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Section 4.4
                  Curve Sketching

                V63.0121.002.2010Su, Calculus I

                        New York University


                        June 10, 2010



Announcements
   Homework 4 due Tuesday


                                              .   .   .   .   .   .
Announcements




           Homework 4 due Tuesday




                                                                      .   .   .     .      .      .

V63.0121.002.2010Su, Calculus I (NYU)   Section 4.4 Curve Sketching               June 10, 2010       2 / 45
Objectives




           given a function, graph it
           completely, indicating
                   zeroes (if easy)
                   asymptotes if applicable
                   critical points
                   local/global max/min
                   inflection points




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V63.0121.002.2010Su, Calculus I (NYU)   Section 4.4 Curve Sketching               June 10, 2010       3 / 45
Why?




  Graphing functions is like
  dissection




                                                                      .   .   .     .      .      .

V63.0121.002.2010Su, Calculus I (NYU)   Section 4.4 Curve Sketching               June 10, 2010       4 / 45
Why?




  Graphing functions is like
  dissection … or diagramming
  sentences




                                                                      .   .   .     .      .      .

V63.0121.002.2010Su, Calculus I (NYU)   Section 4.4 Curve Sketching               June 10, 2010       4 / 45
Why?




  Graphing functions is like
  dissection … or diagramming
  sentences
  You can really know a lot about
  a function when you know all of
  its anatomy.




                                                                      .   .   .     .      .      .

V63.0121.002.2010Su, Calculus I (NYU)   Section 4.4 Curve Sketching               June 10, 2010       4 / 45
The Increasing/Decreasing Test

 Theorem (The Increasing/Decreasing Test)
 If f′ > 0 on (a, b), then f is increasing on (a, b). If f′ < 0 on (a, b), then f
 is decreasing on (a, b).

 Example
 Here f(x) = x3 + x2 , and f′ (x) = 3x2 + 2x.

                                                                      f
                                                                      .(x)
                                                           .′ (x)
                                                           f



                                                .


                                                                       .     .   .     .      .      .

V63.0121.002.2010Su, Calculus I (NYU)   Section 4.4 Curve Sketching                  June 10, 2010       5 / 45
Testing for Concavity
 Theorem (Concavity Test)
 If f′′ (x) > 0 for all x in (a, b), then the graph of f is concave upward on
 (a, b) If f′′ (x) < 0 for all x in (a, b), then the graph of f is concave
 downward on (a, b).

 Example
 Here f(x) = x3 + x2 , f′ (x) = 3x2 + 2x, and f′′ (x) = 6x + 2.
                                            .′′ (x)
                                            f                    f
                                                                 .(x)
                                                      .′ (x)
                                                      f




                                                .


                                                                        .   .   .     .      .      .

V63.0121.002.2010Su, Calculus I (NYU)   Section 4.4 Curve Sketching                 June 10, 2010       6 / 45
Graphing Checklist


To graph a function f, follow this plan:
  0. Find when f is positive, negative, zero,
     not defined.
  1. Find f′ and form its sign chart. Conclude
     information about increasing/decreasing
     and local max/min.
  2. Find f′′ and form its sign chart. Conclude
     concave up/concave down and inflection.
  3. Put together a big chart to assemble
     monotonicity and concavity data
  4. Graph!



                                                                      .   .   .     .      .      .

V63.0121.002.2010Su, Calculus I (NYU)   Section 4.4 Curve Sketching               June 10, 2010       7 / 45
Outline



 Simple examples
    A cubic function
    A quartic function


 More Examples
   Points of nondifferentiability
   Horizontal asymptotes
   Vertical asymptotes
   Trigonometric and polynomial together
   Logarithmic



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V63.0121.002.2010Su, Calculus I (NYU)   Section 4.4 Curve Sketching               June 10, 2010       8 / 45
Graphing a cubic


 Example
 Graph f(x) = 2x3 − 3x2 − 12x.




                                                                      .   .   .     .      .      .

V63.0121.002.2010Su, Calculus I (NYU)   Section 4.4 Curve Sketching               June 10, 2010       9 / 45
Graphing a cubic


 Example
 Graph f(x) = 2x3 − 3x2 − 12x.

 (Step 0) First, let’s find the zeros. We can at least factor out one power
 of x:
                             f(x) = x(2x2 − 3x − 12)
 so f(0) = 0. The other factor is a quadratic, so we the other two roots
 are                        √
                                                     √
                       3 ± 32 − 4(2)(−12)        3 ± 105
                  x=                          =
                                  4                  4
 It’s OK to skip this step for now since the roots are so complicated.


                                                                      .   .   .     .      .      .

V63.0121.002.2010Su, Calculus I (NYU)   Section 4.4 Curve Sketching               June 10, 2010       9 / 45
Step 1: Monotonicity



                                 f(x) = 2x3 − 3x2 − 12x
                        =⇒ f′ (x) = 6x2 − 6x − 12 = 6(x + 1)(x − 2)

 We can form a sign chart from this:

                                        .




                                                                          .   .   .      .       .    .

V63.0121.002.2010Su, Calculus I (NYU)       Section 4.4 Curve Sketching               June 10, 2010   10 / 45
Step 1: Monotonicity



                                 f(x) = 2x3 − 3x2 − 12x
                        =⇒ f′ (x) = 6x2 − 6x − 12 = 6(x + 1)(x − 2)

 We can form a sign chart from this:

                                        .                     .               . −2
                                                                              x
                                                            2
                                                            .
                                  .                                           x
                                                                              . +1
                                −
                                . 1
                                                                              .′ (x)
                                                                              f
                                  .                           .
                                −
                                . 1                         2
                                                            .                 f
                                                                              .(x)


                                                                          .   .        .      .       .    .

V63.0121.002.2010Su, Calculus I (NYU)       Section 4.4 Curve Sketching                    June 10, 2010   10 / 45
Step 1: Monotonicity



                                 f(x) = 2x3 − 3x2 − 12x
                        =⇒ f′ (x) = 6x2 − 6x − 12 = 6(x + 1)(x − 2)

 We can form a sign chart from this:

                            −
                            .             −
                                        . .               .       .
                                                                  +
                                                                          . −2
                                                                          x
                                                        2
                                                        .
                                  .                                       x
                                                                          . +1
                                −
                                . 1
                                                                          .′ (x)
                                                                          f
                                  .                       .
                                −
                                . 1                     2
                                                        .                 f
                                                                          .(x)


                                                                      .   .        .      .       .    .

V63.0121.002.2010Su, Calculus I (NYU)   Section 4.4 Curve Sketching                    June 10, 2010   10 / 45
Step 1: Monotonicity



                                 f(x) = 2x3 − 3x2 − 12x
                        =⇒ f′ (x) = 6x2 − 6x − 12 = 6(x + 1)(x − 2)

 We can form a sign chart from this:

                            −
                            .             −
                                        . .               .       .
                                                                  +
                                                                          . −2
                                                                          x
                                                        2
                                                        .
                            −
                            . .          .
                                         +                        .
                                                                  +
                                                                          x
                                                                          . +1
                              −
                              . 1
                                                                          .′ (x)
                                                                          f
                                  .                       .
                                −
                                . 1                     2
                                                        .                 f
                                                                          .(x)


                                                                      .   .        .      .       .    .

V63.0121.002.2010Su, Calculus I (NYU)   Section 4.4 Curve Sketching                    June 10, 2010   10 / 45
Step 1: Monotonicity



                                 f(x) = 2x3 − 3x2 − 12x
                        =⇒ f′ (x) = 6x2 − 6x − 12 = 6(x + 1)(x − 2)

 We can form a sign chart from this:

                            −
                            .             −
                                        . .               .       .
                                                                  +
                                                                          . −2
                                                                          x
                                                        2
                                                        .
                            −
                            . .          .
                                         +                        .
                                                                  +
                                                                          x
                                                                          . +1
                              −
                              . 1
                            . .
                            +                                             .′ (x)
                                                                          f
                                                          .
                                −
                                . 1                     2
                                                        .                 f
                                                                          .(x)


                                                                      .   .        .      .       .    .

V63.0121.002.2010Su, Calculus I (NYU)   Section 4.4 Curve Sketching                    June 10, 2010   10 / 45
Step 1: Monotonicity



                                 f(x) = 2x3 − 3x2 − 12x
                        =⇒ f′ (x) = 6x2 − 6x − 12 = 6(x + 1)(x − 2)

 We can form a sign chart from this:

                            −
                            .             −
                                        . .               .       .
                                                                  +
                                                                          . −2
                                                                          x
                                                        2
                                                        .
                            −
                            . .          .
                                         +                        .
                                                                  +
                                                                          x
                                                                          . +1
                              −
                              . 1
                            . .
                            +            −
                                         .                                .′ (x)
                                                                          f
                                                          .
                                −
                                . 1                     2
                                                        .                 f
                                                                          .(x)


                                                                      .   .        .      .       .    .

V63.0121.002.2010Su, Calculus I (NYU)   Section 4.4 Curve Sketching                    June 10, 2010   10 / 45
Step 1: Monotonicity



                                 f(x) = 2x3 − 3x2 − 12x
                        =⇒ f′ (x) = 6x2 − 6x − 12 = 6(x + 1)(x − 2)

 We can form a sign chart from this:

                            −
                            .             −
                                        . .               .       .
                                                                  +
                                                                          . −2
                                                                          x
                                                        2
                                                        .
                            −
                            . .          .
                                         +                        .
                                                                  +
                                                                          x
                                                                          . +1
                              −
                              . 1
                            . .
                            +            −
                                         .                        .
                                                                  +       .′ (x)
                                                                          f
                                                          .
                                −
                                . 1                     2
                                                        .                 f
                                                                          .(x)


                                                                      .   .        .      .       .    .

V63.0121.002.2010Su, Calculus I (NYU)   Section 4.4 Curve Sketching                    June 10, 2010   10 / 45
Step 1: Monotonicity



                                 f(x) = 2x3 − 3x2 − 12x
                        =⇒ f′ (x) = 6x2 − 6x − 12 = 6(x + 1)(x − 2)

 We can form a sign chart from this:

                            −
                            .             −
                                        . .               .       .
                                                                  +
                                                                          . −2
                                                                          x
                                                        2
                                                        .
                            −
                            . .          .
                                         +                        .
                                                                  +
                                                                          x
                                                                          . +1
                              −
                              . 1
                            . .
                            +            −
                                         .                        .
                                                                  +       .′ (x)
                                                                          f
                                                          .
                            ↗−
                            . . 1                       2
                                                        .                 f
                                                                          .(x)


                                                                      .   .        .      .       .    .

