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6.3 
Parametric 
Equations and 
Motion 
Copyright © 2011 Pearson, Inc.
What you’ll learn about 
 Parametric Equations 
 Parametric Curves 
 Eliminating the Parameter 
 Lines and Line Segments 
 Simulating Motion with a Grapher 
… and why 
These topics can be used to model the path of an object 
such as a baseball or golf ball. 
Copyright © 2011 Pearson, Inc. Slide 6.3 - 2
Parametric Curve, Parametric 
Equations 
The graph of the ordered pairs (x,y) where 
x = f(t) and y = g(t) 
are functions defined on an interval I of t-values 
is a parametric curve. The equations are 
parametric equations for the curve, the variable 
t is a parameter, and I is the parameter 
interval. 
Copyright © 2011 Pearson, Inc. Slide 6.3 - 3
Example Graphing Parametric 
Equations 
For the given parametric interval, graph the 
parametric equations x  t 2  2, y  3t. 
(a)  3  t  1 (b)  2  t  3 (c)  3  t  3 
Copyright © 2011 Pearson, Inc. Slide 6.3 - 4
Example Graphing Parametric 
Equations 
For the given parametric interval, graph the 
parametric equations x  t 2  2, y  3t. 
(a)  3  t  1 (b)  2  t  3 (c)  3  t  3 
Copyright © 2011 Pearson, Inc. Slide 6.3 - 5
Example Eliminating the Parameter 
Eliminate the parameter and identify the graph of the 
parametric curve x  t 1, y  2t,    t  . 
Copyright © 2011 Pearson, Inc. Slide 6.3 - 6
Example Eliminating the Parameter 
Eliminate the parameter and identify the graph of the 
parametric curve x  t 1, y  2t,    t  . 
Solve one equation for t: 
x  t 1 
t  x 1 
Substitute t into the second equation: 
y  2t  2(x 1) 
y  2x  2 
The graph of y  2x  2 is a line. 
Copyright © 2011 Pearson, Inc. Slide 6.3 - 7
Example Eliminating the Parameter 
Eliminate the parameter and identify the graph of the 
parametric curve x  3cost, y  3sint, 0  t  2 . 
Copyright © 2011 Pearson, Inc. Slide 6.3 - 8
Example Eliminating the Parameter 
Eliminate the parameter and identify the graph of the 
parametric curve x  3cost, y  3sint, 0  t  2 . 
x2  y2  9cos2 t  9sin2 t 
 9cos2 t  sin2 t 
 9(1) 
The graph of x2  y2  9 is a circle with the 
center at (0,0) and a radius of 3. 
Copyright © 2011 Pearson, Inc. Slide 6.3 - 9
Example Eliminating the Parameter 
Eliminate the parameter and identify the graph of the 
parametric curve x  5 t 2 , y  6t. 
Copyright © 2011 Pearson, Inc. Slide 6.3 - 10
Example Eliminating the Parameter 
Eliminate the parameter and identify the graph of the 
parametric curve x  5 t 2 , y  6t. 
Solve the second equation for t: t  
y 
6 
Substitute that result into the first equation: 
x  5  t 2 
x  5  
y 
6 
 
  
  2 
 
x  5  
y2 
36 
The graph of this 
equation is a parabola 
that opens to the left 
with vertex 5,0. 
36x  180  y2 
y2  180  36x 
y2  36x  5 
Copyright © 2011 Pearson, Inc. Slide 6.3 - 11
Example Eliminating the Parameter 
Eliminate the parameter and identify the graph of the 
parametric curve x  5 t 2 , y  6t. 
Confirm Graphically 
This is consistent with 
the graph. 
Copyright © 2011 Pearson, Inc. Slide 6.3 - 12
Example Finding Parametric 
Equations for a Line 
Find a parametrization of the line through the points 
A  (2,3) and B  (3,6). 
Copyright © 2011 Pearson, Inc. Slide 6.3 - 13
Example Finding Parametric 
Equations for a Line 
Find a parametrization of the line through the points 
A  (2,3) and B  (3,6). 
Let P(x, y) be an arbitrary point on the line through A and B. 
Vector OP is the tail-to-head vector sum of OA and AP. 
AP is a scalar multiple of AB. Let the scalar be t and 
OP  OA AP 
OP  OA t  AB 
x, y  2,3  t 3 2,6  3 
x, y  2,3  t 5,3 
x, y  2  5t,3 3t 
Copyright © 2011 Pearson, Inc. Slide 6.3 - 14
Quick Review 
1. Find the component form of the vectors 
(a) OA, (b) OB, and (c) AB where O is the origin, 
A  (3,2) and B  (-4,-6). 
2. Write an equation in point-slope form for the line 
through the points (3,2) and (-4,-6). 
3. Find the two functions defined implicitly by y2  2x. 
4. Find the equation for the circle with the center at (2,3) 
and a radius of 3. 
5. A wheel with radius 12 in spins at the rate 400 rpm. 
Find the angular velocity in radians per second. 
Copyright © 2011 Pearson, Inc. Slide 6.3 - 15
Quick Review Solutions 
1. Find the component form of the vectors 
(a) OA, (b) OB, and (c) AB where O is the origin, 
A  (3,2) and B  (4, 6). 
(a) 3,2 (b) 4, 6 (c) 7, 8 
2. Write an equation in point-slope form for the line 
through the points (3,2) and (  4,  6). y  2  
8 
7 
(x  3) 
3. Find the two functions defined implicitly by y2  2x. 
y  2x; y   2x 
Copyright © 2011 Pearson, Inc. Slide 6.3 - 16
Quick Review Solutions 
4. Find the equation for the circle with the center at 
(2,3) and a radius of 3. 
x  22 
 y  32 
 9 
5. A wheel with radius 12 in spins at the rate 400 rpm. 
Find the angular velocity in radians per second. 
40 / 3 rad/sec 
Copyright © 2011 Pearson, Inc. Slide 6.3 - 17

