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Example 6: Find the mean of the probability
distribution.
X P(x)
0 0.2
1 0.3
2 0.2
3 0.2
4 0.1
Example 6: Find the mean of the probability
distribution.
πœ‡ = π‘₯ βˆ™ 𝑃(π‘₯)X P(x)
0 0.2
1 0.3
2 0.2
3 0.2
4 0.1
Example 6: Find the mean of the probability
distribution.
X P(x)
0 0.2
1 0.3
2 0.2
3 0.2
4 0.1
πœ‡ = π‘₯ βˆ™ 𝑃(π‘₯)
Create a column of xβˆ™P(x)
Example 6: Find the mean of the probability
distribution.
X P(x) xβˆ™P(x)
0 0.2
1 0.3
2 0.2
3 0.2
4 0.1
πœ‡ = π‘₯ βˆ™ 𝑃(π‘₯)
Create a column of xβˆ™P(x)
Example 6: Find the mean of the probability
distribution.
X P(x) xβˆ™P(x)
0 0.2 0(0.2) = 0
1 0.3
2 0.2
3 0.2
4 0.1
πœ‡ = π‘₯ βˆ™ 𝑃(π‘₯)
Create a column of xβˆ™P(x)
Example 6: Find the mean of the probability
distribution.
X P(x) xβˆ™P(x)
0 0.2 0(0.2) = 0
1 0.3 1(0.3) = 0.3
2 0.2
3 0.2
4 0.1
πœ‡ = π‘₯ βˆ™ 𝑃(π‘₯)
Create a column of xβˆ™P(x)
Example 6: Find the mean of the probability
distribution.
X P(x) xβˆ™P(x)
0 0.2 0(0.2) = 0
1 0.3 1(0.3) = 0.3
2 0.2 2(0.2) = 0.4
3 0.2
4 0.1
πœ‡ = π‘₯ βˆ™ 𝑃(π‘₯)
Create a column of xβˆ™P(x)
Example 6: Find the mean of the probability
distribution.
X P(x) xβˆ™P(x)
0 0.2 0(0.2) = 0
1 0.3 1(0.3) = 0.3
2 0.2 2(0.2) = 0.4
3 0.2 3(0.2) = 0.6
4 0.1
πœ‡ = π‘₯ βˆ™ 𝑃(π‘₯)
Create a column of xβˆ™P(x)
Example 6: Find the mean of the probability
distribution.
X P(x) xβˆ™P(x)
0 0.2 0(0.2) = 0
1 0.3 1(0.3) = 0.3
2 0.2 2(0.2) = 0.4
3 0.2 3(0.2) = 0.6
4 0.1 4(0.1) = 0.4
πœ‡ = π‘₯ βˆ™ 𝑃(π‘₯)
Create a column of xβˆ™P(x)
Example 6: Find the mean of the probability
distribution.
X P(x) xβˆ™P(x)
0 0.2 0(0.2) = 0
1 0.3 1(0.3) = 0.3
2 0.2 2(0.2) = 0.4
3 0.2 3(0.2) = 0.6
4 0.1 4(0.1) = 0.4
πœ‡ = π‘₯ βˆ™ 𝑃(π‘₯)
Sum the column of xβˆ™P(x)
Example 6: Find the mean of the probability
distribution.
X P(x) xβˆ™P(x)
0 0.2 0(0.2) = 0
1 0.3 1(0.3) = 0.3
2 0.2 2(0.2) = 0.4
3 0.2 3(0.2) = 0.6
4 0.1 4(0.1) = 0.4
πœ‡ = π‘₯ βˆ™ 𝑃(π‘₯)
Sum the column of xβˆ™P(x)
Ξ£[xβˆ™P(x)]=1.7
Example 6: Find the mean of the probability
distribution.
