaritma
exponen dan logaritmaexponen dan logaritma
exponen dan logaritma
 
Polynomial operations (1)
Polynomial operations (1)Polynomial operations (1)
Polynomial operations (1)
 
Laws of Exponent
Laws of ExponentLaws of Exponent
Laws of Exponent
 
Lesson 10 derivative of exponential functions
Lesson 10 derivative of exponential functionsLesson 10 derivative of exponential functions
Lesson 10 derivative of exponential functions
 
Chapter 6 taylor and maclaurin series
Chapter 6 taylor and maclaurin seriesChapter 6 taylor and maclaurin series
Chapter 6 taylor and maclaurin series
 
Algebra 2 Section 4-6
Algebra 2 Section 4-6Algebra 2 Section 4-6
Algebra 2 Section 4-6
 
Ah unit 1 differentiation
Ah unit 1 differentiationAh unit 1 differentiation
Ah unit 1 differentiation
 
8.1
8.18.1
8.1
 
Integration_of_Rational_Functions_by_Partial_Fraction.ppt
Integration_of_Rational_Functions_by_Partial_Fraction.pptIntegration_of_Rational_Functions_by_Partial_Fraction.ppt
Integration_of_Rational_Functions_by_Partial_Fraction.ppt
 
Module 3 quadratic functions
Module 3   quadratic functionsModule 3   quadratic functions
Module 3 quadratic functions
 
Transforming Quadratic functions from General Form to Standard Form
Transforming Quadratic functions from General Form to Standard FormTransforming Quadratic functions from General Form to Standard Form
Transforming Quadratic functions from General Form to Standard Form
 
Review
ReviewReview
Review
 

More from Jimbo Lamb

Geometry Section 1-5
Geometry Section 1-5Geometry Section 1-5
Geometry Section 1-5
Jimbo Lamb
 
Geometry Section 1-4
Geometry Section 1-4Geometry Section 1-4
Geometry Section 1-4
Jimbo Lamb
 
Geometry Section 1-3
Geometry Section 1-3Geometry Section 1-3
Geometry Section 1-3
Jimbo Lamb
 
Geometry Section 1-2
Geometry Section 1-2Geometry Section 1-2
Geometry Section 1-2
Jimbo Lamb
 
Geometry Section 1-2
Geometry Section 1-2Geometry Section 1-2
Geometry Section 1-2
Jimbo Lamb
 
Geometry Section 1-1
Geometry Section 1-1Geometry Section 1-1
Geometry Section 1-1
Jimbo Lamb
 
Algebra 2 Section 5-3
Algebra 2 Section 5-3Algebra 2 Section 5-3
Algebra 2 Section 5-3
Jimbo Lamb
 
Algebra 2 Section 5-2
Algebra 2 Section 5-2Algebra 2 Section 5-2
Algebra 2 Section 5-2
Jimbo Lamb
 
Algebra 2 Section 5-1
Algebra 2 Section 5-1Algebra 2 Section 5-1
Algebra 2 Section 5-1
Jimbo Lamb
 
Algebra 2 Section 4-9
Algebra 2 Section 4-9Algebra 2 Section 4-9
Algebra 2 Section 4-9
Jimbo Lamb
 
Algebra 2 Section 4-8
Algebra 2 Section 4-8Algebra 2 Section 4-8
Algebra 2 Section 4-8
Jimbo Lamb
 
Geometry Section 6-6
Geometry Section 6-6Geometry Section 6-6
Geometry Section 6-6
Jimbo Lamb
 
Geometry Section 6-5
Geometry Section 6-5Geometry Section 6-5
Geometry Section 6-5
Jimbo Lamb
 
Geometry Section 6-4
Geometry Section 6-4Geometry Section 6-4
Geometry Section 6-4
Jimbo Lamb
 
Geometry Section 6-3
Geometry Section 6-3Geometry Section 6-3
Geometry Section 6-3
Jimbo Lamb
 
Geometry Section 6-2
Geometry Section 6-2Geometry Section 6-2
Geometry Section 6-2
Jimbo Lamb
 
Geometry Section 6-1
Geometry Section 6-1Geometry Section 6-1
Geometry Section 6-1
Jimbo Lamb
 
Algebra 2 Section 4-5
Algebra 2 Section 4-5Algebra 2 Section 4-5
Algebra 2 Section 4-5
Jimbo Lamb
 
Algebra 2 Section 4-4
Algebra 2 Section 4-4Algebra 2 Section 4-4
Algebra 2 Section 4-4
Jimbo Lamb
 
