CHAPTER 2 : EXPONENTS
& LOGARITHMS
2.1 EXPONENT
2.2 LOGARITHMS
2.3 EXPONENT & LOGARITHMS
EQUATION
INTRODUCTION
Why study exponential & logarithmic
functions?
 They are very important in many technical areas,
such as business, finance, nuclear technology,
acoustics, electronics & astronomy.
 Many of the applications will involve growth
(INCREASING) or decay (DECREASING).
 There are many things that grow exponentially, for
example population, compound interest &
charge in capacitor.
 We can also have exponentially decay for
example radioactive decay.
 Logarithm is a method of reducing long
multiplications into much simpler additions (and
reducing divisions into subtractions).
2.1 EXPONENT
Definition
 If a is any real number & n is a positive
integer, then the n – th power of a is ;
Exponent
(index / power)

a n = a × a × .... × a

Example:
base
x
Graph the function f ( x ) = 2
Solution;
Produce the table values of x from -2 to 3.
x

-2

f(x)

0.25

-1

0

1

2

3
2.1 EXPONENT
Law of exponents
Law

Example

am × an = am+n

x3x7 = x3+7 = x10

a ÷ a =a
m

n

m-n

k4
= k 4− 6 = k − 2
k6

(am)n = amn

(43)2 = 43(2)=46

(ab)n = anbn

(2b)3 = 23b3= 8b3

Try 
x2x-5 =
h5
=
−2
h

(55)2 =
(3xy)4 =
2.1 EXPONENT
Law of exponents
Law

Example

n

2 4 16
2
  = 4 =
81
3
3

4

 a  an
  = n
 b b

1
a = n
a
−n

 a
 
 b

−n

2
n

b
= n
a

−3

2
 
5

1 1
= 3 =
8
2

−2

=

2

5
25
=
4
22

Try 
2

w 
  =
4

3 −2 =
4
 
3

−3

=
2.1 EXPONENT
Radical, Rational, - ve & Zero exponent
 Radical : √  “ the positive square root of “
n – th root,
n any +ve
integer

n

a = b means b n = a
a ≥ 0, b ≥ 0

 Rational exponent : a

m

n

=

( a)
n

m

= n am

m & n are
integers, n > 0

 Zero exponent : a 0 = 1
 Negative exponent : a

−n

1
= n
a
PRACTICE 1
1. Evaluate the expression.

(

a) 4 −3 ⋅ 4 5

( )

b) 3 −2
c) 9( 9 )

a) 25 x 3 y 4

(

3

)(

)

−1 / 2

b) 4 x −2 − 3 x 5

−1 / 2

 1  2 
d)  −  
 3  



2. Simplify the expression.

−3

( − 3) 4 ( − 3) 5
e)
( − 3) 8
f) 23 / 4 ⋅ 4 −3 / 2

6a −4
c) −3
3a

)

d) y −3 / 2 y 5 / 3

(

e) 4 x 2 y 2 z 3

f)

)

2

( x + y )( x − y )
( x − y )0
2.2 LOGARITHMS
Definition
 Logarithm function with base a, denoted by loga is
Exponent
defined by;
Equivalent
(index / power)

base

loga y = x ⇔
 
 
logaritmic form

x

a 
=y

exponential form

3
Example: log5 125 = 3 ⇔ 5 = 125

log2 8 = 3 ⇔ 23 = 8
3 4 = 81 ⇔

form
2.2 LOGARITHMS
Type of Log
 Common logarithm : Logarithm with base 10, denoted
by,
log y = log y
10

 Natural logarithm : Logarithm with base e, denoted by
ln y = loge y
 Base conversion :

loga x log10 x ln x
logb x =
=
=
loga b log10 b ln b
Any
base

Base
10

Base e
Example 1
1. Rewrite each function below in exponential or
logarithm form.
a) 72 = 49
b) Log2128 = 7
c) 5-2 = 1/25
d) Logb1=0
2. Determine the value of log27 and log3 12.
log10 7
log2 7 =
= 2.8074
log10 2
2.2 LOGARITHMS
Law of logarithms
Logarithms
loga xy = loga x + loga y
loga (x/y) = loga x − loga y
loga (xn) = n loga x

Example
log 45x = log 45 + log 4x
ln 8 – ln 2 = ln (8/2) = ln 4
log 53 = 3log 5

loga a = 1

log33 = 1

loga 1 = 0

ln 1 = 0
Example 2
1. Use the property of logarithms to rewrite each of the
following:
a) ln 18 = ln (2.3.3) =
b) log 5 + log 2 =
c) log (3/5) =
d) log 8x2 – log 2x =
e) Log 1003.4 = log (102)3.4 =
2. Simplify & determine the value of ;
2log 5 + 3log 4 – 4log 2
PRACTICE 2
If log 2 = 0.3010, log 3 = 0.4771 and log 5 = 0.6990,
determine each of the following without using a
calculator:
a) log 6 = log 2x3 = log 2 + log 3
= 0.3010 + 0.4771 = 0.7781
b) log 81
c)

log 1.5

d)

log √5

e)

log 50
2.3 EXPONENTIAL & LOGARITHS
EQUATION
 Exponential Equation




The variable occurs in
the exponent.
E.g. 2x = 7
To solve:
1) Use the properties of
exp.
2) Rewrite in equivalent
form.
3) Solve the resulting
equation.

