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Geometry Section 5-1 1112

The document discusses bisectors of triangles, including perpendicular bisectors and angle bisectors. It defines key terms like perpendicular bisector, concurrent lines, circumcenter, and incenter. Theorems are presented about the properties of points on perpendicular bisectors, including that they are equidistant from the endpoints of the bisected segment. Similarly, points on angle bisectors are equidistant from the sides of the bisected angle. The circumcenter and incenter are shown to be equidistant from the vertices and sides of a triangle respectively. Examples demonstrate applying the concepts.

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Chapter 5 Relationships in Triangles Tuesday, February 28, 2012
SECTION 5-1 Bisectors of Triangles Tuesday, February 28, 2012
Essential Questions How do you identify and use perpendicular bisectors in triangles? How do you identify and use angle bisectors in triangles? Tuesday, February 28, 2012
Vocabulary 1. Perpendicular Bisector: 2. Concurrent Lines: 3. Point of Concurrency: 4. Circumcenter: 5. Incenter: Tuesday, February 28, 2012
Vocabulary 1. Perpendicular Bisector: A segment that not only cuts another segment in half, but it also forms a 90° angle at the intersection 2. Concurrent Lines: 3. Point of Concurrency: 4. Circumcenter: 5. Incenter: Tuesday, February 28, 2012
Vocabulary 1. Perpendicular Bisector: A segment that not only cuts another segment in half, but it also forms a 90° angle at the intersection 2. Concurrent Lines: Three or more lines that intersect at the same point 3. Point of Concurrency: 4. Circumcenter: 5. Incenter: Tuesday, February 28, 2012
Vocabulary 1. Perpendicular Bisector: A segment that not only cuts another segment in half, but it also forms a 90° angle at the intersection 2. Concurrent Lines: Three or more lines that intersect at the same point 3. Point of Concurrency: The common point where three or more lines intersect 4. Circumcenter: 5. Incenter: Tuesday, February 28, 2012
Vocabulary 1. Perpendicular Bisector: A segment that not only cuts another segment in half, but it also forms a 90° angle at the intersection 2. Concurrent Lines: Three or more lines that intersect at the same point 3. Point of Concurrency: The common point where three or more lines intersect 4. Circumcenter: The concurrent point where the perpendicular bisectors of the sides of a triangle meet 5. Incenter: Tuesday, February 28, 2012
Vocabulary 1. Perpendicular Bisector: A segment that not only cuts another segment in half, but it also forms a 90° angle at the intersection 2. Concurrent Lines: Three or more lines that intersect at the same point 3. Point of Concurrency: The common point where three or more lines intersect 4. Circumcenter: The concurrent point where the perpendicular bisectors of the sides of a triangle meet 5. Incenter: The concurrent point where the angle bisectors of the angles of a triangle meet Tuesday, February 28, 2012
5.1 - Perpendicular Bisector Theorem If a point lies on the perpendicular bisector of a segment, the it is equidistant from the endpoints of the segment Tuesday, February 28, 2012
5.1 - Perpendicular Bisector Theorem If a point lies on the perpendicular bisector of a segment, the it is equidistant from the endpoints of the segment Tuesday, February 28, 2012
