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YES We Can !!YES We Can !! always translate a statementalways translate a statement
problem in the form of an equationproblem in the form of an equation
By Using InequalitiesInequalities ???
• i.e., using equations which have the following
signs between L.H.S And R.H.S
• For eg :- 40x + 20y ≥ 120
YES We Can !!YES We Can !! always translate a statementalways translate a statement
problem in the form of an equationproblem in the form of an equation
By Using InequalitiesInequalities ???
• i.e., using equations which have the following
signs between L.H.S And R.H.S
• For eg :- 40x + 20y ≤ 120
YES We Can !!YES We Can !! always translate a statementalways translate a statement
problem in the form of an equationproblem in the form of an equation
By Using InequalitiesInequalities ???
• i.e., using equations which have the following
signs between L.H.S And R.H.S
• For eg :- 40x + 20y < 120
YES We Can !!YES We Can !! always translate a statementalways translate a statement
problem in the form of an equationproblem in the form of an equation
By Using InequalitiesInequalities ???
• i.e., using equations which have the following
signs between L.H.S And R.H.S
• For eg :- 40x + 20y > 120
Types of inequalities
STRICT
• The ineqalities with < or >The ineqalities with < or >
between the L.H.S & R.H.Sbetween the L.H.S & R.H.S
SLACK
• The ineqalities with ≤, or ≥The ineqalities with ≤, or ≥
between the L.H.S & R.H.Sbetween the L.H.S & R.H.S
• The ineqalities having theThe ineqalities having the
degree 1degree 1
Eg :- 5x +2y > 10Eg :- 5x +2y > 10
• The ineqalities having theThe ineqalities having the
degree 2degree 2
Eg :- 5x^2 +2y > 10Eg :- 5x^2 +2y > 10
LINEAR QUADRATIC
Rules For Solving InequalitiesRules For Solving Inequalities
Solving Linear Inequalities On A Number Line
Q1 » » Solve and Show solution on Number Line 7x +3 < 5x +9Solve and Show solution on Number Line 7x +3 < 5x +9
Sol » »» » 7x – 5x < 9 – 3 » 2x < 6 » x < 37x – 5x < 9 – 3 » 2x < 6 » x < 3
Point to note : -Point to note : - If the equality had been 7x +3 ≤ 5x +9 the theIf the equality had been 7x +3 ≤ 5x +9 the the
number line would had been like thisnumber line would had been like this
It is important to notice the open or closed interval , which has to beIt is important to notice the open or closed interval , which has to be
used according to the sign between the inequalityused according to the sign between the inequality
What about solving this oneWhat about solving this one
-5 -4 -3 -2 -1 0 1 2 3 4 5
-5 -4 -3 -2 -1 0 1 2 3 4 5
2 ≤ 3x – 4 ≤ 52 ≤ 3x – 4 ≤ 5
View Here
Q1 » »Q1 » » Solve and Show solution on Number Line 2 ≤ 3x – 4 ≤ 5Solve and Show solution on Number Line 2 ≤ 3x – 4 ≤ 5
Sol » »Sol » »
..2 ≤ 3x – 4 ≤ 5 » 2 + 4 ≤ 3x ≤ 5 + 4 »2 ≤ 3x – 4 ≤ 5 » 2 + 4 ≤ 3x ≤ 5 + 4 »
» 6 ≤ 3x ≤ 9 » 2 ≤ x ≤ 3» 6 ≤ 3x ≤ 9 » 2 ≤ x ≤ 3
-5 -4 -3 -2 -1 0 1 2 3 4 5-5 -4 -3 -2 -1 0 1 2 3 4 5
2.0 2.1 2.2 2.3 2.4 2.5 2.6 2.7 2.8 2.9 3.02.0 2.1 2.2 2.3 2.4 2.5 2.6 2.7 2.8 2.9 3.0
Closed Interval ( )Closed Interval ( )
Open Interval ( )Open Interval ( )
Introduction To Types Of Graphs
I
II
X - Axis
Y - Axis
Left half
plane
Right half
plane
OO
X - Axis
Y - Axis
Upper half
plane
Lower half
plane
OO
Sol. »Sol. » Steps to solving and graphing the InequalitySteps to solving and graphing the Inequality
Step 1 :- Assume that X + Y = 5 and find the following values
Step 2 :- Plot these points on graph
Step 3 :- Choose the half by taking some value for X or Y. if it satisfies the
inequality then shade that region as the Answer and if doesn’t then the other
graph is the solution
Qs. »Qs. » Solve Graphically x +y < 5Solve Graphically x +y < 5 X 0 5
Y 5 0
Graph of Equation x + y = 5
If the inequality
has ≤ or ≥ sign
then the the line
of equation is also
the part of the
graph otherwise it
isn’t Graph of Given InequalityGraph of Given Inequality
Sol. »Sol. » Steps to solving and graphing the InequalitySteps to solving and graphing the Inequality
Step 1 :- Assume that X + Y = 5 and find the following values
Step 2 :- Plot these points on graph
Step 3 :- Choose the half by taking some value for X or Y. if it satisfies the
inequality then shade that region as the Answer and if doesn’t then the other
graph is the solution
Step 4 : - For x > 3 , if we follow the above
3 steps we get the graphs (green colour)
And the solution of the given question
will be the part of the graph common
to both the inequalities. (Dark Green Colour)
Qs. »Qs. » Solve Graphically x +y < 5 , x > 3Solve Graphically x +y < 5 , x > 3
X 0 5
Y 5 0
Graph of Equation x + y = 5
0
-1
1
2
3
4
5
6
-1-2 21 433 5 6
Graph of Equation x = 3
CBSE Class XI Maths Linear inequalities

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CBSE Class XI Maths Linear inequalities

  • 1.