Algebra 2 Section 4-2
Algebra 2 Section 4-2Algebra 2 Section 4-2
Algebra 2 Section 4-2
Jimbo Lamb
 

More from Jimbo Lamb (20)

Geometry Section 1-5
Geometry Section 1-5Geometry Section 1-5
Geometry Section 1-5
 
Geometry Section 1-4
Geometry Section 1-4Geometry Section 1-4
Geometry Section 1-4
 
Geometry Section 1-3
Geometry Section 1-3Geometry Section 1-3
Geometry Section 1-3
 
Geometry Section 1-2
Geometry Section 1-2Geometry Section 1-2
Geometry Section 1-2
 
Geometry Section 1-2
Geometry Section 1-2Geometry Section 1-2
Geometry Section 1-2
 
Geometry Section 1-1
Geometry Section 1-1Geometry Section 1-1
Geometry Section 1-1
 
Algebra 2 Section 5-3
Algebra 2 Section 5-3Algebra 2 Section 5-3
Algebra 2 Section 5-3
 
Algebra 2 Section 5-2
Algebra 2 Section 5-2Algebra 2 Section 5-2
Algebra 2 Section 5-2
 
Algebra 2 Section 5-1
Algebra 2 Section 5-1Algebra 2 Section 5-1
Algebra 2 Section 5-1
 
Algebra 2 Section 4-9
Algebra 2 Section 4-9Algebra 2 Section 4-9
Algebra 2 Section 4-9
 
Algebra 2 Section 4-8
Algebra 2 Section 4-8Algebra 2 Section 4-8
Algebra 2 Section 4-8
 
Geometry Section 6-6
Geometry Section 6-6Geometry Section 6-6
Geometry Section 6-6
 
Geometry Section 6-5
Geometry Section 6-5Geometry Section 6-5
Geometry Section 6-5
 
Geometry Section 6-4
Geometry Section 6-4Geometry Section 6-4
Geometry Section 6-4
 
Geometry Section 6-3
Geometry Section 6-3Geometry Section 6-3
Geometry Section 6-3
 
Geometry Section 6-2
Geometry Section 6-2Geometry Section 6-2
Geometry Section 6-2
 
Geometry Section 6-1
Geometry Section 6-1Geometry Section 6-1
Geometry Section 6-1
 
Algebra 2 Section 4-5
Algebra 2 Section 4-5Algebra 2 Section 4-5
Algebra 2 Section 4-5
 
Algebra 2 Section 4-4
Algebra 2 Section 4-4Algebra 2 Section 4-4
Algebra 2 Section 4-4
 
Algebra 2 Section 4-2
Algebra 2 Section 4-2Algebra 2 Section 4-2
Algebra 2 Section 4-2
 

Recently uploaded

Cambridge International AS A Level Biology Coursebook - EBook (MaryFosbery J...
Cambridge International AS  A Level Biology Coursebook - EBook (MaryFosbery J...Cambridge International AS  A Level Biology Coursebook - EBook (MaryFosbery J...
Cambridge International AS A Level Biology Coursebook - EBook (MaryFosbery J...
AzmatAli747758
 
Basic phrases for greeting and assisting costumers
Basic phrases for greeting and assisting costumersBasic phrases for greeting and assisting costumers
Basic phrases for greeting and assisting costumers
PedroFerreira53928
 
How to Split Bills in the Odoo 17 POS Module
How to Split Bills in the Odoo 17 POS ModuleHow to Split Bills in the Odoo 17 POS Module
How to Split Bills in the Odoo 17 POS Module
Celine George
 
2024.06.01 Introducing a competency framework for languag learning materials ...
2024.06.01 Introducing a competency framework for languag learning materials ...2024.06.01 Introducing a competency framework for languag learning materials ...
2024.06.01 Introducing a competency framework for languag learning materials ...
Sandy Millin
 
Overview on Edible Vaccine: Pros & Cons with Mechanism
Overview on Edible Vaccine: Pros & Cons with MechanismOverview on Edible Vaccine: Pros & Cons with Mechanism
Overview on Edible Vaccine: Pros & Cons with Mechanism
DeeptiGupta154
 
The French Revolution Class 9 Study Material pdf free download
The French Revolution Class 9 Study Material pdf free downloadThe French Revolution Class 9 Study Material pdf free download
The French Revolution Class 9 Study Material pdf free download
Vivekanand Anglo Vedic Academy
 