5.1 - Perpendicular Bisector Theorem If a point lies on the perpendicular bisector of a segment, the it is equidistant from the endpoints of the segment AC = BC Tuesday, February 28, 2012
5.2 - Converse of the Perpendicular Bisector Theorem If a point is equidistant from the endpoints of a segment, then it is on the perpendicular bisector of the segment Tuesday, February 28, 2012
5.2 - Converse of the Perpendicular Bisector Theorem If a point is equidistant from the endpoints of a segment, then it is on the perpendicular bisector of the segment Tuesday, February 28, 2012
5.2 - Converse of the Perpendicular Bisector Theorem If a point is equidistant from the endpoints of a segment, then it is on the perpendicular bisector of the segment If WX = WZ, then XY = ZY Tuesday, February 28, 2012
5.3 - Circumcenter Theorem The circumcenter (concurrent point where perpendicular bisectors intersect) is equidistant from the vertices of a triangle Tuesday, February 28, 2012
5.3 - Circumcenter Theorem The circumcenter (concurrent point where perpendicular bisectors intersect) is equidistant from the vertices of a triangle Tuesday, February 28, 2012
5.3 - Circumcenter Theorem The circumcenter (concurrent point where perpendicular bisectors intersect) is equidistant from the vertices of a triangle If G is the circumcenter, then GA = GB = GC Tuesday, February 28, 2012
5.4 - Angle Bisector Theorem If a point is on the bisector of an angle, then it is equidistant from the sides of the angle Tuesday, February 28, 2012
5.4 - Angle Bisector Theorem If a point is on the bisector of an angle, then it is equidistant from the sides of the angle Tuesday, February 28, 2012
5.4 - Angle Bisector Theorem If a point is on the bisector of an angle, then it is equidistant from the sides of the angle If AD bisects ∠BAC, BD ⊥ AB, and CD ⊥ AC, then BD = CD Tuesday, February 28, 2012
5.5 - Converse of the Angle Bisector Theorem If a point in the interior of an angle is equidistant from the sides of the angle, then it is on the bisector of the angle Tuesday, February 28, 2012
5.5 - Converse of the Angle Bisector Theorem If a point in the interior of an angle is equidistant from the sides of the angle, then it is on the bisector of the angle Tuesday, February 28, 2012
5.5 - Converse of the Angle Bisector Theorem If a point in the interior of an angle is equidistant from the sides of the angle, then it is on the bisector of the angle If BD ⊥ AB, CD ⊥ AC, and BD = CD, then AD bisects ∠BAC Tuesday, February 28, 2012
5.6 - Incenter Theorem The incenter (concurrent point where angle bisectors meet) is equidistant from each side of the triangle Tuesday, February 28, 2012
5.6 - Incenter Theorem The incenter (concurrent point where angle bisectors meet) is equidistant from each side of the triangle Tuesday, February 28, 2012
5.6 - Incenter Theorem The incenter (concurrent point where angle bisectors meet) is equidistant from each side of the triangle If S is the incenter of ∆MNP, then RS = TS = US Tuesday, February 28, 2012
Example 1 Find each measure. a. BC b. XY Tuesday, February 28, 2012
Example 1 Find each measure. a. BC b. XY BC = 8.5 Tuesday, February 28, 2012
Example 1 Find each measure. a. BC b. XY BC = 8.5 XY = 6 Tuesday, February 28, 2012
Example 1 Find each measure. c. PQ Tuesday, February 28, 2012
Example 1 Find each measure. c. PQ 3x + 1 = 5x − 3 Tuesday, February 28, 2012
Example 1 Find each measure. c. PQ 3x + 1 = 5x − 3 -3x -3x Tuesday, February 28, 2012
