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Section 10.5
                           Parametric Surfaces

                                    Math 21a


                                February 25, 2008


       Announcements
              Problem Sessions: Monday, 8:30 (Sophie); Thursday, 7:30
              (Jeremy); SC 103b
              Office hours Tuesday, Wednesday 2–4pm SC 323.
              Mathematica assignment due February 29.

Image: Mike Baird
Outline


   Explicit versus implicit descriptions


   Easy parametrizations
      Graphs
      Planes
      Other coordinate surfaces
      Surfaces of revolution


   Other parametrizations
An implicit description of a surface is an equation satisfied by all
points in the surface.
An implicit description of a surface is an equation satisfied by all
       points in the surface.

    Example
    The unit sphere in R3 is the
    set of all points (x, y , z) such
    that

              x2 + y2 + z2 = 1




Image: dharmesh84
An explicit description of a surface is as the image of a function
r : D → R3 , where D is a subset of the plane.
An explicit description of a surface is as the image of a function
r : D → R3 , where D is a subset of the plane.
Example
    The unit sphere can be described as the image of two maps:

              r+ : D → R3 , (x, y ) → (x, y ,   1 − x 2 − y 2)
             r− : D → R3 , (x, y ) → (x, y , − 1 − x 2 − y 2 )


    Here D is the unit disk in the plane:
    D = (x, y ) x 2 + y 2 ≤ 1
An explicit description of a surface is as the image of a function
r : D → R3 , where D is a subset of the plane.
Example
    The unit sphere can be described as the image of two maps:

              r+ : D → R3 , (x, y ) → (x, y ,   1 − x 2 − y 2)
             r− : D → R3 , (x, y ) → (x, y , − 1 − x 2 − y 2 )


    Here D is the unit disk in the plane:
    D = (x, y ) x 2 + y 2 ≤ 1
    It can also be described as the image of one map

           r : I → R3 , (θ, ϕ) → (cos θ sin ϕ, sin θ sin ϕ, cos ϕ)

    Here I = [0, 2π] × [0, π].
Goals




        Given a surface, find a parametrization r of it
        Given a function r : D → R3 , find the image surface.
Outline


   Explicit versus implicit descriptions


   Easy parametrizations
      Graphs
      Planes
      Other coordinate surfaces
      Surfaces of revolution


   Other parametrizations
Parametrizing graphs


   If S is the graph of a function f : D → R, then the function can be
   used for a parametrization:

                   r : D → R3 , (x, y ) → (x, y , f (x, y ))
Parametrizing graphs


   If S is the graph of a function f : D → R, then the function can be
   used for a parametrization:

                   r : D → R3 , (x, y ) → (x, y , f (x, y ))

   The grid lines x = constant and y = constant trace out curves on
   the surface.
Parametrizing graphs


   If S is the graph of a function f : D → R, then the function can be
   used for a parametrization:

                   r : D → R3 , (x, y ) → (x, y , f (x, y ))

   The grid lines x = constant and y = constant trace out curves on
   the surface.
   Advantages/Disadvantages
       Often this is easy
       bad if f is not differentiable at points in D
       sometimes you need more than one
Planes
   An implicit description of a surface is

                              n · (r − r0 ) = 0

   A parametric description would be as the image of

                    r : R2 → R3 , (s, t) → r0 + su + tv
Planes
   An implicit description of a surface is

                              n · (r − r0 ) = 0

   A parametric description would be as the image of

                    r : R2 → R3 , (s, t) → r0 + su + tv


   Example (Worksheet problem 1)
   Write a parameterization for the plane through the point (2, −1, 3)
   containing the vectors u = 2i + 3j − k and v = i − 4j + 5k.
Planes
   An implicit description of a surface is

                              n · (r − r0 ) = 0

   A parametric description would be as the image of

                    r : R2 → R3 , (s, t) → r0 + su + tv


   Example (Worksheet problem 1)
   Write a parameterization for the plane through the point (2, −1, 3)
   containing the vectors u = 2i + 3j − k and v = i − 4j + 5k.
   Answer
   Take
             r(s, t) = 2, −1, 3 + s 2, 3, −1 + t 1, −4, 5
                    = 2 + 2s + t, −1 + 3s − 4t, 3 − s + 5t
Example
Find a parametrization for the plane x + y + z = 1.
Example
Find a parametrization for the plane x + y + z = 1.

