3
 Notes
All Khan Due @ end of the day
Final Exam Grades Posted @ v6 Math
Khan for this Week Posted
Alt.Khan Available Now
Notebooks: 1st leave today, 2nd Tuesday, 3rd
Wed., 4th Thursday.
Warm Up:
1. Solve the inequality: -1 <
𝟑 −𝟐𝒙
𝟓
< 3
4 > x and x > -6; write as one inequality -6 < x < 4
2. Solve for x: 1 -
𝟐
𝒙 −𝟐
1 +
𝟐
𝒙 −𝟐
Eliminate both denominators.
Hint: There are 2 terms in
both the numerator and the
denominator.
𝒙 − 𝟐 1 -
𝟐
𝒙 −𝟐
𝒙 − 𝟐 − 𝟐
𝒙 − 𝟐 + 𝟐
𝒙 − 𝟒
𝒙
A quick look at the 3rd quarter
Warm Up:
5. Graph the inequality: 2x + 3y > 12
x
y
2-2
(0,4)
(6,0)
3. Write an equation for a horizontal line
6. Write an equation for a line perpendicular to:
−𝟏
𝟑
x = 2y + 12.
4. Write an equation with an undefined slope
Recall…
Graph n < 3 on a number line.
-3 -2 -1 0 1 2 3 4
a. (4, 5); y < x + 1
Tell whether the ordered pair is a
solution of the inequality.
y < x + 1
Substitute (4, 5) for (x, y).
Substitute (1, 1) for (x, y).
b. (1, 1); y > x – 7
y > x – 7
5 4 + 1
5 5<
1 1 – 7
>1 –6
(4, 5) is not a solution. (1, 1) is a solution.
 
The boundary line also represents the related linear
equation....what is the related equation?
What is the
Inequality?
y > x + 4
Graphing Linear Inequalities
Step 1
Solve the inequality for y (solved EXACTLY
like an equation; slope-intercept form).
Step 2
Graph the solution (the boundary line).
Use a solid line for ≤ or ≥. Use a dashed
line for < or >.
Step 3
Shade the half-plane above the line for y >
or ≥. Shade the half-plane below the line for
y < or y ≤. Check your answer.
Graph y > 3 on the coordinate plane.
x
y
x
y
Graph x < -2 on the coordinate plane.
Graph y > -3x + 2 on the coordinate plane.
x
y
Boundary Line
y = -3x + 2
m = -3 b = 2
Test a point not on the line
test (0,0)
0 > -3(0) + 2
Not true!
Graph y -3x + 2 on the coordinate plane.
x
y

Instead of testing a point
If in y = mx + b form...
Shade
up
Shade
down
Solid
line
Dashed
line
 
> <
Graphing Linear Inequalities
Graph the solution of the linear inequality.
5x + 2y > –8
Step 1 Solve the inequality for y.
Step 2 Graph the boundary line and
Use a dashed line for >.
y =
−𝟓
𝟐
x – 4
Step 3: Test a point not on the
line. Use (0,0) when you can.
5(0) + 2(0) > -8, True or False?
If true, include that point in your
shading.
Graph the inequality.
3x - 4y > 12
-3x -3x
-4y > -3x + 12
-4 -4
y < x - 3
m = b = -3
Boundary Line
x
y
3
4
𝟑
𝟒
𝟑
𝟒
Problem
You have less than $5.00 in nickels and dimes,
find an inequality and sketch a graph to describe
how many of each coin you have.
Let n = # of nickels
Let d = # of dimes
0.05 n + 0.10 d < 5.00
or
5 n + 10 d < 500
Graphing Linear Inequalities
5n + 10d < 500
n d
0 50
100 0
0 10 20 30 40 50 60 70 80 90 100
n
d
60
50
40
30
20
10
0
When dealing with angled lines,
If the inequality is > or > ,then you shade above
If the inequality is < or < ,then
you shade below
Finding a point not on the
line is still the safest and
surest method to determine
where to shade.
Graph y -3x + 2 on the coordinate plane.
x
y

Instead of testing a point
Arrange the equation in
y = mx + b form...
Shade
up
Shade
down
Solid
line
Dashed
line
 
> <
Graphing Linear Inequalities
Graph on the coordinate plane.
3x - 4y > 12
-3x -3x
-4y > -3x + 12
-4 -4
y < x - 3
3
4
m = b = -3
3
4
Boundary Line
x
y
Graphing Linear Inequalities
If the point makes the
inequality true, shade
that side of the line.
If the point does not
make the inequality true,
shade the opposite side of
the line.
Use (0,0) as a test if this
point is not on the line.
Quadrilateral ABCD has diagonals AC and BD.
Determine whether segment AC is perpendicular to BD
AC, m = 7
BD, m =
−𝟏
𝟕
The lines are perpendicular.
February 3, 2015
February 3, 2015