Example 1 Find each measure. c. PQ 3x + 1 = 5x − 3 -3x +3 -3x +3 Tuesday, February 28, 2012
Example 1 Find each measure. c. PQ 3x + 1 = 5x − 3 -3x +3 -3x +3 4 = 2x Tuesday, February 28, 2012
Example 1 Find each measure. c. PQ 3x + 1 = 5x − 3 -3x +3 -3x +3 4 = 2x x=2 Tuesday, February 28, 2012
Example 1 Find each measure. c. PQ 3x + 1 = 5x − 3 PQ = 3x + 1 -3x +3 -3x +3 4 = 2x x=2 Tuesday, February 28, 2012
Example 1 Find each measure. c. PQ 3x + 1 = 5x − 3 PQ = 3x + 1 -3x +3 -3x +3 PQ = 3(2) + 1 4 = 2x x=2 Tuesday, February 28, 2012
Example 1 Find each measure. c. PQ 3x + 1 = 5x − 3 PQ = 3x + 1 -3x +3 -3x +3 PQ = 3(2) + 1 4 = 2x PQ = 6 + 1 x=2 Tuesday, February 28, 2012
Example 1 Find each measure. c. PQ 3x + 1 = 5x − 3 PQ = 3x + 1 -3x +3 -3x +3 PQ = 3(2) + 1 4 = 2x PQ = 6 + 1 x=2 PQ = 7 Tuesday, February 28, 2012
Example 2 A triangular shaped garden is shown. Can a fountain be placed at the circumcenter and still be in the garden? Tuesday, February 28, 2012
Example 2 A triangular shaped garden is shown. Can a fountain be placed at the circumcenter and still be in the garden? Tuesday, February 28, 2012
Example 2 A triangular shaped garden is shown. Can a fountain be placed at the circumcenter and still be in the garden? No, it cannot Tuesday, February 28, 2012
Question If you have an obtuse triangle, where will the circumcenter be? If you have an acute triangle, where will the circumcenter be? If you have an right triangle, where will the circumcenter be? Tuesday, February 28, 2012
Question If you have an obtuse triangle, where will the circumcenter be? It will be outside the triangle If you have an acute triangle, where will the circumcenter be? If you have an right triangle, where will the circumcenter be? Tuesday, February 28, 2012
Question If you have an obtuse triangle, where will the circumcenter be? It will be outside the triangle If you have an acute triangle, where will the circumcenter be? It will be inside the triangle If you have an right triangle, where will the circumcenter be? Tuesday, February 28, 2012
Question If you have an obtuse triangle, where will the circumcenter be? It will be outside the triangle If you have an acute triangle, where will the circumcenter be? It will be inside the triangle If you have an right triangle, where will the circumcenter be? It will be on the hypotenuse of the triangle Tuesday, February 28, 2012
Example 3 Find each measure. a. DB b. m∠WYZ m∠WYX = 28° Tuesday, February 28, 2012
Example 3 Find each measure. a. DB b. m∠WYZ m∠WYX = 28° DB = 5 Tuesday, February 28, 2012
Example 3 Find each measure. a. DB b. m∠WYZ m∠WYX = 28° DB = 5 m∠WYZ = 28° Tuesday, February 28, 2012
Example 3 Find each measure. c. QS Tuesday, February 28, 2012
Example 3 Find each measure. c. QS 4x - 1 = 3x + 2 Tuesday, February 28, 2012
Example 3 Find each measure. c. QS 4x - 1 = 3x + 2 -3x -3x Tuesday, February 28, 2012
Example 3 Find each measure. c. QS 4x - 1 = 3x + 2 -3x +1 -3x +1 Tuesday, February 28, 2012
Example 3 Find each measure. c. QS 4x - 1 = 3x + 2 -3x +1 -3x +1 x=3 Tuesday, February 28, 2012
Example 3 Find each measure. c. QS 4x - 1 = 3x + 2 QS = 4x - 1 -3x +1 -3x +1 x=3 Tuesday, February 28, 2012
Example 3 Find each measure. c. QS 4x - 1 = 3x + 2 QS = 4x - 1 -3x +1 -3x +1 QS = 4(3) - 1 x=3 Tuesday, February 28, 2012
Example 3 Find each measure. c. QS 4x - 1 = 3x + 2 QS = 4x - 1 -3x +1 -3x +1 QS = 4(3) - 1 x=3 QS = 12 - 1 Tuesday, February 28, 2012