  • 2.
  • 3. YES We Can !!YES We Can !! always translate a statementalways translate a statement problem in the form of an equationproblem in the form of an equation By Using InequalitiesInequalities ??? • i.e., using equations which have the following signs between L.H.S And R.H.S • For eg :- 40x + 20y ≥ 120
  • 4. YES We Can !!YES We Can !! always translate a statementalways translate a statement problem in the form of an equationproblem in the form of an equation By Using InequalitiesInequalities ??? • i.e., using equations which have the following signs between L.H.S And R.H.S • For eg :- 40x + 20y ≤ 120
  • 5. YES We Can !!YES We Can !! always translate a statementalways translate a statement problem in the form of an equationproblem in the form of an equation By Using InequalitiesInequalities ??? • i.e., using equations which have the following signs between L.H.S And R.H.S • For eg :- 40x + 20y < 120
  • 6. YES We Can !!YES We Can !! always translate a statementalways translate a statement problem in the form of an equationproblem in the form of an equation By Using InequalitiesInequalities ??? • i.e., using equations which have the following signs between L.H.S And R.H.S • For eg :- 40x + 20y > 120
  • 7. Types of inequalities STRICT • The ineqalities with < or >The ineqalities with < or > between the L.H.S & R.H.Sbetween the L.H.S & R.H.S SLACK • The ineqalities with ≤, or ≥The ineqalities with ≤, or ≥ between the L.H.S & R.H.Sbetween the L.H.S & R.H.S • The ineqalities having theThe ineqalities having the degree 1degree 1 Eg :- 5x +2y > 10Eg :- 5x +2y > 10 • The ineqalities having theThe ineqalities having the degree 2degree 2 Eg :- 5x^2 +2y > 10Eg :- 5x^2 +2y > 10 LINEAR QUADRATIC
  • 8. Rules For Solving InequalitiesRules For Solving Inequalities
  • 9. Solving Linear Inequalities On A Number Line Q1 » » Solve and Show solution on Number Line 7x +3 < 5x +9Solve and Show solution on Number Line 7x +3 < 5x +9 Sol » »» » 7x – 5x < 9 – 3 » 2x < 6 » x < 37x – 5x < 9 – 3 » 2x < 6 » x < 3 Point to note : -Point to note : - If the equality had been 7x +3 ≤ 5x +9 the theIf the equality had been 7x +3 ≤ 5x +9 the the number line would had been like thisnumber line would had been like this It is important to notice the open or closed interval , which has to beIt is important to notice the open or closed interval , which has to be used according to the sign between the inequalityused according to the sign between the inequality What about solving this oneWhat about solving this one -5 -4 -3 -2 -1 0 1 2 3 4 5 -5 -4 -3 -2 -1 0 1 2 3 4 5 2 ≤ 3x – 4 ≤ 52 ≤ 3x – 4 ≤ 5 View Here
  • 10. Q1 » »Q1 » » Solve and Show solution on Number Line 2 ≤ 3x – 4 ≤ 5Solve and Show solution on Number Line 2 ≤ 3x – 4 ≤ 5 Sol » »Sol » » ..2 ≤ 3x – 4 ≤ 5 » 2 + 4 ≤ 3x ≤ 5 + 4 »2 ≤ 3x – 4 ≤ 5 » 2 + 4 ≤ 3x ≤ 5 + 4 » » 6 ≤ 3x ≤ 9 » 2 ≤ x ≤ 3» 6 ≤ 3x ≤ 9 » 2 ≤ x ≤ 3 -5 -4 -3 -2 -1 0 1 2 3 4 5-5 -4 -3 -2 -1 0 1 2 3 4 5 2.0 2.1 2.2 2.3 2.4 2.5 2.6 2.7 2.8 2.9 3.02.0 2.1 2.2 2.3 2.4 2.5 2.6 2.7 2.8 2.9 3.0 Closed Interval ( )Closed Interval ( ) Open Interval ( )Open Interval ( )
  • 11.
  • 12. Introduction To Types Of Graphs I II X - Axis Y - Axis Left half plane Right half plane OO X - Axis Y - Axis Upper half plane Lower half plane OO
  • 13. Sol. »Sol. » Steps to solving and graphing the InequalitySteps to solving and graphing the Inequality Step 1 :- Assume that X + Y = 5 and find the following values Step 2 :- Plot these points on graph Step 3 :- Choose the half by taking some value for X or Y. if it satisfies the inequality then shade that region as the Answer and if doesn’t then the other graph is the solution Qs. »Qs. » Solve Graphically x +y < 5Solve Graphically x +y < 5 X 0 5 Y 5 0 Graph of Equation x + y = 5 If the inequality has ≤ or ≥ sign then the the line of equation is also the part of the graph otherwise it isn’t Graph of Given InequalityGraph of Given Inequality
  • 14. Sol. »Sol. » Steps to solving and graphing the InequalitySteps to solving and graphing the Inequality Step 1 :- Assume that X + Y = 5 and find the following values Step 2 :- Plot these points on graph Step 3 :- Choose the half by taking some value for X or Y. if it satisfies the inequality then shade that region as the Answer and if doesn’t then the other graph is the solution Step 4 : - For x > 3 , if we follow the above 3 steps we get the graphs (green colour) And the solution of the given question will be the part of the graph common to both the inequalities. (Dark Green Colour) Qs. »Qs. » Solve Graphically x +y < 5 , x > 3Solve Graphically x +y < 5 , x > 3 X 0 5 Y 5 0 Graph of Equation x + y = 5 0 -1 1 2 3 4 5 6 -1-2 21 433 5 6 Graph of Equation x = 3