Right Circular Cylinders
Volume of Right Circular Cylinders
Example 3: pg: 425
Derive the formula for the volume of a sphere of
radius r.
Solid of Revolution (Example: Torus)
1: DISK METHOD
2: WASHERS METHOD
6.2 Volumes by slicing (pg:421)
1. Volumes by Disk Method (pg:424)
6.2.4
(p. 424)
Figure 6.2.9
(p. 424)
Equation
(5)
(p. 425)
About x-axis
Example 2: (pg: 425)
 Find the volume of the
solid that is obtained
when the region under
the curve
over the interval [1, 4]
is revolved about the x-
axis.
xxfy  )(
11–18 Find the volume of the solid that results when the
region
enclosed by the given curves is revolved about the x-
axis. "
11. y = '25 − x2, y = 3
12. y = 9 − x2, y = 0
13. x = 'y, x = y/4
14. y = sin x, y = cos x, x = 0, x = "/4
[Hint: Use the identity cos 2x = cos2 x − sin2 x.]
15. y = ex, y = 0, x = 0, x = ln 3
16. y = e−2x, y = 0, x = 0, x = 1
17. y =1'4 + x2
, x = −2, x = 2, y = 0
18. y =
e3x
'1 + e6x
, x = 0, x = 1, y = 0
2: Volumes by Washer Method (pg: 426)
 Washer  Washers
Doughnuts are like Washers
Volumes by washers:
1. Perpendicular to the x-axis
2. Perpendicular to the y-axis
6.2.5
(p. 425)
Figure 6.2.12
(p. 425)
Equation (6)
(p. 426)
Example 4: (pg: 426)
 Find the volume of the
solid generated when
the region between the
graphs of the equations
and g(x)=x over the
interval [0, 2] is
revolved about the x-
axis.
2
2
1
)( xxf 
Volumes by disks and washers
perpendicular to the y-axis (page:426)
Equation
(8)
Figure 6.2.14 (p. 427)
Equation (7)
Example 5: (pg: 427)
 Find the volume of the
solid that is obtained
when the region
enclosed by the curve
y=2, and x=0 is
revolved about the y-
axis.
xxfy  )(
Figure 6.2.15 (p. 427)
Volumes by washers
 
b
a
dxrRA )( 22
 
b
a
dxrRV )( 22

Vwasher = p(R2 – r2)dx
6.3.1
(p. 432)
6.3.2
(p. 434)
http://mathdemos.org/mathdemos/washe
rmethod/gallery/gallery.html

6.2 volume of solid of revolution