V63.0121.002.2010Su, Calculus I (NYU)   Section 4.4 Curve Sketching                    June 10, 2010   10 / 45
Step 1: Monotonicity



                                 f(x) = 2x3 − 3x2 − 12x
                        =⇒ f′ (x) = 6x2 − 6x − 12 = 6(x + 1)(x − 2)

 We can form a sign chart from this:

                            −
                            .             −
                                        . .               .       .
                                                                  +
                                                                          . −2
                                                                          x
                                                        2
                                                        .
                            −
                            . .          .
                                         +                        .
                                                                  +
                                                                          x
                                                                          . +1
                              −
                              . 1
                            . .
                            +            −
                                         .                        .
                                                                  +       .′ (x)
                                                                          f
                                                          .
                            ↗−
                            . . 1        ↘
                                         .              2
                                                        .                 f
                                                                          .(x)


                                                                      .   .        .      .       .    .

V63.0121.002.2010Su, Calculus I (NYU)   Section 4.4 Curve Sketching                    June 10, 2010   10 / 45
Step 1: Monotonicity



                                 f(x) = 2x3 − 3x2 − 12x
                        =⇒ f′ (x) = 6x2 − 6x − 12 = 6(x + 1)(x − 2)

 We can form a sign chart from this:

                            −
                            .             −
                                        . .               .       .
                                                                  +
                                                                          . −2
                                                                          x
                                                        2
                                                        .
                            −
                            . .          .
                                         +                        .
                                                                  +
                                                                          x
                                                                          . +1
                              −
                              . 1
                            . .
                            +            −
                                         .                       .
                                                                 +        .′ (x)
                                                                          f
                                                          .
                            ↗−
                            . . 1        ↘
                                         .              2
                                                        .        ↗
                                                                 .        f
                                                                          .(x)


                                                                      .   .        .      .       .    .

V63.0121.002.2010Su, Calculus I (NYU)   Section 4.4 Curve Sketching                    June 10, 2010   10 / 45
Step 1: Monotonicity



                                 f(x) = 2x3 − 3x2 − 12x
                        =⇒ f′ (x) = 6x2 − 6x − 12 = 6(x + 1)(x − 2)

 We can form a sign chart from this:

                            −
                            .             −
                                        . .               .       .
                                                                  +
                                                                          . −2
                                                                          x
                                                        2
                                                        .
                            −
                            . .          .
                                         +                        .
                                                                  +
                                                                          x
                                                                          . +1
                               −
                               . 1
                            . .
                            +            −
                                         .                       .
                                                                 +        .′ (x)
                                                                          f
                                                          .
                            ↗−
                            . . 1        ↘
                                         .              2
                                                        .        ↗
                                                                 .        f
                                                                          .(x)
                              m
                              . ax

                                                                      .   .        .      .       .    .

V63.0121.002.2010Su, Calculus I (NYU)   Section 4.4 Curve Sketching                    June 10, 2010   10 / 45
Step 1: Monotonicity



                                 f(x) = 2x3 − 3x2 − 12x
                        =⇒ f′ (x) = 6x2 − 6x − 12 = 6(x + 1)(x − 2)

 We can form a sign chart from this:

                            −
                            .             −
                                        . .               .       .
                                                                  +
                                                                          . −2
                                                                          x
                                                        2
                                                        .
                            −
                            . .          .
                                         +                        .
                                                                  +
                                                                          x
                                                                          . +1
                               −
                               . 1
                            . .
                            +            −
                                         .                       .
                                                                 +        .′ (x)
                                                                          f
                                                         .
                            ↗−
                            . . 1        ↘
                                         .             2
                                                       .         ↗
                                                                 .        f
                                                                          .(x)
                              m
                              . ax                    m
                                                      . in

                                                                      .   .        .      .       .    .

V63.0121.002.2010Su, Calculus I (NYU)   Section 4.4 Curve Sketching                    June 10, 2010   10 / 45
Step 2: Concavity




                                        f′ (x) = 6x2 − 6x − 12
                                 =⇒ f′′ (x) = 12x − 6 = 6(2x − 1)

 Another sign chart:                     .




                                                                           .   .   .      .      .     .

V63.0121.002.2010Su, Calculus I (NYU)        Section 4.4 Curve Sketching               June 10, 2010   11 / 45
Step 2: Concavity




                                        f′ (x) = 6x2 − 6x − 12
                                 =⇒ f′′ (x) = 12x − 6 = 6(2x − 1)

 Another sign chart:                     .
                                                                               .′′ (x)
                                                                               f
                                                .
                                              ./2
                                              1                                f
                                                                               .(x)




                                                                           .   .      .      .      .     .

V63.0121.002.2010Su, Calculus I (NYU)        Section 4.4 Curve Sketching                  June 10, 2010   11 / 45
Step 2: Concavity




                                        f′ (x) = 6x2 − 6x − 12
                                 =⇒ f′′ (x) = 12x − 6 = 6(2x − 1)

 Another sign chart:                     .

                                −
                                . −                                            .′′ (x)
                                                                               f
                                                .
                                              ./2
                                              1                                f
                                                                               .(x)




                                                                           .   .      .      .      .     .

V63.0121.002.2010Su, Calculus I (NYU)        Section 4.4 Curve Sketching                  June 10, 2010   11 / 45
Step 2: Concavity




                                        f′ (x) = 6x2 − 6x − 12
                                 =⇒ f′′ (x) = 12x − 6 = 6(2x − 1)

 Another sign chart:                     .

                                −
                                . −                    . +
                                                       +                       .′′ (x)
                                                                               f
                                                .
                                              ./2
                                              1                                f
                                                                               .(x)




                                                                           .   .      .      .      .     .

V63.0121.002.2010Su, Calculus I (NYU)        Section 4.4 Curve Sketching                  June 10, 2010   11 / 45
Step 2: Concavity




                                        f′ (x) = 6x2 − 6x − 12
                                 =⇒ f′′ (x) = 12x − 6 = 6(2x − 1)

 Another sign chart:                     .

                                −
                                . −                    . +
                                                       +                       .′′ (x)
                                                                               f
                                                .
                                 .
                                 ⌢            ./2
                                              1                                f
                                                                               .(x)




                                                                           .   .      .      .      .     .

V63.0121.002.2010Su, Calculus I (NYU)        Section 4.4 Curve Sketching                  June 10, 2010   11 / 45
Step 2: Concavity




                                        f′ (x) = 6x2 − 6x − 12
                                 =⇒ f′′ (x) = 12x − 6 = 6(2x − 1)

 Another sign chart:                     .

                                −
                                . −                    . +
                                                       +                       .′′ (x)
                                                                               f
                                                .
                                 .
                                 ⌢            ./2
                                              1         .
                                                        ⌣                      f
                                                                               .(x)




                                                                           .   .      .      .      .     .

V63.0121.002.2010Su, Calculus I (NYU)        Section 4.4 Curve Sketching                  June 10, 2010   11 / 45
Step 2: Concavity




                                        f′ (x) = 6x2 − 6x − 12
                                 =⇒ f′′ (x) = 12x − 6 = 6(2x − 1)

 Another sign chart:                     .

                                −
                                . −                    . +
                                                       +                       .′′ (x)
                                                                               f
                                                .
                                 .
                                 ⌢            ./2
                                              1         .
                                                        ⌣                      f
                                                                               .(x)
                                              I
                                              .P




                                                                           .   .      .      .      .     .

V63.0121.002.2010Su, Calculus I (NYU)        Section 4.4 Curve Sketching                  June 10, 2010   11 / 45
Step 3: One sign chart to rule them all



 Remember, f(x) = 2x3 − 3x2 − 12x.

                                        .




                                                                          .   .   .      .       .    .

V63.0121.002.2010Su, Calculus I (NYU)       Section 4.4 Curve Sketching               June 10, 2010   12 / 45
Step 3: One sign chart to rule them all



 Remember, f(x) = 2x3 − 3x2 − 12x.

                            −
                      . . . .
                      +                   −
                                          .                .
                                                           +              .′ (x)
                                                                          f
                                                    .
                      ↗− ↘
                      . . 1 .             ↘
                                          .       2
                                                  .        ↗
                                                           .              m
                                                                          . onotonicity




                                                                      .            .   .      .       .    .

V63.0121.002.2010Su, Calculus I (NYU)   Section 4.4 Curve Sketching                        June 10, 2010   12 / 45
Step 3: One sign chart to rule them all



 Remember, f(x) = 2x3 − 3x2 − 12x.

                     . .
                     +            −
                                  . .       −
                                            .                .
                                                             +              .′ (x)
                                                                            f
                                                .
                     ↗−
                     . . 1        ↘
                                  .         ↘ .
                                            .  2             ↗
                                                             .              m
                                                                            .′′ onotonicity
                    −
                    . −          −
                                 . − .     . +
                                           +                . +
                                                            +               f
                                                                            . (x)
                     .
                     ⌢            .
                                  ⌢ 1/2
                                      .     .
                                            ⌣                .
                                                             ⌣              c
                                                                            . oncavity




                                                                        .            .   .      .       .    .

V63.0121.002.2010Su, Calculus I (NYU)     Section 4.4 Curve Sketching                        June 10, 2010   12 / 45
Step 3: One sign chart to rule them all



 Remember, f(x) = 2x3 − 3x2 − 12x.

                     . .
                     +         −
                               . .       −
                                         .        .
                                                  +                       .′ (x)
                                                                          f
                                               .
                     ↗−
                     . . 1     ↘
                               .         ↘ .
                                         .   2    ↗
                                                  .                       m
                                                                          .′′ onotonicity
                    −
                    . −       −
                              . − . . + +        . +
                                                 +                        f
                                                                          . (x)
                     .
                     ⌢         ⌢ ./2 .
                               .   1     ⌣        .
                                                  ⌣                       c
                                                                          . oncavity
                           7
                           ..    −
                                 . 6 1/2   −.
                                           . 20                           f
                                                                          .(x)
                                     .
                          −
                          . 1      .
                                   1/2       2
                                             .                            s
                                                                          . hape of f
                         m
                         . ax      I
                                   .P       m
                                            . in




                                                                      .            .   .      .       .    .

V63.0121.002.2010Su, Calculus I (NYU)   Section 4.4 Curve Sketching                        June 10, 2010   12 / 45
Combinations of monotonicity and concavity




                                        I
                                        .I                              I
                                                                        .


                                                       .



                                        I
                                        .II                        I
                                                                   .V




                                                                            .   .   .      .       .    .

V63.0121.002.2010Su, Calculus I (NYU)     Section 4.4 Curve Sketching                   June 10, 2010   13 / 45
Combinations of monotonicity and concavity
                                                                                .
                                                                                decreasing,
                                                                                concave
                                                                                down

                                        I
                                        .I                              I
                                                                        .


                                                       .



                                        I
                                        .II                        I
                                                                   .V




                                                                            .      .   .      .       .    .

V63.0121.002.2010Su, Calculus I (NYU)     Section 4.4 Curve Sketching                      June 10, 2010   13 / 45
Combinations of monotonicity and concavity
                     .                                                          .
                     increasing,                                                decreasing,
                     concave                                                    concave
                     down                                                       down

                                        I
                                        .I                              I
                                                                        .


                                                       .