GIÁO ÁN DẠY THÊM (KẾ HOẠCH BÀI BUỔI 2) - TIẾNG ANH 8 GLOBAL SUCCESS (2 CỘT) N...
GIÁO ÁN DẠY THÊM (KẾ HOẠCH BÀI BUỔI 2) - TIẾNG ANH 8 GLOBAL SUCCESS (2 CỘT) N...GIÁO ÁN DẠY THÊM (KẾ HOẠCH BÀI BUỔI 2) - TIẾNG ANH 8 GLOBAL SUCCESS (2 CỘT) N...
GIÁO ÁN DẠY THÊM (KẾ HOẠCH BÀI BUỔI 2) - TIẾNG ANH 8 GLOBAL SUCCESS (2 CỘT) N...
Nguyen Thanh Tu Collection
 
How to Break the cycle of negative Thoughts
How to Break the cycle of negative ThoughtsHow to Break the cycle of negative Thoughts
How to Break the cycle of negative Thoughts
Col Mukteshwar Prasad
 
Unit 2- Research Aptitude (UGC NET Paper I).pdf
Unit 2- Research Aptitude (UGC NET Paper I).pdfUnit 2- Research Aptitude (UGC NET Paper I).pdf
Unit 2- Research Aptitude (UGC NET Paper I).pdf
Thiyagu K
 
Chapter 3 - Islamic Banking Products and Services.pptx
Chapter 3 - Islamic Banking Products and Services.pptxChapter 3 - Islamic Banking Products and Services.pptx
Chapter 3 - Islamic Banking Products and Services.pptx
Mohd Adib Abd Muin, Senior Lecturer at Universiti Utara Malaysia
 
Unit 8 - Information and Communication Technology (Paper I).pdf
Unit 8 - Information and Communication Technology (Paper I).pdfUnit 8 - Information and Communication Technology (Paper I).pdf
Unit 8 - Information and Communication Technology (Paper I).pdf
Thiyagu K
 
Thesis Statement for students diagnonsed withADHD.ppt
Thesis Statement for students diagnonsed withADHD.pptThesis Statement for students diagnonsed withADHD.ppt
Thesis Statement for students diagnonsed withADHD.ppt
EverAndrsGuerraGuerr
 
Home assignment II on Spectroscopy 2024 Answers.pdf
Home assignment II on Spectroscopy 2024 Answers.pdfHome assignment II on Spectroscopy 2024 Answers.pdf
Home assignment II on Spectroscopy 2024 Answers.pdf
Tamralipta Mahavidyalaya
 
The approach at University of Liverpool.pptx
The approach at University of Liverpool.pptxThe approach at University of Liverpool.pptx
The approach at University of Liverpool.pptx
Jisc
 
The Roman Empire A Historical Colossus.pdf
The Roman Empire A Historical Colossus.pdfThe Roman Empire A Historical Colossus.pdf
The Roman Empire A Historical Colossus.pdf
kaushalkr1407
 
Model Attribute Check Company Auto Property
Model Attribute  Check Company Auto PropertyModel Attribute  Check Company Auto Property
Model Attribute Check Company Auto Property
Celine George
 
ESC Beyond Borders _From EU to You_ InfoPack general.pdf
ESC Beyond Borders _From EU to You_ InfoPack general.pdfESC Beyond Borders _From EU to You_ InfoPack general.pdf
ESC Beyond Borders _From EU to You_ InfoPack general.pdf
Fundacja Rozwoju Społeczeństwa Przedsiębiorczego
 
Phrasal Verbs.XXXXXXXXXXXXXXXXXXXXXXXXXX
Phrasal Verbs.XXXXXXXXXXXXXXXXXXXXXXXXXXPhrasal Verbs.XXXXXXXXXXXXXXXXXXXXXXXXXX
Phrasal Verbs.XXXXXXXXXXXXXXXXXXXXXXXXXX
MIRIAMSALINAS13
 
Language Across the Curriculm LAC B.Ed.
Language Across the  Curriculm LAC B.Ed.Language Across the  Curriculm LAC B.Ed.
Language Across the Curriculm LAC B.Ed.
Atul Kumar Singh
 
Students, digital devices and success - Andreas Schleicher - 27 May 2024..pptx
Students, digital devices and success - Andreas Schleicher - 27 May 2024..pptxStudents, digital devices and success - Andreas Schleicher - 27 May 2024..pptx
Students, digital devices and success - Andreas Schleicher - 27 May 2024..pptx
EduSkills OECD
 

Recently uploaded (20)

Cambridge International AS A Level Biology Coursebook - EBook (MaryFosbery J...
Cambridge International AS  A Level Biology Coursebook - EBook (MaryFosbery J...Cambridge International AS  A Level Biology Coursebook - EBook (MaryFosbery J...
Cambridge International AS A Level Biology Coursebook - EBook (MaryFosbery J...
 
