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1
Statistical Analysis
Prof.Dr.Chinna Chadayan.N
RN.RM., B.Sc (N)., M.Sc (N)., Ph.D (N).,
Professor
Enam Nursing College
M.Sc (N) I year
Unit 17a
Statistical Analysis
1
DEFINITION
• Statistics is a branch of science that deals with the
collection, organisation, analysis of data and drawing of
inferences from the samples to the whole population.
• Sample is a small portion of population which truly
represents the population with respect to the study
characteristic of the population.
2
DEFINITION
• Statistical analysis is the organisation and analysis of
quantitative or qualitative data using statistical procedures,
including both descriptive and inferential statistics.
• It’s the science of collecting, exploring and presenting
large amounts of data to discover underlying patterns and
trends.
3
PURPOSES
1. • To measure things
2. • To examine on relationship
3. • To predict or make predictions or infer from the samples to a
theoretical model
4. • To test the proposed relationships in a theoretical model
5. • To test hypothesis
6. • To construct concept and develop theories
7. • To explore issues and the meaning of deviations in data
8. • To explain activities or attitude
9. • To describe what is happening
10.• Make comparison or contrast descriptively to find similarities
and differences
11.• To draw conclusions about populations based on the sample
result
12.• To Summarize the result and present an information
13.• To inform that the findings from sample are indicative
4
ELEMENTS OF STATISTICAL ANALYSIS
Understand the complex relationship among the
correlates of the disease under study.
The analysis should start with simple comparison of
proportions and means.
Interpretation of result should be guided by clinical and
biological consideration.
5
6
STATISTICAL MEASURES
▶Mean
▶Mode
▶Median
▶Interquartile Range
▶Standard Deviation.
7
MEAN
• The mean is the average of all numbers
8
Example
• Mean of 10, 20, 30, 40
25
9
MEDIAN
• When all the observations are arranged in ascending or descending
orders of magnitude, the middle one is the median.
• For raw data, If n is the total number of observations, the value of the
2
𝑛+1
[ ] th item will be called median .
th 𝑛
2
• if n is the even number, the mean of n/2 item and [ + 1] th item
will be median.
Example : Median of given data 10, 20, 30 is
20
10
MODE
• The Mode is the value of a series which appears most frequently than
any other .
• For grouped data,
0 = 0
Mode, M L +{
𝛥1
𝛥1+𝛥2
} x c
Where, L0 is lower limit of modal class,
C is class interval
𝛥1 is difference between modal frequency and its preceding class
∆2 is difference between modal frequency and following class
frequency.
Example: mode of given data 80, 90, 86, 80, 72, 80, 96 is
80 11
INTERQUARTILE RANGE
• The interquartile range (IQR), is a measure of statistical dispersion,
being equal to the difference between 75th and 25th percentiles, or
between upper and lower quartiles.
• IQR = Q3 − Q1.
12
Example
Interquartile range of following data 30, 20, 40, 60 , 50
4
• Q1 =[ 𝑛+1
]th item = 1.5th item = 20+ 0.5 (30-20) = 25
4
• Q3 = 3[ 𝑛+1
]th item = 50 +0.5x (60-50) = 55.
• IQR = 30
13
STANDARD DEVIATION
• The standard deviation is the most useful and most popular measure
of dispersion.
• The standard deviation is defined as the positive square root of the
arithmetic mean of the square of the deviations of given observations
from their arithmetic mean.
• The standard deviation is denoted by ‘𝜎 ’.
14
STANDARD DEVIATION
Formula
15
EXAMPLE
• Standard deviation of data 10, 20, 30, 40, 50 where n= 5 , 𝑥̅ = 30
• 𝜎 = √1000/4 = √250 = 15. 811
16
STANDARD NORMAL DISTRIBUTION CURVE AND MEAN, MEDIAN,
INTERQUARTILE RANGE AND STANDARD DEVIATION
17
TYPES
• PARAMETRIC STATISTICAL ANALYSIS
• NONPARAMETRIC STATISTICAL ANALYSIS
18
PARAMETRIC STATISTICAL
ANALYSIS
• Most commonly used type of statistical analysis.
• This analysis is referred to as parametric statistical analysis because
the findings are inferred to the parameters of a normally distributed
populations.
• Numerical data (quantitative variables) that are normally distributed
are analysed with parametric tests.
19
ASSUMPTIONS
• The assumption of normality which specifies that the means of the
sample group are normally distributed
• The assumption of equal variance which specifies that the variances
of the samples and of their corresponding population are equal.
• The data can be treated as random samples
20
NONPARAMETRIC STATISTICAL
ANALYSIS
• Nonparametric statistical analysis or distribution free techniques
• It can be used in studies that do not meet the first two assumptions.
• Most nonparametric techniques are not as powerful as their
parametric counter parts.
21
• If the distribution of the sample is skewed towards one side or the
distribution is unknown due to the small sample size, non-parametric
statistical techniques are used.
• Non-parametric tests are used to analyse ordinal and categorical data.
22
EXPLORATORY DATA ANALYSIS AND
CONFIRMATORY DATA ANALYSIS
• John Tukey
• Exploratory data analysis to obtain a preliminary indication of the
nature of the data and to search data for hidden structure or models.
• Confirmatory data analysis involves traditional inferential statistics ,
which you can use to make an inference about a population or a
process based on evidence from the study sample.
23
STATISTICAL ANALYSIS DECISION
MAKING
Two group
comparison
Mean
Parametric Independent 2 sample t test
Percentage
One group
comparison
Mean
Nonparametric Mann Witney U test
Chi-Square Test
Single mean One sample t test
Mean
difference
Parametric Paired t test
Non parametric Wilcoxan Signed Scale test
More than 2
group
comparison
Mean
Parametric ANOVA
Non parametric Kruskal Walli’s test
Percentage Chi square test 24
P
ARAMETRIC
STATISTICAL
ANALYSIS
Student's t-test
 Z test
Analysis of variance (ANOVA)
25
Student's t-test
• Developed by Prof.W.S.Gossett
• Student's t-test is used to test the null hypothesis that there is no
difference between the means of the two groups
• One-sample t-test
• Independent Two Sample T Test (the unpaired t-test)
• The paired t-test
26
One-sample t-test
• To test if a sample mean (as an estimate of a population mean) differs
significantly from a given population mean.
