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Precalculus
Chapter 10
1
This Slideshow was developed to accompany the textbook
Precalculus
By Richard Wright
https://www.andrews.edu/~rwright/Precalculus-RLW/Text/TOC.html
Some examples and diagrams are taken from the textbook.
Slides created by
Richard Wright, Andrews Academy
rwright@andrews.edu
In this section, you will:
• Write a sequence from a rule.
• Write an explicit rule for a sequence.
• Write a recursive rule for a sequence.
• Simplify factorial expressions.
3
Sequence
List of numbers following a rule
0, 3, 6, 9, 12 <− finite (ends)
0, 3, 6, 9, 12, … <− infinite (doesn’t end)
𝑛 = 1, 2, 3, 4, 5, … (term #) like x
𝑎𝑛 = 0, 3, 6, 9, 12, … (term value) like y
4
Find the 1st 5 terms of 𝑎𝑛 = 5 + 2𝑛 −1 𝑛
5
Write the rule for the nth term.
1, 5, 9, 13, 17, …
2, -9, 28, -65, 126, …
6
Recursive Rules
Use the answer of one term to
find the next term.
𝑎𝑛 means current term
𝑎𝑛+1 means next term
Find the first 5 terms.
𝑎1 = 6
𝑎𝑛+1 = 𝑎𝑛 + 1
7
Factorial (!)
Product of a whole number
with all the whole numbers less
than it through 1.
6! = 6 ∙ 5 ∙ 4 ∙ 3 ∙ 2 ∙ 1
5! = 5 ∙ 4 ∙ 3 ∙ 2 ∙ 1
0! = 1
Simplify
9!
3!7!
8
Simplify
𝑛+1 !
𝑛!
9
In this section, you will:
• Evaluate a summation.
• Write a series as a summation.
10
Series
Sum of a sequence
Sequence
2, 4, 6, 8
Series
2 + 4 + 6 + 8
Summation Notation
(Sigma Notation)
𝑖=1
𝑛
𝑎_𝑖 = 𝑎1 + 𝑎2 + 𝑎3 + ⋯ + 𝑎𝑛
11
Find each sum
𝑖=1
4
(4𝑖 + 1) 𝑘=2
5
2 + 𝑘3
12
𝑛=1
∞
5
10𝑛
13
Shortcut formulas
1 + 1 + 1 + 1 + ⋯ =
𝑖=1
𝑛
1 = 𝑛
1 + 2 + 3 + 4 + ⋯ =
𝑖=1
𝑛
𝑖 =
𝑛 𝑛 + 1
2
1 + 4 + 9 + 16 + ⋯ =
𝑖=1
𝑛
𝑖2
=
𝑛 𝑛 + 1 2𝑛 + 1
6
14
1 + 8 + 27 + 64 + ⋯ =
𝑖=1
𝑛
𝑖3
=
𝑛2
𝑛 + 1 2
4
1 + 16 + 81 + 256 + ⋯ =
𝑖=1
𝑛
𝑖4
=
𝑛 𝑛 + 1 2𝑛 + 1 3𝑛2
+ 3𝑛 − 1
30
1 + 32 + 243 + 1024 + ⋯ =
𝑖=1
𝑛
𝑖5
=
𝑛2
𝑛 + 1 2
2𝑛2
+ 2𝑛 − 1
12
15
Evaluate
𝑖=1
5
3𝑖2
− 5𝑖
16
In this section, you will:
• Write the explicit rule for an arithmetic sequence.
• Write the recursive rule for an arithmetic sequence.
• Evaluate the sum for an arithmetic series.
17
Arithmetic
Common difference (d)
3, 7, 11, 15, 19, …
Rule for the nth term
𝑎𝑛 = 𝑑𝑛 + 𝑐
Where 𝑐 = 𝑎1 − 𝑑
𝑎𝑛 = 𝑎1 + 𝑛 − 1 𝑑
18
Find the rule for the nth term for 3, 7, 11, 15, 19, …
19
The 8th term of an arithmetic sequence is 25, and the 12th term is 41.
Write the rule for the nth term.
20
Recursive Rule for Arithmetic Sequences
𝑎1 = 𝑎1
𝑎𝑛+1 = 𝑎𝑛 + 𝑑
21
Arithmetic Series
1 + 3 + 5 + 7 + 9 + 11 + 13 + 15 + 17 + 19
1 + 3 + 5 + 7 + 9
19 + 17 + 15 + 13 + 11
20 + 20 + 20 + 20 + 20 = 5 20 = 100
𝑆𝑛 =
𝑛
2
𝑎1 + 𝑎𝑛
22
Find the sum of the integers 1 to 57.
