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*Dalton’s Law of
Partial Pressures
By Shawn P. Shields, Ph. D.
This work is licensed by Shawn P. Shields-Maxwell under a Creative Commons Attribution-
NonCommercial-ShareAlike 4.0 International License.
*Recall: The Ideal Gas Law
*The equation: PV = nRT
*Gases are described in terms of four
macroscopic observables:
*Pressure (P in atm)
*Temperature (T in Kelvin)
*Volume (V in L)
*Moles of gas (n)
*Recall that R is the gas constant: R =
0.0826 L atm
mol K
2
*Dalton’s Law of Partial Pressures
Recall that the Ideal Gas Law simply states that
the behavior of a gas in terms of its pressure,
temperature, and volume depends ONLY on the
number of moles of gas, NOT on the identity of
the gas.
Gas AThe moles of a
gas can be
thought of as
the number of
molecules of gas.
*Dalton’s Law of Partial Pressures
Dalton’s Law extends this idea to mixtures of
gases. The P-V-T properties of a mixture of
gases will behave just like a pure gas.
The behavior of the gas only depends on the total
number of moles of gas, no matter their identity!
Gas A Gas A
Gas B
Gas C
Gas D
*Dalton’s Law of Partial Pressures
Both containers have the same volume and the
same number of gas particles (moles of gas).
At the same temperature, both the pure gas and
the mixture of gases will exert the same
pressure!
Gas A Gas A
Gas B
Gas C
Gas D
*Dalton’s Law of Partial Pressures
We can write an equation to calculate the
pressure of gas A in the container as
𝐏 𝐀 =
𝐧 𝐀 𝐑𝐓
𝐕
Gas A
All we’ve done is identify
“gas A” as a subscript in
the Ideal Gas Equation.
The pressure due to gas A
is just dependent on the
moles of gas A, at a given
T and V.
*Dalton’s Law of Partial Pressures
Now, let’s do the same thing for the mixture of
gases…
We can write an equation to calculate the total
pressure of all four gases in the container as
𝐏 𝐓𝐨𝐭𝐚𝐥 =
𝐧 𝐀 𝐑𝐓
𝐕
+
𝐧 𝐁 𝐑𝐓
𝐕
+
𝐧 𝐂 𝐑𝐓
𝐕
+
𝐧 𝐃 𝐑𝐓
𝐕
Gas A
Gas B
Gas C
Gas D
*Dalton’s Law of Partial Pressures
The total pressure due to the gases in the
container is
Gas A
Gas B
Gas C
Gas D
𝐏 𝐓𝐨𝐭𝐚𝐥 = 𝐏 𝐀 + 𝐏 𝐁 + 𝐏𝐂 + 𝐏 𝐃
Each gas exerts one-
fourth (¼) of the total
pressure!
The gases all behave
independently of one
another.
*The Mole Fraction
Let’s just look at the contribution from
gas B to the total pressure in the
container and write an equation for it.
𝐏 𝐁 =
𝒏 𝑩 𝑹𝑻
𝑽
Let’s also write the equation for the
total pressure another way…
𝐏 𝐓𝐨𝐭𝐚𝐥 =
𝒏 𝑻𝒐𝒕𝒂𝒍 𝑹𝑻
𝑽
*The Mole Fraction
Now, divide the equation for the “partial
pressure of gas B” (PB) by the total
pressure
𝐏 𝐁
𝐏 𝐓𝐨𝐭𝐚𝐥
=
𝒏 𝑩 𝑹𝑻
𝑽
𝒏 𝑻𝒐𝒕𝒂𝒍 𝑹𝑻
𝑽
Cancel out R, T, and V, since each has
the same value in both equations…
*The Mole Fraction
Now, divide the equation for the “partial
pressure of gas B” (PB) by the total
pressure
𝐏 𝐁
𝐏 𝐓𝐨𝐭𝐚𝐥
=
𝒏 𝑩 𝑹𝑻
𝑽
𝒏 𝑻𝒐𝒕𝒂𝒍 𝑹𝑻
𝑽
We are left with
𝐏 𝐁
𝐏 𝐓𝐨𝐭𝐚𝐥
=
𝐧 𝐁
𝐧 𝐓𝐨𝐭𝐚𝐥
*The Mole Fraction
Notice that the partial pressure of B is
equal to the fraction of gas B in the total
moles of gas…
We call this the “mole fraction” gas B.