• The mean of one sample is compared with population mean
where 𝑥̅ = sample mean, u = population mean and S = standard
deviation, n = sample size
27
Example
A random sample of size 20 from a normal population gives a sample
mean of 40, standard deviation of 6. Test the hypothesis is population
mean is 44. Check whether there is any difference between mean.
• H0: There is no significant difference between sample mean and
population mean
• H1: There is no significant difference between sample mean and
population mean
mean = 40 , 𝜇 = 44, n = 20 and S = 6
28
•tcalculated = 2.981
•t table value = 2.093
•tcalculated > t table value ;
Reject H0.
29
Independent Two Sample T Test
(the unpaired t-test)
• To test if the population means estimated by two independent
samples differ significantly.
• Two different samples with same mean at initial point and compare
mean at the end
30
t =
𝑥1−𝑥̅2
1 2
𝑛1−1 𝑆2+ 𝑛2−1 𝑆2
𝑛1+𝑛2−2
+
1 1
𝑛1 𝑛2
Where 𝑥̅1 -𝑥̅2 is the difference between the means of the two groups
and S denotes the standard deviation.
31
Example
Mean Hb level of 5 male are 10, 11, 12.5, 10.5, 12 and 5 female are 10,
17.5, 14.2,15 and 14.1 . Test whether there is any significant difference
between Hb values.
• H0: There is no significant difference between Hb Level
• H1: There is no significant difference between Hb level.
t =
𝑥1−𝑥̅2
1 2
𝑛1−1 𝑆2+ 𝑛2−1 𝑆2
𝑛1+𝑛2−2
+
1 1
𝑛1 𝑛2
32
• 𝑥1 = 11.2 , 𝑥2 =14.16 , 𝑆2 = 1.075, 𝑆2 = 7.293
1 2
•tcalculated = 2.287, t table = 2.306, tcalculated > t table value ; reject H0.
X1 X2 X1 - 𝑥1 X2 - 𝑥2 (X1 - 𝑥1)2 (X2 - 𝑥2)2
10 10 -1.2 -4.16 1.44 17.305
11 17.5 - 0.2 3.34 0.04 11.156
12.5 14.2 1.3 0.04 1.69 0.0016
10.5 15 -0.7 0.84 0.49 0.706
12 14.1 0.8 -0.06 0.64 0.0036
Σ = 56 70.8 4.3 29.172
33
The paired t-test
• To test if the population means estimated by two dependent samples differ
significantly .
• A usual setting for paired t-test is when measurements are made on the
same subjects before and after a treatment.
where 𝑑̅ is the mean difference and Sd denotes the standard deviation of the
difference.
34
Example
Systolic BP of 5 patients before and after a drug therapy is
Before 160, 150, 170, 130, 140
After 140, 110, 120, 140, 130
Test whether there is any significant difference between BP level.
• H0: There is no significant difference between BP Level before and after
drug
• H1: There is no significant difference between BP level before and after
drug
35
• 𝑑̅ = 22, Sd = 23.875
•tcalculated = 2.060, t table = 2.567, tcalculated < t table value ; Accept H0.
Before After d d-𝑑̅ (d-𝑑̅ )2
160 140 20 -2 4
150 110 40 18 324
170 120 50 28 784
130 140 -10 -32 1024
140 130 10 -12 144
𝛴𝑑 = 110 2280
36
Z test
Generally, z-tests are used when we have large sample sizes (n > 30),
whereas t-tests are most helpful with a smaller sample size (n < 30).
Both methods assume a normal distribution of the data, but the z-tests
are most useful when the standard deviation is known.
z = (x – μ) / (σ / √n)
37
ANALYSIS OF VARIANCE
(ANOVA)
• R. A. Fischer.
• The Student's t-test cannot be used for comparison of three or more groups.
• The purpose of ANOVA is to test if there is any significant difference between the
means of two or more groups.
• The analysis of variance is the systematic algebraic procedure of decomposing the
overall variation in the responses observed in an experiment into variation.
• Two variances – (a) between-group variability and (b) within-group variability that
is variation existing between the samples and variations existing within the
sample.
• The within-group variability (error variance) is the variation that cannot be
accounted for in the study design.
• The between-group (or effect variance) is the result of treatment
38
• A simplified formula for the F statistic is
where MST is the mean squares between the groups and MSE is the
mean squares within groups
39
NONP
ARAMETRIC
STATISTICAL
ANALYSIS
 CHI-SQUARE TEST
 THE WILCOXON'S SIGNED RANK TEST
 MANN-WHITNEY U TEST
 KRUSKAL-WALLIS TEST
40
CHI-SQUARE TEST
• Tests to analyse the categorical data
• The chi-square test is a widely used test in statistical decision making.
• The test is first used by Karl pearson in 1900.
• The Chi-square test compares the frequencies and tests whether the
observed data differ significantly from that of the expected data.
41
CHI-SQUARE TEST
It is calculated by the sum of the squared difference between observed
(O) and the expected (E) data (or the deviation, d) divided by the
expected data by the following formula:
42
Example
• Attack rates among vaccinated and not vaccinated against measles
are given in the following table. Test the association between
association between vaccination and attack of measles
Groups Attacked Not attacked
Vaccinated 10 90
Not vaccinated 26 74
43
• H0: There is no significant association between vaccination and attack
of measles
• H1: There is significant association between vaccination and attack of
measles
44
• Chi square table value = 3.841 , chi square calculated value = 8.672
• 𝑥2
calculated > 𝑥2
table value ; Reject H0.