Example 3 Find each measure. c. QS 4x - 1 = 3x + 2 QS = 4x - 1 -3x +1 -3x +1 QS = 4(3) - 1 x=3 QS = 12 - 1 QS = 11 Tuesday, February 28, 2012
Example 4 Find each measure if S is the incenter of ∆MNP. a. SU Tuesday, February 28, 2012
Example 4 Find each measure if S is the incenter of ∆MNP. a. SU SU is a leg in a right triangle Tuesday, February 28, 2012
Example 4 Find each measure if S is the incenter of ∆MNP. a. SU SU is a leg in a right triangle a +b =c 2 2 2 Tuesday, February 28, 2012
Example 4 Find each measure if S is the incenter of ∆MNP. a. SU SU is a leg in a right triangle a +b =c 2 2 2 a + 8 = 10 2 2 2 Tuesday, February 28, 2012
Example 4 Find each measure if S is the incenter of ∆MNP. a. SU SU is a leg in a right triangle a +b =c 2 2 2 a + 8 = 10 2 2 2 a + 64 = 100 2 Tuesday, February 28, 2012
Example 4 Find each measure if S is the incenter of ∆MNP. a. SU SU is a leg in a right triangle a +b =c 2 2 2 a + 8 = 10 2 2 2 a + 64 = 100 2 a = 36 2 Tuesday, February 28, 2012
Example 4 Find each measure if S is the incenter of ∆MNP. a. SU SU is a leg in a right triangle a +b =c 2 2 2 a + 8 = 10 2 2 2 a + 64 = 100 2 a = 36 2 a=6 Tuesday, February 28, 2012
Example 4 Find each measure if S is the incenter of ∆MNP. a. SU SU is a leg in a right triangle a +b =c 2 2 2 a + 8 = 10 2 2 2 a + 64 = 100 2 a = 36 2 a=6 SU = 6 Tuesday, February 28, 2012
Example 4 Find each measure if S is the incenter of ∆MNP. b. m∠SPU Tuesday, February 28, 2012
Example 4 Find each measure if S is the incenter of ∆MNP. b. m∠SPU An incenter is created at the concurrent point of the angle bisectors Tuesday, February 28, 2012
Example 4 Find each measure if S is the incenter of ∆MNP. b. m∠SPU An incenter is created at the concurrent point of the angle bisectors m∠MNP = 28 + 28 = 56° Tuesday, February 28, 2012
Example 4 Find each measure if S is the incenter of ∆MNP. b. m∠SPU An incenter is created at the concurrent point of the angle bisectors m∠MNP = 28 + 28 = 56° m∠NMP = 31 + 31 = 62° Tuesday, February 28, 2012
Example 4 Find each measure if S is the incenter of ∆MNP. b. m∠SPU An incenter is created at the concurrent point of the angle bisectors m∠MNP = 28 + 28 = 56° m∠NMP = 31 + 31 = 62° m∠MPN = 180 − 62 − 56 = 62° Tuesday, February 28, 2012
Example 4 Find each measure if S is the incenter of ∆MNP. b. m∠SPU An incenter is created at the concurrent point of the angle bisectors m∠MNP = 28 + 28 = 56° m∠NMP = 31 + 31 = 62° m∠MPN = 180 − 62 − 56 = 62° 1 m∠SPU = (62) = 31° 2 Tuesday, February 28, 2012
Example 4 Find each measure if S is the incenter of ∆MNP. b. m∠SPU An incenter is created at the concurrent point of the angle bisectors m∠MNP = 28 + 28 = 56° m∠NMP = 31 + 31 = 62° m∠MPN = 180 − 62 − 56 = 62° 1 m∠SPU = (62) = 31° 2 Check: 28 + 28 + 31 + 31 + 31 + 31 = 180 Tuesday, February 28, 2012
Check Your Understading Make sure to review p. 327 #1-8 Tuesday, February 28, 2012
Problem Set Tuesday, February 28, 2012
Problem Set p. 327 #9-29 odd, 48 "Great opportunities to help others seldom come, but small ones surround us every day." - Sally Koch Tuesday, February 28, 2012

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Geometry Section 5-1 1112

  • 1.
    Chapter 5 Relationships in Triangles Tuesday, February 28, 2012
  • 2.
    SECTION 5-1 Bisectors of Triangles Tuesday, February 28, 2012
  • 3.
    Essential Questions How do you identify and use perpendicular bisectors in triangles? How do you identify and use angle bisectors in triangles? Tuesday, February 28, 2012
  • 4.