23
Find the 50th partial sum of the arithmetic sequence -6, -2, 2, 6, …
24
Evaluate
𝑖=1
100
(3𝑖 + 2)
25
In this section, you will:
• Write the explicit rule for an geometric sequence.
• Write the recursive rule for an geometric sequence.
• Evaluate the sum for an geometric series.
26
Geometric
Common ratio (r)
1, 3, 9, 27, 81, 243, …
Rule for nth term
𝑎𝑛 = 𝑎1𝑟𝑛−1
Find the rule for 6, −2,
2
3
, …
27
The 2nd term of a geometric sequence is -18, the 5th term is 2/3. Find the
rule for the nth term.
28
Geometric Series
𝑆𝑛 = 𝑎1
1−𝑟𝑛
1−𝑟
𝑆∞ =
𝑎1
1−𝑟
Where 𝑟 < 1
Evaluate
𝑛=1
7
2𝑛−1
29
Evaluate
5 + 0.5 + 0.05 + 0.005 + ⋯
𝑛=0
∞
5
1
2
𝑛
30
In this section, you will:
• Write a proof for a sum formula using mathematical induction.
• Prove other mathematical statements using mathematical induction.
31
Proofs for sum formulas
Show it works when n = 1
Show it works for n + 1
Steps
1. Show it works for n = 1
2. Assume formula works for 𝑛 = 𝑘
3. Show it works for 𝑛 = 𝑘 + 1
If proving sum formula use 𝑆𝑘+1 = 𝑆𝑘 + 𝑎𝑘+1
32
Prove 5 + 7 + 9 + 11 + 13 + ⋯ + 3 + 2𝑛 = 𝑛 𝑛 + 4
33
Prove 1 1 − 1 + 2 2 − 1 + 3 3 − 1 + ⋯ + 𝑛 𝑛 − 1 =
𝑛 𝑛−1 𝑛+1
3
34
Prove 𝑛 + 1 ! > 2𝑛
where 𝑛 ≥ 2
35
Prove 4 is a factor of 5𝑛
− 1
36
In this section, you will:
• Evaluate combinations.
• Expand binomial expressions.
37
(x + y)0 1
(x + y)1 1x 1y
(x + y)2 1x2 2xy 1y2
(x + y)3 1x3 3x2y 3xy2 1y3
(x + y)4 1x4 4x3y 6x2y2 4xy3 1y4
Properties
1. n + 1 terms
2. Powers of x count down, y’s count up
38
3. Sum of exponents of each term = n
4. Coefficients are symmetrical
𝑛𝐶𝑟
Binomial theorem
𝑎 + 𝑏 𝑛
=
𝑟=0
𝑛
𝑛𝐶𝑟𝑎𝑛−𝑟
𝑏𝑟
Where 𝑛𝐶𝑟 =
𝑛!
𝑛−𝑟 !𝑟!
Evaluate
 9𝐶2

11
4

8
8

4
2
39
Expand 𝑥 + 2 4
40
Expand 3 − 𝑥2 5
41
Find the coefficient of the term 𝑎4
𝑏7
in 2𝑎 − 3𝑏 11
42
In this section, you will:
• Apply the fundamental counting principle
• Calculate permutations
• Calculate combinations
43
Fundamental Counting Principle
If events E1 and E2 occur in m1 and m2 ways, the number of ways both
events can occur is m1∙m2.
A lock will open with the right choice of 3 numbers. How many different
sets of 3 numbers can you choose if each number is from 1 to 30
inclusive? (a) with repetition (b) without repetition
44
How many license plates can be made if each is 2 letters follow by 4-
digits? (a) with repetition (b) without repetition
45
Permutation
Number of ways to order n objects taken r at a time
 𝑛𝑃𝑟 =
𝑛!
𝑛−𝑟 !
How many ways can 8 children line up in a row?
46
A club has 24 members, how many ways can 5 officers be selected?
47
Distinguishable Permutations
What is some objects are exactly the same?
ABB
BAB and BAB are the same eventhough the B’s were switched
We want the orders that look different (choosing all the objects)
𝑛!
𝑞1! ∙ 𝑞2! ∙ 𝑞3! ⋯
Where n = number of objects; q = how many times each is repeated
48
How many distinguishable ways to order the letters in BANANA?
49
Combinations
Grouping of objects without order
ABC is the same as BAC
𝑛𝐶𝑟 =
𝑛!
𝑛 − 𝑟 ! 𝑟!
There are 31 students. How many different groups of 4 can be made?
50
You are forming a 10-person committee from 9 women and 12 men. How
many different committees if 5 women and 5 men?
51
In this section, you will:
• Calculate simple probability
• Calculate the probability of compound events
• Calculate the probability of multiple events
• Calculate the complement of an event
52
Probability
Number from 0 to 1 indicating how likely something is to happen.
