Review: UNIT CIRCLE
The equation of a circle:
(x-h)2
+ (y-k)2
= r2
Where:
- (h, k) is the coordinate of the center of the
circle
- r is the radius
- (x, y) is the point of the circle
What is a UNIT CIRCLE?
A unit circle is a circle whose radius is equal
to 1 unit and its center is at the origin (0, 0).
Substituting the coordinates of the center
and the radius to the general equation of a
circle would determine the equation of a unit
circle.
Hence, the equation of the unit circle is
(x - 0)2
+ (y – 0)2
=1
or simply
x2
+ y2
= 1
The center (h, k) is (0, 0) and the radius (r) is
1.
Since x² = (−x)² for all x, and since the reflection of
any point on the unit circle about the x- or y-axis is
also on the unit circle, the above equation holds for
all points (x, y) on the unit circle, not only those in the
first quadrant.
Review: QUADRANTAL ANGLES
Quadrantal angles are angles in standard position
whose terminal ray lies along one of the axes.
Examples are: 90 ° (π/2 radian), 180 ° (π radian),
270 ° ( 3π/2 radian) and 360 ° (2π radian) and
their coterminal angles.
The Six Trigonometric functional
identities in a unit circle
Cos θ = x/r x
Sin θ = y/r y
Tan θ = y/x y/x
Sec θ = r/x 1/x
Csc θ = r/y 1/y
Cot θ = x/y x/y
x
y
r
θ
Circular Functions of Quadrantal Angles
Following the counterclockwise direction, the
quadrantal angles dividing the unit circle are as
follows: π/2 (90 °), π (180 °), 3(π)/2 (270 °), and
2π(360 °)If the direction point is clockwise, then the angles
become negative: -π/2 (-90), -π(-180), -3π/2 (-270), -
2π(-360).
(π) | 180 °
(π)/2 | 90 °
3(π)/2 | 270 °
2(π) | 360 °
As seen in this figure,
The coordinates of π/2 is (0, 1) and lies on Quadrant I;
the coordinates of π is (-1, 0) and lies on Quadrant II;
the coordinates of 3π/2 is (0, -1) and lies on Quadrant
III; while the coordinates of 2π is (0, -1) and lies on
Quadrant IV.
(π) | 180 °
(π)/2 | 90 °
3(π)/2 | 270 °
2(π) | 360 °
Radian Angle Coordinates Cos Sin Tan Sec Csc Cot
π/2 90 ( 0, 1) 0 1 1 0
π 180 (-1, 0) -1 0 0 -1
3π/2 270 (0, -1) 0 -1 -1 0
2π 360 (1, 0) 1 0 0 1
To summarize, this table presents the quadrantal
angles and their following coordinates, and
trigonometric values.
8
8
8
8
8
8
8
8
Oral Exercise
Find the value of the circular functions of the
given quadrantal angles.
1. sin π
2
2. sin 3π
2
3. sin 8π
4
1
-1
0
4. sin
8π
8
1=
=
=
5. cos 5π
2
6. sec 10
π2
0
-1
=
=
=
Now that the coordinates of the quadrantal angles are
defined, it is possible to identify the six trigonometric
functions of each angles.
Review on Special Triangles
Through the Pythagorean Theorem, the lengths of the sides
of 45° - 45° and 30° - 60° - 90°right triangles are derived.
x
y
r x2
+ y2
= r2
7. cos
99
π99
8. sec 24
π2
-1
1
9. tan
π
2
10. cot 3π
2
11. tan 8π
4
12. cot 8π
8
8
0
0
8
Oral Exercise
Find the value of the circular functions of the
given quadrantal angles.
=
=
=
=
=
=
Review on Special Triangles
The length of the hypotenuse is
equivalent to the length of the
leg times square root of 2 in a
45 - 45 right triangle.
a
a
a√2
45°
45°
The length of the hypotenuse is
equivalent to twice the length of
the shorter leg (side opposite
30°), and the length of the
longer leg (side opposite 60°) is
equivalent to √3 times the
shorter leg.
a
a√3
2a
30°
60°
The trigonometric functions of special angles
would be determined with the aid of the unit
circle.
x
y
1
θ
Knowing the properties of these two special
triangles will allow you to easily find the
trigonometric functions of special angles, 30°,
45° and 60°.
Circular functions of multiples of
30° or π/6
x
y
1
30°
Cos θ = x
Sin θ = y
Tan θ = y/x
Sec θ = 1/x
Csc θ = 1/y
Cot θ = x/y
Circular functions of multiples of
30° or π/6
Cos
Sin
Tan
=
=
=
√3
2
1
2
√3
3
Sec
Csc
Cot
=
=
=
2√3
3
2
√3
Coordinates:
Circular functions of multiples of
150° or 5π/6
Circular functions of multiples of 210°
or 7π/6
Circular functions of multiples of
330° or 11π/6
To summarize, this table presents the circular
functions of π/3 and its multiples.