 Logarithmic Equation




A logarithm of the
variable occurs.
E.g. log2 (x+2) = 5
To solve:
1) Use the properties of
log.
2) Rewrite in equivalent
form.
3) Solve the resulting
equation.
Example 3
Solve each of the following;
a) 3x = 81
ln 3 x = ln 81
x ln 3 = ln 81
ln 81
x=
=4
ln 3

Take ln of each side
Law 3 (bring down the exponent)
Solve for x, use a calculator

b) 5 2 x +1 = (254x-1−1
52x+1 = 5 2 ) 4 x
log5 5 2 x +1 = log5 5 8 x −2

( 2x + 1) log5 5 = ( 8 x − 2) log5 5
2x + 1 = 8 x − 2
1
x=
2

Take log5 of each side
App ly Law 3 and Law 4
Solve for x
Example 3
Solve each of the following;
c) 8e2x = 20
8e 2 x = 20
20
8
= ln 2.5

e2x =
ln e 2 x

2x = 0.9163
x = 0.4582

Divide by 8
Take ln of each side
Property of ln
Solve for x
Example 4
Solve each of the following;
a) ln x = 7
x = e7
≈ 1096.6

Equivalent form
Use calculator

b) log2 (x+2) = 5
log2 ( x + 2) = 5

x + 2 = 25
x = 32 − 2
= 30

c) Log2(25 – x) = 3

Exponentia l form
Solve for x
Example 4
Solve each of the following;
d) 4 + 3log 2x = 16
3 log 2 x = 12
Subtract 4
log 2 x = 4
Divide by 3
2 x = 10 4
x = 5000

Exponentia l form
Divide by 2

2 ln 2 + ln x = ln 3
e) C
2 ln( x + 3 ) = ln( 4 x + 12)
f)

c
PRACTICE 3
Solve each of the following.
a) e 0.4t = 8

b) 5e −2t = 6
c) 12 − e 0.4t = 3

d) log2 x = 3

e) log3 27 = 2 x
f) log2 ( 2 x + 5 ) = 4
g) log2 x − log2 ( x − 2) = 3
h) log3 ( x + 1) − log3 ( x − 1) = 1