February 3, 2015

  • 1.
  • 2.
     Notes All KhanDue @ end of the day Final Exam Grades Posted @ v6 Math Khan for this Week Posted Alt.Khan Available Now Notebooks: 1st leave today, 2nd Tuesday, 3rd Wed., 4th Thursday.
  • 3.
    Warm Up: 1. Solvethe inequality: -1 < 𝟑 −𝟐𝒙 𝟓 < 3 4 > x and x > -6; write as one inequality -6 < x < 4 2. Solve for x: 1 - 𝟐 𝒙 −𝟐 1 + 𝟐 𝒙 −𝟐 Eliminate both denominators. Hint: There are 2 terms in both the numerator and the denominator. 𝒙 − 𝟐 1 - 𝟐 𝒙 −𝟐 𝒙 − 𝟐 − 𝟐 𝒙 − 𝟐 + 𝟐 𝒙 − 𝟒 𝒙 A quick look at the 3rd quarter
  • 4.
    Warm Up: 5. Graphthe inequality: 2x + 3y > 12 x y 2-2 (0,4) (6,0) 3. Write an equation for a horizontal line 6. Write an equation for a line perpendicular to: −𝟏 𝟑 x = 2y + 12. 4. Write an equation with an undefined slope
  • 5.
    Recall… Graph n <3 on a number line. -3 -2 -1 0 1 2 3 4
  • 6.
    a. (4, 5);y < x + 1 Tell whether the ordered pair is a solution of the inequality. y < x + 1 Substitute (4, 5) for (x, y). Substitute (1, 1) for (x, y). b. (1, 1); y > x – 7 y > x – 7 5 4 + 1 5 5< 1 1 – 7 >1 –6 (4, 5) is not a solution. (1, 1) is a solution.  
  • 8.
    The boundary linealso represents the related linear equation....what is the related equation? What is the Inequality? y > x + 4
  • 9.
    Graphing Linear Inequalities Step1 Solve the inequality for y (solved EXACTLY like an equation; slope-intercept form). Step 2 Graph the solution (the boundary line). Use a solid line for ≤ or ≥. Use a dashed line for < or >. Step 3 Shade the half-plane above the line for y > or ≥. Shade the half-plane below the line for y < or y ≤. Check your answer.
  • 10.
    Graph y >3 on the coordinate plane. x y
  • 11.
    x y Graph x <-2 on the coordinate plane.
  • 12.
    Graph y >-3x + 2 on the coordinate plane. x y Boundary Line y = -3x + 2 m = -3 b = 2 Test a point not on the line test (0,0) 0 > -3(0) + 2 Not true!
  • 13.
    Graph y -3x+ 2 on the coordinate plane. x y  Instead of testing a point If in y = mx + b form... Shade up Shade down Solid line Dashed line   > < Graphing Linear Inequalities
  • 14.
    Graph the solutionof the linear inequality. 5x + 2y > –8 Step 1 Solve the inequality for y. Step 2 Graph the boundary line and Use a dashed line for >. y = −𝟓 𝟐 x – 4 Step 3: Test a point not on the line. Use (0,0) when you can. 5(0) + 2(0) > -8, True or False? If true, include that point in your shading.
  • 15.
    Graph the inequality. 3x- 4y > 12 -3x -3x -4y > -3x + 12 -4 -4 y < x - 3 m = b = -3 Boundary Line x y 3 4 𝟑 𝟒 𝟑 𝟒
  • 16.
    Problem You have lessthan $5.00 in nickels and dimes, find an inequality and sketch a graph to describe how many of each coin you have. Let n = # of nickels Let d = # of dimes 0.05 n + 0.10 d < 5.00 or 5 n + 10 d < 500 Graphing Linear Inequalities
  • 17.
    5n + 10d< 500 n d 0 50 100 0 0 10 20 30 40 50 60 70 80 90 100 n d 60 50 40 30 20 10 0
  • 18.
    When dealing withangled lines, If the inequality is > or > ,then you shade above If the inequality is < or < ,then you shade below Finding a point not on the line is still the safest and surest method to determine where to shade.
  • 19.
    Graph y -3x+ 2 on the coordinate plane. x y  Instead of testing a point Arrange the equation in y = mx + b form... Shade up Shade down Solid line Dashed line   > < Graphing Linear Inequalities
  • 20.
    Graph on thecoordinate plane. 3x - 4y > 12 -3x -3x -4y > -3x + 12 -4 -4 y < x - 3 3 4 m = b = -3 3 4 Boundary Line x y Graphing Linear Inequalities
  • 21.
    If the pointmakes the inequality true, shade that side of the line. If the point does not make the inequality true, shade the opposite side of the line. Use (0,0) as a test if this point is not on the line.
  • 22.
    Quadrilateral ABCD hasdiagonals AC and BD. Determine whether segment AC is perpendicular to BD AC, m = 7 BD, m = −𝟏 𝟕 The lines are perpendicular.