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DESIGN OF AIR PRE HEATER 
AND ECONOMIZER 
Under the guidance of(Internal) 
N.B.PRAKASH TIRUVEEDULA 
ASSISTANT PROFESSOR 
VIGNAN UNIVERSITY 
Under the guidance of(External) 
Mr. SREEKANTH JABADE 
GMAND PROJECT ENGG 
HARTEX RUBBER PVT LTD 
Submitted by 
J.SHANMUKA VENKATA GOPICHAND (101FA08133) 
L.SURYA TEJA (101FA08141)
CONTENTS 
1. Process of Air pre-heater 
2. Economizer 
3. Boiler basics 
4. Heat Exchangers 
5. Cross Flow & Compact Heat Exchangers 
6. Design Calculation of Economizer 
7. Design Calculation of Air pre-heater 
8. Boiler Efficiency 
9. Heat Balance sheet 
10. Conclusion
Process of Air pre-heater 
• An air pre-heater (APH) is a general term to describe any device designed to heat air 
before another process (for example, combustion in a boiler) with the primary objective of 
increasing the thermal efficiency of the process. 
• There are two types of air pre-heaters for use in steam generators in thermal power 
stations: One is a tubular type built into the boiler flue gas ducting, and the other is a 
regenerative air pre-heater. 
• Ambient air is forced by a fan through ducting at one end of the pre-heater tubes and at 
other end the heated air from inside of the tubes emerges into another set of ducting, 
which carries it to the boiler furnace for combustion
• There are two types of regenerative air pre-heaters: the rotating-plate regenerative air pre-heaters 
(RAPH) and the stationary-plate regenerative air pre-heaters. 
• Rotating-plate regenerative air pre-heater
• The rotating-plate design (RAPH) consists of a central rotating-plate element installed 
within a casing that is divided into two (bi-sector type), three (tri-sector type) or four 
(quad-sector type) sectors containing seals around the element. 
• In stationary-plate regenerative air pre-heaters the heating plate elements are also installed 
in a casing, but the heating plate elements are stationary rather than rotating.
Economizer 
• Economizers are mechanical devices intended to reduce energy 
consumption, or to perform another useful function such as preheating a 
fluid. 
• Economizer performs a key function in providing high overall boiler 
thermal efficiency by recovering low level energy from the flue gas before 
it is exhausted to the atmosphere. 
• Economizer recovers the energy by heating the boiler feed water.
• It scavenge the waste heat from thermal exhaust flue gases by passing the 
exhaust effluent through heat transfer surfaces to transfer some of the 
waste heat to a process media. 
• It Efficiency is in direct relationship to equipment design and stack gas 
velocities. 
• Velocity increases through the stack as firing rate increases, which results 
in a decrease in contact time with the economizer heating surfaces
BOILER BASICS 
• The hot water or steam under pressure is then usable for transferring the heat for the steam 
requirements of process industries or for power generation. 
• During the combustion process, oxygen reacts with carbon, hydrogen and other elements 
in the fuel to produce a flame and hot combustion gases. 
• As these gases are drawn through the boiler, they cool as heat is transferred to water 
• The main components in a boiler system are boiler feed water heaters, deaerator, feed 
pump, economizer, super heater, Attemperators, condenser and condensate pump.
Heat Exchangers 
Heat Exchangers are classified according to their function and geometry: 
Function: 
Recuperative: two fluids separated by a solid wall 
Evaporative: enthalpy of evaporation of one fluid is used to heat or cool the other fluid. 
Regenerative: use a third material which stores/releases heat 
Geometry: 1. Double Tube 2. Shell and Tube 
3. Cross-flow Heat Exchangers 4. Compact Heat Exchangers
Heat Exchangers 
• The heat transfer rate for most heat exchangers can be calculated using the LMTD-method 
(Log Mean Temperature Difference), if the inlet (T1) and outlet (T2) temperatures are 
known: 
U = Overall heat transfer coefficient [ W/m2-oC ] 
A = Effective heat transfer surface area [ m2 ] 
F = Geometry correction factor 
= Log mean temperature difference 
T T 
   
2 1 
  
F 
T T 
T 
ln  /  
2 1 
Q U A T   
T
Cross flow and compact heat exchangers 
• Cross-flow and compact heat exchangers are used where space is limited. These aim to 
maximize the heat transfer surface area. 