Business Math Chapter 2

  • 1.
    CHAPTER 2 :EXPONENTS & LOGARITHMS 2.1 EXPONENT 2.2 LOGARITHMS 2.3 EXPONENT & LOGARITHMS EQUATION
  • 2.
    INTRODUCTION Why study exponential& logarithmic functions?
  • 3.
     They arevery important in many technical areas, such as business, finance, nuclear technology, acoustics, electronics & astronomy.  Many of the applications will involve growth (INCREASING) or decay (DECREASING).  There are many things that grow exponentially, for example population, compound interest & charge in capacitor.  We can also have exponentially decay for example radioactive decay.  Logarithm is a method of reducing long multiplications into much simpler additions (and reducing divisions into subtractions).
  • 4.
    2.1 EXPONENT Definition  Ifa is any real number & n is a positive integer, then the n – th power of a is ; Exponent (index / power) a n = a × a × .... × a Example: base x Graph the function f ( x ) = 2 Solution; Produce the table values of x from -2 to 3. x -2 f(x) 0.25 -1 0 1 2 3
  • 5.
    2.1 EXPONENT Law ofexponents Law Example am × an = am+n x3x7 = x3+7 = x10 a ÷ a =a m n m-n k4 = k 4− 6 = k − 2 k6 (am)n = amn (43)2 = 43(2)=46 (ab)n = anbn (2b)3 = 23b3= 8b3 Try  x2x-5 = h5 = −2 h (55)2 = (3xy)4 =
  • 6.
    2.1 EXPONENT Law ofexponents Law Example n 2 4 16 2   = 4 = 81 3 3 4  a  an   = n  b b 1 a = n a −n  a    b −n 2 n b = n a −3 2   5 1 1 = 3 = 8 2 −2 = 2 5 25 = 4 22 Try  2 w    = 4 3 −2 = 4   3 −3 =
  • 7.
    2.1 EXPONENT Radical, Rational,- ve & Zero exponent  Radical : √  “ the positive square root of “ n – th root, n any +ve integer n a = b means b n = a a ≥ 0, b ≥ 0  Rational exponent : a m n = ( a) n m = n am m & n are integers, n > 0  Zero exponent : a 0 = 1  Negative exponent : a −n 1 = n a
  • 8.
    PRACTICE 1 1. Evaluatethe expression. ( a) 4 −3 ⋅ 4 5 ( ) b) 3 −2 c) 9( 9 ) a) 25 x 3 y 4 ( 3 )( ) −1 / 2 b) 4 x −2 − 3 x 5 −1 / 2  1  2  d)  −    3     2. Simplify the expression. −3 ( − 3) 4 ( − 3) 5 e) ( − 3) 8 f) 23 / 4 ⋅ 4 −3 / 2 6a −4 c) −3 3a ) d) y −3 / 2 y 5 / 3 ( e) 4 x 2 y 2 z 3 f) ) 2 ( x + y )( x − y ) ( x − y )0
  • 9.
    2.2 LOGARITHMS Definition  Logarithmfunction with base a, denoted by loga is Exponent defined by; Equivalent (index / power) base loga y = x ⇔     logaritmic form x a  =y  exponential form 3 Example: log5 125 = 3 ⇔ 5 = 125 log2 8 = 3 ⇔ 23 = 8 3 4 = 81 ⇔ form
  • 10.
    2.2 LOGARITHMS Type ofLog  Common logarithm : Logarithm with base 10, denoted by, log y = log y 10  Natural logarithm : Logarithm with base e, denoted by ln y = loge y  Base conversion : loga x log10 x ln x logb x = = = loga b log10 b ln b Any base Base 10 Base e
  • 11.
    Example 1 1. Rewriteeach function below in exponential or logarithm form. a) 72 = 49 b) Log2128 = 7 c) 5-2 = 1/25 d) Logb1=0 2. Determine the value of log27 and log3 12. log10 7 log2 7 = = 2.8074 log10 2
  • 12.
    2.2 LOGARITHMS Law oflogarithms Logarithms loga xy = loga x + loga y loga (x/y) = loga x − loga y loga (xn) = n loga x Example log 45x = log 45 + log 4x ln 8 – ln 2 = ln (8/2) = ln 4 log 53 = 3log 5 loga a = 1 log33 = 1 loga 1 = 0 ln 1 = 0
  • 13.
    Example 2 1. Usethe property of logarithms to rewrite each of the following: a) ln 18 = ln (2.3.3) = b) log 5 + log 2 = c) log (3/5) = d) log 8x2 – log 2x = e) Log 1003.4 = log (102)3.4 = 2. Simplify & determine the value of ; 2log 5 + 3log 4 – 4log 2
  • 14.
    PRACTICE 2 If log2 = 0.3010, log 3 = 0.4771 and log 5 = 0.6990, determine each of the following without using a calculator: a) log 6 = log 2x3 = log 2 + log 3 = 0.3010 + 0.4771 = 0.7781 b) log 81 c) log 1.5 d) log √5 e) log 50
  • 15.
    2.3 EXPONENTIAL &LOGARITHS EQUATION  Exponential Equation    The variable occurs in the exponent. E.g. 2x = 7 To solve: 1) Use the properties of exp. 2) Rewrite in equivalent form. 3) Solve the resulting equation.  Logarithmic Equation    A logarithm of the variable occurs. E.g. log2 (x+2) = 5 To solve: 1) Use the properties of log. 2) Rewrite in equivalent form. 3) Solve the resulting equation.
  • 16.
    Example 3 Solve eachof the following; a) 3x = 81 ln 3 x = ln 81 x ln 3 = ln 81 ln 81 x= =4 ln 3 Take ln of each side Law 3 (bring down the exponent) Solve for x, use a calculator b) 5 2 x +1 = (254x-1−1 52x+1 = 5 2 ) 4 x log5 5 2 x +1 = log5 5 8 x −2 ( 2x + 1) log5 5 = ( 8 x − 2) log5 5 2x + 1 = 8 x − 2 1 x= 2 Take log5 of each side App ly Law 3 and Law 4 Solve for x
  • 17.
    Example 3 Solve eachof the following; c) 8e2x = 20 8e 2 x = 20 20 8 = ln 2.5 e2x = ln e 2 x 2x = 0.9163 x = 0.4582 Divide by 8 Take ln of each side Property of ln Solve for x
  • 18.
    Example 4 Solve eachof the following; a) ln x = 7 x = e7 ≈ 1096.6 Equivalent form Use calculator b) log2 (x+2) = 5 log2 ( x + 2) = 5 x + 2 = 25 x = 32 − 2 = 30 c) Log2(25 – x) = 3 Exponentia l form Solve for x
  • 19.
    Example 4 Solve eachof the following; d) 4 + 3log 2x = 16 3 log 2 x = 12 Subtract 4 log 2 x = 4 Divide by 3 2 x = 10 4 x = 5000 Exponentia l form Divide by 2 2 ln 2 + ln x = ln 3 e) C 2 ln( x + 3 ) = ln( 4 x + 12) f) c
  • 20.
    PRACTICE 3 Solve eachof the following. a) e 0.4t = 8 b) 5e −2t = 6 c) 12 − e 0.4t = 3 d) log2 x = 3 e) log3 27 = 2 x f) log2 ( 2 x + 5 ) = 4 g) log2 x − log2 ( x − 2) = 3 h) log3 ( x + 1) − log3 ( x − 1) = 1