    Vocabulary 1. Perpendicular Bisector: 2. Concurrent Lines: 3. Point of Concurrency: 4. Circumcenter: 5. Incenter: Tuesday, February 28, 2012
  • 5.
    Vocabulary 1. Perpendicular Bisector: A segment that not only cuts another segment in half, but it also forms a 90° angle at the intersection 2. Concurrent Lines: 3. Point of Concurrency: 4. Circumcenter: 5. Incenter: Tuesday, February 28, 2012
  • 6.
    Vocabulary 1. Perpendicular Bisector: A segment that not only cuts another segment in half, but it also forms a 90° angle at the intersection 2. Concurrent Lines: Three or more lines that intersect at the same point 3. Point of Concurrency: 4. Circumcenter: 5. Incenter: Tuesday, February 28, 2012
  • 7.
    Vocabulary 1. Perpendicular Bisector: A segment that not only cuts another segment in half, but it also forms a 90° angle at the intersection 2. Concurrent Lines: Three or more lines that intersect at the same point 3. Point of Concurrency: The common point where three or more lines intersect 4. Circumcenter: 5. Incenter: Tuesday, February 28, 2012
  • 8.
    Vocabulary 1. Perpendicular Bisector: A segment that not only cuts another segment in half, but it also forms a 90° angle at the intersection 2. Concurrent Lines: Three or more lines that intersect at the same point 3. Point of Concurrency: The common point where three or more lines intersect 4. Circumcenter: The concurrent point where the perpendicular bisectors of the sides of a triangle meet 5. Incenter: Tuesday, February 28, 2012
  • 9.
    Vocabulary 1. Perpendicular Bisector: A segment that not only cuts another segment in half, but it also forms a 90° angle at the intersection 2. Concurrent Lines: Three or more lines that intersect at the same point 3. Point of Concurrency: The common point where three or more lines intersect 4. Circumcenter: The concurrent point where the perpendicular bisectors of the sides of a triangle meet 5. Incenter: The concurrent point where the angle bisectors of the angles of a triangle meet Tuesday, February 28, 2012
  • 10.
    5.1 - PerpendicularBisector Theorem If a point lies on the perpendicular bisector of a segment, the it is equidistant from the endpoints of the segment Tuesday, February 28, 2012
  • 11.
    5.1 - PerpendicularBisector Theorem If a point lies on the perpendicular bisector of a segment, the it is equidistant from the endpoints of the segment Tuesday, February 28, 2012
  • 12.
    5.1 - PerpendicularBisector Theorem If a point lies on the perpendicular bisector of a segment, the it is equidistant from the endpoints of the segment AC = BC Tuesday, February 28, 2012
  • 13.
    5.2 - Converseof the Perpendicular Bisector Theorem If a point is equidistant from the endpoints of a segment, then it is on the perpendicular bisector of the segment Tuesday, February 28, 2012
  • 14.
    5.2 - Converseof the Perpendicular Bisector Theorem If a point is equidistant from the endpoints of a segment, then it is on the perpendicular bisector of the segment Tuesday, February 28, 2012
  • 15.
    5.2 - Converseof the Perpendicular Bisector Theorem If a point is equidistant from the endpoints of a segment, then it is on the perpendicular bisector of the segment If WX = WZ, then XY = ZY Tuesday, February 28, 2012
  • 16.
    5.3 - Circumcenter Theorem The circumcenter (concurrent point where perpendicular bisectors intersect) is equidistant from the vertices of a triangle Tuesday, February 28, 2012
  • 17.
    5.3 - Circumcenter Theorem The circumcenter (concurrent point where perpendicular bisectors intersect) is equidistant from the vertices of a triangle Tuesday, February 28, 2012
  • 18.
    5.3 - Circumcenter Theorem The circumcenter (concurrent point where perpendicular bisectors intersect) is equidistant from the vertices of a triangle If G is the circumcenter, then GA = GB = GC Tuesday, February 28, 2012
  • 19.
