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Section 9-9
Advanced Factoring Techniques
Warm-up
                   Factor.

1. 2x + 3x + x
    3    2
                             2. 2x + 2x + x + x
                                 3    2   2
Warm-up
                   Factor.

1. 2x + 3x + x
    3    2
                             2. 2x + 2x + x + x
                                 3    2   2




x(2x + 3x + 1)
    2
Warm-up
                      Factor.

1. 2x + 3x + x
     3     2
                                2. 2x + 2x + x + x
                                    3    2   2




x(2x + 3x + 1)
     2




x(2x + 1)( x + 1)
Warm-up
                      Factor.

1. 2x + 3x + x
     3     2
                                2. 2x + 2x + x + x
                                       3       2       2



                                (2x + 2x ) + ( x + x )
                                   3       2       2


x(2x + 3x + 1)
     2




x(2x + 1)( x + 1)
Warm-up
                      Factor.

1. 2x + 3x + x
     3     2
                                2. 2x + 2x + x + x
                                       3       2       2



                                (2x + 2x ) + ( x + x )
                                   3       2       2


x(2x + 3x + 1)
     2

                                2x ( x + 1) + x( x + 1)
                                   2




x(2x + 1)( x + 1)
Warm-up
                      Factor.

1. 2x + 3x + x
     3     2
                                2. 2x + 2x + x + x
                                       3           2       2



                                (2x + 2x ) + ( x + x )
                                   3           2       2


x(2x + 3x + 1)
     2

                                2x ( x + 1) + x( x + 1)
                                   2



                                   (2x + x )( x + 1)
                                           2

x(2x + 1)( x + 1)
Warm-up
                      Factor.

1. 2x + 3x + x
     3     2
                                2. 2x + 2x + x + x
                                       3           2       2



                                (2x + 2x ) + ( x + x )
                                   3           2       2


x(2x + 3x + 1)
     2

                                2x ( x + 1) + x( x + 1)
                                   2



                                   (2x + x )( x + 1)
                                           2

x(2x + 1)( x + 1)
                                   x(2x + 1)( x + 1)
Factoring by Grouping
Factoring by Grouping


Grouping terms with common factors, then factoring out the
             GCF and applying distribution
Factoring by Grouping


Grouping terms with common factors, then factoring out the
              GCF and applying distribution
     ...you know, like we do with factoring quadratics
Example 1
        Factor

6a b + 2ac + 3ab + bc
  2              2
Example 1
             Factor

 6a b + 2ac + 3ab + bc
       2              2




(6a b + 2ac) + (3ab + bc)
   2                      2
Example 1
             Factor

 6a b + 2ac + 3ab + bc
       2              2




(6a b + 2ac) + (3ab + bc)
   2                      2




 2a(3ab + c) + b(3ab + c)
Example 1
             Factor

 6a b + 2ac + 3ab + bc
       2              2




(6a b + 2ac) + (3ab + bc)
   2                      2




 2a(3ab + c) + b(3ab + c)

       (3ab + c)(2a + b)
Example 2
      Factor

4x + 4x − 15
  2
Example 2
          Factor

  4x + 4x − 15
      2



4x + 10x − 6x − 15
  2
Example 2
               Factor

       4x + 4x − 15
           2



 4x + 10x − 6x − 15
       2



(4x + 10x ) + (−6x − 15)
   2
Example 2
               Factor

       4x + 4x − 15
           2



  4x + 10x − 6x − 15
       2



(4x + 10x ) + (−6x − 15)
   2



2x(2x + 5) − 3(2x − 5)
Example 2
               Factor

       4x + 4x − 15
           2



  4x + 10x − 6x − 15
       2



(4x + 10x ) + (−6x − 15)
   2



2x(2x + 5) − 3(2x − 5)
   (2x − 3)(2x + 5)
Factoring by Grouping and
        Graphing
Factoring by Grouping and
              Graphing


Factoring into linear factors and graphing to see possible
                         solutions
Example 3
Describe the set of ordered pairs (x, y) satisfying
            x + 3x − yx − 3 y = 0
              3      2
Example 3
Describe the set of ordered pairs (x, y) satisfying
            x + 3x − yx − 3 y = 0
              3      2


         ( x + 3x ) + (− yx − 3 y) = 0
            3    2
Example 3
Describe the set of ordered pairs (x, y) satisfying
            x + 3x − yx − 3 y = 0
              3      2