                                        I
                                        .II                        I
                                                                   .V




                                                                            .      .   .      .       .    .

V63.0121.002.2010Su, Calculus I (NYU)     Section 4.4 Curve Sketching                      June 10, 2010   13 / 45
Combinations of monotonicity and concavity
                     .                                                          .
                     increasing,                                                decreasing,
                     concave                                                    concave
                     down                                                       down

                                        I
                                        .I                              I
                                                                        .


                                                       .



                                        I
                                        .II                        I
                                                                   .V

                     .
                     decreasing,
                     concave up
                                                                            .      .   .      .       .    .

V63.0121.002.2010Su, Calculus I (NYU)     Section 4.4 Curve Sketching                      June 10, 2010   13 / 45
Combinations of monotonicity and concavity
                     .                                                          .
                     increasing,                                                decreasing,
                     concave                                                    concave
                     down                                                       down

                                        I
                                        .I                              I
                                                                        .


                                                       .



                                        I
                                        .II                        I
                                                                   .V

                     .                                                          .
                     decreasing,                                                increasing,
                     concave up                                                 concave up
                                                                            .      .   .      .       .    .

V63.0121.002.2010Su, Calculus I (NYU)     Section 4.4 Curve Sketching                      June 10, 2010   13 / 45
Step 3: One sign chart to rule them all



 Remember, f(x) = 2x3 − 3x2 − 12x.

                     . .
                     +        −
                              . .       −
                                        .        .
                                                 +                        .′ (x)
                                                                          f
                                              .
                     ↗−
                     . . 1    ↘
                              .         ↘ .
                                        .   2    ↗
                                                 .                        m
                                                                          .′′ onotonicity
                    −
                    . −      −
                             . − . . + +        . +
                                                +                         f
                                                                          . (x)
                     .
                     ⌢        ⌢ ./2 .
                              .   1     ⌣        .
                                                 ⌣                        c
                                                                          . oncavity
                          7
                          ..    −
                                . 6 1/2   −.
                                          . 20                            f
                                                                          .(x)
                                    .
                      . . 1
                         −        .
                                  1/2       2
                                            .                             s
                                                                          . hape of f
                        m
                        . ax      I
                                  .P       m
                                           . in




                                                                      .            .   .      .       .    .

V63.0121.002.2010Su, Calculus I (NYU)   Section 4.4 Curve Sketching                        June 10, 2010   14 / 45
Step 3: One sign chart to rule them all



 Remember, f(x) = 2x3 − 3x2 − 12x.

                     . .
                     +        −
                              . .       −
                                        .        .
                                                 +                        .′ (x)
                                                                          f
                                              .
                     ↗−
                     . . 1    ↘
                              .         ↘ .
                                        .   2    ↗
                                                 .                        m
                                                                          .′′ onotonicity
                    −
                    . −      −
                             . − . . + +        . +
                                                +                         f
                                                                          . (x)
                     .
                     ⌢        ⌢ ./2 .
                              .   1     ⌣        .
                                                 ⌣                        c
                                                                          . oncavity
                          7
                          ..    −
                                . 6 1/2   −.
                                          . 20                            f
                                                                          .(x)
                                    .
                      . . 1 . ./2
                         −        1         2
                                            .                             s
                                                                          . hape of f
                        m
                        . ax      I
                                  .P       m
                                           . in




                                                                      .            .   .      .       .    .

V63.0121.002.2010Su, Calculus I (NYU)   Section 4.4 Curve Sketching                        June 10, 2010   14 / 45
Step 3: One sign chart to rule them all



 Remember, f(x) = 2x3 − 3x2 − 12x.

                     . .
                     +        −
                              . .       −
                                        .        .
                                                 +                        .′ (x)
                                                                          f
                                              .
                     ↗−
                     . . 1    ↘
                              .         ↘ .
                                        .   2    ↗
                                                 .                        m
                                                                          .′′ onotonicity
                    −
                    . −      −
                             . − . . + +        . +
                                                +                         f
                                                                          . (x)
                     .
                     ⌢        ⌢ ./2 .
                              .   1     ⌣        .
                                                 ⌣                        c
                                                                          . oncavity
                          7
                          ..    −
                                . 6 1/2   −.
                                          . 20                            f
                                                                          .(x)
                                    .
                      . . 1 . ./2 .
                         −        1         2
                                            .                             s
                                                                          . hape of f
                        m
                        . ax      I
                                  .P       m
                                           . in




                                                                      .            .   .      .       .    .

V63.0121.002.2010Su, Calculus I (NYU)   Section 4.4 Curve Sketching                        June 10, 2010   14 / 45
Step 3: One sign chart to rule them all



 Remember, f(x) = 2x3 − 3x2 − 12x.

                     . .
                     +        −
                              . .       −
                                        .        .
                                                 +                        .′ (x)
                                                                          f
                                              .
                     ↗−
                     . . 1    ↘
                              .         ↘ .
                                        .   2    ↗
                                                 .                        m
                                                                          .′′ onotonicity
                    −
                    . −      −
                             . − . . + +        . +
                                                +                         f
                                                                          . (x)
                     .
                     ⌢        ⌢ ./2 .
                              .   1     ⌣        .
                                                 ⌣                        c
                                                                          . oncavity
                          7
                          ..    −
                                . 6 1/2   −.
                                          . 20                            f
                                                                          .(x)
                                    .
                      . . 1 . ./2 .
                         −        1         2
                                            .     .                       s
                                                                          . hape of f
                        m
                        . ax      I
                                  .P       m
                                           . in




                                                                      .            .   .      .       .    .

V63.0121.002.2010Su, Calculus I (NYU)   Section 4.4 Curve Sketching                        June 10, 2010   14 / 45
Step 4: Graph
                                                   f
                                                   .(x)




                      .(x) = 2x3 − 3x2 − 12x
                      f

                     ( √          )         . −1, 7)
                                            (
                                                .
                     . 3− 4105 , 0                            . 0, 0)
                                                              (
                                        .                 .                                 .
                                                                    . 1/2, −61/2)
                                                                    (                           ( . x
                                                                                                    √        )
                                                                .                               . 3+ 4105 , 0

                                                                        . 2, −20)
                                                                        (
                                                                              .

                                                7
                                                ..  −
                                                    . 61/2 −.
                                                           . 20                                         f
                                                                                                        .(x)
                                                        .
                                            . . 1 . ./2 .
                                               −      1      2
                                                             .                          .               s
                                                                                                        . hape of f
                                              m
                                              . ax    I
                                                      .P    m
                                                            . in            .       .       .       .          .   .

V63.0121.002.2010Su, Calculus I (NYU)        Section 4.4 Curve Sketching                         June 10, 2010     15 / 45
Step 4: Graph
                                                   f
                                                   .(x)




                      .(x) = 2x3 − 3x2 − 12x
                      f

                     ( √          )         . −1, 7)
                                            (
                                                .
                     . 3− 4105 , 0                            . 0, 0)
                                                              (
                                        .                 .                                 .
                                                                    . 1/2, −61/2)
                                                                    (                           ( . x
                                                                                                    √        )
                                                                .                               . 3+ 4105 , 0

                                                                        . 2, −20)
                                                                        (
                                                                              .

                                                7
                                                ..  −
                                                    . 61/2 −.
                                                           . 20                                         f
                                                                                                        .(x)
                                                        .
                                            . . 1 . ./2 .
                                               −      1      2
                                                             .                          .               s
                                                                                                        . hape of f
                                              m
                                              . ax    I
                                                      .P    m
                                                            . in            .       .       .       .          .   .

V63.0121.002.2010Su, Calculus I (NYU)        Section 4.4 Curve Sketching                         June 10, 2010     15 / 45
Step 4: Graph
                                                   f
                                                   .(x)




                      .(x) = 2x3 − 3x2 − 12x
                      f

                     ( √          )         . −1, 7)
                                            (
                                                .
                     . 3− 4105 , 0                            . 0, 0)
                                                              (
                                        .                 .                                 .
                                                                    . 1/2, −61/2)
                                                                    (                           ( . x
                                                                                                    √        )
                                                                .                               . 3+ 4105 , 0

                                                                        . 2, −20)
                                                                        (
                                                                              .

                                                7
                                                ..  −
                                                    . 61/2 −.
                                                           . 20                                         f
                                                                                                        .(x)
                                                        .
                                            . . 1 . ./2 .
                                               −      1      2
                                                             .                          .               s
                                                                                                        . hape of f
                                              m
                                              . ax    I
                                                      .P    m
                                                            . in            .       .       .       .          .   .

V63.0121.002.2010Su, Calculus I (NYU)        Section 4.4 Curve Sketching                         June 10, 2010     15 / 45
Step 4: Graph
                                                   f
                                                   .(x)




                      .(x) = 2x3 − 3x2 − 12x
                      f

                     ( √          )         . −1, 7)
                                            (
                                                .
                     . 3− 4105 , 0                            . 0, 0)
                                                              (
                                        .                 .                                 .
                                                                    . 1/2, −61/2)
                                                                    (                           ( . x
                                                                                                    √        )
                                                                .                               . 3+ 4105 , 0

                                                                        . 2, −20)
                                                                        (
                                                                              .

                                                7
                                                ..  −
                                                    . 61/2 −.
                                                           . 20                                         f
                                                                                                        .(x)
                                                        .
                                            . . 1 . ./2 .
                                               −      1      2
                                                             .                          .               s
                                                                                                        . hape of f
                                              m
                                              . ax    I
                                                      .P    m
                                                            . in            .       .       .       .          .   .

V63.0121.002.2010Su, Calculus I (NYU)        Section 4.4 Curve Sketching                         June 10, 2010     15 / 45
Step 4: Graph
                                                   f
                                                   .(x)




                      .(x) = 2x3 − 3x2 − 12x
                      f

                     ( √          )         . −1, 7)
                                            (
                                                .
                     . 3− 4105 , 0                            . 0, 0)
                                                              (
                                        .                 .                                 .
                                                                    . 1/2, −61/2)
                                                                    (                           ( . x
                                                                                                    √        )
                                                                .                               . 3+ 4105 , 0

                                                                        . 2, −20)
                                                                        (
                                                                              .

                                                7
                                                ..  −
                                                    . 61/2 −.
                                                           . 20                                         f
                                                                                                        .(x)
                                                        .
                                            . . 1 . ./2 .
                                               −      1      2
                                                             .                          .               s
                                                                                                        . hape of f
                                              m
                                              . ax    I
                                                      .P    m
                                                            . in            .       .       .       .          .   .

V63.0121.002.2010Su, Calculus I (NYU)        Section 4.4 Curve Sketching                         June 10, 2010     15 / 45
Graphing a quartic




 Example
 Graph f(x) = x4 − 4x3 + 10




                                                                      .   .   .      .       .    .