Circular functions of multiples of
45° or π/4
x
y
1
45°
4
π
4
3π
4
7π
4
5π
Since is in the 2nd
Quadrant, its coordinates are
Since is in the 3rd
Quadrant, its coordinates are
4
3π
4
5π
Since is in the 4th
Quadrant, its coordinates are
4
7π
),(
2
2
2
2
),(
2
2
2
2
−
),(
2
2
2
2
−−
),(
2
2
2
2
−
Cos θ = x
Sin θ = y
Tan θ = y/x
Sec θ = 1/x
Csc θ = 1/y
Cot θ = x/y
Circular functions of multiples of
45° or π/4
Cos
Sin
Tan
=
=
=
√2
2
√2
2
1
Sec
Csc
Cot
=
=
=
√2
Coordinates: ),(
2
2
2
2
4
π
4
π
4
π
4
π
4
π
4
π
1
√2
Cos
Sin
Tan
=
=
=
√2
2
√2
2
1
Sec
Csc
Cot
=
=
=
√2
Coordinates: )
2
2
,
2
2
(−
4
3π
1
√24
3π
4
3π
4
3π
4
3π
4
3π
-
-
Circular functions of
multiples of 135° or 3π/4
-
-
Cos
Sin
Tan
=
=
=
√2
2
√2
2
1
Sec
Csc
Cot
=
=
=
√2
Coordinates: )
2
2
,
2
2
( −−
4
3π
1
√24
3π
4
3π
4
3π
4
3π
4
3π
-
-
Circular functions of
multiples of 225° or 5π/4
-
-
Cos
Sin
Tan
=
=
=
√2
2
√2
2
1
Sec
Csc
Cot
=
=
=
√2
Coordinates: )
2
2
,
2
2
( −
4
3π
1
√24
3π
4
3π
4
3π
4
3π
4
3π
-
-
Circular functions of
multiples of 315° or 7π/4
-
-
Circular functions of multiples of
60° or π/3
x
y
1
60°
3
π
3
2π
3
5π
3
4π
Since is in the 2nd
Quadrant, its coordinates are
Since is in the 3rd
Quadrant, its coordinates are
Since is in the 4th
Quadrant, its coordinates are
),(
2
3
2
1
3
2π
3
4π
3
5π
),(
2
3
2
1
−
),(
2
3
2
1
−
),(
2
3
2
1
−−
Cos θ = x
Sin θ = y
Tan θ = y/x
Sec θ = 1/x
Csc θ = 1/y
Cot θ = x/y
Circular functions of multiples of
60° or π/3
Cos
Sin
Tan
=
=
=
1
2
Sec
Csc
Cot
=
=
=
2
Coordinates:
3
π
3
π
3
π
3
π
3
π
3
π
),(
2
3
2
1
√3
2
√3
2√3
3
√3
3
Exercise #1 – Part A
Directions: Write True if the statement is correct; otherwise,
changed the underlined word. Write your answers in a whole
sheet of paper. You only have 5 minutes to answer the following.
_________1. Quadrantal angles are angles whose terminal rays
lies in one of the axes.
_________2. (π)/2 lies in the positive x-axis.
_________3. Quadrantal real numbers are numbers whose
starting and terminal points lies on one of the axes.
_________4. The value of cos (π) is 0.
_________5. 3(π)/2 is equivalent to 360 ° .
Let us Check!
1. True
2. Negative
3. Arc lengths
4. -1
5. 2(π)
Exercise #1 – Part B
Directions: Identify the values being asked in the following. Write
your answers in a one whole sheet of paper. You only have 15
minutes to answer the following.
________1. sin(π)
________ 2. cot (2π)
________3. sec (5π/2)
________4. Csc (3 π/2)
________5. Tan (π/2)
Let us Check!
1. 0
2. Undefined
3. Undefined
4. -1
5. Undefined
________6. Cos (3π)
________7. tan (6π)
________8. Sin (11/2)
________9. Sec (7π/2)
________10. Cot (4π)
6. -1
7. 0
8. -1
9. -1
10. undefined
Exercises
1. sin45 + cot210 =
2. sec30+ tan 135=
3. csc630 – cot210 +
tan45=
4. sin240+ cos315=
5. sin90+ cos60=
Let Us Check!
1.
2.
3.
3
2
2
+
2
322 +
1
3
32
+
3
332 +
131 +−−
3−
4.
5.