Oi Ei Oi - Ei (Oi - Ei )2 (Oi - Ei )2 /
Ei
10 18 -8 64 3.556
90 82 8 64 0.780
26 18 8 64 3.556
74 82 -8 64 0.780
𝛴 = 8.672
45
THE WILCOXON'S SIGNED RANK TEST
• Wilcoxon's rank sum test ranks all data points in order, calculates the
rank sum of each sample and compares the difference in the rank
sums.
• For testing whether the differences observed in the values of the
quantitative variable between two correlated samples (before and
after design ) are statistically different or not
• This test corresponds to the paired t test.
46
Method
• H0: There is no difference in the paired values, on an average, between the two
groups.
• H1: There is difference in the paired values, on an average, between the two
groups.
• Compute the difference between each group of paired values in the two group.
• Rank the difference from smallest, without considering the sign of difference.
• After giving ranks, the corresponding sign should be attached.
• T+ (Sum of ranks of positive sign) and T- (Sum of ranks between negative sign). T
is taken as smallest of T+ and T-. Then Wstat is the smallest value of T- and T+ .
• Find the W critical value from Wilcoxon’s Signed rank Table .
• if Wstat < WCritical Value; Reject H0.
47
EXAMPLE
• IQ values of 8 malnourished children of 4 years age before and after
giving some nutritious diet for 3 months are given below
Before 40 60 55 65 43 70 80 60
After 50 80 50 70 40 60 90 85
48
• H0: There is no difference in the paired values
• H1: There is difference in the paired values
Before 40 60 55 65 43 70 80 60
After 50 80 50 70 40 60 90 85
Differe
nce
-10 -20 5 -5 3 10 -10 -15
Absolu
te
differe
nce
10 20 5 5 3 10 10 15
Rank 5 8 2.5 2.5 1 5 5 7
49
• T+ = 8.5, T- = 27.5. T = 8.5
• Wstat = 8.5, Wcritic = 3
• Wstat > WCritical Value; Accept H0.
50
• If Assuming normal distribution for the differences, test statistic is,
Z = {|T-m| -0.5} / SD
Where T = smaller of T+ and T- , m= mean sum of ranks {n(n+1)}/4 and
SD = √{
𝑛 𝑛+1 2𝑛
+1
24
}
• If Z is less than 1.96, H0 is accepted and if Z>1.96 , H0 is rejected
51
MANN-WHITNEY U TEST
• For testing whether two independent samples with respect to a
quantitative variable come from the same population or not.
• Wilcoxon’s Rank Sum test.
• It is used to test the null hypothesis that two samples have the same
median or, alternatively, whether observations in one sample tend to
be larger than observations in the other.
• This test is alternative of t test for two independent samples
52
METHOD
H0: The average values in the two groups are the same
H1: The average values in the two groups are the different
• Let n1 is the sample size of one group and n2 is the sample size of
second group, Rank all the values in the two groups take together.
Tied values should be given same ranks.
• The ranksum of each group is taken and Ustat is calculated using
Ustat = Rank Sum - {n(n +1)/2 }.
• Both U1 and U2 is calculated and smaller value is taken as Ustat. and
Ucritical value is calculated from the Mann- Whitney U test table
• if Ustat < UCritical value; ; Reject H0.
53
Example
Treatment A Treatment B
3 9
4 7
2 5
6 10
2 6
5 8
54
• H0: The average values in the 2 treatment are the same
• H1: The average values in the 2 treatment are the different
Ustat = Rank Sum - {n(n +1)/2 }.
Ranks 1 2 3 4 5 6 7 8 9 10 11 12
Values 2 2 3 4 5 5 6 6 7 8 9 10
Rank 1.5 1.5 3 4 5.5 5.5 7.5 7.5 9 10 11 12
55
• UA = 23 – 21 = 2, UB = 55- 21 =34 so Ustat = 2 (lowest value)
• Ucritic = 5
• Ustat < UCritical value; Reject H0.
56
• Assuming that the ranks are randomly distributed in the two groups,
the test statisticis
Z = {|m-T| -0.5} / SD
Where T = smaller of T1 and T2.
T1 = sum of the ranks of smaller group, T2 = {(n1 +n2)(n1 +n2 +1) / 2} – T1 ,
m= mean sum of ranks { n1 ( n1 +n2+1)}/2
SD = √{
)( + +
n1 X
n2 n1 n2 1
12
}
• If Z is less than 1.96, H0 is accepted
• if Z>1.96 , H0 is rejected at 5% level of significance
57
KRUSKAL-WALLIS TEST
• The Kruskal–Wallis test is a non-parametric test to analyse the
variance.
• It is for the comparison among several independent samples.
• For testing whether several independent samples of a quantitative
variable come from the same population or not
• It corresponds to one way analysis of variance in parametric methods.
58
• It analyses if there is any difference in the median values of three or more
independent samples.
• The data values are ranked in an increasing order, and the rank sums
calculated followed by calculation of the test
Where n is the total of sample sizes in all the groups and Ri is the sum of the
ranks in the ith group.
59
Method
H0: The average values in the different groups are the same
H1: The average values in the different groups are the different
• Rank the all values taking all the group together.