V63.0121.002.2010Su, Calculus I (NYU)   Section 4.4 Curve Sketching               June 10, 2010   16 / 45
Graphing a quartic




 Example
 Graph f(x) = x4 − 4x3 + 10

 (Step 0) We know f(0) = 10 and lim f(x) = +∞. Not too many other
                                                 x→±∞
 points on the graph are evident.




                                                                      .   .   .      .       .    .

V63.0121.002.2010Su, Calculus I (NYU)   Section 4.4 Curve Sketching               June 10, 2010   16 / 45
Step 1: Monotonicity



                                        f(x) = x4 − 4x3 + 10
                              =⇒ f′ (x) = 4x3 − 12x2 = 4x2 (x − 3)




                                                                          .   .   .      .       .    .

V63.0121.002.2010Su, Calculus I (NYU)       Section 4.4 Curve Sketching               June 10, 2010   17 / 45
Step 1: Monotonicity



                                            f(x) = x4 − 4x3 + 10
                              =⇒ f′ (x) = 4x3 − 12x2 = 4x2 (x − 3)

 We make its sign chart.

                                        .




                                                                              .   .   .      .       .    .

V63.0121.002.2010Su, Calculus I (NYU)           Section 4.4 Curve Sketching               June 10, 2010   17 / 45
Step 1: Monotonicity



                                             f(x) = x4 − 4x3 + 10
                              =⇒ f′ (x) = 4x3 − 12x2 = 4x2 (x − 3)

 We make its sign chart.

                                        0
                                        ..
                                                                               . x2
                                                                               4
                                        0
                                        .




                                                                               .      .   .      .       .    .

V63.0121.002.2010Su, Calculus I (NYU)            Section 4.4 Curve Sketching                  June 10, 2010   17 / 45
Step 1: Monotonicity



                                        f(x) = x4 − 4x3 + 10
                              =⇒ f′ (x) = 4x3 − 12x2 = 4x2 (x − 3)

 We make its sign chart.

                               . ..
                               + 0
                                                                          . x2
                                                                          4
                                 0
                                 .




                                                                          .      .   .      .       .    .

V63.0121.002.2010Su, Calculus I (NYU)       Section 4.4 Curve Sketching                  June 10, 2010   17 / 45
Step 1: Monotonicity



                                        f(x) = x4 − 4x3 + 10
                              =⇒ f′ (x) = 4x3 − 12x2 = 4x2 (x − 3)

 We make its sign chart.

                               . ..
                               + 0              .
                                                +
                                                                          . x2
                                                                          4
                                 0
                                 .




                                                                          .      .   .      .       .    .

V63.0121.002.2010Su, Calculus I (NYU)       Section 4.4 Curve Sketching                  June 10, 2010   17 / 45
Step 1: Monotonicity



                                        f(x) = x4 − 4x3 + 10
                              =⇒ f′ (x) = 4x3 − 12x2 = 4x2 (x − 3)

 We make its sign chart.

                               . ..
                               + 0              .
                                                +                   .
                                                                    +
                                                                          . x2
                                                                          4
                                 0
                                 .




                                                                          .      .   .      .       .    .

V63.0121.002.2010Su, Calculus I (NYU)       Section 4.4 Curve Sketching                  June 10, 2010   17 / 45
Step 1: Monotonicity



                                        f(x) = x4 − 4x3 + 10
                              =⇒ f′ (x) = 4x3 − 12x2 = 4x2 (x − 3)

 We make its sign chart.

                               . ..
                               + 0              .
                                                +                    .
                                                                     +
                                                                          . x2
                                                                          4
                                 0
                                 .
                                                                0
                                                                ..
                                                                          . x − 3)
                                                                          (
                                                                3
                                                                .




                                                                          .      .   .      .       .    .

V63.0121.002.2010Su, Calculus I (NYU)       Section 4.4 Curve Sketching                  June 10, 2010   17 / 45
Step 1: Monotonicity



                                        f(x) = x4 − 4x3 + 10
                              =⇒ f′ (x) = 4x3 − 12x2 = 4x2 (x − 3)

 We make its sign chart.

                               . ..
                               + 0              .
                                                +                    .
                                                                     +
                                                                          . x2
                                                                          4
                                 0
                                 .
                               −
                               .                                0
                                                                ..
                                                                          . x − 3)
                                                                          (
                                                                3
                                                                .




                                                                          .      .   .      .       .    .

V63.0121.002.2010Su, Calculus I (NYU)       Section 4.4 Curve Sketching                  June 10, 2010   17 / 45
Step 1: Monotonicity



                                        f(x) = x4 − 4x3 + 10
                              =⇒ f′ (x) = 4x3 − 12x2 = 4x2 (x − 3)

 We make its sign chart.

                               . ..
                               + 0              .
                                                +                    .
                                                                     +
                                                                          . x2
                                                                          4
                                 0
                                 .
                               −
                               .                −
                                                .               0
                                                                ..
                                                                          . x − 3)
                                                                          (
                                                                3
                                                                .




                                                                          .      .   .      .       .    .

V63.0121.002.2010Su, Calculus I (NYU)       Section 4.4 Curve Sketching                  June 10, 2010   17 / 45
Step 1: Monotonicity



                                        f(x) = x4 − 4x3 + 10
                              =⇒ f′ (x) = 4x3 − 12x2 = 4x2 (x − 3)

 We make its sign chart.

                               . ..
                               + 0              .
                                                +                   .
                                                                    +
                                                                          . x2
                                                                          4
                                 0
                                 .
                               −
                               .                −
                                                .               .. .
                                                                0 +
                                                                          . x − 3)
                                                                          (
                                                                3
                                                                .




                                                                          .      .   .      .       .    .

V63.0121.002.2010Su, Calculus I (NYU)       Section 4.4 Curve Sketching                  June 10, 2010   17 / 45
Step 1: Monotonicity



                                             f(x) = x4 − 4x3 + 10
                              =⇒ f′ (x) = 4x3 − 12x2 = 4x2 (x − 3)

 We make its sign chart.

                               . ..
                               + 0                   .
                                                     +                   .
                                                                         +
                                                                               . x2
                                                                               4
                                 0
                                 .
                               −
                               .                     −
                                                     .               .. .
                                                                     0 +
                                                                               . x − 3)
                                                                               (
                                                                     3
                                                                     .
                                        0
                                        ..                           0
                                                                     ..        .′ (x)
                                                                               f
                                        0
                                        .                            3
                                                                     .         f
                                                                               .(x)


                                                                               .        .   .      .       .    .

V63.0121.002.2010Su, Calculus I (NYU)            Section 4.4 Curve Sketching                    June 10, 2010   17 / 45
Step 1: Monotonicity



                                        f(x) = x4 − 4x3 + 10
                              =⇒ f′ (x) = 4x3 − 12x2 = 4x2 (x − 3)

 We make its sign chart.

                               . ..
                               + 0              .
                                                +                   .
                                                                    +
                                                                          . x2
                                                                          4
                                 0
                                 .
                               −
                               .                −
                                                .               .. .
                                                                0 +
                                                                          . x − 3)
                                                                          (
                                                                3
                                                                .
                               − 0
                               . ..                             0
                                                                ..        .′ (x)
                                                                          f
                                 0
                                 .                              3
                                                                .         f
                                                                          .(x)


                                                                          .        .   .      .       .    .

V63.0121.002.2010Su, Calculus I (NYU)       Section 4.4 Curve Sketching                    June 10, 2010   17 / 45
Step 1: Monotonicity



                                        f(x) = x4 − 4x3 + 10
                              =⇒ f′ (x) = 4x3 − 12x2 = 4x2 (x − 3)

 We make its sign chart.

                               . ..
                               + 0              .
                                                +                   .
                                                                    +
                                                                          . x2
                                                                          4
                                 0
                                 .
                               −
                               .                −
                                                .               .. .
                                                                0 +
                                                                          . x − 3)
                                                                          (
                                                                3
                                                                .
                               − 0
                               . ..             −
                                                .               0
                                                                ..        .′ (x)
                                                                          f
                                 0
                                 .                              3
                                                                .         f
                                                                          .(x)


                                                                          .        .   .      .       .    .

V63.0121.002.2010Su, Calculus I (NYU)       Section 4.4 Curve Sketching                    June 10, 2010   17 / 45
Step 1: Monotonicity



                                        f(x) = x4 − 4x3 + 10
                              =⇒ f′ (x) = 4x3 − 12x2 = 4x2 (x − 3)

 We make its sign chart.

                               . ..
                               + 0              .
                                                +                   .
                                                                    +
                                                                          . x2
                                                                          4
                                 0
                                 .
                               −
                               .                −
                                                .               .. .
                                                                0 +
                                                                          . x − 3)
                                                                          (
                                                                3
                                                                .
                               − 0
                               . ..             −
                                                .               .. .
                                                                0 +       .′ (x)
                                                                          f
                                 0
                                 .                              3
                                                                .         f
                                                                          .(x)


                                                                          .        .   .      .       .    .

V63.0121.002.2010Su, Calculus I (NYU)       Section 4.4 Curve Sketching                    June 10, 2010   17 / 45
Step 1: Monotonicity



                                        f(x) = x4 − 4x3 + 10
                              =⇒ f′ (x) = 4x3 − 12x2 = 4x2 (x − 3)

 We make its sign chart.

                               . ..
                               + 0              .
                                                +                   .
                                                                    +
                                                                          . x2
                                                                          4
                                 0
                                 .
                               −
                               .                −
                                                .               .. .
                                                                0 +
                                                                          . x − 3)
                                                                          (
                                                                3
                                                                .
                               − 0
                               . ..             −
                                                .               .. .
                                                                0 +       .′ (x)
                                                                          f
                               ↘ 0
                               . .                              3
                                                                .         f
                                                                          .(x)


                                                                          .        .   .      .       .    .

V63.0121.002.2010Su, Calculus I (NYU)       Section 4.4 Curve Sketching                    June 10, 2010   17 / 45
Step 1: Monotonicity



                                        f(x) = x4 − 4x3 + 10
                              =⇒ f′ (x) = 4x3 − 12x2 = 4x2 (x − 3)

 We make its sign chart.

                               . ..
                               + 0              .
                                                +                   .
                                                                    +
                                                                          . x2
                                                                          4
                                 0
                                 .
                               −
                               .                −
                                                .               .. .
                                                                0 +
                                                                          . x − 3)
                                                                          (
                                                                3
                                                                .
                               − 0
                               . ..             −
                                                .               .. .
                                                                0 +       .′ (x)
                                                                          f
                               ↘ 0
                               . .              ↘
                                                .               3
                                                                .         f
                                                                          .(x)


                                                                          .        .   .      .       .    .

V63.0121.002.2010Su, Calculus I (NYU)       Section 4.4 Curve Sketching                    June 10, 2010   17 / 45
Step 1: Monotonicity



                                        f(x) = x4 − 4x3 + 10
                              =⇒ f′ (x) = 4x3 − 12x2 = 4x2 (x − 3)

 We make its sign chart.