• Commonly used in gas (air) heating applications. 
• The heat transfer is influenced by whether the fluids are unmixed (i.e. confined in a 
channel) or mixed (i.e. not confined, hence free to contact several different heat transfer 
surfaces). 
• In a cross-flow heat exchanger the direction of fluids are perpendicular to each other.
Compact heat exchangers 
• In Compact heat exchangers, the heat transfer rate is directly related to pressure loss 
Advantages: 
• very small 
• Ideal for transferring heat to / from fluids with very low conductivity or where the heat 
transfer must be done in very small spaces 
Disadvantages: 
• high manufacturing costs 
• very heavy 
• Extremely high pressure losses.
DESIGN OF ECONOMIZER 
ASSUMPTION: 
• The properties are remains constant under steady state conditions and neglect 
surrounding losses. Kinetic and potential energies are neglected. 
DESIGN ANALYSIS: 
Heat Transfer, 
Q = m x c x Δt 
• Where m = mass of fluid in kg 
C = specific heat of water in kj/kg oc 
Δt = temperature difference
• Here m = 1800 kg/h 
= 5 kg/sec 
• Specific heat of water is 4.18 kj/kg oc 
• Temperature difference, Δt = (70oc - 40oc) = 30oc 
Q = 5 x 4.18 x 30oc 
Q = 627 kW 
• Heat loosing fluid 
Qc = m x c x Δt 
= 16 x 1.005 x (200 – 160) 
= 643.2 kw.
• In Counter flow 
LMTD = ((Th1 – Tc2) - (Th2– Tc1)) / ln ((Th1 – Tc2 ) - ( Th2 – Tc1 )) 
= ((200-70) – (160-40)) / ln ((200-70)/ (160-40)) 
= (130-120) / ln (130/120) 
= 10 / ln (1.083) 
= 10 / 0.0797 
• LMTD = 125.47oc
• Actually this economizer is a cross flow economizer so, the LMTD equation becomes, 
(LMTD)cross = F X (LMTD)counter 
Here F = correction factor 
• It is calculated by using graphical method by using dimension parameters P, Z from graph, 
P= (Tc2-Tc1)/(Th1-Tc2) 
P= (70-40)/ (200-70) 
P= 0.2307
• Z= (Th1-Th2)/(Tc2-Tc1) 
Z= (200-160)/ (70-40) 
Z= 1.33 
• From this values we get F = 0.98 (from graphically, pgno:31) 
• So we have multiplied the counter flow LMTD with correction factor F, then we 
get LMTD of cross flow 
(LMTD) cross = F X (LMTD) counter 
= 0.98 x 125.47 
= 122.96oc
• From heat transfer equation we calculate the area of economizer as follows 
Q = UA ΔTm x F 
Here F = Correction factor F = 0.98 
A = Area of Economizer 
A = (627 x 1000) / (850 x 125.4 x 0.98) 
A = 6.01 m2 
U = 850 w / m2 oc (from tables)
• From Average velocity in the tube and discharge we Calculate total flow area 
m = ρ A u 
Here m = mass of water 
A = Tube flow area 
U = velocity of flow = 0.2 m/sec 
A = 5 / (1000 x 0.2) 
A = 0.025 m2
• The above area is equal to actual cross – sectional area of tube 
0.025 =n x π/4 x d2 
0.025 = n x 3.14 x (0.025)2 / 4 
n= 50 
• From Equation 1 the area is 17.47 m2 
• Then the total surface area in 2 tube pass is given below 
2nπdL = 6.01 
L = 6.01/(2 x 0.025 x 3.14 x 50) 
L = 76 mtrs
• Each tube = 2.2 mtrs 
No. of passes = 2 
No. of tubes = 50
DESIGN OF AIR PRE HEATER 
• ASSUMPTIONS: The properties are remains constant under steady state conditions and 
neglect surrounding losses. Kinetic and potential energies are neglected. 