• The chisquare table is used to get table value at 5% level of significane
• if Hstat is < Htable value ; reject H0
60
Example
Sample 1 Sample 2 Sample 3
8 10 13
10 9 8
9 13 9
12 14 13
11 9 17
13 16 15
61
• H0: The average values in the three groups are the same
• H1: The average values in the three groups are the different
Rank 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18
Value
s
8 8 9 9 9 9 10 10 11 12 13 13 13 13 14 15 16 17
Tied
rank
1.5 1.5 4.75 4.75 4.75 4.75 7.5 7.5 9 10 12.5 12.5 12.5 12.5 15 16 17 18
62
• H = {12/18x19 [ (45.252 /6 ) + (61.52/6) + (65.52/6 )]} – 3x19
•Hcalculated = 56.99 , 𝑥2
table value = 5.99
•Hstat > 𝑥2
table value ; Reject H0
Sample 1 Rank 1 Sample 2 Rank 2 Sample 3 Rank 3
8 1.5 10 7.5 13 12.5
10 7.5 9 4.75 8 1.5
9 4.75 13 12.5 9 4.75
12 10 14 15 13 12.5
11 9 9 4.75 17 18
13 12.5 16 17 15 16
𝛴 = 45.25 𝛴 = 61.5 𝛴 = 65.25
63
WAYS TO RULE OUT ALTERNATIVE
EXPLANATIONS FOR OUTCOMES BY
USING STATISTICAL ANALYSIS
• Testing null hypothesis
• Determining the probability of type I and type II error
• Calculating and reporting tests of effect size
• Ensuring data meet the fundamental assumptions of the statistical
test
64
TESTING NULL HYPOTHESIS
• When attempting to determine if an outcome is related to a cause, it is necessary to
know if the outcomes or results could have occurred by chance alone.
• This cannot be done with certainity, but researchers can determine the probability that
the hypothesis is true.
• Accepting a null hypothesis is a statement that there are no differences in the
outcomes based on the intervention or observation(that is, there is no cause and effect
relationship).
• Using a null hypothesis enables the researcher to quantify and report the probability
that the outcome was due to random error.
65
DETERMINING THE PROBABILITY OF
TYPE I AND TYPE II ERROR
• Before accepting the results as evidence for practice, however
the probability that an error was made should be evaluated.
• This coupled with the results of the hypothesis test, enables
the researcher to quantify the role of error in the outcome.
• The relationship between Type I and Type II error is
paradoxical – as one is controlled, the risk of other increases.
• Both types of error should be avoided
66
CALCULATING AND REPORTING TESTS
OF EFFECT SIZE
• Effect size refers to how much impact the intervention
or variable is expected to have on the outcome.
• Large effect sizes enhance the confidence of the
findings. When a treatment exerts a dramatic effect,
then the validity of the findings is not so called into
question.
• On the other hand, when effect sizes are very small,
then the potential for effects from extraneous
variables is more likely and the results may have less 67
ENSURING DATA MEET THE FUNDAMENTAL
ASSUMPTIONS OF THE STATISTICAL TEST
• Data analysis is based on many assumptions about the
nature of the data, the statistical procedures that are used
to conduct the analysis and the match between the data
and the procedure
• If assumption is violated, the result can be an inaccurate
estimate of the real relationship.
• In accurate conclusions lead to an error, which in turn
affects the validity of a study.
68
RESOURCES FOR STATISTICAL
ANALYSIS PROGRAM
• Packaged computer programs can perform the data analysis
and provide with the results of analysis on a computer
printout.
• SPSS, SAS and Biomedical Data Processing (BMDP)
• If the analysis selected are inappropriate for the data, the
computer program is often unable to detect that error and
proceed to perform the analysis
69
STATISTICALANALYSIS SYSTEM
Comprehensive software developed by North Carolina University.
This software is divided into many modules and its licensing is
flexible, based upon the need for functions.
This system contains a very large variety of statistical methods and is
the software of choice of many major businesses, including the entire
pharmaceutical industry.
SAS has also developed a PC SAS, which is compatible with the
personal computer and has a user-friendly windows interface.
70
PITFALLSOF STATISTICALANALYSIS
• Statistics can be used, intentionally or unintentionally, to reach faulty
conclusions. Misleading information is unfortunately the norm in
advertising. The drug companies, for example, are well known to
indulge in misleading information.
• Data dredging
• Survey questions
It is therefore important that to understand not just the numbers but
the meaning behind the numbers. Statistics is a tool, not a substitute
for in-depth reasoning and analysis
71
APPLICATION OF STATISTICAL ANALYSIS IN
NURSING FIELD
• To analyze a trend in the vital statistics of a particular patient.
• Research in nursing processes and procedures
• A statistical analysis of patient outcomes
• Trends in nursing
72
JOURNALABSTRACT
Use of Statistical Analysis in The New England Journal of Medicine
• A sorting of the statistical methods used by authors of the 760 research
and review articles in Volumes 298 to 301 of The New England Journal of
Medicine indicates that a reader who is conversant with descriptive
statistics (percentages, means, and standard deviations) has statistical
access to 58 per cent of the articles. Understanding t-tests increases this
access to 67 per cent.
• The addition of contingency tables gives statistical access to 73 per cent of
the articles.
• Familiarity with each additional statistical method gradually increases the
percentage of accessible articles.
• Original Articles use statistical techniques more extensively than other
articles in the Journal.
73
Statistical analysis and design in marketing
journal articles
• The use of statistical analysis in 922 articles from the 1980 through 1985
issues of the Journal of The Academy of Marketing Science (JAMS), the
Journal of Marketing (JM), the Journal of Marketing Research (JMR), and
the Journal of Consumer Research (JCR) was analyzed.
• A reader with no statistical background can understand 31, 56, 9, and 21
percent of the articles respectively in these four journals.
• Knowledge of regression and analysis of variance is important in
comprehending many of the articles.
• 38 percent of the JAMS articles and 25, 57 and 56 percent, respectively, of
the other three journals make use of these statistical techniques.
74
ASSIGNMENT
• Mean and Standard deviation of weight (Kg) of 100 School going(A) and
100 children not going to school(B) of 5 years of age in slum areas are given
below
Which test is used to find the statistical significance?
Population Sample
size
Mean SD
A 100 17.4 3
B 100 13.2 2.5
75
REFERENCES
• Indrayan A. Basic methods of medical research. NewDelhi: AITBS
Publishers; 2006.
• Kader P . Nursing Research: Principles, process and issues. Second
edition. Newyork : Palgrave Macmillan; 2006.