                               . ..
                               + 0              .
                                                +                   .
                                                                    +
                                                                          . x2
                                                                          4
                                 0
                                 .
                               −
                               .                −
                                                .               .. .
                                                                0 +
                                                                          . x − 3)
                                                                          (
                                                                3
                                                                .
                               − 0
                               . ..             −
                                                .               .. .
                                                                0 +       .′ (x)
                                                                          f
                               ↘ 0
                               . .              ↘
                                                .               3 ↗
                                                                . .       f
                                                                          .(x)


                                                                          .        .   .      .       .    .

V63.0121.002.2010Su, Calculus I (NYU)       Section 4.4 Curve Sketching                    June 10, 2010   17 / 45
Step 1: Monotonicity



                                        f(x) = x4 − 4x3 + 10
                              =⇒ f′ (x) = 4x3 − 12x2 = 4x2 (x − 3)

 We make its sign chart.

                               . ..
                               + 0              .
                                                +                   .
                                                                    +
                                                                          . x2
                                                                          4
                                 0
                                 .
                               −
                               .                −
                                                .              .. .
                                                               0 +
                                                                          . x − 3)
                                                                          (
                                                               3
                                                               .
                               − 0
                               . ..             −
                                                .              .. .
                                                               0 +        .′ (x)
                                                                          f
                               ↘ 0
                               . .              ↘
                                                .              3 ↗
                                                               . .        f
                                                                          .(x)
                                                              m
                                                              . in

                                                                          .        .   .      .       .    .

V63.0121.002.2010Su, Calculus I (NYU)       Section 4.4 Curve Sketching                    June 10, 2010   17 / 45
Step 2: Concavity



                                        f′ (x) = 4x3 − 12x2
                             =⇒ f′′ (x) = 12x2 − 24x = 12x(x − 2)



                                        .




                                                                           .   .   .      .       .    .

V63.0121.002.2010Su, Calculus I (NYU)        Section 4.4 Curve Sketching               June 10, 2010   18 / 45
Step 2: Concavity



                                        f′ (x) = 4x3 − 12x2
                             =⇒ f′′ (x) = 12x2 − 24x = 12x(x − 2)

 Here is its sign chart:

                                        .




                                                                           .   .   .      .       .    .

V63.0121.002.2010Su, Calculus I (NYU)        Section 4.4 Curve Sketching               June 10, 2010   18 / 45
Step 2: Concavity



                                        f′ (x) = 4x3 − 12x2
                             =⇒ f′′ (x) = 12x2 − 24x = 12x(x − 2)

 Here is its sign chart:

                                        0
                                        ..
                                                                               1
                                                                               . 2x
                                        0
                                        .




                                                                           .      .   .      .       .    .

V63.0121.002.2010Su, Calculus I (NYU)        Section 4.4 Curve Sketching                  June 10, 2010   18 / 45
Step 2: Concavity



                                        f′ (x) = 4x3 − 12x2
                             =⇒ f′′ (x) = 12x2 − 24x = 12x(x − 2)

 Here is its sign chart:

                                 − 0
                                 . ..
                                                                               1
                                                                               . 2x
                                   0
                                   .




                                                                           .      .   .      .       .    .

V63.0121.002.2010Su, Calculus I (NYU)        Section 4.4 Curve Sketching                  June 10, 2010   18 / 45
Step 2: Concavity



                                        f′ (x) = 4x3 − 12x2
                             =⇒ f′′ (x) = 12x2 − 24x = 12x(x − 2)

 Here is its sign chart:

                                 − 0
                                 . ..         .
                                              +
                                                                               1
                                                                               . 2x
                                   0
                                   .




                                                                           .      .   .      .       .    .

V63.0121.002.2010Su, Calculus I (NYU)        Section 4.4 Curve Sketching                  June 10, 2010   18 / 45
Step 2: Concavity



                                        f′ (x) = 4x3 − 12x2
                             =⇒ f′′ (x) = 12x2 − 24x = 12x(x − 2)

 Here is its sign chart:

                                 − 0
                                 . ..         .
                                              +                   .
                                                                  +
                                                                               1
                                                                               . 2x
                                   0
                                   .




                                                                           .      .   .      .       .    .

V63.0121.002.2010Su, Calculus I (NYU)        Section 4.4 Curve Sketching                  June 10, 2010   18 / 45
Step 2: Concavity



                                        f′ (x) = 4x3 − 12x2
                             =⇒ f′′ (x) = 12x2 − 24x = 12x(x − 2)

 Here is its sign chart:

                                 − 0
                                 . ..         .
                                              +                   .
                                                                  +
                                                                               1
                                                                               . 2x
                                   0
                                   .
                                                        0
                                                        ..
                                                                               . −2
                                                                               x
                                                        2
                                                        .




                                                                           .      .   .      .       .    .

V63.0121.002.2010Su, Calculus I (NYU)        Section 4.4 Curve Sketching                  June 10, 2010   18 / 45
Step 2: Concavity



                                        f′ (x) = 4x3 − 12x2
                             =⇒ f′′ (x) = 12x2 − 24x = 12x(x − 2)

 Here is its sign chart:

                                 − 0
                                 . ..         .
                                              +                   .
                                                                  +
                                                                               1
                                                                               . 2x
                                   0
                                   .
                                 −
                                 .                      0
                                                        ..
                                                                               . −2
                                                                               x
                                                        2
                                                        .




                                                                           .      .   .      .       .    .

V63.0121.002.2010Su, Calculus I (NYU)        Section 4.4 Curve Sketching                  June 10, 2010   18 / 45
Step 2: Concavity



                                        f′ (x) = 4x3 − 12x2
                             =⇒ f′′ (x) = 12x2 − 24x = 12x(x − 2)

 Here is its sign chart:

                                 − 0
                                 . ..         .
                                              +                   .
                                                                  +
                                                                               1
                                                                               . 2x
                                   0
                                   .
                                 −
                                 .            −
                                              .         0
                                                        ..
                                                                               . −2
                                                                               x
                                                        2
                                                        .




                                                                           .      .   .      .       .    .

V63.0121.002.2010Su, Calculus I (NYU)        Section 4.4 Curve Sketching                  June 10, 2010   18 / 45
Lesson 21: Curve Sketching
Lesson 21: Curve Sketching
Lesson 21: Curve Sketching
Lesson 21: Curve Sketching
Lesson 21: Curve Sketching
Lesson 21: Curve Sketching
Lesson 21: Curve Sketching
Lesson 21: Curve Sketching
Lesson 21: Curve Sketching
Lesson 21: Curve Sketching
Lesson 21: Curve Sketching
Lesson 21: Curve Sketching
Lesson 21: Curve Sketching
Lesson 21: Curve Sketching
Lesson 21: Curve Sketching
Lesson 21: Curve Sketching
Lesson 21: Curve Sketching
Lesson 21: Curve Sketching
Lesson 21: Curve Sketching
Lesson 21: Curve Sketching
Lesson 21: Curve Sketching
Lesson 21: Curve Sketching
Lesson 21: Curve Sketching
Lesson 21: Curve Sketching
Lesson 21: Curve Sketching
Lesson 21: Curve Sketching
Lesson 21: Curve Sketching
Lesson 21: Curve Sketching
Lesson 21: Curve Sketching
Lesson 21: Curve Sketching
Lesson 21: Curve Sketching
Lesson 21: Curve Sketching
Lesson 21: Curve Sketching
Lesson 21: Curve Sketching
Lesson 21: Curve Sketching
Lesson 21: Curve Sketching
Lesson 21: Curve Sketching
Lesson 21: Curve Sketching
Lesson 21: Curve Sketching
Lesson 21: Curve Sketching
Lesson 21: Curve Sketching
Lesson 21: Curve Sketching
Lesson 21: Curve Sketching
Lesson 21: Curve Sketching
Lesson 21: Curve Sketching
Lesson 21: Curve Sketching
Lesson 21: Curve Sketching
Lesson 21: Curve Sketching
Lesson 21: Curve Sketching
Lesson 21: Curve Sketching
Lesson 21: Curve Sketching
Lesson 21: Curve Sketching
Lesson 21: Curve Sketching
Lesson 21: Curve Sketching
Lesson 21: Curve Sketching
Lesson 21: Curve Sketching
Lesson 21: Curve Sketching
Lesson 21: Curve Sketching
Lesson 21: Curve Sketching
Lesson 21: Curve Sketching
Lesson 21: Curve Sketching
Lesson 21: Curve Sketching
Lesson 21: Curve Sketching
Lesson 21: Curve Sketching
Lesson 21: Curve Sketching
Lesson 21: Curve Sketching
Lesson 21: Curve Sketching
Lesson 21: Curve Sketching
Lesson 21: Curve Sketching
Lesson 21: Curve Sketching
Lesson 21: Curve Sketching
Lesson 21: Curve Sketching
Lesson 21: Curve Sketching
Lesson 21: Curve Sketching
Lesson 21: Curve Sketching
Lesson 21: Curve Sketching
Lesson 21: Curve Sketching
Lesson 21: Curve Sketching
Lesson 21: Curve Sketching
Lesson 21: Curve Sketching
Lesson 21: Curve Sketching
Lesson 21: Curve Sketching
Lesson 21: Curve Sketching
Lesson 21: Curve Sketching
Lesson 21: Curve Sketching
Lesson 21: Curve Sketching
Lesson 21: Curve Sketching
Lesson 21: Curve Sketching
Lesson 21: Curve Sketching
Lesson 21: Curve Sketching
Lesson 21: Curve Sketching
Lesson 21: Curve Sketching
Lesson 21: Curve Sketching
Lesson 21: Curve Sketching
Lesson 21: Curve Sketching
Lesson 21: Curve Sketching
Lesson 21: Curve Sketching
Lesson 21: Curve Sketching
Lesson 21: Curve Sketching
Lesson 21: Curve Sketching
Lesson 21: Curve Sketching
Lesson 21: Curve Sketching
Lesson 21: Curve Sketching
Lesson 21: Curve Sketching
Lesson 21: Curve Sketching
Lesson 21: Curve Sketching
Lesson 21: Curve Sketching
Lesson 21: Curve Sketching