𝐏 𝐁
𝐏 𝐓𝐨𝐭𝐚𝐥
=
𝐧 𝐁
𝐧 𝐓𝐨𝐭𝐚𝐥
= 𝛘 𝑩
𝐧 𝐁
𝐧 𝐓𝐨𝐭𝐚𝐥
= 𝛘 𝑩
*The Mole Fraction
Now, rearrange the equation to calculate
the fraction (or part) of the total
pressure that is contributed by gas B…
If we multiply the mole fraction of gas B by the
total pressure in the container, we get the
“partial pressure” of gas B.
In other words, we can calculate the pressure
that gas B is contributing all by itself. 
𝑷 𝑩 = 𝝌 𝑩 𝑷 𝑻𝒐𝒕𝒂𝒍
*A Simple Example…
The atmosphere is composed of 78% N2
gas, 21% O2 gas, and about 1% other
gases. If the total pressure of the
atmosphere is 1 atm, then what is the
partial pressure of N2?
What is the partial pressure of O2?
𝑷 𝑵 𝟐
= 𝝌 𝑵 𝟐
𝑷 𝑻𝒐𝒕𝒂𝒍
𝐏 𝐍 𝟐
= 𝟎. 𝟕𝟖 𝟏 𝐚𝐭𝐦 = 𝟎. 𝟕𝟖 𝐚𝐭𝐦
*Summary of Dalton’s Law
of Partial Pressures
The partial pressure of each gas in the
container is only dependent on its mole fraction.
Gas A
Gas B
Gas C
Gas D
If each gas in the container
has a mole fraction of one
fourth, then each gas
contributes ¼ of the total
pressure.
The gases do not interact,
so the mixture of gases
obeys the Ideal Gas Law. 
*Summary of Dalton’s Law
of Partial Pressures
Suppose the total pressure in the container is
6.0 atm. What is the partial pressure of gas D
in the container?
(Hint: Count the gas molecules)
Gas A
Gas B
Gas C
Gas D
*Summary of Dalton’s Law
of Partial Pressures
Suppose the total pressure in the container is
6.0 atm. What is the partial pressure of gas D
in the container? Hint: Count the gas molecules.
Gas A
Gas B
Gas C
Gas D
Gas D contributes ¼ of 6.0 atm.
𝐏 𝐃 = 𝛘 𝐃 𝐏 𝐓𝐨𝐭𝐚𝐥
𝐏 𝐃 = 𝟎. 𝟐𝟓 𝟔. 𝟎 𝐚𝐭𝐦
𝐏 𝐃 = 𝟏. 𝟓 𝐚𝐭𝐦
Could you do this in your head?

*Summary of Dalton’s Law
of Partial Pressures
Suppose the total pressure in the container is 10 atm.
What is the partial pressure of gases B and C in the
container? (Hint: Count the gas molecules.)
Gas A
Gas B
Gas C
Gas D
*Summary of Dalton’s Law
of Partial Pressures
Suppose the total pressure in the container is 10 atm.
What is the partial pressure of gases B and C in the
container? (Hint: Count the gas molecules.)
Gas A
Gas B
Gas C
Gas D
Together, gases B and C
contribute ½ of 10 atm.
𝐏 𝐁+𝐂 = 𝛘 𝐁 +𝛘 𝐂 𝐏 𝐓𝐨𝐭𝐚𝐥
𝐏 𝐁+𝐂 = 𝟎. 𝟐𝟓 + 𝟎. 𝟐𝟓 𝟏𝟎 𝐚𝐭𝐦
𝐏 𝐁+𝐂 = 𝟓 𝐚𝐭𝐦


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Unit 10 daltons law fl14 final

  • 1. *Dalton’s Law of Partial Pressures By Shawn P. Shields, Ph. D. This work is licensed by Shawn P. Shields-Maxwell under a Creative Commons Attribution- NonCommercial-ShareAlike 4.0 International License.