• Sundaram RK, Dwivedi SN, Sreenivas V. Medical Statistics : Principles
and methods. Second edition. New Delhi: Wolter Kluwer publication;
2015
• Rao SSSP. Biostatistics. Third edition. New Delhi: Prentice Hall India
Pvt Ltd;2004
76
Thank u
77

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  • 1. 1 Statistical Analysis Prof.Dr.Chinna Chadayan.N RN.RM., B.Sc (N)., M.Sc (N)., Ph.D (N)., Professor Enam Nursing College M.Sc (N) I year Unit 17a Statistical Analysis 1
  • 2. DEFINITION • Statistics is a branch of science that deals with the collection, organisation, analysis of data and drawing of inferences from the samples to the whole population. • Sample is a small portion of population which truly represents the population with respect to the study characteristic of the population. 2
  • 3. DEFINITION • Statistical analysis is the organisation and analysis of quantitative or qualitative data using statistical procedures, including both descriptive and inferential statistics. • It’s the science of collecting, exploring and presenting large amounts of data to discover underlying patterns and trends. 3
  • 4. PURPOSES 1. • To measure things 2. • To examine on relationship 3. • To predict or make predictions or infer from the samples to a theoretical model 4. • To test the proposed relationships in a theoretical model 5. • To test hypothesis 6. • To construct concept and develop theories 7. • To explore issues and the meaning of deviations in data 8. • To explain activities or attitude 9. • To describe what is happening 10.• Make comparison or contrast descriptively to find similarities and differences 11.• To draw conclusions about populations based on the sample result 12.• To Summarize the result and present an information 13.• To inform that the findings from sample are indicative 4
  • 5. ELEMENTS OF STATISTICAL ANALYSIS Understand the complex relationship among the correlates of the disease under study. The analysis should start with simple comparison of proportions and means. Interpretation of result should be guided by clinical and biological consideration. 5
  • 6. 6
  • 8. MEAN • The mean is the average of all numbers 8
  • 9. Example • Mean of 10, 20, 30, 40 25 9
  • 10. MEDIAN • When all the observations are arranged in ascending or descending orders of magnitude, the middle one is the median. • For raw data, If n is the total number of observations, the value of the 2 𝑛+1 [ ] th item will be called median . th 𝑛 2 • if n is the even number, the mean of n/2 item and [ + 1] th item will be median. Example : Median of given data 10, 20, 30 is 20 10
  • 11. MODE • The Mode is the value of a series which appears most frequently than any other . • For grouped data, 0 = 0 Mode, M L +{ 𝛥1 𝛥1+𝛥2 } x c Where, L0 is lower limit of modal class, C is class interval 𝛥1 is difference between modal frequency and its preceding class ∆2 is difference between modal frequency and following class frequency. Example: mode of given data 80, 90, 86, 80, 72, 80, 96 is 80 11
  • 12. INTERQUARTILE RANGE • The interquartile range (IQR), is a measure of statistical dispersion, being equal to the difference between 75th and 25th percentiles, or between upper and lower quartiles. • IQR = Q3 − Q1. 12
  • 13. Example Interquartile range of following data 30, 20, 40, 60 , 50 4 • Q1 =[ 𝑛+1 ]th item = 1.5th item = 20+ 0.5 (30-20) = 25 4 • Q3 = 3[ 𝑛+1 ]th item = 50 +0.5x (60-50) = 55. • IQR = 30 13
  • 14. STANDARD DEVIATION • The standard deviation is the most useful and most popular measure of dispersion. • The standard deviation is defined as the positive square root of the arithmetic mean of the square of the deviations of given observations from their arithmetic mean. • The standard deviation is denoted by ‘𝜎 ’. 14
  • 16. EXAMPLE • Standard deviation of data 10, 20, 30, 40, 50 where n= 5 , 𝑥̅ = 30 • 𝜎 = √1000/4 = √250 = 15. 811 16
  • 17. STANDARD NORMAL DISTRIBUTION CURVE AND MEAN, MEDIAN, INTERQUARTILE RANGE AND STANDARD DEVIATION 17
  • 18. TYPES • PARAMETRIC STATISTICAL ANALYSIS • NONPARAMETRIC STATISTICAL ANALYSIS 18
  • 19. PARAMETRIC STATISTICAL ANALYSIS • Most commonly used type of statistical analysis. • This analysis is referred to as parametric statistical analysis because the findings are inferred to the parameters of a normally distributed populations. • Numerical data (quantitative variables) that are normally distributed are analysed with parametric tests. 19
  • 20. ASSUMPTIONS • The assumption of normality which specifies that the means of the sample group are normally distributed • The assumption of equal variance which specifies that the variances of the samples and of their corresponding population are equal. • The data can be treated as random samples 20
  • 21. NONPARAMETRIC STATISTICAL ANALYSIS • Nonparametric statistical analysis or distribution free techniques • It can be used in studies that do not meet the first two assumptions. • Most nonparametric techniques are not as powerful as their parametric counter parts. 21
  • 22. • If the distribution of the sample is skewed towards one side or the distribution is unknown due to the small sample size, non-parametric statistical techniques are used. • Non-parametric tests are used to analyse ordinal and categorical data. 22
  • 23. EXPLORATORY DATA ANALYSIS AND CONFIRMATORY DATA ANALYSIS • John Tukey • Exploratory data analysis to obtain a preliminary indication of the nature of the data and to search data for hidden structure or models. • Confirmatory data analysis involves traditional inferential statistics , which you can use to make an inference about a population or a process based on evidence from the study sample. 23
  • 24. STATISTICAL ANALYSIS DECISION MAKING Two group comparison Mean Parametric Independent 2 sample t test Percentage One group comparison Mean Nonparametric Mann Witney U test Chi-Square Test Single mean One sample t test Mean difference Parametric Paired t test Non parametric Wilcoxan Signed Scale test More than 2 group comparison Mean Parametric ANOVA Non parametric Kruskal Walli’s test Percentage Chi square test 24