    5.4 - AngleBisector Theorem If a point is on the bisector of an angle, then it is equidistant from the sides of the angle Tuesday, February 28, 2012
  • 20.
    5.4 - AngleBisector Theorem If a point is on the bisector of an angle, then it is equidistant from the sides of the angle Tuesday, February 28, 2012
  • 21.
    5.4 - AngleBisector Theorem If a point is on the bisector of an angle, then it is equidistant from the sides of the angle If AD bisects ∠BAC, BD ⊥ AB, and CD ⊥ AC, then BD = CD Tuesday, February 28, 2012
  • 22.
    5.5 - Converseof the Angle Bisector Theorem If a point in the interior of an angle is equidistant from the sides of the angle, then it is on the bisector of the angle Tuesday, February 28, 2012
  • 23.
    5.5 - Converseof the Angle Bisector Theorem If a point in the interior of an angle is equidistant from the sides of the angle, then it is on the bisector of the angle Tuesday, February 28, 2012
  • 24.
    5.5 - Converseof the Angle Bisector Theorem If a point in the interior of an angle is equidistant from the sides of the angle, then it is on the bisector of the angle If BD ⊥ AB, CD ⊥ AC, and BD = CD, then AD bisects ∠BAC Tuesday, February 28, 2012
  • 25.
    5.6 - IncenterTheorem The incenter (concurrent point where angle bisectors meet) is equidistant from each side of the triangle Tuesday, February 28, 2012
  • 26.
    5.6 - IncenterTheorem The incenter (concurrent point where angle bisectors meet) is equidistant from each side of the triangle Tuesday, February 28, 2012
  • 27.
    5.6 - IncenterTheorem The incenter (concurrent point where angle bisectors meet) is equidistant from each side of the triangle If S is the incenter of ∆MNP, then RS = TS = US Tuesday, February 28, 2012
  • 28.
    Example 1 Find each measure. a. BC b. XY Tuesday, February 28, 2012
  • 29.
    Example 1 Find each measure. a. BC b. XY BC = 8.5 Tuesday, February 28, 2012
  • 30.
    Example 1 Find each measure. a. BC b. XY BC = 8.5 XY = 6 Tuesday, February 28, 2012
  • 31.
    Example 1 Find each measure. c. PQ Tuesday, February 28, 2012
  • 32.
    Example 1 Find each measure. c. PQ 3x + 1 = 5x − 3 Tuesday, February 28, 2012
  • 33.
    Example 1 Find each measure. c. PQ 3x + 1 = 5x − 3 -3x -3x Tuesday, February 28, 2012
  • 34.
    Example 1 Find each measure. c. PQ 3x + 1 = 5x − 3 -3x +3 -3x +3 Tuesday, February 28, 2012
  • 35.
    Example 1 Find each measure. c. PQ 3x + 1 = 5x − 3 -3x +3 -3x +3 4 = 2x Tuesday, February 28, 2012
  • 36.
    Example 1 Find each measure. c. PQ 3x + 1 = 5x − 3 -3x +3 -3x +3 4 = 2x x=2 Tuesday, February 28, 2012
  • 37.
    Example 1 Find each measure. c. PQ 3x + 1 = 5x − 3 PQ = 3x + 1 -3x +3 -3x +3 4 = 2x x=2 Tuesday, February 28, 2012
  • 38.
    Example 1 Find each measure. c. PQ 3x + 1 = 5x − 3 PQ = 3x + 1 -3x +3 -3x +3 PQ = 3(2) + 1 4 = 2x x=2 Tuesday, February 28, 2012
  • 39.
    Example 1 Find each measure. c. PQ 3x + 1 = 5x − 3 PQ = 3x + 1 -3x +3 -3x +3 PQ = 3(2) + 1 4 = 2x PQ = 6 + 1 x=2 Tuesday, February 28, 2012
  • 40.