• DESIGN ANALYSIS: 
Heat Transfer, 
Q = m x c x Δt 
Where m = mass flow rate 
C = specific heat of air in kJ/kg oc 
C = 1.005 
Δt = temperature difference in oc
• Here m = 5 kg/sec 
Specific heat of water is 4.18 kJ/kg oc 
Temperature difference, Δt = (110 oc - 50 oc) = 60 oc 
Q = 5 x 1.005 x 60 oc 
Q = 301.5 kw 
Heat loosing of fluid Q = m x c x Δt 
= 5 x 1.005 x (270-200) 
= 351.75 kw
• LMTD = ((Th1 – Tc2 ) - ( Th2 – Tc1 )) / ln((Th1 – Tc2 )- ( Th2 – Tc1 )) 
= ((270-110) – (200-50))/ln ((270-110)/(200-50)) 
= (160-150)/ln (160/150) 
LMTD = 156.46 oc 
• Actually this Air pre-heater is a cross flow Air pre-heater so the LMTD equation 
Becomes, 
(LMTD)cross = F X (LMTD)counter 
Here F = correction factor
• It is calculated by using graphical method by using dimension parameters P, Z from graph, 
P= (Tc2-Tc1)/(Th1-Tc2) 
P= (110-50)/(270-110) 
P= 60/160 
P=0.375 
Z = (Th1-Th2)/(Tc2-Tc1) 
Z = (270-200)/(110-50) 
Z = 70/60 
Z = 1.16 
• From this values we get F = 0.94 (from graphically)
• So we have multiplied the counter flow LMTD with correction factor F, then we get 
LMTD of cross flow 
(LMTD)cross = F X (LMTD)counter 
= 0.94 x 156.46 
= 147.07 oc 
• Q = UA ΔTm x F 
Where U = overall heat transfer coefficient 
A = Area of Air Pre heater 
F = correction factor 
U = 50 w / m2 oc (As per standard tables)
• From Average velocity in the tube and discharge we Calculate total flow area 
Here correction factor F = 0.94 
A = q / U ΔTm x F 
= (301.5X 1000) / (50 x 0.94 x 156.4) 
= 43.015m2 
m = ρA u 
Here m = mass flow rate kg/sec 
A = Tube flow area m2 
U = velocity of flow = 0.2 m/sec 
ρ = 1.5 kg / m3
• From continuity equation 
Q = A1 X V1 
5 / 1000 = 3.14 X (0.04)2 X V1 
V1 = 3.98 m/sec 
m = ρA u 
A= m/(ρ x V1) 
A=5/(1.5 x 3.98 ) = 0.83 m2 
A = 0.83 m2
• The above area is equal to actual cross – sectional area of tube 
0.83 m2 = n X π/4 X d2 
n = 658 tubes 
Length of tube for two passes 
nπdL = 43.015m2 
L = 43.015 / (658 x 3.14 x 0.04) 
L = 0.52m 
No. of tubes = 658 
No. of passes = 2, Length = 0.52m
BOILER EFFICIENCY 
• Now we calculate the boiler efficiency of thermax boiler. 
