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Lesson 19 (Section 4.1)
Related Rates
Math 1a
November 7, 2007
Announcements
OH: Mondays 1–2, Tuesdays 3–4, Wednesdays 1–3 (SC 323)
Outline
Introduction
Warmup
Strategy
Examples
Your Turn
Today we’ll look at a direct application of the chain rule to
real-world problems. Examples of these can be found whenever you
have some system or object changing, and you want to measure
the rate of change of something related to it.
Outline
Introduction
Warmup
Strategy
Examples
Your Turn
Problem
Example
An oil slick in the shape of a disk is growing. At a certain time, the
radius is 1 km and the volume is growing at the rate of 10,000
liters per second. If the slick is always 20 cm deep, how fast is the
radius of the disk growing at the same time?
A solution
The volume of the disk is
V = 2πr2
h.
We are given
dV
dt
, a certain value of r, and the object is to find
dr
dt
at that instant.
Solution
Solution
Differentiating with respect to time we have
dV
dt
= 2πrh
dr
dt
=⇒
dr
dt
=
1
2πrh
·
dV
dt
.
Now we evaluate:
dr
dt r=1000 m
=
1
2π(1 km)(20 cm)
·
10, 000 L
s
Converting every length to meters we have
dr
dt r=1 km
=
1
2π(1000 km)(0.2 cm)
·
10 m3
s
=
1
40π
m
s
Outline
Introduction
Warmup
Strategy
Examples
Your Turn
Strategies for Related Rates Problems
Strategies for Related Rates Problems
1. Read the problem.
Strategies for Related Rates Problems
1. Read the problem.
2. Draw a diagram.
Strategies for Related Rates Problems
1. Read the problem.
2. Draw a diagram.
3. Introduce notation. Give symbols to all quantities that are
functions of time (and maybe some constants)
Strategies for Related Rates Problems
1. Read the problem.
2. Draw a diagram.
3. Introduce notation. Give symbols to all quantities that are
functions of time (and maybe some constants)
4. Express the given information and the required rate in terms
of derivatives
Strategies for Related Rates Problems
1. Read the problem.
2. Draw a diagram.
3. Introduce notation. Give symbols to all quantities that are
functions of time (and maybe some constants)
4. Express the given information and the required rate in terms
of derivatives
5. Write an equation that relates the various quantities of the
problem. If necessary, use the geometry of the situation to
eliminate all but one of the variables.
Strategies for Related Rates Problems
1. Read the problem.
2. Draw a diagram.
3. Introduce notation. Give symbols to all quantities that are
functions of time (and maybe some constants)
4. Express the given information and the required rate in terms
of derivatives
5. Write an equation that relates the various quantities of the
problem. If necessary, use the geometry of the situation to
eliminate all but one of the variables.
6. Use the Chain Rule to differentiate both sides with respect to
t.
Strategies for Related Rates Problems
1. Read the problem.
2. Draw a diagram.
3. Introduce notation. Give symbols to all quantities that are
functions of time (and maybe some constants)
4. Express the given information and the required rate in terms
of derivatives
5. Write an equation that relates the various quantities of the
problem. If necessary, use the geometry of the situation to
eliminate all but one of the variables.
6. Use the Chain Rule to differentiate both sides with respect to
t.
7. Substitute the given information into the resulting equation
and solve for the unknown rate.
Outline
Introduction
Warmup
Strategy
Examples
Your Turn
Another one
Example
A man starts walking north at 4 ft/sec from a point P. Five minutes
later a woman starts walking south at 4 ft/sec from a point 500 ft
due east of P. At what rate are the people walking apart 15 min
after the woman starts walking?
Diagram
m
500
ww
500
s
4 ft/sec
4 ft/sec
s = (m + w)2 + 5002
15 minutes after the woman starts walking, the woman has traveled
4 ft
sec
60 sec
min
(15 min) = 3600 ft
while the man has traveled
4 ft
sec
60 sec
min
(20 min) = 4800 ft
We want to know
ds
dt
when m = 4800, w = 3600,
dm
dt
= 4, and
dw
dt
= 4.