         ( x + 3x ) + (− yx − 3 y) = 0
            3    2


            x ( x + 3) − y( x + 3) = 0
             2
Example 3
Describe the set of ordered pairs (x, y) satisfying
            x + 3x − yx − 3 y = 0
              3        2


         ( x + 3x ) + (− yx − 3 y) = 0
            3    2


            x ( x + 3) − y( x + 3) = 0
             2


                 ( x − y)( x + 3) = 0
                   2
Example 3
Describe the set of ordered pairs (x, y) satisfying
            x + 3x − yx − 3 y = 0
                3         2


         ( x + 3x ) + (− yx − 3 y) = 0
            3    2


            x ( x + 3) − y( x + 3) = 0
                2


                    ( x − y)( x + 3) = 0
                      2


          x − y=0
            2
Example 3
Describe the set of ordered pairs (x, y) satisfying
            x + 3x − yx − 3 y = 0
                3         2


         ( x + 3x ) + (− yx − 3 y) = 0
            3    2


            x ( x + 3) − y( x + 3) = 0
                2


                    ( x − y)( x + 3) = 0
                      2


          x − y=0
            2
                                 x+3=0
Example 3
Describe the set of ordered pairs (x, y) satisfying
            x + 3x − yx − 3 y = 0
                3             2


         ( x + 3x ) + (− yx − 3 y) = 0
            3    2


            x ( x + 3) − y( x + 3) = 0
                2


                    ( x − y)( x + 3) = 0
                      2


          x − y=0
            2
                                  x+3=0
                y= x      2
Example 3
Describe the set of ordered pairs (x, y) satisfying
            x + 3x − yx − 3 y = 0
                3             2


         ( x + 3x ) + (− yx − 3 y) = 0
            3    2


            x ( x + 3) − y( x + 3) = 0
                2


                    ( x − y)( x + 3) = 0
                      2


          x − y=0
            2
                                  x+3=0
                y= x      2        x=3
Example 3
       Describe the set of ordered pairs (x, y) satisfying
                    x + 3x − yx − 3 y = 0
                        3             2


                 ( x + 3x ) + (− yx − 3 y) = 0
                    3    2


                    x ( x + 3) − y( x + 3) = 0
                        2


                            ( x − y)( x + 3) = 0
                              2


                  x − y=0
                    2
                                          x+3=0
                        y= x      2        x=3

The union of the sets of ordered pairs satisfying y = x2 and x = 3.
Homework
Homework