0 = never happens
1 = always happens
𝑃 𝐴 =
𝑓𝑎𝑣𝑜𝑟𝑎𝑏𝑙𝑒 𝑜𝑢𝑡𝑐𝑜𝑚𝑒𝑠
𝑡𝑜𝑡𝑎𝑙 𝑜𝑢𝑡𝑐𝑜𝑚𝑒𝑠
53
A box contains 3 red marbles, 5 black marbles, and 2 yellow marbles. If a
marble is selected at random, what is the probability of choosing yellow?
54
2 dice are rolled, what is the probability that the sum is 8?
55
1 1 2 1 3 1 4 1 5 1 6 1
1 2 2 2 3 2 4 2 5 2 6 2
1 3 2 3 3 3 4 3 5 3 6 3
1 4 2 4 3 4 4 4 5 4 6 4
1 5 2 5 3 5 4 5 5 5 6 5
1 6 2 6 3 6 4 6 5 6 6 6
Compound Events
1 event with 2 accepted outcomes
𝑃 𝐴 ∪ 𝐵 = 𝑃 𝐴 + 𝑃 𝐵 − 𝑃 𝐴 ∩ 𝐵
If 𝑃 𝐴 ∩ 𝐵 = 0, then called mutually
exclusive
56
You draw one card from a standard 52-card deck. What is the probability
of drawing a heart or red?
57
Multiple Events
Two events with 2 outcomes
Independent – Event A does not affect event B
𝑃 𝐴 𝑎𝑛𝑑 𝐵 = 𝑃 𝐴 ∙ 𝑃 𝐵
Dependent – Event A does affect event B
𝑃 𝐴 𝑎𝑛𝑑 𝐵 = 𝑃 𝐴 ∙ 𝑃 𝐵 𝐴
Where 𝑃(𝐵|𝐴) is the probability that B occurs given that A already
occured
58
You draw 2 cards from a standard 52-card deck. What is the probability
you draw a heart and a red? (a) with replacement (b) without
replacement
59
Complement
Opposite
𝑃 𝐴 = 1 − 𝑃 𝐴
At least one P(n ≥ 1) is easier with the complement never 𝑃(0)
60

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Precalculus 10 Sequences and Series.pptx

  • 2. This Slideshow was developed to accompany the textbook Precalculus By Richard Wright https://www.andrews.edu/~rwright/Precalculus-RLW/Text/TOC.html Some examples and diagrams are taken from the textbook. Slides created by Richard Wright, Andrews Academy rwright@andrews.edu
  • 3. In this section, you will: • Write a sequence from a rule. • Write an explicit rule for a sequence. • Write a recursive rule for a sequence. • Simplify factorial expressions. 3
  • 4. Sequence List of numbers following a rule 0, 3, 6, 9, 12 <− finite (ends) 0, 3, 6, 9, 12, … <− infinite (doesn’t end) 𝑛 = 1, 2, 3, 4, 5, … (term #) like x 𝑎𝑛 = 0, 3, 6, 9, 12, … (term value) like y 4
  • 5. Find the 1st 5 terms of 𝑎𝑛 = 5 + 2𝑛 −1 𝑛 5
  • 6. Write the rule for the nth term. 1, 5, 9, 13, 17, … 2, -9, 28, -65, 126, … 6
  • 7. Recursive Rules Use the answer of one term to find the next term. 𝑎𝑛 means current term 𝑎𝑛+1 means next term Find the first 5 terms. 𝑎1 = 6 𝑎𝑛+1 = 𝑎𝑛 + 1 7
  • 8. Factorial (!) Product of a whole number with all the whole numbers less than it through 1. 6! = 6 ∙ 5 ∙ 4 ∙ 3 ∙ 2 ∙ 1 5! = 5 ∙ 4 ∙ 3 ∙ 2 ∙ 1 0! = 1 Simplify 9! 3!7! 8