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Lesson 21: Curve Sketching

  • 1. Section 4.4 Curve Sketching V63.0121.002.2010Su, Calculus I New York University June 10, 2010 Announcements Homework 4 due Tuesday . . . . . .
  • 2. Announcements Homework 4 due Tuesday . . . . . . V63.0121.002.2010Su, Calculus I (NYU) Section 4.4 Curve Sketching June 10, 2010 2 / 45
  • 3. Objectives given a function, graph it completely, indicating zeroes (if easy) asymptotes if applicable critical points local/global max/min inflection points . . . . . . V63.0121.002.2010Su, Calculus I (NYU) Section 4.4 Curve Sketching June 10, 2010 3 / 45
  • 4. Why? Graphing functions is like dissection . . . . . . V63.0121.002.2010Su, Calculus I (NYU) Section 4.4 Curve Sketching June 10, 2010 4 / 45
  • 5. Why? Graphing functions is like dissection … or diagramming sentences . . . . . . V63.0121.002.2010Su, Calculus I (NYU) Section 4.4 Curve Sketching June 10, 2010 4 / 45
  • 6. Why? Graphing functions is like dissection … or diagramming sentences You can really know a lot about a function when you know all of its anatomy. . . . . . . V63.0121.002.2010Su, Calculus I (NYU) Section 4.4 Curve Sketching June 10, 2010 4 / 45
  • 7. The Increasing/Decreasing Test Theorem (The Increasing/Decreasing Test) If f′ > 0 on (a, b), then f is increasing on (a, b). If f′ < 0 on (a, b), then f is decreasing on (a, b). Example Here f(x) = x3 + x2 , and f′ (x) = 3x2 + 2x. f .(x) .′ (x) f . . . . . . . V63.0121.002.2010Su, Calculus I (NYU) Section 4.4 Curve Sketching June 10, 2010 5 / 45
  • 8. Testing for Concavity Theorem (Concavity Test) If f′′ (x) > 0 for all x in (a, b), then the graph of f is concave upward on (a, b) If f′′ (x) < 0 for all x in (a, b), then the graph of f is concave downward on (a, b). Example Here f(x) = x3 + x2 , f′ (x) = 3x2 + 2x, and f′′ (x) = 6x + 2. .′′ (x) f f .(x) .′ (x) f . . . . . . . V63.0121.002.2010Su, Calculus I (NYU) Section 4.4 Curve Sketching June 10, 2010 6 / 45
  • 9. Graphing Checklist To graph a function f, follow this plan: 0. Find when f is positive, negative, zero, not defined. 1. Find f′ and form its sign chart. Conclude information about increasing/decreasing and local max/min. 2. Find f′′ and form its sign chart. Conclude concave up/concave down and inflection. 3. Put together a big chart to assemble monotonicity and concavity data 4. Graph! . . . . . . V63.0121.002.2010Su, Calculus I (NYU) Section 4.4 Curve Sketching June 10, 2010 7 / 45
  • 10. Outline Simple examples A cubic function A quartic function More Examples Points of nondifferentiability Horizontal asymptotes Vertical asymptotes Trigonometric and polynomial together Logarithmic . . . . . . V63.0121.002.2010Su, Calculus I (NYU) Section 4.4 Curve Sketching June 10, 2010 8 / 45
  • 11. Graphing a cubic Example Graph f(x) = 2x3 − 3x2 − 12x. . . . . . . V63.0121.002.2010Su, Calculus I (NYU) Section 4.4 Curve Sketching June 10, 2010 9 / 45
  • 12. Graphing a cubic Example Graph f(x) = 2x3 − 3x2 − 12x. (Step 0) First, let’s find the zeros. We can at least factor out one power of x: f(x) = x(2x2 − 3x − 12) so f(0) = 0. The other factor is a quadratic, so we the other two roots are √ √ 3 ± 32 − 4(2)(−12) 3 ± 105 x= = 4 4 It’s OK to skip this step for now since the roots are so complicated. . . . . . . V63.0121.002.2010Su, Calculus I (NYU) Section 4.4 Curve Sketching June 10, 2010 9 / 45
  • 13. Step 1: Monotonicity f(x) = 2x3 − 3x2 − 12x =⇒ f′ (x) = 6x2 − 6x − 12 = 6(x + 1)(x − 2) We can form a sign chart from this: . . . . . . . V63.0121.002.2010Su, Calculus I (NYU) Section 4.4 Curve Sketching June 10, 2010 10 / 45
  • 14. Step 1: Monotonicity f(x) = 2x3 − 3x2 − 12x =⇒ f′ (x) = 6x2 − 6x − 12 = 6(x + 1)(x − 2) We can form a sign chart from this: . . . −2 x 2 . . x . +1 − . 1 .′ (x) f . . − . 1 2 . f .(x) . . . . . . V63.0121.002.2010Su, Calculus I (NYU) Section 4.4 Curve Sketching June 10, 2010 10 / 45
  • 15. Step 1: Monotonicity f(x) = 2x3 − 3x2 − 12x =⇒ f′ (x) = 6x2 − 6x − 12 = 6(x + 1)(x − 2) We can form a sign chart from this: − . − . . . . + . −2 x 2 . . x . +1 − . 1 .′ (x) f . . − . 1 2 . f .(x) . . . . . . V63.0121.002.2010Su, Calculus I (NYU) Section 4.4 Curve Sketching June 10, 2010 10 / 45
  • 16. Step 1: Monotonicity f(x) = 2x3 − 3x2 − 12x =⇒ f′ (x) = 6x2 − 6x − 12 = 6(x + 1)(x − 2) We can form a sign chart from this: − . − . . . . + . −2 x 2 . − . . . + . + x . +1 − . 1 .′ (x) f . . − . 1 2 . f .(x) . . . . . . V63.0121.002.2010Su, Calculus I (NYU) Section 4.4 Curve Sketching June 10, 2010 10 / 45
  • 17. Step 1: Monotonicity f(x) = 2x3 − 3x2 − 12x =⇒ f′ (x) = 6x2 − 6x − 12 = 6(x + 1)(x − 2) We can form a sign chart from this: − . − . . . . + . −2 x 2 . − . . . + . + x . +1 − . 1 . . + .′ (x) f . − . 1 2 . f .(x) . . . . . . V63.0121.002.2010Su, Calculus I (NYU) Section 4.4 Curve Sketching June 10, 2010 10 / 45
  • 18. Step 1: Monotonicity f(x) = 2x3 − 3x2 − 12x =⇒ f′ (x) = 6x2 − 6x − 12 = 6(x + 1)(x − 2) We can form a sign chart from this: − . − . . . . + . −2 x 2 . − . . . + . + x . +1 − . 1 . . + − . .′ (x) f . − . 1 2 . f .(x) . . . . . . V63.0121.002.2010Su, Calculus I (NYU) Section 4.4 Curve Sketching June 10, 2010 10 / 45
  • 19. Step 1: Monotonicity f(x) = 2x3 − 3x2 − 12x =⇒ f′ (x) = 6x2 − 6x − 12 = 6(x + 1)(x − 2) We can form a sign chart from this: − . − . . . . + . −2 x 2 . − . . . + . + x . +1 − . 1 . . + − . . + .′ (x) f . − . 1 2 . f .(x) . . . . . . V63.0121.002.2010Su, Calculus I (NYU) Section 4.4 Curve Sketching June 10, 2010 10 / 45
  • 20. Step 1: Monotonicity f(x) = 2x3 − 3x2 − 12x =⇒ f′ (x) = 6x2 − 6x − 12 = 6(x + 1)(x − 2) We can form a sign chart from this: − . − . . . . + . −2 x 2 . − . . . + . + x . +1 − . 1 . . + − . . + .′ (x) f . ↗− . . 1 2 . f .(x) . . . . . . V63.0121.002.2010Su, Calculus I (NYU) Section 4.4 Curve Sketching June 10, 2010 10 / 45
  • 21. Step 1: Monotonicity f(x) = 2x3 − 3x2 − 12x =⇒ f′ (x) = 6x2 − 6x − 12 = 6(x + 1)(x − 2) We can form a sign chart from this: − . − . . . . + . −2 x 2 . − . . . + . + x . +1 − . 1 . . + − . . + .′ (x) f . ↗− . . 1 ↘ . 2 . f .(x) . . . . . . V63.0121.002.2010Su, Calculus I (NYU) Section 4.4 Curve Sketching June 10, 2010 10 / 45
  • 22. Step 1: Monotonicity f(x) = 2x3 − 3x2 − 12x =⇒ f′ (x) = 6x2 − 6x − 12 = 6(x + 1)(x − 2) We can form a sign chart from this: − . − . . . . + . −2 x 2 . − . . . + . + x . +1 − . 1 . . + − . . + .′ (x) f . ↗− . . 1 ↘ . 2 . ↗ . f .(x) . . . . . . V63.0121.002.2010Su, Calculus I (NYU) Section 4.4 Curve Sketching June 10, 2010 10 / 45
  • 23. Step 1: Monotonicity f(x) = 2x3 − 3x2 − 12x =⇒ f′ (x) = 6x2 − 6x − 12 = 6(x + 1)(x − 2) We can form a sign chart from this: − . − . . . . + . −2 x 2 . − . . . + . + x . +1 − . 1 . . + − . . + .′ (x) f . ↗− . . 1 ↘ . 2 . ↗ . f .(x) m . ax . . . . . . V63.0121.002.2010Su, Calculus I (NYU) Section 4.4 Curve Sketching June 10, 2010 10 / 45
  • 24. Step 1: Monotonicity f(x) = 2x3 − 3x2 − 12x =⇒ f′ (x) = 6x2 − 6x − 12 = 6(x + 1)(x − 2) We can form a sign chart from this: − . − . . . . + . −2 x 2 . − . . . + . + x . +1 − . 1 . . + − . . + .′ (x) f . ↗− . . 1 ↘ . 2 . ↗ . f .(x) m . ax m . in . . . . . . V63.0121.002.2010Su, Calculus I (NYU) Section 4.4 Curve Sketching June 10, 2010 10 / 45
  • 25. Step 2: Concavity f′ (x) = 6x2 − 6x − 12 =⇒ f′′ (x) = 12x − 6 = 6(2x − 1) Another sign chart: . . . . . . . V63.0121.002.2010Su, Calculus I (NYU) Section 4.4 Curve Sketching June 10, 2010 11 / 45