  • 25. P ARAMETRIC STATISTICAL ANALYSIS Student's t-test  Z test Analysis of variance (ANOVA) 25
  • 26. Student's t-test • Developed by Prof.W.S.Gossett • Student's t-test is used to test the null hypothesis that there is no difference between the means of the two groups • One-sample t-test • Independent Two Sample T Test (the unpaired t-test) • The paired t-test 26
  • 27. One-sample t-test • To test if a sample mean (as an estimate of a population mean) differs significantly from a given population mean. • The mean of one sample is compared with population mean where 𝑥̅ = sample mean, u = population mean and S = standard deviation, n = sample size 27
  • 28. Example A random sample of size 20 from a normal population gives a sample mean of 40, standard deviation of 6. Test the hypothesis is population mean is 44. Check whether there is any difference between mean. • H0: There is no significant difference between sample mean and population mean • H1: There is no significant difference between sample mean and population mean mean = 40 , 𝜇 = 44, n = 20 and S = 6 28
  • 29. •tcalculated = 2.981 •t table value = 2.093 •tcalculated > t table value ; Reject H0. 29
  • 30. Independent Two Sample T Test (the unpaired t-test) • To test if the population means estimated by two independent samples differ significantly. • Two different samples with same mean at initial point and compare mean at the end 30
  • 31. t = 𝑥1−𝑥̅2 1 2 𝑛1−1 𝑆2+ 𝑛2−1 𝑆2 𝑛1+𝑛2−2 + 1 1 𝑛1 𝑛2 Where 𝑥̅1 -𝑥̅2 is the difference between the means of the two groups and S denotes the standard deviation. 31
  • 32. Example Mean Hb level of 5 male are 10, 11, 12.5, 10.5, 12 and 5 female are 10, 17.5, 14.2,15 and 14.1 . Test whether there is any significant difference between Hb values. • H0: There is no significant difference between Hb Level • H1: There is no significant difference between Hb level. t = 𝑥1−𝑥̅2 1 2 𝑛1−1 𝑆2+ 𝑛2−1 𝑆2 𝑛1+𝑛2−2 + 1 1 𝑛1 𝑛2 32
  • 33. • 𝑥1 = 11.2 , 𝑥2 =14.16 , 𝑆2 = 1.075, 𝑆2 = 7.293 1 2 •tcalculated = 2.287, t table = 2.306, tcalculated > t table value ; reject H0. X1 X2 X1 - 𝑥1 X2 - 𝑥2 (X1 - 𝑥1)2 (X2 - 𝑥2)2 10 10 -1.2 -4.16 1.44 17.305 11 17.5 - 0.2 3.34 0.04 11.156 12.5 14.2 1.3 0.04 1.69 0.0016 10.5 15 -0.7 0.84 0.49 0.706 12 14.1 0.8 -0.06 0.64 0.0036 Σ = 56 70.8 4.3 29.172 33
  • 34. The paired t-test • To test if the population means estimated by two dependent samples differ significantly . • A usual setting for paired t-test is when measurements are made on the same subjects before and after a treatment. where 𝑑̅ is the mean difference and Sd denotes the standard deviation of the difference. 34
  • 35. Example Systolic BP of 5 patients before and after a drug therapy is Before 160, 150, 170, 130, 140 After 140, 110, 120, 140, 130 Test whether there is any significant difference between BP level. • H0: There is no significant difference between BP Level before and after drug • H1: There is no significant difference between BP level before and after drug 35
  • 36. • 𝑑̅ = 22, Sd = 23.875 •tcalculated = 2.060, t table = 2.567, tcalculated < t table value ; Accept H0. Before After d d-𝑑̅ (d-𝑑̅ )2 160 140 20 -2 4 150 110 40 18 324 170 120 50 28 784 130 140 -10 -32 1024 140 130 10 -12 144 𝛴𝑑 = 110 2280 36
  • 37. Z test Generally, z-tests are used when we have large sample sizes (n > 30), whereas t-tests are most helpful with a smaller sample size (n < 30). Both methods assume a normal distribution of the data, but the z-tests are most useful when the standard deviation is known. z = (x – μ) / (σ / √n) 37
  • 38. ANALYSIS OF VARIANCE (ANOVA) • R. A. Fischer. • The Student's t-test cannot be used for comparison of three or more groups. • The purpose of ANOVA is to test if there is any significant difference between the means of two or more groups. • The analysis of variance is the systematic algebraic procedure of decomposing the overall variation in the responses observed in an experiment into variation. • Two variances – (a) between-group variability and (b) within-group variability that is variation existing between the samples and variations existing within the sample. • The within-group variability (error variance) is the variation that cannot be accounted for in the study design. • The between-group (or effect variance) is the result of treatment 38
  • 39. • A simplified formula for the F statistic is where MST is the mean squares between the groups and MSE is the mean squares within groups 39
  • 40. NONP ARAMETRIC STATISTICAL ANALYSIS  CHI-SQUARE TEST  THE WILCOXON'S SIGNED RANK TEST  MANN-WHITNEY U TEST  KRUSKAL-WALLIS TEST 40
  • 41. CHI-SQUARE TEST • Tests to analyse the categorical data • The chi-square test is a widely used test in statistical decision making. • The test is first used by Karl pearson in 1900. • The Chi-square test compares the frequencies and tests whether the observed data differ significantly from that of the expected data. 41
  • 42. CHI-SQUARE TEST It is calculated by the sum of the squared difference between observed (O) and the expected (E) data (or the deviation, d) divided by the expected data by the following formula: 42
  • 43. Example • Attack rates among vaccinated and not vaccinated against measles are given in the following table. Test the association between association between vaccination and attack of measles Groups Attacked Not attacked Vaccinated 10 90 Not vaccinated 26 74 43
  • 44. • H0: There is no significant association between vaccination and attack of measles • H1: There is significant association between vaccination and attack of measles 44
  • 45. • Chi square table value = 3.841 , chi square calculated value = 8.672 • 𝑥2 calculated > 𝑥2 table value ; Reject H0. Oi Ei Oi - Ei (Oi - Ei )2 (Oi - Ei )2 / Ei 10 18 -8 64 3.556 90 82 8 64 0.780 26 18 8 64 3.556 74 82 -8 64 0.780 𝛴 = 8.672 45