• Capacity of boiler = 6 tons/hour 
• Exisisting values 
• Water temperature (tw) = 35 oc 
• Mass of steam (ms) = 6000kg/hr 
• Mass of fuel (mf) = 1250 kg/hr 
• Calorific value of husk = 3500 k.cal/kg = 14644.35kj/kg ( 1 joule = 0.239 k.cal ) 
• Temperature of steam (ts ) = 190 oc 
• Boiler efficiency = ms (hs-hw)/mf x c.v
• Enthalpy of water at 35 oc hw =hf +x hfg 
(x = 0, i.e., dryness factor, by using steam tables) 
hw = 151.5 + 0 x hfg 
hw = 151.5 kj/kg 
• Enthalpy of steam at 190 oc 
hs =hf +x hfg 
hs = 8067 + (0.8 X 1977.5) 
hs = 2388.7 kj/kg 
• Therefore, boiler efficiency = ms (hs-hw) /(mf x c.v) x 100 
= 6000(2388.7-151.5)/1250 x 14644.35) x 100 
= 0.733 x 100 = 73.3%
8.1 BOILER EFFICIENCY WITH ECONOMIZER 
• Now introducing economizer the temperature of water increases from 35 oc TO 50 oc 
now water temperature (tw) = 50 oc 
And quality of steam increases up to 90 percent 
• Economizer with boiler efficiency = ms(hs-hw)/mf x c.vx100 
• enthalpy of water at 50 oc (hw) = hf + x hfg 
= 213.7 + 0 x hfg 
hw = 213.7 kj/kg
• enthalpy of steam at 190 oc (hs) = hf+ x hfg 
= 806.7 + (0.9 x 1977.5) (here quality of the steam 90%) 
= 806.7 + 1779.5 
= 2586.45 kj/kg 
• Economizer with boiler effieciency = ms(hs-hw)/mf x c.v x 100 
= 6000 (2586.45 - 213.7)/(1250 x 14644.35) x 100 
=0.77 x 100 
=77%
8.2 BOILER EFFICIENCY WITH AIR PRE-HEATER 
• Now we are introducing air preheater the husk consumption reduced to 1250 kg to 
1083 kg/hr 
• Boiler efficiency with air preheater = MS (HS –HW)/MF X CV X 100 
= 6000 (2586.45-213.7)/1083 X 14644.35) X 100 
= 14236500/15859831.05 X 100 
= 0.89 X 100 
• Boiler efficiency with air preheater = 89%
• Water consumption per hour = 4250 
• Specific heat of water = 1 
ΔT = T2-T1 
= 95 OC -85 OC 
= 10OC 
• MCPΔT = 4250 X 1 X 10 X 24 = 1020000 K.CAL 
= 291.42857 KJ/KG 
• Therefore 291.42857 KJ/KG Rice husk is saving
Heat Balance Sheet 
• Pressure of Steam = 14.2 bar 
• Steam produced = 6000 kg/hour 
• Coal used = 1250 kg/hour 
• Moisture in Fuel = 2% of mass 
• Mass of Dry Fuel gas = 9 kg of fuel 
• Calorific Value of Fuel = 3500 k.cal 
• Temperature of gas = 2000c 
• Temperature of Boiler room = 280c 
• Feed water Temperature = 500c 
• Specific heat of gas = 1.005 kj/kg 
• Quality of steam = 0.9%
• Heat supplied for the fuel = mf x c.v 
H.S = 1 x 3500 
= 3500 k.cal 
• Heat supplied = 3500 k.cal 
• If moisture is present then heat supplied by 1 kg of fuel = (1- mm) c.v 
• Where mm is percentage of moisture 
= (1-0.02) x 3500 
= 3430 k.cal 
= 4913.043 kj 
• Heat utilized in producing Steam = ms/mf (hs-hw) →1 
Where hs = hf + x hfg 
= 806.7 + (0.9 x 977.5) 
= 2586.45 kg
• hw = hf 
hw = 806.7 
= 6000/1250 (2586.45 – 206.7) 
= 4.8 x 2379.75 
= 11422.8 kj
• Heat carried away by the exert gases = mg cp g (Tg-Ts) 
= 9 x 1.005 (2000c – 500c) 
= 1356.75 kj 
• Heat carried away by the moisture in the fuel = mm (2676 + 2.1 (Tg – 100) – hf) 
= 0.02 (2676 + 2.1 (200 – 100) - hf) 
= 0.02 (2676 + 2.1 (200 – 100) – 121.4) 
= 55.292 kj
1250 1250 
1083 
1300 
1250 
1200 
1150 
1100 
1050 
1000 
950 
100 
90 
80 
70 
60 
50 
40 
30 
20 
10 
0 
1 2 3 
fuel consumption ( kg/hr 
) 
boiler efficiency (%) 
Name fuel consumption 
( kg/hr ) 
Boiler efficiency 
(%) 
without airpreheater and 
economizer 
1250 73.3 
with economizer 1250 77 
with airpreheater 1083 89
CONCLUSION 
• In this course of project it came to learn about the Design of Air pre-heater and 
Economizer in boiler. 
• By using the Air pre-heater and Economizer boiler Efficiency can be increased. 