Basic phrases for greeting and assisting costumers
Basic phrases for greeting and assisting costumersBasic phrases for greeting and assisting costumers
Basic phrases for greeting and assisting costumers
 
How to Split Bills in the Odoo 17 POS Module
How to Split Bills in the Odoo 17 POS ModuleHow to Split Bills in the Odoo 17 POS Module
How to Split Bills in the Odoo 17 POS Module
 
2024.06.01 Introducing a competency framework for languag learning materials ...
2024.06.01 Introducing a competency framework for languag learning materials ...2024.06.01 Introducing a competency framework for languag learning materials ...
2024.06.01 Introducing a competency framework for languag learning materials ...
 
Overview on Edible Vaccine: Pros & Cons with Mechanism
Overview on Edible Vaccine: Pros & Cons with MechanismOverview on Edible Vaccine: Pros & Cons with Mechanism
Overview on Edible Vaccine: Pros & Cons with Mechanism
 
The French Revolution Class 9 Study Material pdf free download
The French Revolution Class 9 Study Material pdf free downloadThe French Revolution Class 9 Study Material pdf free download
The French Revolution Class 9 Study Material pdf free download
 
GIÁO ÁN DẠY THÊM (KẾ HOẠCH BÀI BUỔI 2) - TIẾNG ANH 8 GLOBAL SUCCESS (2 CỘT) N...
GIÁO ÁN DẠY THÊM (KẾ HOẠCH BÀI BUỔI 2) - TIẾNG ANH 8 GLOBAL SUCCESS (2 CỘT) N...GIÁO ÁN DẠY THÊM (KẾ HOẠCH BÀI BUỔI 2) - TIẾNG ANH 8 GLOBAL SUCCESS (2 CỘT) N...
GIÁO ÁN DẠY THÊM (KẾ HOẠCH BÀI BUỔI 2) - TIẾNG ANH 8 GLOBAL SUCCESS (2 CỘT) N...
 
How to Break the cycle of negative Thoughts
How to Break the cycle of negative ThoughtsHow to Break the cycle of negative Thoughts
How to Break the cycle of negative Thoughts
 
Unit 2- Research Aptitude (UGC NET Paper I).pdf
Unit 2- Research Aptitude (UGC NET Paper I).pdfUnit 2- Research Aptitude (UGC NET Paper I).pdf
Unit 2- Research Aptitude (UGC NET Paper I).pdf
 
Chapter 3 - Islamic Banking Products and Services.pptx
Chapter 3 - Islamic Banking Products and Services.pptxChapter 3 - Islamic Banking Products and Services.pptx
Chapter 3 - Islamic Banking Products and Services.pptx
 
Unit 8 - Information and Communication Technology (Paper I).pdf
Unit 8 - Information and Communication Technology (Paper I).pdfUnit 8 - Information and Communication Technology (Paper I).pdf
Unit 8 - Information and Communication Technology (Paper I).pdf
 
Thesis Statement for students diagnonsed withADHD.ppt
Thesis Statement for students diagnonsed withADHD.pptThesis Statement for students diagnonsed withADHD.ppt
Thesis Statement for students diagnonsed withADHD.ppt
 
Home assignment II on Spectroscopy 2024 Answers.pdf
Home assignment II on Spectroscopy 2024 Answers.pdfHome assignment II on Spectroscopy 2024 Answers.pdf
Home assignment II on Spectroscopy 2024 Answers.pdf
 
The approach at University of Liverpool.pptx
The approach at University of Liverpool.pptxThe approach at University of Liverpool.pptx
The approach at University of Liverpool.pptx
 
The Roman Empire A Historical Colossus.pdf
The Roman Empire A Historical Colossus.pdfThe Roman Empire A Historical Colossus.pdf
The Roman Empire A Historical Colossus.pdf
 
Model Attribute Check Company Auto Property
Model Attribute  Check Company Auto PropertyModel Attribute  Check Company Auto Property
Model Attribute Check Company Auto Property
 
ESC Beyond Borders _From EU to You_ InfoPack general.pdf
ESC Beyond Borders _From EU to You_ InfoPack general.pdfESC Beyond Borders _From EU to You_ InfoPack general.pdf
ESC Beyond Borders _From EU to You_ InfoPack general.pdf
 
Phrasal Verbs.XXXXXXXXXXXXXXXXXXXXXXXXXX
Phrasal Verbs.XXXXXXXXXXXXXXXXXXXXXXXXXXPhrasal Verbs.XXXXXXXXXXXXXXXXXXXXXXXXXX
Phrasal Verbs.XXXXXXXXXXXXXXXXXXXXXXXXXX
 
Language Across the Curriculm LAC B.Ed.
Language Across the  Curriculm LAC B.Ed.Language Across the  Curriculm LAC B.Ed.
Language Across the Curriculm LAC B.Ed.
 