2
2
2
3
+−
2
23 +−
2
1
1+
2
3
Exercises
1. sin60=
2. cot30=
3. tan150=
4. sec450=
5. csc120=
6. sin90=
1. sin60=
2. cot30=
3. tan150=
4. sec450=
5. csc120=
6. sin90=
Let Us Check!
1. sin60 =
2. cot30 =
3. tan150 =
4. sec450 =
5. csc120 =
6. sin90 =
√3
2
√3
√3
3
-
0
2√3
3
1

Trigonometry: Circular Functions

  • 1.
    Review: UNIT CIRCLE Theequation of a circle: (x-h)2 + (y-k)2 = r2 Where: - (h, k) is the coordinate of the center of the circle - r is the radius - (x, y) is the point of the circle
  • 2.
    What is aUNIT CIRCLE? A unit circle is a circle whose radius is equal to 1 unit and its center is at the origin (0, 0). Substituting the coordinates of the center and the radius to the general equation of a circle would determine the equation of a unit circle.
  • 3.
    Hence, the equationof the unit circle is (x - 0)2 + (y – 0)2 =1 or simply x2 + y2 = 1 The center (h, k) is (0, 0) and the radius (r) is 1. Since x² = (−x)² for all x, and since the reflection of any point on the unit circle about the x- or y-axis is also on the unit circle, the above equation holds for all points (x, y) on the unit circle, not only those in the first quadrant.
  • 4.
    Review: QUADRANTAL ANGLES Quadrantalangles are angles in standard position whose terminal ray lies along one of the axes. Examples are: 90 ° (π/2 radian), 180 ° (π radian), 270 ° ( 3π/2 radian) and 360 ° (2π radian) and their coterminal angles.
  • 5.
    The Six Trigonometricfunctional identities in a unit circle Cos θ = x/r x Sin θ = y/r y Tan θ = y/x y/x Sec θ = r/x 1/x Csc θ = r/y 1/y Cot θ = x/y x/y x y r θ
  • 6.
    Circular Functions ofQuadrantal Angles Following the counterclockwise direction, the quadrantal angles dividing the unit circle are as follows: π/2 (90 °), π (180 °), 3(π)/2 (270 °), and 2π(360 °)If the direction point is clockwise, then the angles become negative: -π/2 (-90), -π(-180), -3π/2 (-270), - 2π(-360). (π) | 180 ° (π)/2 | 90 ° 3(π)/2 | 270 ° 2(π) | 360 °
  • 7.
    As seen inthis figure, The coordinates of π/2 is (0, 1) and lies on Quadrant I; the coordinates of π is (-1, 0) and lies on Quadrant II; the coordinates of 3π/2 is (0, -1) and lies on Quadrant III; while the coordinates of 2π is (0, -1) and lies on Quadrant IV. (π) | 180 ° (π)/2 | 90 ° 3(π)/2 | 270 ° 2(π) | 360 °
  • 9.
    Radian Angle CoordinatesCos Sin Tan Sec Csc Cot π/2 90 ( 0, 1) 0 1 1 0 π 180 (-1, 0) -1 0 0 -1 3π/2 270 (0, -1) 0 -1 -1 0 2π 360 (1, 0) 1 0 0 1 To summarize, this table presents the quadrantal angles and their following coordinates, and trigonometric values. 8 8 8 8 8 8 8 8
  • 10.
    Oral Exercise Find thevalue of the circular functions of the given quadrantal angles. 1. sin π 2 2. sin 3π 2 3. sin 8π 4 1 -1 0 4. sin 8π 8 1= = = 5. cos 5π 2 6. sec 10 π2 0 -1 = = =
  • 11.
    Now that thecoordinates of the quadrantal angles are defined, it is possible to identify the six trigonometric functions of each angles.
  • 12.
    Review on SpecialTriangles Through the Pythagorean Theorem, the lengths of the sides of 45° - 45° and 30° - 60° - 90°right triangles are derived. x y r x2 + y2 = r2
  • 13.
    7. cos 99 π99 8. sec24 π2 -1 1 9. tan π 2 10. cot 3π 2 11. tan 8π 4 12. cot 8π 8 8 0 0 8 Oral Exercise Find the value of the circular functions of the given quadrantal angles. = = = = = =
  • 14.
    Review on SpecialTriangles The length of the hypotenuse is equivalent to the length of the leg times square root of 2 in a 45 - 45 right triangle. a a a√2 45° 45° The length of the hypotenuse is equivalent to twice the length of the shorter leg (side opposite 30°), and the length of the longer leg (side opposite 60°) is equivalent to √3 times the shorter leg. a a√3 2a 30° 60°
  • 15.
    The trigonometric functionsof special angles would be determined with the aid of the unit circle. x y 1 θ Knowing the properties of these two special triangles will allow you to easily find the trigonometric functions of special angles, 30°, 45° and 60°.