X P(x) xβˆ™P(x)
0 0.2 0(0.2) = 0
1 0.3 1(0.3) = 0.3
2 0.2 2(0.2) = 0.4
3 0.2 3(0.2) = 0.6
4 0.1 4(0.1) = 0.4
πœ‡ = π‘₯ βˆ™ 𝑃(π‘₯) = 1.7
Ξ£[xβˆ™P(x)]=1.7

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Mean of a discrete random variable.ppt

  • 1. Example 6: Find the mean of the probability distribution. X P(x) 0 0.2 1 0.3 2 0.2 3 0.2 4 0.1
  • 2. Example 6: Find the mean of the probability distribution. πœ‡ = π‘₯ βˆ™ 𝑃(π‘₯)X P(x) 0 0.2 1 0.3 2 0.2 3 0.2 4 0.1
  • 3. Example 6: Find the mean of the probability distribution. X P(x) 0 0.2 1 0.3 2 0.2 3 0.2 4 0.1 πœ‡ = π‘₯ βˆ™ 𝑃(π‘₯) Create a column of xβˆ™P(x)
  • 4. Example 6: Find the mean of the probability distribution. X P(x) xβˆ™P(x) 0 0.2 1 0.3 2 0.2 3 0.2 4 0.1 πœ‡ = π‘₯ βˆ™ 𝑃(π‘₯) Create a column of xβˆ™P(x)
  • 5. Example 6: Find the mean of the probability distribution. X P(x) xβˆ™P(x) 0 0.2 0(0.2) = 0 1 0.3 2 0.2 3 0.2 4 0.1 πœ‡ = π‘₯ βˆ™ 𝑃(π‘₯) Create a column of xβˆ™P(x)
  • 6. Example 6: Find the mean of the probability distribution. X P(x) xβˆ™P(x) 0 0.2 0(0.2) = 0 1 0.3 1(0.3) = 0.3 2 0.2 3 0.2 4 0.1 πœ‡ = π‘₯ βˆ™ 𝑃(π‘₯) Create a column of xβˆ™P(x)
  • 7. Example 6: Find the mean of the probability distribution. X P(x) xβˆ™P(x) 0 0.2 0(0.2) = 0 1 0.3 1(0.3) = 0.3 2 0.2 2(0.2) = 0.4 3 0.2 4 0.1 πœ‡ = π‘₯ βˆ™ 𝑃(π‘₯) Create a column of xβˆ™P(x)
  • 8. Example 6: Find the mean of the probability distribution. X P(x) xβˆ™P(x) 0 0.2 0(0.2) = 0 1 0.3 1(0.3) = 0.3 2 0.2 2(0.2) = 0.4 3 0.2 3(0.2) = 0.6 4 0.1 πœ‡ = π‘₯ βˆ™ 𝑃(π‘₯) Create a column of xβˆ™P(x)
  • 9. Example 6: Find the mean of the probability distribution. X P(x) xβˆ™P(x) 0 0.2 0(0.2) = 0 1 0.3 1(0.3) = 0.3 2 0.2 2(0.2) = 0.4 3 0.2 3(0.2) = 0.6 4 0.1 4(0.1) = 0.4 πœ‡ = π‘₯ βˆ™ 𝑃(π‘₯) Create a column of xβˆ™P(x)
  • 10. Example 6: Find the mean of the probability distribution. X P(x) xβˆ™P(x) 0 0.2 0(0.2) = 0 1 0.3 1(0.3) = 0.3 2 0.2 2(0.2) = 0.4 3 0.2 3(0.2) = 0.6 4 0.1 4(0.1) = 0.4 πœ‡ = π‘₯ βˆ™ 𝑃(π‘₯) Sum the column of xβˆ™P(x)
  • 11. Example 6: Find the mean of the probability distribution. X P(x) xβˆ™P(x) 0 0.2 0(0.2) = 0 1 0.3 1(0.3) = 0.3 2 0.2 2(0.2) = 0.4 3 0.2 3(0.2) = 0.6 4 0.1 4(0.1) = 0.4 πœ‡ = π‘₯ βˆ™ 𝑃(π‘₯) Sum the column of xβˆ™P(x) Ξ£[xβˆ™P(x)]=1.7
  • 12. Example 6: Find the mean of the probability distribution. X P(x) xβˆ™P(x) 0 0.2 0(0.2) = 0 1 0.3 1(0.3) = 0.3 2 0.2 2(0.2) = 0.4 3 0.2 3(0.2) = 0.6 4 0.1 4(0.1) = 0.4 πœ‡ = π‘₯ βˆ™ 𝑃(π‘₯) = 1.7 Ξ£[xβˆ™P(x)]=1.7