Solution
The normal vector is n = 1, 1, 1 ; the plane passes through
(1, 0, 0). We still need two vectors perpendicular to n: 1, 1, −2
and 1, −1, 0 will work (there are other choices). We get

            r (s, t) = 1, 0, 0 + s 1, 1, −2 + t 1, −1, 0
                   = 1 + s + t, s − t, −2s

Notice that x(s, t) + y (s, t) + z(s, t) = 1 for all s and t.
Other coordinate surfaces


   The conversion from other coordinate systems to rectangular
   coordinates is a kind of parametrization.
Other coordinate surfaces


   The conversion from other coordinate systems to rectangular
   coordinates is a kind of parametrization.
   Example (Worksheet problem 2)
   Write an equation in x, y , and z for the parametric surface

                x = 3 sin s    y = 3 cos s     z = t + 1,

   where 0 ≤ s ≤ π and 0 ≤ t ≤ 1.
Other coordinate surfaces


   The conversion from other coordinate systems to rectangular
   coordinates is a kind of parametrization.
   Example (Worksheet problem 2)
   Write an equation in x, y , and z for the parametric surface

                x = 3 sin s    y = 3 cos s     z = t + 1,

   where 0 ≤ s ≤ π and 0 ≤ t ≤ 1.

   Answer
   The image is the part of the cylinder x 2 + y 2 = 9 which also has
   1 ≤ z ≤ 2 and x ≥ 0.
0
                1
                    2
                        3
                            2.0

                            1.5

                        1.0
            2
    0
2
Surfaces of revolution


   These can be parametrized by drawing circles whose radius is the
   function value.
   Example
   The graph of y = sin x on 0 ≤ x ≤ π is revolved around the x-axis.
   Find a parametrization of the the surface.
Surfaces of revolution


   These can be parametrized by drawing circles whose radius is the
   function value.
   Example
   The graph of y = sin x on 0 ≤ x ≤ π is revolved around the x-axis.
   Find a parametrization of the the surface.

   Solution
   For each x0 , a circles of radius f (x0 ) is traced out in the plane
   x = x0 . So a parametrization could be

       r → [0, π] × [0, 2π] → R3 (x, θ) → (x, f (x) cos θ, f (x) sin θ)
Outline


   Explicit versus implicit descriptions


   Easy parametrizations
      Graphs
      Planes
      Other coordinate surfaces
      Surfaces of revolution


   Other parametrizations
Rest of Worksheet problems




Image: Erick Cifuentes

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Lesson 9: Parametric Surfaces