  • 10. In this section, you will: • Evaluate a summation. • Write a series as a summation. 10
  • 11. Series Sum of a sequence Sequence 2, 4, 6, 8 Series 2 + 4 + 6 + 8 Summation Notation (Sigma Notation) 𝑖=1 𝑛 𝑎_𝑖 = 𝑎1 + 𝑎2 + 𝑎3 + ⋯ + 𝑎𝑛 11
  • 12. Find each sum 𝑖=1 4 (4𝑖 + 1) 𝑘=2 5 2 + 𝑘3 12
  • 14. Shortcut formulas 1 + 1 + 1 + 1 + ⋯ = 𝑖=1 𝑛 1 = 𝑛 1 + 2 + 3 + 4 + ⋯ = 𝑖=1 𝑛 𝑖 = 𝑛 𝑛 + 1 2 1 + 4 + 9 + 16 + ⋯ = 𝑖=1 𝑛 𝑖2 = 𝑛 𝑛 + 1 2𝑛 + 1 6 14
  • 15. 1 + 8 + 27 + 64 + ⋯ = 𝑖=1 𝑛 𝑖3 = 𝑛2 𝑛 + 1 2 4 1 + 16 + 81 + 256 + ⋯ = 𝑖=1 𝑛 𝑖4 = 𝑛 𝑛 + 1 2𝑛 + 1 3𝑛2 + 3𝑛 − 1 30 1 + 32 + 243 + 1024 + ⋯ = 𝑖=1 𝑛 𝑖5 = 𝑛2 𝑛 + 1 2 2𝑛2 + 2𝑛 − 1 12 15
  • 17. In this section, you will: • Write the explicit rule for an arithmetic sequence. • Write the recursive rule for an arithmetic sequence. • Evaluate the sum for an arithmetic series. 17
  • 18. Arithmetic Common difference (d) 3, 7, 11, 15, 19, … Rule for the nth term 𝑎𝑛 = 𝑑𝑛 + 𝑐 Where 𝑐 = 𝑎1 − 𝑑 𝑎𝑛 = 𝑎1 + 𝑛 − 1 𝑑 18
  • 19. Find the rule for the nth term for 3, 7, 11, 15, 19, … 19
  • 20. The 8th term of an arithmetic sequence is 25, and the 12th term is 41. Write the rule for the nth term. 20
  • 21. Recursive Rule for Arithmetic Sequences 𝑎1 = 𝑎1 𝑎𝑛+1 = 𝑎𝑛 + 𝑑 21
  • 22. Arithmetic Series 1 + 3 + 5 + 7 + 9 + 11 + 13 + 15 + 17 + 19 1 + 3 + 5 + 7 + 9 19 + 17 + 15 + 13 + 11 20 + 20 + 20 + 20 + 20 = 5 20 = 100 𝑆𝑛 = 𝑛 2 𝑎1 + 𝑎𝑛 22
  • 23. Find the sum of the integers 1 to 57. 23
  • 24. Find the 50th partial sum of the arithmetic sequence -6, -2, 2, 6, … 24
  • 26. In this section, you will: • Write the explicit rule for an geometric sequence. • Write the recursive rule for an geometric sequence. • Evaluate the sum for an geometric series. 26
  • 27. Geometric Common ratio (r) 1, 3, 9, 27, 81, 243, … Rule for nth term 𝑎𝑛 = 𝑎1𝑟𝑛−1 Find the rule for 6, −2, 2 3 , … 27
  • 28. The 2nd term of a geometric sequence is -18, the 5th term is 2/3. Find the rule for the nth term. 28
  • 29. Geometric Series 𝑆𝑛 = 𝑎1 1−𝑟𝑛 1−𝑟 𝑆∞ = 𝑎1 1−𝑟 Where 𝑟 < 1 Evaluate 𝑛=1 7 2𝑛−1 29
  • 30. Evaluate 5 + 0.5 + 0.05 + 0.005 + ⋯ 𝑛=0 ∞ 5 1 2 𝑛 30
  • 31. In this section, you will: • Write a proof for a sum formula using mathematical induction. • Prove other mathematical statements using mathematical induction. 31