  • 46. THE WILCOXON'S SIGNED RANK TEST • Wilcoxon's rank sum test ranks all data points in order, calculates the rank sum of each sample and compares the difference in the rank sums. • For testing whether the differences observed in the values of the quantitative variable between two correlated samples (before and after design ) are statistically different or not • This test corresponds to the paired t test. 46
  • 47. Method • H0: There is no difference in the paired values, on an average, between the two groups. • H1: There is difference in the paired values, on an average, between the two groups. • Compute the difference between each group of paired values in the two group. • Rank the difference from smallest, without considering the sign of difference. • After giving ranks, the corresponding sign should be attached. • T+ (Sum of ranks of positive sign) and T- (Sum of ranks between negative sign). T is taken as smallest of T+ and T-. Then Wstat is the smallest value of T- and T+ . • Find the W critical value from Wilcoxon’s Signed rank Table . • if Wstat < WCritical Value; Reject H0. 47
  • 48. EXAMPLE • IQ values of 8 malnourished children of 4 years age before and after giving some nutritious diet for 3 months are given below Before 40 60 55 65 43 70 80 60 After 50 80 50 70 40 60 90 85 48
  • 49. • H0: There is no difference in the paired values • H1: There is difference in the paired values Before 40 60 55 65 43 70 80 60 After 50 80 50 70 40 60 90 85 Differe nce -10 -20 5 -5 3 10 -10 -15 Absolu te differe nce 10 20 5 5 3 10 10 15 Rank 5 8 2.5 2.5 1 5 5 7 49
  • 50. • T+ = 8.5, T- = 27.5. T = 8.5 • Wstat = 8.5, Wcritic = 3 • Wstat > WCritical Value; Accept H0. 50
  • 51. • If Assuming normal distribution for the differences, test statistic is, Z = {|T-m| -0.5} / SD Where T = smaller of T+ and T- , m= mean sum of ranks {n(n+1)}/4 and SD = √{ 𝑛 𝑛+1 2𝑛 +1 24 } • If Z is less than 1.96, H0 is accepted and if Z>1.96 , H0 is rejected 51
  • 52. MANN-WHITNEY U TEST • For testing whether two independent samples with respect to a quantitative variable come from the same population or not. • Wilcoxon’s Rank Sum test. • It is used to test the null hypothesis that two samples have the same median or, alternatively, whether observations in one sample tend to be larger than observations in the other. • This test is alternative of t test for two independent samples 52
  • 53. METHOD H0: The average values in the two groups are the same H1: The average values in the two groups are the different • Let n1 is the sample size of one group and n2 is the sample size of second group, Rank all the values in the two groups take together. Tied values should be given same ranks. • The ranksum of each group is taken and Ustat is calculated using Ustat = Rank Sum - {n(n +1)/2 }. • Both U1 and U2 is calculated and smaller value is taken as Ustat. and Ucritical value is calculated from the Mann- Whitney U test table • if Ustat < UCritical value; ; Reject H0. 53
  • 54. Example Treatment A Treatment B 3 9 4 7 2 5 6 10 2 6 5 8 54
  • 55. • H0: The average values in the 2 treatment are the same • H1: The average values in the 2 treatment are the different Ustat = Rank Sum - {n(n +1)/2 }. Ranks 1 2 3 4 5 6 7 8 9 10 11 12 Values 2 2 3 4 5 5 6 6 7 8 9 10 Rank 1.5 1.5 3 4 5.5 5.5 7.5 7.5 9 10 11 12 55
  • 56. • UA = 23 – 21 = 2, UB = 55- 21 =34 so Ustat = 2 (lowest value) • Ucritic = 5 • Ustat < UCritical value; Reject H0. 56
  • 57. • Assuming that the ranks are randomly distributed in the two groups, the test statisticis Z = {|m-T| -0.5} / SD Where T = smaller of T1 and T2. T1 = sum of the ranks of smaller group, T2 = {(n1 +n2)(n1 +n2 +1) / 2} – T1 , m= mean sum of ranks { n1 ( n1 +n2+1)}/2 SD = √{ )( + + n1 X n2 n1 n2 1 12 } • If Z is less than 1.96, H0 is accepted • if Z>1.96 , H0 is rejected at 5% level of significance 57
  • 58. KRUSKAL-WALLIS TEST • The Kruskal–Wallis test is a non-parametric test to analyse the variance. • It is for the comparison among several independent samples. • For testing whether several independent samples of a quantitative variable come from the same population or not • It corresponds to one way analysis of variance in parametric methods. 58
  • 59. • It analyses if there is any difference in the median values of three or more independent samples. • The data values are ranked in an increasing order, and the rank sums calculated followed by calculation of the test Where n is the total of sample sizes in all the groups and Ri is the sum of the ranks in the ith group. 59
  • 60. Method H0: The average values in the different groups are the same H1: The average values in the different groups are the different • Rank the all values taking all the group together. • The chisquare table is used to get table value at 5% level of significane • if Hstat is < Htable value ; reject H0 60
  • 61. Example Sample 1 Sample 2 Sample 3 8 10 13 10 9 8 9 13 9 12 14 13 11 9 17 13 16 15 61
  • 62. • H0: The average values in the three groups are the same • H1: The average values in the three groups are the different Rank 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 Value s 8 8 9 9 9 9 10 10 11 12 13 13 13 13 14 15 16 17 Tied rank 1.5 1.5 4.75 4.75 4.75 4.75 7.5 7.5 9 10 12.5 12.5 12.5 12.5 15 16 17 18 62
  • 63. • H = {12/18x19 [ (45.252 /6 ) + (61.52/6) + (65.52/6 )]} – 3x19 •Hcalculated = 56.99 , 𝑥2 table value = 5.99 •Hstat > 𝑥2 table value ; Reject H0 Sample 1 Rank 1 Sample 2 Rank 2 Sample 3 Rank 3 8 1.5 10 7.5 13 12.5 10 7.5 9 4.75 8 1.5 9 4.75 13 12.5 9 4.75 12 10 14 15 13 12.5 11 9 9 4.75 17 18 13 12.5 16 17 15 16 𝛴 = 45.25 𝛴 = 61.5 𝛴 = 65.25 63
  • 64. WAYS TO RULE OUT ALTERNATIVE EXPLANATIONS FOR OUTCOMES BY USING STATISTICAL ANALYSIS • Testing null hypothesis • Determining the probability of type I and type II error • Calculating and reporting tests of effect size • Ensuring data meet the fundamental assumptions of the statistical test 64