  • 2. *Recall: The Ideal Gas Law *The equation: PV = nRT *Gases are described in terms of four macroscopic observables: *Pressure (P in atm) *Temperature (T in Kelvin) *Volume (V in L) *Moles of gas (n) *Recall that R is the gas constant: R = 0.0826 L atm mol K 2
  • 3. *Dalton’s Law of Partial Pressures Recall that the Ideal Gas Law simply states that the behavior of a gas in terms of its pressure, temperature, and volume depends ONLY on the number of moles of gas, NOT on the identity of the gas. Gas AThe moles of a gas can be thought of as the number of molecules of gas.
  • 4. *Dalton’s Law of Partial Pressures Dalton’s Law extends this idea to mixtures of gases. The P-V-T properties of a mixture of gases will behave just like a pure gas. The behavior of the gas only depends on the total number of moles of gas, no matter their identity! Gas A Gas A Gas B Gas C Gas D
  • 5. *Dalton’s Law of Partial Pressures Both containers have the same volume and the same number of gas particles (moles of gas). At the same temperature, both the pure gas and the mixture of gases will exert the same pressure! Gas A Gas A Gas B Gas C Gas D
  • 6. *Dalton’s Law of Partial Pressures We can write an equation to calculate the pressure of gas A in the container as 𝐏 𝐀 = 𝐧 𝐀 𝐑𝐓 𝐕 Gas A All we’ve done is identify “gas A” as a subscript in the Ideal Gas Equation. The pressure due to gas A is just dependent on the moles of gas A, at a given T and V.
  • 7. *Dalton’s Law of Partial Pressures Now, let’s do the same thing for the mixture of gases… We can write an equation to calculate the total pressure of all four gases in the container as 𝐏 𝐓𝐨𝐭𝐚𝐥 = 𝐧 𝐀 𝐑𝐓 𝐕 + 𝐧 𝐁 𝐑𝐓 𝐕 + 𝐧 𝐂 𝐑𝐓 𝐕 + 𝐧 𝐃 𝐑𝐓 𝐕 Gas A Gas B Gas C Gas D
  • 8. *Dalton’s Law of Partial Pressures The total pressure due to the gases in the container is Gas A Gas B Gas C Gas D 𝐏 𝐓𝐨𝐭𝐚𝐥 = 𝐏 𝐀 + 𝐏 𝐁 + 𝐏𝐂 + 𝐏 𝐃 Each gas exerts one- fourth (¼) of the total pressure! The gases all behave independently of one another.