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Unit 6.3

  • 1. 6.3 Parametric Equations and Motion Copyright © 2011 Pearson, Inc.
  • 2. What you’ll learn about  Parametric Equations  Parametric Curves  Eliminating the Parameter  Lines and Line Segments  Simulating Motion with a Grapher … and why These topics can be used to model the path of an object such as a baseball or golf ball. Copyright © 2011 Pearson, Inc. Slide 6.3 - 2
  • 3. Parametric Curve, Parametric Equations The graph of the ordered pairs (x,y) where x = f(t) and y = g(t) are functions defined on an interval I of t-values is a parametric curve. The equations are parametric equations for the curve, the variable t is a parameter, and I is the parameter interval. Copyright © 2011 Pearson, Inc. Slide 6.3 - 3
  • 4. Example Graphing Parametric Equations For the given parametric interval, graph the parametric equations x  t 2  2, y  3t. (a)  3  t  1 (b)  2  t  3 (c)  3  t  3 Copyright © 2011 Pearson, Inc. Slide 6.3 - 4
  • 5. Example Graphing Parametric Equations For the given parametric interval, graph the parametric equations x  t 2  2, y  3t. (a)  3  t  1 (b)  2  t  3 (c)  3  t  3 Copyright © 2011 Pearson, Inc. Slide 6.3 - 5
  • 6. Example Eliminating the Parameter Eliminate the parameter and identify the graph of the parametric curve x  t 1, y  2t,    t  . Copyright © 2011 Pearson, Inc. Slide 6.3 - 6
  • 7. Example Eliminating the Parameter Eliminate the parameter and identify the graph of the parametric curve x  t 1, y  2t,    t  . Solve one equation for t: x  t 1 t  x 1 Substitute t into the second equation: y  2t  2(x 1) y  2x  2 The graph of y  2x  2 is a line. Copyright © 2011 Pearson, Inc. Slide 6.3 - 7
  • 8. Example Eliminating the Parameter Eliminate the parameter and identify the graph of the parametric curve x  3cost, y  3sint, 0  t  2 . Copyright © 2011 Pearson, Inc. Slide 6.3 - 8
  • 9. Example Eliminating the Parameter Eliminate the parameter and identify the graph of the parametric curve x  3cost, y  3sint, 0  t  2 . x2  y2  9cos2 t  9sin2 t  9cos2 t  sin2 t  9(1) The graph of x2  y2  9 is a circle with the center at (0,0) and a radius of 3. Copyright © 2011 Pearson, Inc. Slide 6.3 - 9
  • 10. Example Eliminating the Parameter Eliminate the parameter and identify the graph of the parametric curve x  5 t 2 , y  6t. Copyright © 2011 Pearson, Inc. Slide 6.3 - 10
  • 11. Example Eliminating the Parameter Eliminate the parameter and identify the graph of the parametric curve x  5 t 2 , y  6t. Solve the second equation for t: t  y 6 Substitute that result into the first equation: x  5  t 2 x  5  y 6      2  x  5  y2 36 The graph of this equation is a parabola that opens to the left with vertex 5,0. 36x  180  y2 y2  180  36x y2  36x  5 Copyright © 2011 Pearson, Inc. Slide 6.3 - 11
  • 12. Example Eliminating the Parameter Eliminate the parameter and identify the graph of the parametric curve x  5 t 2 , y  6t. Confirm Graphically This is consistent with the graph. Copyright © 2011 Pearson, Inc. Slide 6.3 - 12
  • 13. Example Finding Parametric Equations for a Line Find a parametrization of the line through the points A  (2,3) and B  (3,6). Copyright © 2011 Pearson, Inc. Slide 6.3 - 13
  • 14. Example Finding Parametric Equations for a Line Find a parametrization of the line through the points A  (2,3) and B  (3,6). Let P(x, y) be an arbitrary point on the line through A and B. Vector OP is the tail-to-head vector sum of OA and AP. AP is a scalar multiple of AB. Let the scalar be t and OP  OA AP OP  OA t  AB x, y  2,3  t 3 2,6  3 x, y  2,3  t 5,3 x, y  2  5t,3 3t Copyright © 2011 Pearson, Inc. Slide 6.3 - 14
  • 15. Quick Review 1. Find the component form of the vectors (a) OA, (b) OB, and (c) AB where O is the origin, A  (3,2) and B  (-4,-6). 2. Write an equation in point-slope form for the line through the points (3,2) and (-4,-6). 3. Find the two functions defined implicitly by y2  2x. 4. Find the equation for the circle with the center at (2,3) and a radius of 3. 5. A wheel with radius 12 in spins at the rate 400 rpm. Find the angular velocity in radians per second. Copyright © 2011 Pearson, Inc. Slide 6.3 - 15
  • 16. Quick Review Solutions 1. Find the component form of the vectors (a) OA, (b) OB, and (c) AB where O is the origin, A  (3,2) and B  (4, 6). (a) 3,2 (b) 4, 6 (c) 7, 8 2. Write an equation in point-slope form for the line through the points (3,2) and (  4,  6). y  2  8 7 (x  3) 3. Find the two functions defined implicitly by y2  2x. y  2x; y   2x Copyright © 2011 Pearson, Inc. Slide 6.3 - 16
  • 17. Quick Review Solutions 4. Find the equation for the circle with the center at (2,3) and a radius of 3. x  22  y  32  9 5. A wheel with radius 12 in spins at the rate 400 rpm. Find the angular velocity in radians per second. 40 / 3 rad/sec Copyright © 2011 Pearson, Inc. Slide 6.3 - 17