    Example 1 Find each measure. c. PQ 3x + 1 = 5x − 3 PQ = 3x + 1 -3x +3 -3x +3 PQ = 3(2) + 1 4 = 2x PQ = 6 + 1 x=2 PQ = 7 Tuesday, February 28, 2012
  • 41.
    Example 2 A triangular shaped garden is shown. Can a fountain be placed at the circumcenter and still be in the garden? Tuesday, February 28, 2012
  • 42.
    Example 2 A triangular shaped garden is shown. Can a fountain be placed at the circumcenter and still be in the garden? Tuesday, February 28, 2012
  • 43.
    Example 2 A triangular shaped garden is shown. Can a fountain be placed at the circumcenter and still be in the garden? No, it cannot Tuesday, February 28, 2012
  • 44.
    Question If you have an obtuse triangle, where will the circumcenter be? If you have an acute triangle, where will the circumcenter be? If you have an right triangle, where will the circumcenter be? Tuesday, February 28, 2012
  • 45.
    Question If you have an obtuse triangle, where will the circumcenter be? It will be outside the triangle If you have an acute triangle, where will the circumcenter be? If you have an right triangle, where will the circumcenter be? Tuesday, February 28, 2012
  • 46.
    Question If you have an obtuse triangle, where will the circumcenter be? It will be outside the triangle If you have an acute triangle, where will the circumcenter be? It will be inside the triangle If you have an right triangle, where will the circumcenter be? Tuesday, February 28, 2012
  • 47.
    Question If you have an obtuse triangle, where will the circumcenter be? It will be outside the triangle If you have an acute triangle, where will the circumcenter be? It will be inside the triangle If you have an right triangle, where will the circumcenter be? It will be on the hypotenuse of the triangle Tuesday, February 28, 2012
  • 48.
    Example 3 Find each measure. a. DB b. m∠WYZ m∠WYX = 28° Tuesday, February 28, 2012
  • 49.
    Example 3 Find each measure. a. DB b. m∠WYZ m∠WYX = 28° DB = 5 Tuesday, February 28, 2012
  • 50.
    Example 3 Find each measure. a. DB b. m∠WYZ m∠WYX = 28° DB = 5 m∠WYZ = 28° Tuesday, February 28, 2012
  • 51.
    Example 3 Find each measure. c. QS Tuesday, February 28, 2012
  • 52.
    Example 3 Find each measure. c. QS 4x - 1 = 3x + 2 Tuesday, February 28, 2012
  • 53.
    Example 3 Find each measure. c. QS 4x - 1 = 3x + 2 -3x -3x Tuesday, February 28, 2012
  • 54.
    Example 3 Find each measure. c. QS 4x - 1 = 3x + 2 -3x +1 -3x +1 Tuesday, February 28, 2012
  • 55.
    Example 3 Find each measure. c. QS 4x - 1 = 3x + 2 -3x +1 -3x +1 x=3 Tuesday, February 28, 2012
  • 56.
    Example 3 Find each measure. c. QS 4x - 1 = 3x + 2 QS = 4x - 1 -3x +1 -3x +1 x=3 Tuesday, February 28, 2012
  • 57.
    Example 3 Find each measure. c. QS 4x - 1 = 3x + 2 QS = 4x - 1 -3x +1 -3x +1 QS = 4(3) - 1 x=3 Tuesday, February 28, 2012
  • 58.
    Example 3 Find each measure. c. QS 4x - 1 = 3x + 2 QS = 4x - 1 -3x +1 -3x +1 QS = 4(3) - 1 x=3 QS = 12 - 1 Tuesday, February 28, 2012
  • 59.
    Example 3 Find each measure. c. QS 4x - 1 = 3x + 2 QS = 4x - 1 -3x +1 -3x +1 QS = 4(3) - 1 x=3 QS = 12 - 1 QS = 11 Tuesday, February 28, 2012
  • 60.
    Example 4 Find each measure if S is the incenter of ∆MNP. a. SU Tuesday, February 28, 2012
  • 61.