  • 9. *The Mole Fraction Let’s just look at the contribution from gas B to the total pressure in the container and write an equation for it. 𝐏 𝐁 = 𝒏 𝑩 𝑹𝑻 𝑽 Let’s also write the equation for the total pressure another way… 𝐏 𝐓𝐨𝐭𝐚𝐥 = 𝒏 𝑻𝒐𝒕𝒂𝒍 𝑹𝑻 𝑽
  • 10. *The Mole Fraction Now, divide the equation for the “partial pressure of gas B” (PB) by the total pressure 𝐏 𝐁 𝐏 𝐓𝐨𝐭𝐚𝐥 = 𝒏 𝑩 𝑹𝑻 𝑽 𝒏 𝑻𝒐𝒕𝒂𝒍 𝑹𝑻 𝑽 Cancel out R, T, and V, since each has the same value in both equations…
  • 11. *The Mole Fraction Now, divide the equation for the “partial pressure of gas B” (PB) by the total pressure 𝐏 𝐁 𝐏 𝐓𝐨𝐭𝐚𝐥 = 𝒏 𝑩 𝑹𝑻 𝑽 𝒏 𝑻𝒐𝒕𝒂𝒍 𝑹𝑻 𝑽 We are left with 𝐏 𝐁 𝐏 𝐓𝐨𝐭𝐚𝐥 = 𝐧 𝐁 𝐧 𝐓𝐨𝐭𝐚𝐥
  • 12. *The Mole Fraction Notice that the partial pressure of B is equal to the fraction of gas B in the total moles of gas… We call this the “mole fraction” gas B. 𝐏 𝐁 𝐏 𝐓𝐨𝐭𝐚𝐥 = 𝐧 𝐁 𝐧 𝐓𝐨𝐭𝐚𝐥 = 𝛘 𝑩 𝐧 𝐁 𝐧 𝐓𝐨𝐭𝐚𝐥 = 𝛘 𝑩
  • 13. *The Mole Fraction Now, rearrange the equation to calculate the fraction (or part) of the total pressure that is contributed by gas B… If we multiply the mole fraction of gas B by the total pressure in the container, we get the “partial pressure” of gas B. In other words, we can calculate the pressure that gas B is contributing all by itself.  𝑷 𝑩 = 𝝌 𝑩 𝑷 𝑻𝒐𝒕𝒂𝒍
  • 14. *A Simple Example… The atmosphere is composed of 78% N2 gas, 21% O2 gas, and about 1% other gases. If the total pressure of the atmosphere is 1 atm, then what is the partial pressure of N2? What is the partial pressure of O2? 𝑷 𝑵 𝟐 = 𝝌 𝑵 𝟐 𝑷 𝑻𝒐𝒕𝒂𝒍 𝐏 𝐍 𝟐 = 𝟎. 𝟕𝟖 𝟏 𝐚𝐭𝐦 = 𝟎. 𝟕𝟖 𝐚𝐭𝐦
  • 15. *Summary of Dalton’s Law of Partial Pressures The partial pressure of each gas in the container is only dependent on its mole fraction. Gas A Gas B Gas C Gas D If each gas in the container has a mole fraction of one fourth, then each gas contributes ¼ of the total pressure. The gases do not interact, so the mixture of gases obeys the Ideal Gas Law. 
  • 16. *Summary of Dalton’s Law of Partial Pressures Suppose the total pressure in the container is 6.0 atm. What is the partial pressure of gas D in the container? (Hint: Count the gas molecules) Gas A Gas B Gas C Gas D
  • 17. *Summary of Dalton’s Law of Partial Pressures Suppose the total pressure in the container is 6.0 atm. What is the partial pressure of gas D in the container? Hint: Count the gas molecules. Gas A Gas B Gas C Gas D Gas D contributes ¼ of 6.0 atm. 𝐏 𝐃 = 𝛘 𝐃 𝐏 𝐓𝐨𝐭𝐚𝐥 𝐏 𝐃 = 𝟎. 𝟐𝟓 𝟔. 𝟎 𝐚𝐭𝐦 𝐏 𝐃 = 𝟏. 𝟓 𝐚𝐭𝐦 Could you do this in your head? 
  • 18. *Summary of Dalton’s Law of Partial Pressures Suppose the total pressure in the container is 10 atm. What is the partial pressure of gases B and C in the container? (Hint: Count the gas molecules.) Gas A Gas B Gas C Gas D
  • 19. *Summary of Dalton’s Law of Partial Pressures Suppose the total pressure in the container is 10 atm. What is the partial pressure of gases B and C in the container? (Hint: Count the gas molecules.) Gas A Gas B Gas C Gas D Together, gases B and C contribute ½ of 10 atm. 𝐏 𝐁+𝐂 = 𝛘 𝐁 +𝛘 𝐂 𝐏 𝐓𝐨𝐭𝐚𝐥 𝐏 𝐁+𝐂 = 𝟎. 𝟐𝟓 + 𝟎. 𝟐𝟓 𝟏𝟎 𝐚𝐭𝐦 𝐏 𝐁+𝐂 = 𝟓 𝐚𝐭𝐦 