Students, digital devices and success - Andreas Schleicher - 27 May 2024..pptx
Students, digital devices and success - Andreas Schleicher - 27 May 2024..pptxStudents, digital devices and success - Andreas Schleicher - 27 May 2024..pptx
Students, digital devices and success - Andreas Schleicher - 27 May 2024..pptx
 

Algebra 2 Section 4-1

  • 2. Essential Questions • How do you multiply, divide, and simplify monomials and expressions involving powers? • How do you add, subtract, and multiply polynomials?
  • 4. Vocabulary 1. Simplify: To eliminate all powers by applying all rules so that there are no parentheses or negative exponents remaining 2. Degree of a Polynomial:
  • 5. Vocabulary 1. Simplify: To eliminate all powers by applying all rules so that there are no parentheses or negative exponents remaining 2. Degree of a Polynomial: The sum of all of the powers of the term with the highest degree
  • 6. Properties of Powers Property Rule Example 1 Example 2 Product of Powers Power of a Power Power of a Product Quotient of Powers
  • 7. Properties of Powers Property Rule Example 1 Example 2 Product of Powers Power of a Power Power of a Product Quotient of Powers xm i xn = xm+n
  • 8. Properties of Powers Property Rule Example 1 Example 2 Product of Powers Power of a Power Power of a Product Quotient of Powers xm i xn = xm+n x3 i x2
  • 9. Properties of Powers Property Rule Example 1 Example 2 Product of Powers Power of a Power Power of a Product Quotient of Powers xm i xn = xm+n x3 i x2 x5
  • 10. Properties of Powers Property Rule Example 1 Example 2 Product of Powers Power of a Power Power of a Product Quotient of Powers xm i xn = xm+n x3 i x2 24 i 25 x5
  • 11. Properties of Powers Property Rule Example 1 Example 2 Product of Powers Power of a Power Power of a Product Quotient of Powers xm i xn = xm+n x3 i x2 24 i 25 x5 29
  • 12. Properties of Powers Property Rule Example 1 Example 2 Product of Powers Power of a Power Power of a Product Quotient of Powers xm i xn = xm+n x3 i x2 24 i 25 x5 29 512
  • 13. Properties of Powers Property Rule Example 1 Example 2 Product of Powers Power of a Power Power of a Product Quotient of Powers xm i xn = xm+n x3 i x2 24 i 25 x5 29 512 (xm )n = xmn
  • 14. Properties of Powers Property Rule Example 1 Example 2 Product of Powers Power of a Power Power of a Product Quotient of Powers xm i xn = xm+n x3 i x2 24 i 25 x5 29 512 (xm )n = xmn (x7 )3
  • 15. Properties of Powers Property Rule Example 1 Example 2 Product of Powers Power of a Power Power of a Product Quotient of Powers xm i xn = xm+n x3 i x2 24 i 25 x5 29 512 (xm )n = xmn (x7 )3 x21
  • 16. Properties of Powers Property Rule Example 1 Example 2 Product of Powers Power of a Power Power of a Product Quotient of Powers xm i xn = xm+n x3 i x2 24 i 25 x5 29 512 (xm )n = xmn (x7 )3 x21 (32 )4