    Example 4 Find each measure if S is the incenter of ∆MNP. a. SU SU is a leg in a right triangle Tuesday, February 28, 2012
  • 62.
    Example 4 Find each measure if S is the incenter of ∆MNP. a. SU SU is a leg in a right triangle a +b =c 2 2 2 Tuesday, February 28, 2012
  • 63.
    Example 4 Find each measure if S is the incenter of ∆MNP. a. SU SU is a leg in a right triangle a +b =c 2 2 2 a + 8 = 10 2 2 2 Tuesday, February 28, 2012
  • 64.
    Example 4 Find each measure if S is the incenter of ∆MNP. a. SU SU is a leg in a right triangle a +b =c 2 2 2 a + 8 = 10 2 2 2 a + 64 = 100 2 Tuesday, February 28, 2012
  • 65.
    Example 4 Find each measure if S is the incenter of ∆MNP. a. SU SU is a leg in a right triangle a +b =c 2 2 2 a + 8 = 10 2 2 2 a + 64 = 100 2 a = 36 2 Tuesday, February 28, 2012
  • 66.
    Example 4 Find each measure if S is the incenter of ∆MNP. a. SU SU is a leg in a right triangle a +b =c 2 2 2 a + 8 = 10 2 2 2 a + 64 = 100 2 a = 36 2 a=6 Tuesday, February 28, 2012
  • 67.
    Example 4 Find each measure if S is the incenter of ∆MNP. a. SU SU is a leg in a right triangle a +b =c 2 2 2 a + 8 = 10 2 2 2 a + 64 = 100 2 a = 36 2 a=6 SU = 6 Tuesday, February 28, 2012
  • 68.
    Example 4 Find each measure if S is the incenter of ∆MNP. b. m∠SPU Tuesday, February 28, 2012
  • 69.
    Example 4 Find each measure if S is the incenter of ∆MNP. b. m∠SPU An incenter is created at the concurrent point of the angle bisectors Tuesday, February 28, 2012
  • 70.
    Example 4 Find each measure if S is the incenter of ∆MNP. b. m∠SPU An incenter is created at the concurrent point of the angle bisectors m∠MNP = 28 + 28 = 56° Tuesday, February 28, 2012
  • 71.
    Example 4 Find each measure if S is the incenter of ∆MNP. b. m∠SPU An incenter is created at the concurrent point of the angle bisectors m∠MNP = 28 + 28 = 56° m∠NMP = 31 + 31 = 62° Tuesday, February 28, 2012
  • 72.
    Example 4 Find each measure if S is the incenter of ∆MNP. b. m∠SPU An incenter is created at the concurrent point of the angle bisectors m∠MNP = 28 + 28 = 56° m∠NMP = 31 + 31 = 62° m∠MPN = 180 − 62 − 56 = 62° Tuesday, February 28, 2012
  • 73.
    Example 4 Find each measure if S is the incenter of ∆MNP. b. m∠SPU An incenter is created at the concurrent point of the angle bisectors m∠MNP = 28 + 28 = 56° m∠NMP = 31 + 31 = 62° m∠MPN = 180 − 62 − 56 = 62° 1 m∠SPU = (62) = 31° 2 Tuesday, February 28, 2012
  • 74.
    Example 4 Find each measure if S is the incenter of ∆MNP. b. m∠SPU An incenter is created at the concurrent point of the angle bisectors m∠MNP = 28 + 28 = 56° m∠NMP = 31 + 31 = 62° m∠MPN = 180 − 62 − 56 = 62° 1 m∠SPU = (62) = 31° 2 Check: 28 + 28 + 31 + 31 + 31 + 31 = 180 Tuesday, February 28, 2012
  • 75.
    Check Your Understading Make sure to review p. 327 #1-8 Tuesday, February 28, 2012
  • 76.
  • 77.
    Problem Set p. 327 #9-29 odd, 48 "Great opportunities to help others seldom come, but small ones surround us every day." - Sally Koch Tuesday, February 28, 2012