  • 32. Proofs for sum formulas Show it works when n = 1 Show it works for n + 1 Steps 1. Show it works for n = 1 2. Assume formula works for 𝑛 = 𝑘 3. Show it works for 𝑛 = 𝑘 + 1 If proving sum formula use 𝑆𝑘+1 = 𝑆𝑘 + 𝑎𝑘+1 32
  • 33. Prove 5 + 7 + 9 + 11 + 13 + ⋯ + 3 + 2𝑛 = 𝑛 𝑛 + 4 33
  • 34. Prove 1 1 − 1 + 2 2 − 1 + 3 3 − 1 + ⋯ + 𝑛 𝑛 − 1 = 𝑛 𝑛−1 𝑛+1 3 34
  • 35. Prove 𝑛 + 1 ! > 2𝑛 where 𝑛 ≥ 2 35
  • 36. Prove 4 is a factor of 5𝑛 − 1 36
  • 37. In this section, you will: • Evaluate combinations. • Expand binomial expressions. 37
  • 38. (x + y)0 1 (x + y)1 1x 1y (x + y)2 1x2 2xy 1y2 (x + y)3 1x3 3x2y 3xy2 1y3 (x + y)4 1x4 4x3y 6x2y2 4xy3 1y4 Properties 1. n + 1 terms 2. Powers of x count down, y’s count up 38 3. Sum of exponents of each term = n 4. Coefficients are symmetrical 𝑛𝐶𝑟
  • 39. Binomial theorem 𝑎 + 𝑏 𝑛 = 𝑟=0 𝑛 𝑛𝐶𝑟𝑎𝑛−𝑟 𝑏𝑟 Where 𝑛𝐶𝑟 = 𝑛! 𝑛−𝑟 !𝑟! Evaluate  9𝐶2  11 4  8 8  4 2 39
  • 41. Expand 3 − 𝑥2 5 41
  • 42. Find the coefficient of the term 𝑎4 𝑏7 in 2𝑎 − 3𝑏 11 42
  • 43. In this section, you will: • Apply the fundamental counting principle • Calculate permutations • Calculate combinations 43
  • 44. Fundamental Counting Principle If events E1 and E2 occur in m1 and m2 ways, the number of ways both events can occur is m1∙m2. A lock will open with the right choice of 3 numbers. How many different sets of 3 numbers can you choose if each number is from 1 to 30 inclusive? (a) with repetition (b) without repetition 44
  • 45. How many license plates can be made if each is 2 letters follow by 4- digits? (a) with repetition (b) without repetition 45
  • 46. Permutation Number of ways to order n objects taken r at a time  𝑛𝑃𝑟 = 𝑛! 𝑛−𝑟 ! How many ways can 8 children line up in a row? 46
  • 47. A club has 24 members, how many ways can 5 officers be selected? 47
  • 48. Distinguishable Permutations What is some objects are exactly the same? ABB BAB and BAB are the same eventhough the B’s were switched We want the orders that look different (choosing all the objects) 𝑛! 𝑞1! ∙ 𝑞2! ∙ 𝑞3! ⋯ Where n = number of objects; q = how many times each is repeated 48
  • 49. How many distinguishable ways to order the letters in BANANA? 49
  • 50. Combinations Grouping of objects without order ABC is the same as BAC 𝑛𝐶𝑟 = 𝑛! 𝑛 − 𝑟 ! 𝑟! There are 31 students. How many different groups of 4 can be made? 50