  • 26. Step 2: Concavity f′ (x) = 6x2 − 6x − 12 =⇒ f′′ (x) = 12x − 6 = 6(2x − 1) Another sign chart: . .′′ (x) f . ./2 1 f .(x) . . . . . . V63.0121.002.2010Su, Calculus I (NYU) Section 4.4 Curve Sketching June 10, 2010 11 / 45
  • 27. Step 2: Concavity f′ (x) = 6x2 − 6x − 12 =⇒ f′′ (x) = 12x − 6 = 6(2x − 1) Another sign chart: . − . − .′′ (x) f . ./2 1 f .(x) . . . . . . V63.0121.002.2010Su, Calculus I (NYU) Section 4.4 Curve Sketching June 10, 2010 11 / 45
  • 28. Step 2: Concavity f′ (x) = 6x2 − 6x − 12 =⇒ f′′ (x) = 12x − 6 = 6(2x − 1) Another sign chart: . − . − . + + .′′ (x) f . ./2 1 f .(x) . . . . . . V63.0121.002.2010Su, Calculus I (NYU) Section 4.4 Curve Sketching June 10, 2010 11 / 45
  • 29. Step 2: Concavity f′ (x) = 6x2 − 6x − 12 =⇒ f′′ (x) = 12x − 6 = 6(2x − 1) Another sign chart: . − . − . + + .′′ (x) f . . ⌢ ./2 1 f .(x) . . . . . . V63.0121.002.2010Su, Calculus I (NYU) Section 4.4 Curve Sketching June 10, 2010 11 / 45
  • 30. Step 2: Concavity f′ (x) = 6x2 − 6x − 12 =⇒ f′′ (x) = 12x − 6 = 6(2x − 1) Another sign chart: . − . − . + + .′′ (x) f . . ⌢ ./2 1 . ⌣ f .(x) . . . . . . V63.0121.002.2010Su, Calculus I (NYU) Section 4.4 Curve Sketching June 10, 2010 11 / 45
  • 31. Step 2: Concavity f′ (x) = 6x2 − 6x − 12 =⇒ f′′ (x) = 12x − 6 = 6(2x − 1) Another sign chart: . − . − . + + .′′ (x) f . . ⌢ ./2 1 . ⌣ f .(x) I .P . . . . . . V63.0121.002.2010Su, Calculus I (NYU) Section 4.4 Curve Sketching June 10, 2010 11 / 45
  • 32. Step 3: One sign chart to rule them all Remember, f(x) = 2x3 − 3x2 − 12x. . . . . . . . V63.0121.002.2010Su, Calculus I (NYU) Section 4.4 Curve Sketching June 10, 2010 12 / 45
  • 33. Step 3: One sign chart to rule them all Remember, f(x) = 2x3 − 3x2 − 12x. − . . . . + − . . + .′ (x) f . ↗− ↘ . . 1 . ↘ . 2 . ↗ . m . onotonicity . . . . . . V63.0121.002.2010Su, Calculus I (NYU) Section 4.4 Curve Sketching June 10, 2010 12 / 45
  • 34. Step 3: One sign chart to rule them all Remember, f(x) = 2x3 − 3x2 − 12x. . . + − . . − . . + .′ (x) f . ↗− . . 1 ↘ . ↘ . . 2 ↗ . m .′′ onotonicity − . − − . − . . + + . + + f . (x) . ⌢ . ⌢ 1/2 . . ⌣ . ⌣ c . oncavity . . . . . . V63.0121.002.2010Su, Calculus I (NYU) Section 4.4 Curve Sketching June 10, 2010 12 / 45
  • 35. Step 3: One sign chart to rule them all Remember, f(x) = 2x3 − 3x2 − 12x. . . + − . . − . . + .′ (x) f . ↗− . . 1 ↘ . ↘ . . 2 ↗ . m .′′ onotonicity − . − − . − . . + + . + + f . (x) . ⌢ ⌢ ./2 . . 1 ⌣ . ⌣ c . oncavity 7 .. − . 6 1/2 −. . 20 f .(x) . − . 1 . 1/2 2 . s . hape of f m . ax I .P m . in . . . . . . V63.0121.002.2010Su, Calculus I (NYU) Section 4.4 Curve Sketching June 10, 2010 12 / 45
  • 36. Combinations of monotonicity and concavity I .I I . . I .II I .V . . . . . . V63.0121.002.2010Su, Calculus I (NYU) Section 4.4 Curve Sketching June 10, 2010 13 / 45
  • 37. Combinations of monotonicity and concavity . decreasing, concave down I .I I . . I .II I .V . . . . . . V63.0121.002.2010Su, Calculus I (NYU) Section 4.4 Curve Sketching June 10, 2010 13 / 45
  • 38. Combinations of monotonicity and concavity . . increasing, decreasing, concave concave down down I .I I . . I .II I .V . . . . . . V63.0121.002.2010Su, Calculus I (NYU) Section 4.4 Curve Sketching June 10, 2010 13 / 45
  • 39. Combinations of monotonicity and concavity . . increasing, decreasing, concave concave down down I .I I . . I .II I .V . decreasing, concave up . . . . . . V63.0121.002.2010Su, Calculus I (NYU) Section 4.4 Curve Sketching June 10, 2010 13 / 45
  • 40. Combinations of monotonicity and concavity . . increasing, decreasing, concave concave down down I .I I . . I .II I .V . . decreasing, increasing, concave up concave up . . . . . . V63.0121.002.2010Su, Calculus I (NYU) Section 4.4 Curve Sketching June 10, 2010 13 / 45
  • 41. Step 3: One sign chart to rule them all Remember, f(x) = 2x3 − 3x2 − 12x. . . + − . . − . . + .′ (x) f . ↗− . . 1 ↘ . ↘ . . 2 ↗ . m .′′ onotonicity − . − − . − . . + + . + + f . (x) . ⌢ ⌢ ./2 . . 1 ⌣ . ⌣ c . oncavity 7 .. − . 6 1/2 −. . 20 f .(x) . . . 1 − . 1/2 2 . s . hape of f m . ax I .P m . in . . . . . . V63.0121.002.2010Su, Calculus I (NYU) Section 4.4 Curve Sketching June 10, 2010 14 / 45
  • 42. Step 3: One sign chart to rule them all Remember, f(x) = 2x3 − 3x2 − 12x. . . + − . . − . . + .′ (x) f . ↗− . . 1 ↘ . ↘ . . 2 ↗ . m .′′ onotonicity − . − − . − . . + + . + + f . (x) . ⌢ ⌢ ./2 . . 1 ⌣ . ⌣ c . oncavity 7 .. − . 6 1/2 −. . 20 f .(x) . . . 1 . ./2 − 1 2 . s . hape of f m . ax I .P m . in . . . . . . V63.0121.002.2010Su, Calculus I (NYU) Section 4.4 Curve Sketching June 10, 2010 14 / 45
  • 43. Step 3: One sign chart to rule them all Remember, f(x) = 2x3 − 3x2 − 12x. . . + − . . − . . + .′ (x) f . ↗− . . 1 ↘ . ↘ . . 2 ↗ . m .′′ onotonicity − . − − . − . . + + . + + f . (x) . ⌢ ⌢ ./2 . . 1 ⌣ . ⌣ c . oncavity 7 .. − . 6 1/2 −. . 20 f .(x) . . . 1 . ./2 . − 1 2 . s . hape of f m . ax I .P m . in . . . . . . V63.0121.002.2010Su, Calculus I (NYU) Section 4.4 Curve Sketching June 10, 2010 14 / 45
  • 44. Step 3: One sign chart to rule them all Remember, f(x) = 2x3 − 3x2 − 12x. . . + − . . − . . + .′ (x) f . ↗− . . 1 ↘ . ↘ . . 2 ↗ . m .′′ onotonicity − . − − . − . . + + . + + f . (x) . ⌢ ⌢ ./2 . . 1 ⌣ . ⌣ c . oncavity 7 .. − . 6 1/2 −. . 20 f .(x) . . . 1 . ./2 . − 1 2 . . s . hape of f m . ax I .P m . in . . . . . . V63.0121.002.2010Su, Calculus I (NYU) Section 4.4 Curve Sketching June 10, 2010 14 / 45
  • 45. Step 4: Graph f .(x) .(x) = 2x3 − 3x2 − 12x f ( √ ) . −1, 7) ( . . 3− 4105 , 0 . 0, 0) ( . . . . 1/2, −61/2) ( ( . x √ ) . . 3+ 4105 , 0 . 2, −20) ( . 7 .. − . 61/2 −. . 20 f .(x) . . . 1 . ./2 . − 1 2 . . s . hape of f m . ax I .P m . in . . . . . . V63.0121.002.2010Su, Calculus I (NYU) Section 4.4 Curve Sketching June 10, 2010 15 / 45
  • 46. Step 4: Graph f .(x) .(x) = 2x3 − 3x2 − 12x f ( √ ) . −1, 7) ( . . 3− 4105 , 0 . 0, 0) ( . . . . 1/2, −61/2) ( ( . x √ ) . . 3+ 4105 , 0 . 2, −20) ( . 7 .. − . 61/2 −. . 20 f .(x) . . . 1 . ./2 . − 1 2 . . s . hape of f m . ax I .P m . in . . . . . . V63.0121.002.2010Su, Calculus I (NYU) Section 4.4 Curve Sketching June 10, 2010 15 / 45
  • 47. Step 4: Graph f .(x) .(x) = 2x3 − 3x2 − 12x f ( √ ) . −1, 7) ( . . 3− 4105 , 0 . 0, 0) ( . . . . 1/2, −61/2) ( ( . x √ ) . . 3+ 4105 , 0 . 2, −20) ( . 7 .. − . 61/2 −. . 20 f .(x) . . . 1 . ./2 . − 1 2 . . s . hape of f m . ax I .P m . in . . . . . . V63.0121.002.2010Su, Calculus I (NYU) Section 4.4 Curve Sketching June 10, 2010 15 / 45
  • 48. Step 4: Graph f .(x) .(x) = 2x3 − 3x2 − 12x f ( √ ) . −1, 7) ( . . 3− 4105 , 0 . 0, 0) ( . . . . 1/2, −61/2) ( ( . x √ ) . . 3+ 4105 , 0 . 2, −20) ( . 7 .. − . 61/2 −. . 20 f .(x) . . . 1 . ./2 . − 1 2 . . s . hape of f m . ax I .P m . in . . . . . . V63.0121.002.2010Su, Calculus I (NYU) Section 4.4 Curve Sketching June 10, 2010 15 / 45
  • 49. Step 4: Graph f .(x) .(x) = 2x3 − 3x2 − 12x f ( √ ) . −1, 7) ( . . 3− 4105 , 0 . 0, 0) ( . . . . 1/2, −61/2) ( ( . x √ ) . . 3+ 4105 , 0 . 2, −20) ( . 7 .. − . 61/2 −. . 20 f .(x) . . . 1 . ./2 . − 1 2 . . s . hape of f m . ax I .P m . in . . . . . . V63.0121.002.2010Su, Calculus I (NYU) Section 4.4 Curve Sketching June 10, 2010 15 / 45
  • 50. Graphing a quartic Example Graph f(x) = x4 − 4x3 + 10 . . . . . . V63.0121.002.2010Su, Calculus I (NYU) Section 4.4 Curve Sketching June 10, 2010 16 / 45