• Gas flow distribution or heat transfer into the economizer section is improved through use 
of guide vanes at inlet of economizer duct. 
• Analysis of economizer module was carried out to predict the economizer feed water 
outlet temperature. 
• The economizer size optimized by reducing the number of tubes of module by enhancing 
the heat transfer across the module. 
• By installing the Air pre-heater and Economizer the total husk consumption rate is 
reduced and the efficiency of the boiler is also increased to 73% to 89%
DESIGN OF AIR PRE HEATER AND ECONOMIZER

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DESIGN OF AIR PRE HEATER AND ECONOMIZER

  • 1. DESIGN OF AIR PRE HEATER AND ECONOMIZER Under the guidance of(Internal) N.B.PRAKASH TIRUVEEDULA ASSISTANT PROFESSOR VIGNAN UNIVERSITY Under the guidance of(External) Mr. SREEKANTH JABADE GMAND PROJECT ENGG HARTEX RUBBER PVT LTD Submitted by J.SHANMUKA VENKATA GOPICHAND (101FA08133) L.SURYA TEJA (101FA08141)
  • 2. CONTENTS 1. Process of Air pre-heater 2. Economizer 3. Boiler basics 4. Heat Exchangers 5. Cross Flow & Compact Heat Exchangers 6. Design Calculation of Economizer 7. Design Calculation of Air pre-heater 8. Boiler Efficiency 9. Heat Balance sheet 10. Conclusion
  • 3. Process of Air pre-heater • An air pre-heater (APH) is a general term to describe any device designed to heat air before another process (for example, combustion in a boiler) with the primary objective of increasing the thermal efficiency of the process. • There are two types of air pre-heaters for use in steam generators in thermal power stations: One is a tubular type built into the boiler flue gas ducting, and the other is a regenerative air pre-heater. • Ambient air is forced by a fan through ducting at one end of the pre-heater tubes and at other end the heated air from inside of the tubes emerges into another set of ducting, which carries it to the boiler furnace for combustion
  • 4. • There are two types of regenerative air pre-heaters: the rotating-plate regenerative air pre-heaters (RAPH) and the stationary-plate regenerative air pre-heaters. • Rotating-plate regenerative air pre-heater
  • 5. • The rotating-plate design (RAPH) consists of a central rotating-plate element installed within a casing that is divided into two (bi-sector type), three (tri-sector type) or four (quad-sector type) sectors containing seals around the element. • In stationary-plate regenerative air pre-heaters the heating plate elements are also installed in a casing, but the heating plate elements are stationary rather than rotating.
  • 6. Economizer • Economizers are mechanical devices intended to reduce energy consumption, or to perform another useful function such as preheating a fluid. • Economizer performs a key function in providing high overall boiler thermal efficiency by recovering low level energy from the flue gas before it is exhausted to the atmosphere. • Economizer recovers the energy by heating the boiler feed water.
  • 7. • It scavenge the waste heat from thermal exhaust flue gases by passing the exhaust effluent through heat transfer surfaces to transfer some of the waste heat to a process media. • It Efficiency is in direct relationship to equipment design and stack gas velocities. • Velocity increases through the stack as firing rate increases, which results in a decrease in contact time with the economizer heating surfaces
  • 8. BOILER BASICS • The hot water or steam under pressure is then usable for transferring the heat for the steam requirements of process industries or for power generation. • During the combustion process, oxygen reacts with carbon, hydrogen and other elements in the fuel to produce a flame and hot combustion gases. • As these gases are drawn through the boiler, they cool as heat is transferred to water • The main components in a boiler system are boiler feed water heaters, deaerator, feed pump, economizer, super heater, Attemperators, condenser and condensate pump.