  • 51. You are forming a 10-person committee from 9 women and 12 men. How many different committees if 5 women and 5 men? 51
  • 52. In this section, you will: • Calculate simple probability • Calculate the probability of compound events • Calculate the probability of multiple events • Calculate the complement of an event 52
  • 53. Probability Number from 0 to 1 indicating how likely something is to happen. 0 = never happens 1 = always happens 𝑃 𝐴 = 𝑓𝑎𝑣𝑜𝑟𝑎𝑏𝑙𝑒 𝑜𝑢𝑡𝑐𝑜𝑚𝑒𝑠 𝑡𝑜𝑡𝑎𝑙 𝑜𝑢𝑡𝑐𝑜𝑚𝑒𝑠 53
  • 54. A box contains 3 red marbles, 5 black marbles, and 2 yellow marbles. If a marble is selected at random, what is the probability of choosing yellow? 54
  • 55. 2 dice are rolled, what is the probability that the sum is 8? 55 1 1 2 1 3 1 4 1 5 1 6 1 1 2 2 2 3 2 4 2 5 2 6 2 1 3 2 3 3 3 4 3 5 3 6 3 1 4 2 4 3 4 4 4 5 4 6 4 1 5 2 5 3 5 4 5 5 5 6 5 1 6 2 6 3 6 4 6 5 6 6 6
  • 56. Compound Events 1 event with 2 accepted outcomes 𝑃 𝐴 ∪ 𝐵 = 𝑃 𝐴 + 𝑃 𝐵 − 𝑃 𝐴 ∩ 𝐵 If 𝑃 𝐴 ∩ 𝐵 = 0, then called mutually exclusive 56
  • 57. You draw one card from a standard 52-card deck. What is the probability of drawing a heart or red? 57
  • 58. Multiple Events Two events with 2 outcomes Independent – Event A does not affect event B 𝑃 𝐴 𝑎𝑛𝑑 𝐵 = 𝑃 𝐴 ∙ 𝑃 𝐵 Dependent – Event A does affect event B 𝑃 𝐴 𝑎𝑛𝑑 𝐵 = 𝑃 𝐴 ∙ 𝑃 𝐵 𝐴 Where 𝑃(𝐵|𝐴) is the probability that B occurs given that A already occured 58
  • 59. You draw 2 cards from a standard 52-card deck. What is the probability you draw a heart and a red? (a) with replacement (b) without replacement 59
  • 60. Complement Opposite 𝑃 𝐴 = 1 − 𝑃 𝐴 At least one P(n ≥ 1) is easier with the complement never 𝑃(0) 60

Editor's Notes

  1. 𝑎 1 =5+2 1 −1 1 =3 𝑎 2 =5+2 2 −1 2 =9 𝑎 3 =5+2 3 −1 3 =−1 𝑎 4 =5+2 4 −1 4 =13 𝑎 5 =5+2 5 −1 5 =−5
  2. 𝑎 𝑛 =4𝑛−3 𝑎 𝑛 = −1 𝑛+1 ( 𝑛 3 +1)
  3. 𝑎 1 =6 𝑎 2 = 𝑎 1 +1=6+1=7 𝑎 3 = 𝑎 2 +1=7+1=8 𝑎 4 = 𝑎 3 +1=8+1=9 𝑎 5 = 𝑎 4 +1=9+1=10
  4. 9! 3!7! 9∙8∙7∙6∙5∙4∙3∙2∙1 3∙2∙1∙7∙6∙5∙4∙3∙2∙1 9∙8 3∙2∙1 72 6 12
  5. 𝑛+1 ! 𝑛! 𝑛+1 𝑛 𝑛−1 𝑛−2 ⋯ 𝑛 𝑛−1 𝑛−2 ⋯ 𝑛+1
  6. i = index 1 = lower limit n = upper limit
  7. 𝑖=1 4 (4𝑖+1) = 4 1 +1 + 4 2 +1 + 4 3 +1 + 4 4 +1 =5+9+13+17=44 𝑘=2 5 (2+ 𝑘 3 ) = 2+ 2 3 + 2+ 3 3 + 2+ 4 3 + 2+ 5 3 =10+29+66+27=232
  8. 𝑛=1 ∞ 5 10 𝑛 Parital sums 5 10 1 =0.5 5 10 1 + 5 10 2 =0.5+0.05=0.55 5 10 1 + 5 10 2 + 5 10 3 =0.5+0.05+0.005=0.555 5 10 1 + 5 10 2 + 5 10 3 + 5 10 4 =0.5+0.05+0.005+0.0005=0.5555 Approaches 0.55555555555…= 5 9