  • 1. Section 10.5 Parametric Surfaces Math 21a February 25, 2008 Announcements Problem Sessions: Monday, 8:30 (Sophie); Thursday, 7:30 (Jeremy); SC 103b Office hours Tuesday, Wednesday 2–4pm SC 323. Mathematica assignment due February 29. Image: Mike Baird
  • 2. Outline Explicit versus implicit descriptions Easy parametrizations Graphs Planes Other coordinate surfaces Surfaces of revolution Other parametrizations
  • 3. An implicit description of a surface is an equation satisfied by all points in the surface.
  • 4. An implicit description of a surface is an equation satisfied by all points in the surface. Example The unit sphere in R3 is the set of all points (x, y , z) such that x2 + y2 + z2 = 1 Image: dharmesh84
  • 5. An explicit description of a surface is as the image of a function r : D → R3 , where D is a subset of the plane.
  • 6. An explicit description of a surface is as the image of a function r : D → R3 , where D is a subset of the plane. Example The unit sphere can be described as the image of two maps: r+ : D → R3 , (x, y ) → (x, y , 1 − x 2 − y 2) r− : D → R3 , (x, y ) → (x, y , − 1 − x 2 − y 2 ) Here D is the unit disk in the plane: D = (x, y ) x 2 + y 2 ≤ 1
  • 7. An explicit description of a surface is as the image of a function r : D → R3 , where D is a subset of the plane. Example The unit sphere can be described as the image of two maps: r+ : D → R3 , (x, y ) → (x, y , 1 − x 2 − y 2) r− : D → R3 , (x, y ) → (x, y , − 1 − x 2 − y 2 ) Here D is the unit disk in the plane: D = (x, y ) x 2 + y 2 ≤ 1 It can also be described as the image of one map r : I → R3 , (θ, ϕ) → (cos θ sin ϕ, sin θ sin ϕ, cos ϕ) Here I = [0, 2π] × [0, π].
  • 8. Goals Given a surface, find a parametrization r of it Given a function r : D → R3 , find the image surface.
  • 9. Outline Explicit versus implicit descriptions Easy parametrizations Graphs Planes Other coordinate surfaces Surfaces of revolution Other parametrizations
  • 10. Parametrizing graphs If S is the graph of a function f : D → R, then the function can be used for a parametrization: r : D → R3 , (x, y ) → (x, y , f (x, y ))
  • 11. Parametrizing graphs If S is the graph of a function f : D → R, then the function can be used for a parametrization: r : D → R3 , (x, y ) → (x, y , f (x, y )) The grid lines x = constant and y = constant trace out curves on the surface.
  • 12. Parametrizing graphs If S is the graph of a function f : D → R, then the function can be used for a parametrization: r : D → R3 , (x, y ) → (x, y , f (x, y )) The grid lines x = constant and y = constant trace out curves on the surface. Advantages/Disadvantages Often this is easy bad if f is not differentiable at points in D sometimes you need more than one
  • 13. Planes An implicit description of a surface is n · (r − r0 ) = 0 A parametric description would be as the image of r : R2 → R3 , (s, t) → r0 + su + tv
  • 14. Planes An implicit description of a surface is n · (r − r0 ) = 0 A parametric description would be as the image of r : R2 → R3 , (s, t) → r0 + su + tv Example (Worksheet problem 1) Write a parameterization for the plane through the point (2, −1, 3) containing the vectors u = 2i + 3j − k and v = i − 4j + 5k.
  • 15. Planes An implicit description of a surface is n · (r − r0 ) = 0 A parametric description would be as the image of r : R2 → R3 , (s, t) → r0 + su + tv Example (Worksheet problem 1) Write a parameterization for the plane through the point (2, −1, 3) containing the vectors u = 2i + 3j − k and v = i − 4j + 5k. Answer Take r(s, t) = 2, −1, 3 + s 2, 3, −1 + t 1, −4, 5 = 2 + 2s + t, −1 + 3s − 4t, 3 − s + 5t
  • 16. Example Find a parametrization for the plane x + y + z = 1.
  • 17. Example Find a parametrization for the plane x + y + z = 1. Solution The normal vector is n = 1, 1, 1 ; the plane passes through (1, 0, 0). We still need two vectors perpendicular to n: 1, 1, −2 and 1, −1, 0 will work (there are other choices). We get r (s, t) = 1, 0, 0 + s 1, 1, −2 + t 1, −1, 0 = 1 + s + t, s − t, −2s Notice that x(s, t) + y (s, t) + z(s, t) = 1 for all s and t.
  • 18. Other coordinate surfaces The conversion from other coordinate systems to rectangular coordinates is a kind of parametrization.
  • 19. Other coordinate surfaces The conversion from other coordinate systems to rectangular coordinates is a kind of parametrization. Example (Worksheet problem 2) Write an equation in x, y , and z for the parametric surface x = 3 sin s y = 3 cos s z = t + 1, where 0 ≤ s ≤ π and 0 ≤ t ≤ 1.
  • 20. Other coordinate surfaces The conversion from other coordinate systems to rectangular coordinates is a kind of parametrization. Example (Worksheet problem 2) Write an equation in x, y , and z for the parametric surface x = 3 sin s y = 3 cos s z = t + 1, where 0 ≤ s ≤ π and 0 ≤ t ≤ 1. Answer The image is the part of the cylinder x 2 + y 2 = 9 which also has 1 ≤ z ≤ 2 and x ≥ 0.
  • 21. 0 1 2 3 2.0 1.5 1.0 2 0 2
  • 22. Surfaces of revolution These can be parametrized by drawing circles whose radius is the function value. Example The graph of y = sin x on 0 ≤ x ≤ π is revolved around the x-axis. Find a parametrization of the the surface.
  • 23. Surfaces of revolution These can be parametrized by drawing circles whose radius is the function value. Example The graph of y = sin x on 0 ≤ x ≤ π is revolved around the x-axis. Find a parametrization of the the surface. Solution For each x0 , a circles of radius f (x0 ) is traced out in the plane x = x0 . So a parametrization could be r → [0, π] × [0, 2π] → R3 (x, θ) → (x, f (x) cos θ, f (x) sin θ)
  • 24. Outline Explicit versus implicit descriptions Easy parametrizations Graphs Planes Other coordinate surfaces Surfaces of revolution Other parametrizations
  • 25. Rest of Worksheet problems Image: Erick Cifuentes