  • 51. Graphing a quartic Example Graph f(x) = x4 − 4x3 + 10 (Step 0) We know f(0) = 10 and lim f(x) = +∞. Not too many other x→±∞ points on the graph are evident. . . . . . . V63.0121.002.2010Su, Calculus I (NYU) Section 4.4 Curve Sketching June 10, 2010 16 / 45
  • 52. Step 1: Monotonicity f(x) = x4 − 4x3 + 10 =⇒ f′ (x) = 4x3 − 12x2 = 4x2 (x − 3) . . . . . . V63.0121.002.2010Su, Calculus I (NYU) Section 4.4 Curve Sketching June 10, 2010 17 / 45
  • 53. Step 1: Monotonicity f(x) = x4 − 4x3 + 10 =⇒ f′ (x) = 4x3 − 12x2 = 4x2 (x − 3) We make its sign chart. . . . . . . . V63.0121.002.2010Su, Calculus I (NYU) Section 4.4 Curve Sketching June 10, 2010 17 / 45
  • 54. Step 1: Monotonicity f(x) = x4 − 4x3 + 10 =⇒ f′ (x) = 4x3 − 12x2 = 4x2 (x − 3) We make its sign chart. 0 .. . x2 4 0 . . . . . . . V63.0121.002.2010Su, Calculus I (NYU) Section 4.4 Curve Sketching June 10, 2010 17 / 45
  • 55. Step 1: Monotonicity f(x) = x4 − 4x3 + 10 =⇒ f′ (x) = 4x3 − 12x2 = 4x2 (x − 3) We make its sign chart. . .. + 0 . x2 4 0 . . . . . . . V63.0121.002.2010Su, Calculus I (NYU) Section 4.4 Curve Sketching June 10, 2010 17 / 45
  • 56. Step 1: Monotonicity f(x) = x4 − 4x3 + 10 =⇒ f′ (x) = 4x3 − 12x2 = 4x2 (x − 3) We make its sign chart. . .. + 0 . + . x2 4 0 . . . . . . . V63.0121.002.2010Su, Calculus I (NYU) Section 4.4 Curve Sketching June 10, 2010 17 / 45
  • 57. Step 1: Monotonicity f(x) = x4 − 4x3 + 10 =⇒ f′ (x) = 4x3 − 12x2 = 4x2 (x − 3) We make its sign chart. . .. + 0 . + . + . x2 4 0 . . . . . . . V63.0121.002.2010Su, Calculus I (NYU) Section 4.4 Curve Sketching June 10, 2010 17 / 45
  • 58. Step 1: Monotonicity f(x) = x4 − 4x3 + 10 =⇒ f′ (x) = 4x3 − 12x2 = 4x2 (x − 3) We make its sign chart. . .. + 0 . + . + . x2 4 0 . 0 .. . x − 3) ( 3 . . . . . . . V63.0121.002.2010Su, Calculus I (NYU) Section 4.4 Curve Sketching June 10, 2010 17 / 45
  • 59. Step 1: Monotonicity f(x) = x4 − 4x3 + 10 =⇒ f′ (x) = 4x3 − 12x2 = 4x2 (x − 3) We make its sign chart. . .. + 0 . + . + . x2 4 0 . − . 0 .. . x − 3) ( 3 . . . . . . . V63.0121.002.2010Su, Calculus I (NYU) Section 4.4 Curve Sketching June 10, 2010 17 / 45
  • 60. Step 1: Monotonicity f(x) = x4 − 4x3 + 10 =⇒ f′ (x) = 4x3 − 12x2 = 4x2 (x − 3) We make its sign chart. . .. + 0 . + . + . x2 4 0 . − . − . 0 .. . x − 3) ( 3 . . . . . . . V63.0121.002.2010Su, Calculus I (NYU) Section 4.4 Curve Sketching June 10, 2010 17 / 45
  • 61. Step 1: Monotonicity f(x) = x4 − 4x3 + 10 =⇒ f′ (x) = 4x3 − 12x2 = 4x2 (x − 3) We make its sign chart. . .. + 0 . + . + . x2 4 0 . − . − . .. . 0 + . x − 3) ( 3 . . . . . . . V63.0121.002.2010Su, Calculus I (NYU) Section 4.4 Curve Sketching June 10, 2010 17 / 45
  • 62. Step 1: Monotonicity f(x) = x4 − 4x3 + 10 =⇒ f′ (x) = 4x3 − 12x2 = 4x2 (x − 3) We make its sign chart. . .. + 0 . + . + . x2 4 0 . − . − . .. . 0 + . x − 3) ( 3 . 0 .. 0 .. .′ (x) f 0 . 3 . f .(x) . . . . . . V63.0121.002.2010Su, Calculus I (NYU) Section 4.4 Curve Sketching June 10, 2010 17 / 45
  • 63. Step 1: Monotonicity f(x) = x4 − 4x3 + 10 =⇒ f′ (x) = 4x3 − 12x2 = 4x2 (x − 3) We make its sign chart. . .. + 0 . + . + . x2 4 0 . − . − . .. . 0 + . x − 3) ( 3 . − 0 . .. 0 .. .′ (x) f 0 . 3 . f .(x) . . . . . . V63.0121.002.2010Su, Calculus I (NYU) Section 4.4 Curve Sketching June 10, 2010 17 / 45
  • 64. Step 1: Monotonicity f(x) = x4 − 4x3 + 10 =⇒ f′ (x) = 4x3 − 12x2 = 4x2 (x − 3) We make its sign chart. . .. + 0 . + . + . x2 4 0 . − . − . .. . 0 + . x − 3) ( 3 . − 0 . .. − . 0 .. .′ (x) f 0 . 3 . f .(x) . . . . . . V63.0121.002.2010Su, Calculus I (NYU) Section 4.4 Curve Sketching June 10, 2010 17 / 45
  • 65. Step 1: Monotonicity f(x) = x4 − 4x3 + 10 =⇒ f′ (x) = 4x3 − 12x2 = 4x2 (x − 3) We make its sign chart. . .. + 0 . + . + . x2 4 0 . − . − . .. . 0 + . x − 3) ( 3 . − 0 . .. − . .. . 0 + .′ (x) f 0 . 3 . f .(x) . . . . . . V63.0121.002.2010Su, Calculus I (NYU) Section 4.4 Curve Sketching June 10, 2010 17 / 45
  • 66. Step 1: Monotonicity f(x) = x4 − 4x3 + 10 =⇒ f′ (x) = 4x3 − 12x2 = 4x2 (x − 3) We make its sign chart. . .. + 0 . + . + . x2 4 0 . − . − . .. . 0 + . x − 3) ( 3 . − 0 . .. − . .. . 0 + .′ (x) f ↘ 0 . . 3 . f .(x) . . . . . . V63.0121.002.2010Su, Calculus I (NYU) Section 4.4 Curve Sketching June 10, 2010 17 / 45
  • 67. Step 1: Monotonicity f(x) = x4 − 4x3 + 10 =⇒ f′ (x) = 4x3 − 12x2 = 4x2 (x − 3) We make its sign chart. . .. + 0 . + . + . x2 4 0 . − . − . .. . 0 + . x − 3) ( 3 . − 0 . .. − . .. . 0 + .′ (x) f ↘ 0 . . ↘ . 3 . f .(x) . . . . . . V63.0121.002.2010Su, Calculus I (NYU) Section 4.4 Curve Sketching June 10, 2010 17 / 45
  • 68. Step 1: Monotonicity f(x) = x4 − 4x3 + 10 =⇒ f′ (x) = 4x3 − 12x2 = 4x2 (x − 3) We make its sign chart. . .. + 0 . + . + . x2 4 0 . − . − . .. . 0 + . x − 3) ( 3 . − 0 . .. − . .. . 0 + .′ (x) f ↘ 0 . . ↘ . 3 ↗ . . f .(x) . . . . . . V63.0121.002.2010Su, Calculus I (NYU) Section 4.4 Curve Sketching June 10, 2010 17 / 45
  • 69. Step 1: Monotonicity f(x) = x4 − 4x3 + 10 =⇒ f′ (x) = 4x3 − 12x2 = 4x2 (x − 3) We make its sign chart. . .. + 0 . + . + . x2 4 0 . − . − . .. . 0 + . x − 3) ( 3 . − 0 . .. − . .. . 0 + .′ (x) f ↘ 0 . . ↘ . 3 ↗ . . f .(x) m . in . . . . . . V63.0121.002.2010Su, Calculus I (NYU) Section 4.4 Curve Sketching June 10, 2010 17 / 45
  • 70. Step 2: Concavity f′ (x) = 4x3 − 12x2 =⇒ f′′ (x) = 12x2 − 24x = 12x(x − 2) . . . . . . . V63.0121.002.2010Su, Calculus I (NYU) Section 4.4 Curve Sketching June 10, 2010 18 / 45
  • 71. Step 2: Concavity f′ (x) = 4x3 − 12x2 =⇒ f′′ (x) = 12x2 − 24x = 12x(x − 2) Here is its sign chart: . . . . . . . V63.0121.002.2010Su, Calculus I (NYU) Section 4.4 Curve Sketching June 10, 2010 18 / 45
  • 72. Step 2: Concavity f′ (x) = 4x3 − 12x2 =⇒ f′′ (x) = 12x2 − 24x = 12x(x − 2) Here is its sign chart: 0 .. 1 . 2x 0 . . . . . . . V63.0121.002.2010Su, Calculus I (NYU) Section 4.4 Curve Sketching June 10, 2010 18 / 45
  • 73. Step 2: Concavity f′ (x) = 4x3 − 12x2 =⇒ f′′ (x) = 12x2 − 24x = 12x(x − 2) Here is its sign chart: − 0 . .. 1 . 2x 0 . . . . . . . V63.0121.002.2010Su, Calculus I (NYU) Section 4.4 Curve Sketching June 10, 2010 18 / 45
  • 74. Step 2: Concavity f′ (x) = 4x3 − 12x2 =⇒ f′′ (x) = 12x2 − 24x = 12x(x − 2) Here is its sign chart: − 0 . .. . + 1 . 2x 0 . . . . . . . V63.0121.002.2010Su, Calculus I (NYU) Section 4.4 Curve Sketching June 10, 2010 18 / 45
  • 75. Step 2: Concavity f′ (x) = 4x3 − 12x2 =⇒ f′′ (x) = 12x2 − 24x = 12x(x − 2) Here is its sign chart: − 0 . .. . + . + 1 . 2x 0 . . . . . . . V63.0121.002.2010Su, Calculus I (NYU) Section 4.4 Curve Sketching June 10, 2010 18 / 45
  • 76. Step 2: Concavity f′ (x) = 4x3 − 12x2 =⇒ f′′ (x) = 12x2 − 24x = 12x(x − 2) Here is its sign chart: − 0 . .. . + . + 1 . 2x 0 . 0 .. . −2 x 2 . . . . . . . V63.0121.002.2010Su, Calculus I (NYU) Section 4.4 Curve Sketching June 10, 2010 18 / 45
  • 77. Step 2: Concavity f′ (x) = 4x3 − 12x2 =⇒ f′′ (x) = 12x2 − 24x = 12x(x − 2) Here is its sign chart: − 0 . .. . + . + 1 . 2x 0 . − . 0 .. . −2 x 2 . . . . . . . V63.0121.002.2010Su, Calculus I (NYU) Section 4.4 Curve Sketching June 10, 2010 18 / 45
  • 78. Step 2: Concavity f′ (x) = 4x3 − 12x2 =⇒ f′′ (x) = 12x2 − 24x = 12x(x − 2) Here is its sign chart: − 0 . .. . + . + 1 . 2x 0 . − . − . 0 .. . −2 x 2 . . . . . . . V63.0121.002.2010Su, Calculus I (NYU) Section 4.4 Curve Sketching June 10, 2010 18 / 45