  • 9. Heat Exchangers Heat Exchangers are classified according to their function and geometry: Function: Recuperative: two fluids separated by a solid wall Evaporative: enthalpy of evaporation of one fluid is used to heat or cool the other fluid. Regenerative: use a third material which stores/releases heat Geometry: 1. Double Tube 2. Shell and Tube 3. Cross-flow Heat Exchangers 4. Compact Heat Exchangers
  • 10. Heat Exchangers • The heat transfer rate for most heat exchangers can be calculated using the LMTD-method (Log Mean Temperature Difference), if the inlet (T1) and outlet (T2) temperatures are known: U = Overall heat transfer coefficient [ W/m2-oC ] A = Effective heat transfer surface area [ m2 ] F = Geometry correction factor = Log mean temperature difference T T    2 1   F T T T ln  /  2 1 Q U A T   T
  • 11. Cross flow and compact heat exchangers • Cross-flow and compact heat exchangers are used where space is limited. These aim to maximize the heat transfer surface area. • Commonly used in gas (air) heating applications. • The heat transfer is influenced by whether the fluids are unmixed (i.e. confined in a channel) or mixed (i.e. not confined, hence free to contact several different heat transfer surfaces). • In a cross-flow heat exchanger the direction of fluids are perpendicular to each other.
  • 12. Compact heat exchangers • In Compact heat exchangers, the heat transfer rate is directly related to pressure loss Advantages: • very small • Ideal for transferring heat to / from fluids with very low conductivity or where the heat transfer must be done in very small spaces Disadvantages: • high manufacturing costs • very heavy • Extremely high pressure losses.
  • 13. DESIGN OF ECONOMIZER ASSUMPTION: • The properties are remains constant under steady state conditions and neglect surrounding losses. Kinetic and potential energies are neglected. DESIGN ANALYSIS: Heat Transfer, Q = m x c x Δt • Where m = mass of fluid in kg C = specific heat of water in kj/kg oc Δt = temperature difference
  • 14. • Here m = 1800 kg/h = 5 kg/sec • Specific heat of water is 4.18 kj/kg oc • Temperature difference, Δt = (70oc - 40oc) = 30oc Q = 5 x 4.18 x 30oc Q = 627 kW • Heat loosing fluid Qc = m x c x Δt = 16 x 1.005 x (200 – 160) = 643.2 kw.
  • 15. • In Counter flow LMTD = ((Th1 – Tc2) - (Th2– Tc1)) / ln ((Th1 – Tc2 ) - ( Th2 – Tc1 )) = ((200-70) – (160-40)) / ln ((200-70)/ (160-40)) = (130-120) / ln (130/120) = 10 / ln (1.083) = 10 / 0.0797 • LMTD = 125.47oc
  • 16. • Actually this economizer is a cross flow economizer so, the LMTD equation becomes, (LMTD)cross = F X (LMTD)counter Here F = correction factor • It is calculated by using graphical method by using dimension parameters P, Z from graph, P= (Tc2-Tc1)/(Th1-Tc2) P= (70-40)/ (200-70) P= 0.2307
  • 17. • Z= (Th1-Th2)/(Tc2-Tc1) Z= (200-160)/ (70-40) Z= 1.33 • From this values we get F = 0.98 (from graphically, pgno:31) • So we have multiplied the counter flow LMTD with correction factor F, then we get LMTD of cross flow (LMTD) cross = F X (LMTD) counter = 0.98 x 125.47 = 122.96oc
  • 18. • From heat transfer equation we calculate the area of economizer as follows Q = UA ΔTm x F Here F = Correction factor F = 0.98 A = Area of Economizer A = (627 x 1000) / (850 x 125.4 x 0.98) A = 6.01 m2 U = 850 w / m2 oc (from tables)