  • 65. TESTING NULL HYPOTHESIS • When attempting to determine if an outcome is related to a cause, it is necessary to know if the outcomes or results could have occurred by chance alone. • This cannot be done with certainity, but researchers can determine the probability that the hypothesis is true. • Accepting a null hypothesis is a statement that there are no differences in the outcomes based on the intervention or observation(that is, there is no cause and effect relationship). • Using a null hypothesis enables the researcher to quantify and report the probability that the outcome was due to random error. 65
  • 66. DETERMINING THE PROBABILITY OF TYPE I AND TYPE II ERROR • Before accepting the results as evidence for practice, however the probability that an error was made should be evaluated. • This coupled with the results of the hypothesis test, enables the researcher to quantify the role of error in the outcome. • The relationship between Type I and Type II error is paradoxical – as one is controlled, the risk of other increases. • Both types of error should be avoided 66
  • 67. CALCULATING AND REPORTING TESTS OF EFFECT SIZE • Effect size refers to how much impact the intervention or variable is expected to have on the outcome. • Large effect sizes enhance the confidence of the findings. When a treatment exerts a dramatic effect, then the validity of the findings is not so called into question. • On the other hand, when effect sizes are very small, then the potential for effects from extraneous variables is more likely and the results may have less 67
  • 68. ENSURING DATA MEET THE FUNDAMENTAL ASSUMPTIONS OF THE STATISTICAL TEST • Data analysis is based on many assumptions about the nature of the data, the statistical procedures that are used to conduct the analysis and the match between the data and the procedure • If assumption is violated, the result can be an inaccurate estimate of the real relationship. • In accurate conclusions lead to an error, which in turn affects the validity of a study. 68
  • 69. RESOURCES FOR STATISTICAL ANALYSIS PROGRAM • Packaged computer programs can perform the data analysis and provide with the results of analysis on a computer printout. • SPSS, SAS and Biomedical Data Processing (BMDP) • If the analysis selected are inappropriate for the data, the computer program is often unable to detect that error and proceed to perform the analysis 69
  • 70. STATISTICALANALYSIS SYSTEM Comprehensive software developed by North Carolina University. This software is divided into many modules and its licensing is flexible, based upon the need for functions. This system contains a very large variety of statistical methods and is the software of choice of many major businesses, including the entire pharmaceutical industry. SAS has also developed a PC SAS, which is compatible with the personal computer and has a user-friendly windows interface. 70
  • 71. PITFALLSOF STATISTICALANALYSIS • Statistics can be used, intentionally or unintentionally, to reach faulty conclusions. Misleading information is unfortunately the norm in advertising. The drug companies, for example, are well known to indulge in misleading information. • Data dredging • Survey questions It is therefore important that to understand not just the numbers but the meaning behind the numbers. Statistics is a tool, not a substitute for in-depth reasoning and analysis 71
  • 72. APPLICATION OF STATISTICAL ANALYSIS IN NURSING FIELD • To analyze a trend in the vital statistics of a particular patient. • Research in nursing processes and procedures • A statistical analysis of patient outcomes • Trends in nursing 72
  • 73. JOURNALABSTRACT Use of Statistical Analysis in The New England Journal of Medicine • A sorting of the statistical methods used by authors of the 760 research and review articles in Volumes 298 to 301 of The New England Journal of Medicine indicates that a reader who is conversant with descriptive statistics (percentages, means, and standard deviations) has statistical access to 58 per cent of the articles. Understanding t-tests increases this access to 67 per cent. • The addition of contingency tables gives statistical access to 73 per cent of the articles. • Familiarity with each additional statistical method gradually increases the percentage of accessible articles. • Original Articles use statistical techniques more extensively than other articles in the Journal. 73
  • 74. Statistical analysis and design in marketing journal articles • The use of statistical analysis in 922 articles from the 1980 through 1985 issues of the Journal of The Academy of Marketing Science (JAMS), the Journal of Marketing (JM), the Journal of Marketing Research (JMR), and the Journal of Consumer Research (JCR) was analyzed. • A reader with no statistical background can understand 31, 56, 9, and 21 percent of the articles respectively in these four journals. • Knowledge of regression and analysis of variance is important in comprehending many of the articles. • 38 percent of the JAMS articles and 25, 57 and 56 percent, respectively, of the other three journals make use of these statistical techniques. 74
  • 75. ASSIGNMENT • Mean and Standard deviation of weight (Kg) of 100 School going(A) and 100 children not going to school(B) of 5 years of age in slum areas are given below Which test is used to find the statistical significance? Population Sample size Mean SD A 100 17.4 3 B 100 13.2 2.5 75
  • 76. REFERENCES • Indrayan A. Basic methods of medical research. NewDelhi: AITBS Publishers; 2006. • Kader P . Nursing Research: Principles, process and issues. Second edition. Newyork : Palgrave Macmillan; 2006. • Sundaram RK, Dwivedi SN, Sreenivas V. Medical Statistics : Principles and methods. Second edition. New Delhi: Wolter Kluwer publication; 2015 • Rao SSSP. Biostatistics. Third edition. New Delhi: Prentice Hall India Pvt Ltd;2004 76