  9. 𝑖=1 5 3 𝑖 2 − 𝑖=1 5 5𝑖 =3 𝑛 𝑛+1 2𝑛+1 6 −5 𝑛 𝑛+1 2 =3 5 5+1 2 5 +1 6 −5 5 5+1 2 =90
  10. d = 7 – 3 = 4; 11 – 7 = 4, 15 – 11 = 4; 19 – 15 = 4 a1 = 3 𝑎 𝑛 = 𝑎 1 + 𝑛−1 𝑑 𝑎 𝑛 =3+ 𝑛−1 4 𝑎 𝑛 =3+4𝑛−4 𝑎 𝑛 =4𝑛−1
  11. 𝑎 𝑛 = 𝑎 1 + 𝑛−1 𝑑 Fill in 𝑎 8 =25 25= 𝑎 1 + 8−1 𝑑 25= 𝑎 1 +7𝑑 Fill in 𝑎 12 =41 41= 𝑎 1 + 12−1 𝑑 41= 𝑎 1 +11𝑑 Solve system of eq. −25= −𝑎 1 −7𝑑 41= 𝑎 1 +11𝑑 16= 4𝑑 4=𝑑 25= 𝑎 1 +7 4 𝑎 1 =−3 𝑎 𝑛 =−3+ 𝑛−1 4 𝑎 𝑛 =4𝑛−7
  12. 1+2+3+4+⋯+57 d = 1; a1 = 1; an = 57 𝑆 𝑛 = 𝑛 2 𝑎 1 + 𝑎 𝑛 𝑆 57 = 57 2 1+57 𝑆 57 = 57 2 58 =1653
  13. d = 4; a1 = -6 Find nth term to get an 𝑎 𝑛 = 𝑎 1 + 𝑛−1 𝑑 𝑎 𝑛 =−6+ 𝑛−1 4 𝑎 𝑛 =4𝑛−10 𝑎 50 =4 50 −10=190 Find the sum 𝑆 𝑛 = 𝑛 2 ( 𝑎 1 + 𝑎 𝑛 ) 𝑆 50 = 50 2 −6+190 =4600
  14. Linear (in form of 𝑎 𝑛 =𝑑𝑛+𝑐) so arithmetic 𝑆 𝑛 = 𝑛 2 𝑎 1 + 𝑎 𝑛 𝑆 100 = 100 2 3 1 +2 + 3 100 +2 =50 5+302 =15350
  15. 𝑟=− 2 6 =− 1 3 𝑎 𝑛 = 𝑎 1 𝑟 𝑛−1 𝑎 𝑛 =6 − 1 3 𝑛−1
  16. 𝑎 𝑛 = 𝑎 1 𝑟 𝑛−1 Fill in 𝑎 2 =−18 −18= 𝑎 1 𝑟 2−1 −18= 𝑎 1 𝑟 𝑎 1 =− 18 𝑟 Fill in 𝑎 5 = 2 3 2 3 = 𝑎 1 𝑟 5−1 2 3 = 𝑎 1 𝑟 4 Substitute 2 3 =− 18 𝑟 𝑟 4 2 3 =−18 𝑟 3 − 1 27 = 𝑟 3 − 1 3 =𝑟 Substitute − 18 − 1 3 = 𝑎 1 𝑎 1 =54 𝑎 𝑛 =54 − 1 3 𝑛−1
  17. 2 𝑛−1 is in the form 𝑎 1 𝑟 𝑛−1 where 𝑎 1 =1 and 𝑟=2 𝑆 𝑛 = 𝑎 1 1− 𝑟 𝑛 1−𝑟 𝑆 7 =1 1− 2 7 1−2 =127
  18. 𝑎 1 =5 and 𝑟= 1 10 𝑆 ∞ = 𝑎 1 1−𝑟 = 5 1− 1 10 = 5 9 10 =5 10 9 = 50 9 The lower limit is not 1, so calculate n = 0 5 1 2 0 + 𝑛=1 ∞ 5 1 2 𝑛 The exponent is not n-1, so multiply and divide by ½ 5+ 𝑛=1 ∞ 5 1 2 1 2 𝑛 1 2 5+ 𝑛=1 ∞ 5 2 1 2 𝑛−1 𝑎 1 = 5 2 and 𝑟= 1 2 𝑆 ∞ = 𝑎 1 1−𝑟 5+ 5 2 1− 1 2 5+ 5 2 1 2 5+5=10
  19. This is in the form 𝑎 1 + 𝑎 2 + 𝑎 3 +⋯+ 𝑎 𝑛 = 𝑆 𝑛 , so 𝑎 𝑛 =3+2𝑛 𝑆 𝑛 =𝑛 𝑛+4 𝑆 1 =1 1+4 =5= 𝑎 1 Assume 𝑆 𝑘 =𝑘 𝑘+4 𝑆 𝑘+1 = 𝑆 𝑘 + 𝑎 𝑘+1 𝑘+1 𝑘+1 +4 =𝑘 𝑘+4 + 3+2 𝑘+1 𝑘+1 𝑘+5 = 𝑘 2 +4𝑘+3+2𝑘+2 𝑘 2 +6𝑘+5= 𝑘 2 +6𝑘+5
  20. This is in the form 𝑎 1 + 𝑎 2 + 𝑎 3 +⋯+ 𝑎 𝑛 = 𝑆 𝑛 , so 𝑎 𝑛 =𝑛(𝑛−1) 𝑆 𝑛 = 𝑛 𝑛−1 𝑛+1 3 𝑆 1 = 1 1−1 1+1 3 =0= 𝑎 1 Assume 𝑆 𝑘 = 𝑘 𝑘−1 𝑘+1 3 𝑆 𝑘+1 = 𝑆 𝑘 + 𝑎 𝑘+1 𝑘+1 𝑘+1 −1 𝑘+1 +1 3 = 𝑘 𝑘−1 𝑘+1 3 + 𝑘+1 𝑘+1 −1 𝑘+1 𝑘 𝑘+2 3 = 𝑘 3 −𝑘 3 + 𝑘 2 +𝑘 𝑘 3 +3 𝑘 2 +2𝑘 3 = 𝑘 3 −𝑘 3 + 3 𝑘 2 3 + 3𝑘 3 𝑘 3 +3 𝑘 2 +2𝑘 3 = 𝑘 3 +3 𝑘 2 +2𝑘 3
  21. 𝑛=2: 2+1 !> 2 2 3!>4 6>4 Assume 𝑘+1 !> 2 𝑘 Show 𝑛=𝑘+1: 𝑘+1 +1 !> 2 𝑘+1 𝑘+2 !> 2 𝑘+1 𝑘+2 𝑘+1 !> 2 𝑘 ∙2 𝑘+2 >2 always and 𝑘+1 !> 2 𝑘 was true from step 2, so whole thing true.