  • 16.
    Circular functions ofmultiples of 30° or π/6 x y 1 30°
  • 17.
    Cos θ =x Sin θ = y Tan θ = y/x Sec θ = 1/x Csc θ = 1/y Cot θ = x/y Circular functions of multiples of 30° or π/6 Cos Sin Tan = = = √3 2 1 2 √3 3 Sec Csc Cot = = = 2√3 3 2 √3 Coordinates:
  • 18.
    Circular functions ofmultiples of 150° or 5π/6
  • 19.
    Circular functions ofmultiples of 210° or 7π/6
  • 20.
    Circular functions ofmultiples of 330° or 11π/6
  • 21.
    To summarize, thistable presents the circular functions of π/3 and its multiples.
  • 22.
    Circular functions ofmultiples of 45° or π/4 x y 1 45° 4 π 4 3π 4 7π 4 5π Since is in the 2nd Quadrant, its coordinates are Since is in the 3rd Quadrant, its coordinates are 4 3π 4 5π Since is in the 4th Quadrant, its coordinates are 4 7π ),( 2 2 2 2 ),( 2 2 2 2 − ),( 2 2 2 2 −− ),( 2 2 2 2 −
  • 23.
    Cos θ =x Sin θ = y Tan θ = y/x Sec θ = 1/x Csc θ = 1/y Cot θ = x/y Circular functions of multiples of 45° or π/4 Cos Sin Tan = = = √2 2 √2 2 1 Sec Csc Cot = = = √2 Coordinates: ),( 2 2 2 2 4 π 4 π 4 π 4 π 4 π 4 π 1 √2
  • 24.
  • 25.
  • 26.
  • 28.
    Circular functions ofmultiples of 60° or π/3 x y 1 60° 3 π 3 2π 3 5π 3 4π Since is in the 2nd Quadrant, its coordinates are Since is in the 3rd Quadrant, its coordinates are Since is in the 4th Quadrant, its coordinates are ),( 2 3 2 1 3 2π 3 4π 3 5π ),( 2 3 2 1 − ),( 2 3 2 1 − ),( 2 3 2 1 −−
  • 29.
    Cos θ =x Sin θ = y Tan θ = y/x Sec θ = 1/x Csc θ = 1/y Cot θ = x/y Circular functions of multiples of 60° or π/3 Cos Sin Tan = = = 1 2 Sec Csc Cot = = = 2 Coordinates: 3 π 3 π 3 π 3 π 3 π 3 π ),( 2 3 2 1 √3 2 √3 2√3 3 √3 3
  • 32.
    Exercise #1 –Part A Directions: Write True if the statement is correct; otherwise, changed the underlined word. Write your answers in a whole sheet of paper. You only have 5 minutes to answer the following. _________1. Quadrantal angles are angles whose terminal rays lies in one of the axes. _________2. (π)/2 lies in the positive x-axis. _________3. Quadrantal real numbers are numbers whose starting and terminal points lies on one of the axes. _________4. The value of cos (π) is 0. _________5. 3(π)/2 is equivalent to 360 ° . Let us Check! 1. True 2. Negative 3. Arc lengths 4. -1 5. 2(π)
  • 33.
    Exercise #1 –Part B Directions: Identify the values being asked in the following. Write your answers in a one whole sheet of paper. You only have 15 minutes to answer the following. ________1. sin(π) ________ 2. cot (2π) ________3. sec (5π/2) ________4. Csc (3 π/2) ________5. Tan (π/2) Let us Check! 1. 0 2. Undefined 3. Undefined 4. -1 5. Undefined ________6. Cos (3π) ________7. tan (6π) ________8. Sin (11/2) ________9. Sec (7π/2) ________10. Cot (4π) 6. -1 7. 0 8. -1 9. -1 10. undefined
  • 34.
    Exercises 1. sin45 +cot210 = 2. sec30+ tan 135= 3. csc630 – cot210 + tan45= 4. sin240+ cos315= 5. sin90+ cos60= Let Us Check! 1. 2. 3. 3 2 2 + 2 322 + 1 3 32 + 3 332 + 131 +−− 3− 4. 5. 2 2 2 3 +− 2 23 +− 2 1 1+ 2 3
  • 35.
    Exercises 1. sin60= 2. cot30= 3.tan150= 4. sec450= 5. csc120= 6. sin90= 1. sin60= 2. cot30= 3. tan150= 4. sec450= 5. csc120= 6. sin90= Let Us Check! 1. sin60 = 2. cot30 = 3. tan150 = 4. sec450 = 5. csc120 = 6. sin90 = √3 2 √3 √3 3 - 0 2√3 3 1