 p. 610 #1-17

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9-9 Notes

  • 2. Warm-up Factor. 1. 2x + 3x + x 3 2 2. 2x + 2x + x + x 3 2 2
  • 3. Warm-up Factor. 1. 2x + 3x + x 3 2 2. 2x + 2x + x + x 3 2 2 x(2x + 3x + 1) 2
  • 4. Warm-up Factor. 1. 2x + 3x + x 3 2 2. 2x + 2x + x + x 3 2 2 x(2x + 3x + 1) 2 x(2x + 1)( x + 1)
  • 5. Warm-up Factor. 1. 2x + 3x + x 3 2 2. 2x + 2x + x + x 3 2 2 (2x + 2x ) + ( x + x ) 3 2 2 x(2x + 3x + 1) 2 x(2x + 1)( x + 1)
  • 6. Warm-up Factor. 1. 2x + 3x + x 3 2 2. 2x + 2x + x + x 3 2 2 (2x + 2x ) + ( x + x ) 3 2 2 x(2x + 3x + 1) 2 2x ( x + 1) + x( x + 1) 2 x(2x + 1)( x + 1)
  • 7. Warm-up Factor. 1. 2x + 3x + x 3 2 2. 2x + 2x + x + x 3 2 2 (2x + 2x ) + ( x + x ) 3 2 2 x(2x + 3x + 1) 2 2x ( x + 1) + x( x + 1) 2 (2x + x )( x + 1) 2 x(2x + 1)( x + 1)
  • 8. Warm-up Factor. 1. 2x + 3x + x 3 2 2. 2x + 2x + x + x 3 2 2 (2x + 2x ) + ( x + x ) 3 2 2 x(2x + 3x + 1) 2 2x ( x + 1) + x( x + 1) 2 (2x + x )( x + 1) 2 x(2x + 1)( x + 1) x(2x + 1)( x + 1)
  • 10. Factoring by Grouping Grouping terms with common factors, then factoring out the GCF and applying distribution
  • 11. Factoring by Grouping Grouping terms with common factors, then factoring out the GCF and applying distribution ...you know, like we do with factoring quadratics
  • 12. Example 1 Factor 6a b + 2ac + 3ab + bc 2 2
  • 13. Example 1 Factor 6a b + 2ac + 3ab + bc 2 2 (6a b + 2ac) + (3ab + bc) 2 2
  • 14. Example 1 Factor 6a b + 2ac + 3ab + bc 2 2 (6a b + 2ac) + (3ab + bc) 2 2 2a(3ab + c) + b(3ab + c)
  • 15. Example 1 Factor 6a b + 2ac + 3ab + bc 2 2 (6a b + 2ac) + (3ab + bc) 2 2 2a(3ab + c) + b(3ab + c) (3ab + c)(2a + b)
  • 16. Example 2 Factor 4x + 4x − 15 2
  • 17. Example 2 Factor 4x + 4x − 15 2 4x + 10x − 6x − 15 2
  • 18. Example 2 Factor 4x + 4x − 15 2 4x + 10x − 6x − 15 2 (4x + 10x ) + (−6x − 15) 2
  • 19. Example 2 Factor 4x + 4x − 15 2 4x + 10x − 6x − 15 2 (4x + 10x ) + (−6x − 15) 2 2x(2x + 5) − 3(2x − 5)
  • 20. Example 2 Factor 4x + 4x − 15 2 4x + 10x − 6x − 15 2 (4x + 10x ) + (−6x − 15) 2 2x(2x + 5) − 3(2x − 5) (2x − 3)(2x + 5)
  • 21. Factoring by Grouping and Graphing
  • 22. Factoring by Grouping and Graphing Factoring into linear factors and graphing to see possible solutions
  • 23. Example 3 Describe the set of ordered pairs (x, y) satisfying x + 3x − yx − 3 y = 0 3 2
  • 24. Example 3 Describe the set of ordered pairs (x, y) satisfying x + 3x − yx − 3 y = 0 3 2 ( x + 3x ) + (− yx − 3 y) = 0 3 2
  • 25. Example 3 Describe the set of ordered pairs (x, y) satisfying x + 3x − yx − 3 y = 0 3 2 ( x + 3x ) + (− yx − 3 y) = 0 3 2 x ( x + 3) − y( x + 3) = 0 2
  • 26. Example 3 Describe the set of ordered pairs (x, y) satisfying x + 3x − yx − 3 y = 0 3 2 ( x + 3x ) + (− yx − 3 y) = 0 3 2 x ( x + 3) − y( x + 3) = 0 2 ( x − y)( x + 3) = 0 2
  • 27. Example 3 Describe the set of ordered pairs (x, y) satisfying x + 3x − yx − 3 y = 0 3 2 ( x + 3x ) + (− yx − 3 y) = 0 3 2 x ( x + 3) − y( x + 3) = 0 2 ( x − y)( x + 3) = 0 2 x − y=0 2
  • 28. Example 3 Describe the set of ordered pairs (x, y) satisfying x + 3x − yx − 3 y = 0 3 2 ( x + 3x ) + (− yx − 3 y) = 0 3 2 x ( x + 3) − y( x + 3) = 0 2 ( x − y)( x + 3) = 0 2 x − y=0 2 x+3=0
  • 29. Example 3 Describe the set of ordered pairs (x, y) satisfying x + 3x − yx − 3 y = 0 3 2 ( x + 3x ) + (− yx − 3 y) = 0 3 2 x ( x + 3) − y( x + 3) = 0 2 ( x − y)( x + 3) = 0 2 x − y=0 2 x+3=0 y= x 2
  • 30. Example 3 Describe the set of ordered pairs (x, y) satisfying x + 3x − yx − 3 y = 0 3 2 ( x + 3x ) + (− yx − 3 y) = 0 3 2 x ( x + 3) − y( x + 3) = 0 2 ( x − y)( x + 3) = 0 2 x − y=0 2 x+3=0 y= x 2 x=3
  • 31. Example 3 Describe the set of ordered pairs (x, y) satisfying x + 3x − yx − 3 y = 0 3 2 ( x + 3x ) + (− yx − 3 y) = 0 3 2 x ( x + 3) − y( x + 3) = 0 2 ( x − y)( x + 3) = 0 2 x − y=0 2 x+3=0 y= x 2 x=3 The union of the sets of ordered pairs satisfying y = x2 and x = 3.