  22. 𝑛=1: 5 1 −1=4; 4 is a factor of 4 Assume 4 is a factor of 5 𝑘 −1 𝑛=𝑘+1 5 𝑘+1 −1 5 𝑘+1 − 5 𝑘 + 5 𝑘 −1 5 𝑘 ∙5− 5 𝑘 + 5 𝑘 −1 5 𝑘 5−1 + 5 𝑘 −1 4∙ 5 𝑘 + 5 𝑘 −1 4 is factor of both 4∙ 5 𝑘 and ( 5 𝑘 −1)
  23. Rows are n starting at 0 Down to left diagonals are r starting at 0 nCr is the coefficient of the row and diagonal
  24. On TI graphing calc: MATH  PRB | nCr 9 𝐶 2 Type 9 nCr 2 = 36 11 4 = 11 C 4 =330 8 8 = 8 𝐶 8 =1 4 2 = 4 𝐶 2 =6
  25. a = x; b = 2; n = 4 𝑟=0 𝑛 𝑛 𝐶 𝑟 𝑎 𝑛−𝑟 𝑏 𝑟 4 𝐶 0 𝑥 4 2 0 + 4 𝐶 1 𝑥 3 2 1 + 4 𝐶 2 𝑥 2 2 2 + 4 𝐶 3 𝑥 1 2 3 + 4 𝐶 4 𝑥 0 2 4 1∙ 𝑥 4 ∙1+4∙ 𝑥 3 ∙2+6∙ 𝑥 2 ∙4+4∙𝑥∙8+1∙1∙16 𝑥 4 +8 𝑥 3 +24 𝑥 2 +32𝑥+16
  26. a = 3; b = − 𝑥 2 ; n = 5 𝑟=0 𝑛 𝑛 𝐶 𝑟 𝑎 𝑛−𝑟 𝑏 𝑟 5 𝐶 0 3 5 − 𝑥 2 0 + 5 𝐶 1 3 4 − 𝑥 2 1 + 5 𝐶 2 3 3 − 𝑥 2 2 + 5 𝐶 3 3 2 − 𝑥 2 3 + 5 𝐶 4 3 1 − 𝑥 2 4 + 5 𝐶 5 3 0 − 𝑥 2 5 1∙243∙1+5∙81∙ − 𝑥 2 +10∙27∙ 𝑥 4 +10∙9∙ − 𝑥 6 +5∙3∙ 𝑥 8 +1∙1∙ − 𝑥 10 243−405 𝑥 2 +270 𝑥 4 −90 𝑥 6 +15 𝑥 8 − 𝑥 10
  27. a = 2a; b = -3b; n = 11 𝑟=0 𝑛 𝑛 𝐶 𝑟 𝑎 𝑛−𝑟 𝑏 𝑟 Compare this to 𝑎 4 𝑏 7 to see that r = 7 11 𝐶 7 2𝑎 11−7 −3𝑏 7 330 16 𝑎 4 −2187 𝑏 7 −11,547,360 𝑎 4 𝑏 7 -11,547,360
  28. 30∙30∙30 = 27000 30∙29∙28 = 24360
  29. 26∙26∙10∙10∙10∙10 = 6,760,000 26∙25∙10∙9∙8∙7 = 3,276,000
  30. n = 8; r = 8 8 𝑃 8 = 8! 8−8 ! =8!=40,320
  31. Choose from 24  n=24 Actually choosing 5  r=5 24 𝑃 5 = 24! 24−5 ! = 24∙23∙22∙21∙20∙19∙18∙17∙16⋯ 19∙18∙17∙16⋯ =24∙23∙22∙21∙20 =5,100,480
  32. n=6; q1=3 (A); q2=2 (N) 6! 3!∙2! =60
  33. 31 𝐶 4 =31,465
  34. Order is not important  combination Combination of women × combination of men 9 𝐶 5 ∙ 12 𝐶 5 =99,792
  35. 𝑃 𝑌 = 𝑦𝑒𝑙𝑙𝑜𝑤 𝑡𝑜𝑡𝑎𝑙 = 2 10 = 1 5
  36. 𝑃 8 = 8 ′ 𝑠 𝑡𝑜𝑡𝑎𝑙 = 5 36
  37. 𝑃 ℎ𝑒𝑎𝑟𝑡∪𝑟𝑒𝑑 =𝑃 ℎ𝑒𝑎𝑟𝑡 +𝑃 𝑟𝑒𝑑 −𝑃 ℎ𝑒𝑎𝑟𝑡∩𝑟𝑒𝑑 = 13 52 + 26 52 − 13 52 = 26 52 = 1 2
  38. 𝑃 ℎ𝑒𝑎𝑟𝑡 𝑎𝑛𝑑 𝑟𝑒𝑑 =𝑃 ℎ𝑒𝑎𝑟𝑡 ∙𝑃 𝑟𝑒𝑑 = 13 52 ∙ 56 52 = 1 8 =0.125 𝑃 ℎ𝑒𝑎𝑟𝑡 𝑎𝑛𝑑 𝑟𝑒𝑑 =𝑃 ℎ𝑒𝑎𝑟𝑡 ∙𝑃 𝑟𝑒𝑑 ℎ𝑒𝑎𝑟𝑡 = 13 52 ∙ 25 52 =0.123