  • 17. Properties of Powers Property Rule Example 1 Example 2 Product of Powers Power of a Power Power of a Product Quotient of Powers xm i xn = xm+n x3 i x2 24 i 25 x5 29 512 (xm )n = xmn (x7 )3 x21 (32 )4 38
  • 18. Properties of Powers Property Rule Example 1 Example 2 Product of Powers Power of a Power Power of a Product Quotient of Powers xm i xn = xm+n x3 i x2 24 i 25 x5 29 512 (xm )n = xmn (x7 )3 x21 (32 )4 38 6561
  • 19. Properties of Powers Property Rule Example 1 Example 2 Product of Powers Power of a Power Power of a Product Quotient of Powers xm i xn = xm+n x3 i x2 24 i 25 x5 29 512 (xm )n = xmn (x7 )3 x21 (32 )4 38 6561 (ax)m = am xm
  • 20. Properties of Powers Property Rule Example 1 Example 2 Product of Powers Power of a Power Power of a Product Quotient of Powers xm i xn = xm+n x3 i x2 24 i 25 x5 29 512 (xm )n = xmn (x7 )3 x21 (32 )4 38 6561 (ax)m = am xm (2x)3
  • 21. Properties of Powers Property Rule Example 1 Example 2 Product of Powers Power of a Power Power of a Product Quotient of Powers xm i xn = xm+n x3 i x2 24 i 25 x5 29 512 (xm )n = xmn (x7 )3 x21 (32 )4 38 6561 (ax)m = am xm (2x)3 23 x3
  • 22. Properties of Powers Property Rule Example 1 Example 2 Product of Powers Power of a Power Power of a Product Quotient of Powers xm i xn = xm+n x3 i x2 24 i 25 x5 29 512 (xm )n = xmn (x7 )3 x21 (32 )4 38 6561 (ax)m = am xm (2x)3 23 x3 8x3
  • 23. Properties of Powers Property Rule Example 1 Example 2 Product of Powers Power of a Power Power of a Product Quotient of Powers xm i xn = xm+n x3 i x2 24 i 25 x5 29 512 (xm )n = xmn (x7 )3 x21 (32 )4 38 6561 (ax)m = am xm (2x)3 23 x3 8x3 (3x4 )2
  • 24. Properties of Powers Property Rule Example 1 Example 2 Product of Powers Power of a Power Power of a Product Quotient of Powers xm i xn = xm+n x3 i x2 24 i 25 x5 29 512 (xm )n = xmn (x7 )3 x21 (32 )4 38 6561 (ax)m = am xm (2x)3 23 x3 8x3 (3x4 )2 9x8
  • 25. Properties of Powers Property Rule Example 1 Example 2 Product of Powers Power of a Power Power of a Product Quotient of Powers xm i xn = xm+n x3 i x2 24 i 25 x5 29 512 (xm )n = xmn (x7 )3 x21 (32 )4 38 6561 (ax)m = am xm (2x)3 23 x3 8x3 (3x4 )2 9x8 xm xn = xm−n
  • 26. Properties of Powers Property Rule Example 1 Example 2 Product of Powers Power of a Power Power of a Product Quotient of Powers xm i xn = xm+n x3 i x2 24 i 25 x5 29 512 (xm )n = xmn (x7 )3 x21 (32 )4 38 6561 (ax)m = am xm (2x)3 23 x3 8x3 (3x4 )2 9x8 xm xn = xm−n x5 x2 = x3
  • 27. Properties of Powers Property Rule Example 1 Example 2 Product of Powers Power of a Power Power of a Product Quotient of Powers xm i xn = xm+n x3 i x2 24 i 25 x5 29 512 (xm )n = xmn (x7 )3 x21 (32 )4 38 6561 (ax)m = am xm (2x)3 23 x3 8x3 (3x4 )2 9x8 xm xn = xm−n x5 x2 = x3 6x12 y4 8x5 y = 3x7 y3 4
  • 28. Properties of Powers Property Rule Example 1 Example 2 Power of a Quotient Zero Power Negative Exponent