  • 19. • From Average velocity in the tube and discharge we Calculate total flow area m = ρ A u Here m = mass of water A = Tube flow area U = velocity of flow = 0.2 m/sec A = 5 / (1000 x 0.2) A = 0.025 m2
  • 20. • The above area is equal to actual cross – sectional area of tube 0.025 =n x π/4 x d2 0.025 = n x 3.14 x (0.025)2 / 4 n= 50 • From Equation 1 the area is 17.47 m2 • Then the total surface area in 2 tube pass is given below 2nπdL = 6.01 L = 6.01/(2 x 0.025 x 3.14 x 50) L = 76 mtrs
  • 21. • Each tube = 2.2 mtrs No. of passes = 2 No. of tubes = 50
  • 22. DESIGN OF AIR PRE HEATER • ASSUMPTIONS: The properties are remains constant under steady state conditions and neglect surrounding losses. Kinetic and potential energies are neglected. • DESIGN ANALYSIS: Heat Transfer, Q = m x c x Δt Where m = mass flow rate C = specific heat of air in kJ/kg oc C = 1.005 Δt = temperature difference in oc
  • 23. • Here m = 5 kg/sec Specific heat of water is 4.18 kJ/kg oc Temperature difference, Δt = (110 oc - 50 oc) = 60 oc Q = 5 x 1.005 x 60 oc Q = 301.5 kw Heat loosing of fluid Q = m x c x Δt = 5 x 1.005 x (270-200) = 351.75 kw
  • 24. • LMTD = ((Th1 – Tc2 ) - ( Th2 – Tc1 )) / ln((Th1 – Tc2 )- ( Th2 – Tc1 )) = ((270-110) – (200-50))/ln ((270-110)/(200-50)) = (160-150)/ln (160/150) LMTD = 156.46 oc • Actually this Air pre-heater is a cross flow Air pre-heater so the LMTD equation Becomes, (LMTD)cross = F X (LMTD)counter Here F = correction factor
  • 25. • It is calculated by using graphical method by using dimension parameters P, Z from graph, P= (Tc2-Tc1)/(Th1-Tc2) P= (110-50)/(270-110) P= 60/160 P=0.375 Z = (Th1-Th2)/(Tc2-Tc1) Z = (270-200)/(110-50) Z = 70/60 Z = 1.16 • From this values we get F = 0.94 (from graphically)
  • 26. • So we have multiplied the counter flow LMTD with correction factor F, then we get LMTD of cross flow (LMTD)cross = F X (LMTD)counter = 0.94 x 156.46 = 147.07 oc • Q = UA ΔTm x F Where U = overall heat transfer coefficient A = Area of Air Pre heater F = correction factor U = 50 w / m2 oc (As per standard tables)
  • 27. • From Average velocity in the tube and discharge we Calculate total flow area Here correction factor F = 0.94 A = q / U ΔTm x F = (301.5X 1000) / (50 x 0.94 x 156.4) = 43.015m2 m = ρA u Here m = mass flow rate kg/sec A = Tube flow area m2 U = velocity of flow = 0.2 m/sec ρ = 1.5 kg / m3
  • 28. • From continuity equation Q = A1 X V1 5 / 1000 = 3.14 X (0.04)2 X V1 V1 = 3.98 m/sec m = ρA u A= m/(ρ x V1) A=5/(1.5 x 3.98 ) = 0.83 m2 A = 0.83 m2
  • 29. • The above area is equal to actual cross – sectional area of tube 0.83 m2 = n X π/4 X d2 n = 658 tubes Length of tube for two passes nπdL = 43.015m2 L = 43.015 / (658 x 3.14 x 0.04) L = 0.52m No. of tubes = 658 No. of passes = 2, Length = 0.52m
  • 30. BOILER EFFICIENCY • Now we calculate the boiler efficiency of thermax boiler. • Capacity of boiler = 6 tons/hour • Exisisting values • Water temperature (tw) = 35 oc • Mass of steam (ms) = 6000kg/hr • Mass of fuel (mf) = 1250 kg/hr • Calorific value of husk = 3500 k.cal/kg = 14644.35kj/kg ( 1 joule = 0.239 k.cal ) • Temperature of steam (ts ) = 190 oc • Boiler efficiency = ms (hs-hw)/mf x c.v
  • 31. • Enthalpy of water at 35 oc hw =hf +x hfg (x = 0, i.e., dryness factor, by using steam tables) hw = 151.5 + 0 x hfg hw = 151.5 kj/kg • Enthalpy of steam at 190 oc hs =hf +x hfg hs = 8067 + (0.8 X 1977.5) hs = 2388.7 kj/kg • Therefore, boiler efficiency = ms (hs-hw) /(mf x c.v) x 100 = 6000(2388.7-151.5)/1250 x 14644.35) x 100 = 0.733 x 100 = 73.3%