Differentiation
We have
ds
dt
=
1
2
(m + w)2
+ 5002 −1/2
(2)(m + w)
dm
dt
+
dw
dt
=
m + w
s
dm
dt
+
dw
dt
At our particular point in time
ds
dt
=
672
√
7081
≈ 7.98587
Outline
Introduction
Warmup
Strategy
Examples
Your Turn
Worksheet

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Lesson 19: Related Rates

  • 1. Lesson 19 (Section 4.1) Related Rates Math 1a November 7, 2007 Announcements OH: Mondays 1–2, Tuesdays 3–4, Wednesdays 1–3 (SC 323)
  • 3. Today we’ll look at a direct application of the chain rule to real-world problems. Examples of these can be found whenever you have some system or object changing, and you want to measure the rate of change of something related to it.
  • 5. Problem Example An oil slick in the shape of a disk is growing. At a certain time, the radius is 1 km and the volume is growing at the rate of 10,000 liters per second. If the slick is always 20 cm deep, how fast is the radius of the disk growing at the same time?
  • 6.
  • 7.
  • 8. A solution The volume of the disk is V = 2πr2 h. We are given dV dt , a certain value of r, and the object is to find dr dt at that instant.
  • 9. Solution Solution Differentiating with respect to time we have dV dt = 2πrh dr dt =⇒ dr dt = 1 2πrh · dV dt . Now we evaluate: dr dt r=1000 m = 1 2π(1 km)(20 cm) · 10, 000 L s Converting every length to meters we have dr dt r=1 km = 1 2π(1000 km)(0.2 cm) · 10 m3 s = 1 40π m s
  • 11. Strategies for Related Rates Problems
  • 12. Strategies for Related Rates Problems 1. Read the problem.
  • 13. Strategies for Related Rates Problems 1. Read the problem. 2. Draw a diagram.
  • 14. Strategies for Related Rates Problems 1. Read the problem. 2. Draw a diagram. 3. Introduce notation. Give symbols to all quantities that are functions of time (and maybe some constants)
  • 15. Strategies for Related Rates Problems 1. Read the problem. 2. Draw a diagram. 3. Introduce notation. Give symbols to all quantities that are functions of time (and maybe some constants) 4. Express the given information and the required rate in terms of derivatives
  • 16. Strategies for Related Rates Problems 1. Read the problem. 2. Draw a diagram. 3. Introduce notation. Give symbols to all quantities that are functions of time (and maybe some constants) 4. Express the given information and the required rate in terms of derivatives 5. Write an equation that relates the various quantities of the problem. If necessary, use the geometry of the situation to eliminate all but one of the variables.
  • 17. Strategies for Related Rates Problems 1. Read the problem. 2. Draw a diagram. 3. Introduce notation. Give symbols to all quantities that are functions of time (and maybe some constants) 4. Express the given information and the required rate in terms of derivatives 5. Write an equation that relates the various quantities of the problem. If necessary, use the geometry of the situation to eliminate all but one of the variables. 6. Use the Chain Rule to differentiate both sides with respect to t.
  • 18. Strategies for Related Rates Problems 1. Read the problem. 2. Draw a diagram. 3. Introduce notation. Give symbols to all quantities that are functions of time (and maybe some constants) 4. Express the given information and the required rate in terms of derivatives 5. Write an equation that relates the various quantities of the problem. If necessary, use the geometry of the situation to eliminate all but one of the variables. 6. Use the Chain Rule to differentiate both sides with respect to t. 7. Substitute the given information into the resulting equation and solve for the unknown rate.
  • 20. Another one Example A man starts walking north at 4 ft/sec from a point P. Five minutes later a woman starts walking south at 4 ft/sec from a point 500 ft due east of P. At what rate are the people walking apart 15 min after the woman starts walking?
  • 22. 15 minutes after the woman starts walking, the woman has traveled 4 ft sec 60 sec min (15 min) = 3600 ft while the man has traveled 4 ft sec 60 sec min (20 min) = 4800 ft We want to know ds dt when m = 4800, w = 3600, dm dt = 4, and dw dt = 4.
  • 23. Differentiation We have ds dt = 1 2 (m + w)2 + 5002 −1/2 (2)(m + w) dm dt + dw dt = m + w s dm dt + dw dt At our particular point in time ds dt = 672 √ 7081 ≈ 7.98587