  • 29. Properties of Powers Property Rule Example 1 Example 2 Power of a Quotient Zero Power Negative Exponent x y ⎛ ⎝ ⎜ ⎞ ⎠ ⎟ m = xm ym
  • 30. Properties of Powers Property Rule Example 1 Example 2 Power of a Quotient Zero Power Negative Exponent x y ⎛ ⎝ ⎜ ⎞ ⎠ ⎟ m = xm ym x3 y2 ⎛ ⎝ ⎜ ⎞ ⎠ ⎟ 4 = x12 y8
  • 31. Properties of Powers Property Rule Example 1 Example 2 Power of a Quotient Zero Power Negative Exponent x y ⎛ ⎝ ⎜ ⎞ ⎠ ⎟ m = xm ym x3 y2 ⎛ ⎝ ⎜ ⎞ ⎠ ⎟ 4 = x12 y8 2x4 3y2 ⎛ ⎝ ⎜ ⎞ ⎠ ⎟ 5 = 32x20 243y10
  • 32. Properties of Powers Property Rule Example 1 Example 2 Power of a Quotient Zero Power Negative Exponent x y ⎛ ⎝ ⎜ ⎞ ⎠ ⎟ m = xm ym x3 y2 ⎛ ⎝ ⎜ ⎞ ⎠ ⎟ 4 = x12 y8 2x4 3y2 ⎛ ⎝ ⎜ ⎞ ⎠ ⎟ 5 = 32x20 243y10 x0 = 1
  • 33. Properties of Powers Property Rule Example 1 Example 2 Power of a Quotient Zero Power Negative Exponent x y ⎛ ⎝ ⎜ ⎞ ⎠ ⎟ m = xm ym x3 y2 ⎛ ⎝ ⎜ ⎞ ⎠ ⎟ 4 = x12 y8 2x4 3y2 ⎛ ⎝ ⎜ ⎞ ⎠ ⎟ 5 = 32x20 243y10 x0 = 1 (x7 )0 = 1
  • 34. Properties of Powers Property Rule Example 1 Example 2 Power of a Quotient Zero Power Negative Exponent x y ⎛ ⎝ ⎜ ⎞ ⎠ ⎟ m = xm ym x3 y2 ⎛ ⎝ ⎜ ⎞ ⎠ ⎟ 4 = x12 y8 2x4 3y2 ⎛ ⎝ ⎜ ⎞ ⎠ ⎟ 5 = 32x20 243y10 x0 = 1 (x7 )0 = 1 3x12 y4 z11 5x4 yz9 ⎛ ⎝ ⎜ ⎞ ⎠ ⎟ 0 = 1
  • 35. Properties of Powers Property Rule Example 1 Example 2 Power of a Quotient Zero Power Negative Exponent x y ⎛ ⎝ ⎜ ⎞ ⎠ ⎟ m = xm ym x3 y2 ⎛ ⎝ ⎜ ⎞ ⎠ ⎟ 4 = x12 y8 2x4 3y2 ⎛ ⎝ ⎜ ⎞ ⎠ ⎟ 5 = 32x20 243y10 x0 = 1 (x7 )0 = 1 3x12 y4 z11 5x4 yz9 ⎛ ⎝ ⎜ ⎞ ⎠ ⎟ 0 = 1 x−n = 1 xn
  • 36. Properties of Powers Property Rule Example 1 Example 2 Power of a Quotient Zero Power Negative Exponent x y ⎛ ⎝ ⎜ ⎞ ⎠ ⎟ m = xm ym x3 y2 ⎛ ⎝ ⎜ ⎞ ⎠ ⎟ 4 = x12 y8 2x4 3y2 ⎛ ⎝ ⎜ ⎞ ⎠ ⎟ 5 = 32x20 243y10 x0 = 1 (x7 )0 = 1 3x12 y4 z11 5x4 yz9 ⎛ ⎝ ⎜ ⎞ ⎠ ⎟ 0 = 1 x−n = 1 xn 1 x−n = xn
  • 37. Properties of Powers Property Rule Example 1 Example 2 Power of a Quotient Zero Power Negative Exponent x y ⎛ ⎝ ⎜ ⎞ ⎠ ⎟ m = xm ym x3 y2 ⎛ ⎝ ⎜ ⎞ ⎠ ⎟ 4 = x12 y8 2x4 3y2 ⎛ ⎝ ⎜ ⎞ ⎠ ⎟ 5 = 32x20 243y10 x0 = 1 (x7 )0 = 1 3x12 y4 z11 5x4 yz9 ⎛ ⎝ ⎜ ⎞ ⎠ ⎟ 0 = 1 x−n = 1 xn 1 x−n = xn x−4 y z−5 = yz5 x4
  • 38. Example 1 Simplify. a. (a−3 )(a2 b4 )(c−1 ) b. n2 n10 c. 3a2 b4 ⎛ ⎝⎜ ⎞ ⎠⎟ 2
  • 39. Example 1 Simplify. a. (a−3 )(a2 b4 )(c−1 ) b. n2 n10 a−1 b4 c−1 c. 3a2 b4 ⎛ ⎝⎜ ⎞ ⎠⎟ 2
  • 40. Example 1 Simplify. a. (a−3 )(a2 b4 )(c−1 ) b. n2 n10 a−1 b4 c−1 b4 ac c. 3a2 b4 ⎛ ⎝⎜ ⎞ ⎠⎟ 2
  • 41. Example 1 Simplify. a. (a−3 )(a2 b4 )(c−1 ) b. n2 n10 a−1 b4 c−1 b4 ac 1 n8 c. 3a2 b4 ⎛ ⎝⎜ ⎞ ⎠⎟ 2
  • 42. Example 1 Simplify. a. (a−3 )(a2 b4 )(c−1 ) b. n2 n10 a−1 b4 c−1 b4 ac 1 n8 c. 3a2 b4 ⎛ ⎝⎜ ⎞ ⎠⎟ 2 9a4 b8
  • 43. Example 2 Determine whether each expression is a polynomial. If is is, state the degree of the polynomial. a. c4 − 4 c +18 b. −16p5 + 3 4 p2 t7 c. x 2 − 3x −1 + 7