  • 32. 8.1 BOILER EFFICIENCY WITH ECONOMIZER • Now introducing economizer the temperature of water increases from 35 oc TO 50 oc now water temperature (tw) = 50 oc And quality of steam increases up to 90 percent • Economizer with boiler efficiency = ms(hs-hw)/mf x c.vx100 • enthalpy of water at 50 oc (hw) = hf + x hfg = 213.7 + 0 x hfg hw = 213.7 kj/kg
  • 33. • enthalpy of steam at 190 oc (hs) = hf+ x hfg = 806.7 + (0.9 x 1977.5) (here quality of the steam 90%) = 806.7 + 1779.5 = 2586.45 kj/kg • Economizer with boiler effieciency = ms(hs-hw)/mf x c.v x 100 = 6000 (2586.45 - 213.7)/(1250 x 14644.35) x 100 =0.77 x 100 =77%
  • 34. 8.2 BOILER EFFICIENCY WITH AIR PRE-HEATER • Now we are introducing air preheater the husk consumption reduced to 1250 kg to 1083 kg/hr • Boiler efficiency with air preheater = MS (HS –HW)/MF X CV X 100 = 6000 (2586.45-213.7)/1083 X 14644.35) X 100 = 14236500/15859831.05 X 100 = 0.89 X 100 • Boiler efficiency with air preheater = 89%
  • 35. • Water consumption per hour = 4250 • Specific heat of water = 1 ΔT = T2-T1 = 95 OC -85 OC = 10OC • MCPΔT = 4250 X 1 X 10 X 24 = 1020000 K.CAL = 291.42857 KJ/KG • Therefore 291.42857 KJ/KG Rice husk is saving
  • 36. Heat Balance Sheet • Pressure of Steam = 14.2 bar • Steam produced = 6000 kg/hour • Coal used = 1250 kg/hour • Moisture in Fuel = 2% of mass • Mass of Dry Fuel gas = 9 kg of fuel • Calorific Value of Fuel = 3500 k.cal • Temperature of gas = 2000c • Temperature of Boiler room = 280c • Feed water Temperature = 500c • Specific heat of gas = 1.005 kj/kg • Quality of steam = 0.9%
  • 37. • Heat supplied for the fuel = mf x c.v H.S = 1 x 3500 = 3500 k.cal • Heat supplied = 3500 k.cal • If moisture is present then heat supplied by 1 kg of fuel = (1- mm) c.v • Where mm is percentage of moisture = (1-0.02) x 3500 = 3430 k.cal = 4913.043 kj • Heat utilized in producing Steam = ms/mf (hs-hw) →1 Where hs = hf + x hfg = 806.7 + (0.9 x 977.5) = 2586.45 kg
  • 38. • hw = hf hw = 806.7 = 6000/1250 (2586.45 – 206.7) = 4.8 x 2379.75 = 11422.8 kj
  • 39. • Heat carried away by the exert gases = mg cp g (Tg-Ts) = 9 x 1.005 (2000c – 500c) = 1356.75 kj • Heat carried away by the moisture in the fuel = mm (2676 + 2.1 (Tg – 100) – hf) = 0.02 (2676 + 2.1 (200 – 100) - hf) = 0.02 (2676 + 2.1 (200 – 100) – 121.4) = 55.292 kj
  • 40. 1250 1250 1083 1300 1250 1200 1150 1100 1050 1000 950 100 90 80 70 60 50 40 30 20 10 0 1 2 3 fuel consumption ( kg/hr ) boiler efficiency (%) Name fuel consumption ( kg/hr ) Boiler efficiency (%) without airpreheater and economizer 1250 73.3 with economizer 1250 77 with airpreheater 1083 89
  • 41. CONCLUSION • In this course of project it came to learn about the Design of Air pre-heater and Economizer in boiler. • By using the Air pre-heater and Economizer boiler Efficiency can be increased. • Gas flow distribution or heat transfer into the economizer section is improved through use of guide vanes at inlet of economizer duct. • Analysis of economizer module was carried out to predict the economizer feed water outlet temperature. • The economizer size optimized by reducing the number of tubes of module by enhancing the heat transfer across the module. • By installing the Air pre-heater and Economizer the total husk consumption rate is reduced and the efficiency of the boiler is also increased to 73% to 89%