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Sketching Polynomials
Sketching Polynomials
When drawing y = P(x)
Sketching Polynomials
When drawing y = P(x)
• y intercept is the constant
e.g. y   x  1 x  1  x  2 
                            3        2



                                             y


                                         


                                         


                                         


                                         

                                                              x

                                                   

                                         


                                         


                                         


                                         


                                         
Sketching Polynomials
When drawing y = P(x)
• y intercept is the constant
• x intercepts are the roots, solve P(x)=0
e.g. y   x  1 x  1  x  2 
                            3        2



                                             y


                                         


                                         


                                         


                                         

                                                              x

                                                   

                                         


                                         


                                         


                                         


                                         
Sketching Polynomials
When drawing y = P(x)
• y intercept is the constant
• x intercepts are the roots, solve P(x)=0
• as x   , P(x) acts like the leading term
e.g. y   x  1 x  1  x  2 
                            3        2



                                             y


                                         


                                         


                                         


                                         

                                                              x

                                                   

                                         


                                         


                                         


                                         


                                         
e.g. y   x  1 x  1  x  2 
                              3        2



                                               y


graph starts here                          


                                           


                                           


                                           

                                                                x

                                                     

                                           


                                           


                                           


                                           


                                           
e.g. y   x  1 x  1  x  2 
                              3        2



                                               y


graph starts here                                          graph finishes here
                                           


                                           


                                           

                                                                      x

                                                            

                                           


                                           


                                           


                                           


                                           
Sketching Polynomials
When drawing y = P(x)
• y intercept is the constant
• x intercepts are the roots, solve P(x)=0
• as x   , P(x) acts like the leading term
• even powered roots look like        or
e.g. y   x  1 x  1  x  2 
                              3        2



                                               y


graph starts here                                          graph finishes here
                                           


                                           


                                           

                                                                      x

                                                            

                                           


                                           


                                           


                                           


                                           
e.g. y   x  1 x  1  x  2 
                              3        2



                                               y


graph starts here                                          graph finishes here
                                           


                                           


                                           

                                                                      x

                                                            

                                           


                                           


                                           


                                           


                                           
Sketching Polynomials
When drawing y = P(x)
• y intercept is the constant
• x intercepts are the roots, solve P(x)=0
• as x   , P(x) acts like the leading term
• even powered roots look like        or

• odd powered roots look like         or
e.g. y   x  1 x  1  x  2 
                              3        2



                                               y


graph starts here                                          graph finishes here
                                           


                                           


                                           

                                                                      x

                                                            

                                           


                                           


                                           


                                           


                                           
e.g. y   x  1 x  1  x  2 
                              3        2



                                               y


graph starts here                                          graph finishes here
                                           


                                           


                                           

                                                                      x

                                                            

                                           


                                           


                                           


                                           


                                           
e.g. y   x  1 x  1  x  2 
                            3        2



                                             y


                                         


                                         


                                         


                                         

                                                              x

                                                   

                                         


                                         


                                         


                                         


                                         
Sketching Polynomials
When drawing y = P(x)
• y intercept is the constant
• x intercepts are the roots, solve P(x)=0
• as x   , P(x) acts like the leading term
• even powered roots look like          or

• odd powered roots look like          or

• if the curve can be written as  x  a  , then it is a basic curve.
                                            n
(ii )  x  1  x  3  0
            2
(ii )  x  1  x  3  0
            2


                                   y




                              –3       1   x
(ii )  x  1  x  3  0
            2


                                   y




                              –3       1   x
Q: for what values of x is the
(ii )  x  1  x  3  0
            2
                                      curve below the x axis?
                                            y




                              –3                    1               x
Q: for what values of x is the
(ii )  x  1  x  3  0
            2
                                      curve below the x axis?
                                            y




                              –3                    1               x
Q: for what values of x is the
(ii )  x  1  x  3  0
            2
                                      curve below the x axis?
     x  3 or x  1                        y




                              –3                    1               x
Exercise 3B; 2, 3, 4ac, 5ac, 6bdg, 7ac, 8

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11 x1 t16 02 definite integral (2013)
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X2 t01 08 locus & complex nos 2 (2013)
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X2 t01 07 locus & complex nos 1 (2013)
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11 X1 T03 02 sketching polynomials (2010)

  • 3. Sketching Polynomials When drawing y = P(x) • y intercept is the constant
  • 4. e.g. y   x  1 x  1  x  2  3 2  y     x             
  • 5. Sketching Polynomials When drawing y = P(x) • y intercept is the constant • x intercepts are the roots, solve P(x)=0
  • 6. e.g. y   x  1 x  1  x  2  3 2  y     x             
  • 7. Sketching Polynomials When drawing y = P(x) • y intercept is the constant • x intercepts are the roots, solve P(x)=0 • as x   , P(x) acts like the leading term
  • 8. e.g. y   x  1 x  1  x  2  3 2  y     x             
  • 9. e.g. y   x  1 x  1  x  2  3 2  y graph starts here     x             
  • 10. e.g. y   x  1 x  1  x  2  3 2  y graph starts here  graph finishes here    x             
  • 11. Sketching Polynomials When drawing y = P(x) • y intercept is the constant • x intercepts are the roots, solve P(x)=0 • as x   , P(x) acts like the leading term • even powered roots look like or
  • 12. e.g. y   x  1 x  1  x  2  3 2  y graph starts here  graph finishes here    x             
  • 13. e.g. y   x  1 x  1  x  2  3 2  y graph starts here  graph finishes here    x             
  • 14. Sketching Polynomials When drawing y = P(x) • y intercept is the constant • x intercepts are the roots, solve P(x)=0 • as x   , P(x) acts like the leading term • even powered roots look like or • odd powered roots look like or
  • 15. e.g. y   x  1 x  1  x  2  3 2  y graph starts here  graph finishes here    x             
  • 16. e.g. y   x  1 x  1  x  2  3 2  y graph starts here  graph finishes here    x             
  • 17. e.g. y   x  1 x  1  x  2  3 2  y     x             
  • 18. Sketching Polynomials When drawing y = P(x) • y intercept is the constant • x intercepts are the roots, solve P(x)=0 • as x   , P(x) acts like the leading term • even powered roots look like or • odd powered roots look like or • if the curve can be written as  x  a  , then it is a basic curve. n
  • 19. (ii )  x  1  x  3  0 2
  • 20. (ii )  x  1  x  3  0 2 y –3 1 x
  • 21. (ii )  x  1  x  3  0 2 y –3 1 x
  • 22. Q: for what values of x is the (ii )  x  1  x  3  0 2 curve below the x axis? y –3 1 x
  • 23. Q: for what values of x is the (ii )  x  1  x  3  0 2 curve below the x axis? y –3 1 x
  • 24. Q: for what values of x is the (ii )  x  1  x  3  0 2 curve below the x axis? x  3 or x  1 y –3 1 x
  • 25. Exercise 3B; 2, 3, 4ac, 5ac, 6bdg, 7ac, 8