  • 44. Example 2 Determine whether each expression is a polynomial. If is is, state the degree of the polynomial. a. c4 − 4 c +18 b. −16p5 + 3 4 p2 t7 c. x 2 − 3x −1 + 7 No
  • 45. Example 2 Determine whether each expression is a polynomial. If is is, state the degree of the polynomial. a. c4 − 4 c +18 b. −16p5 + 3 4 p2 t7 c. x 2 − 3x −1 + 7 No Yes
  • 46. Example 2 Determine whether each expression is a polynomial. If is is, state the degree of the polynomial. a. c4 − 4 c +18 b. −16p5 + 3 4 p2 t7 c. x 2 − 3x −1 + 7 No Yes Degree: 9
  • 47. Example 2 Determine whether each expression is a polynomial. If is is, state the degree of the polynomial. a. c4 − 4 c +18 b. −16p5 + 3 4 p2 t7 c. x 2 − 3x −1 + 7 No Yes Degree: 9 No
  • 48. Example 3 Simplify each expression. a. (2a3 + 5a − 7)− (a3 − 3a + 2) b. (4x 2 − 9x + 3)+ (−2x 2 − 5x − 6)
  • 49. Example 3 Simplify each expression. a. (2a3 + 5a − 7)− (a3 − 3a + 2) 2a3 + 5a − 7 − a3 + 3a − 2 b. (4x 2 − 9x + 3)+ (−2x 2 − 5x − 6)
  • 50. Example 3 Simplify each expression. a. (2a3 + 5a − 7)− (a3 − 3a + 2) 2a3 + 5a − 7 − a3 + 3a − 2 a3 + 8a − 9 b. (4x 2 − 9x + 3)+ (−2x 2 − 5x − 6)
  • 51. Example 3 Simplify each expression. a. (2a3 + 5a − 7)− (a3 − 3a + 2) 2a3 + 5a − 7 − a3 + 3a − 2 a3 + 8a − 9 b. (4x 2 − 9x + 3)+ (−2x 2 − 5x − 6) 4x 2 − 9x + 3 − 2x 2 − 5x − 6
  • 52. Example 3 Simplify each expression. a. (2a3 + 5a − 7)− (a3 − 3a + 2) 2a3 + 5a − 7 − a3 + 3a − 2 a3 + 8a − 9 b. (4x 2 − 9x + 3)+ (−2x 2 − 5x − 6) 4x 2 − 9x + 3 − 2x 2 − 5x − 6 2x 2 −14x − 3
  • 53. Example 4 Find − y (4y 2 + 2y − 3).
  • 54. Example 4 Find − y (4y 2 + 2y − 3). −4y 3 − 2y 2 + 3y
  • 55. Example 5 0.001x 2 + 5x + 500 Matt Mitarnowski estimates that the cost in dollars associated with selling x units Shecky’s Shoe Shine is given by the expression . The revenue from selling x units is given by 10x. Write a polynomial to represent the profits generated by the product if profit = revenue − cost. x
  • 56. Example 5 0.001x 2 + 5x + 500 Matt Mitarnowski estimates that the cost in dollars associated with selling x units Shecky’s Shoe Shine is given by the expression . The revenue from selling x units is given by 10x. Write a polynomial to represent the profits generated by the product if profit = revenue − cost. x profit = 10x − (0.001x 2 + 5x + 500)
  • 57. Example 5 0.001x 2 + 5x + 500 Matt Mitarnowski estimates that the cost in dollars associated with selling x units Shecky’s Shoe Shine is given by the expression . The revenue from selling x units is given by 10x. Write a polynomial to represent the profits generated by the product if profit = revenue − cost. x profit = 10x − (0.001x 2 + 5x + 500) profit = −0.001x 2 + 5x − 500
  • 58. Example 6 Find (a2 + 3a − 4)(a + 2)
  • 59. Example 6 Find (a2 + 3a − 4)(a + 2) a3 + 2a2 + 3a2 + 6a − 4a − 8
  • 60. Example 6 Find (a2 + 3a − 4)(a + 2) a3 + 2a2 + 3a2 + 6a − 4a − 8 a3 + 5a2 + 2a − 8