The document describes the instruction set of the 8086 microprocessor. It discusses that an instruction set consists of instructions understood by the CPU. The 8086 has six instruction formats - 1-byte, register to register, register to/from memory with no displacement, register to/from memory with displacement, immediate operand to register, and immediate operand to memory with 16-bit displacement. Each instruction format specifies the opcode, operands, and other fields to indicate the operation to be performed. The instruction cycle of the 8086 involves fetching an instruction from memory, decoding the instruction, and executing the instruction.

1. Instruction Set of 8086 Microprocessor

2. What is Instruction Set
 Instruction:- An instruction is a binary pattern
designed inside a microprocessor to perform a
specific function.
 The complete collection of instructions that
are understood by a CPU are known as
instruction sets.

3. Instruction set basics
 Opcode:- It stands for operational code. It
specifies the type of operation to be performed
by CPU. It is the first field in the machine
language instruction format.
 E.g. 08 is the opcode for instruction “MOV X,Y”.
 Operand:- We can also say it as data on which
operation should act. operands may be register
values or memory values. The CPU executes the
instructions using information present in this
field. It may be 8-bit data or 16-bit data.

4. Instruction set basics
 Assembler:- it converts the instruction into
sequence of binary bits, so that this bits can be
read by the processor.
 Mnemonics:- these are the symbolic codes for
either instructions or commands to perform a
particular function.
 E.g. MOV, ADD, SUB etc.

5. Simple Instruction Format

6. Instruction Formats
 In 8086 microprocessor there are following six types
of instruction formats.
(1). 1-Byte instruction,
(2). Register to register,
(3). Register to/from memory with no displacement,
(4). Register to/from memory with displacement,
(5). Immediate operand to register,
(6). Immediate operand to memory with 16-Bit
displacement.

7. 1-Byte instruction
 The instruction is 1-byte long in size.
 It May contain implied data or register operands
(data).
 The least significant three bits of opcode are
used for specifying register operand. Otherwise
all the 8-bits creates an opcode.

8. (2). Register to Register
 The instruction is 2-byte long in size.
 First byte of code denotes opcode & width of
operand.
 Second byte denotes register operands & R/M
field.
OPCODE D W 11 REG R/M
D7 D0D1 D7 D5 D2 D0D6 D3

9. (2). Register to Register
 ‘REG’ field denotes type of register used.
 ‘R/M’ field denotes register or memory location
used.
 If ‘W’ field is ‘0’ then operand is of 8-bits, & If
‘W’ field is ‘1’ then operand is of 16-bits.

10. (3). Register to/from memory with no
Displacement
 The instruction is 2-byte long in size.
 First byte of code denotes opcode & width of
operand.
 Second byte denotes mod,register operands &
R/M field.

11. (3). Register to/from memory with no
Displacement
 ‘MOD’ field denotes type of addressing mode
used.
 In case of no displacement the MOD=00
OPCODE W MOD REG R/M
D7 D7 D6D0D1 D0D2D5 D3

12. (4). Register to/from memory with
Displacement
 The instruction is 4-byte long in size.
 First byte of code denotes opcode.
 Second byte denotes register mod,register
operands & R/M field.

13. (4). Register to/from memory with
Displacement
 Third byte denotes lower byte of displacement.
 Fourth byte denotes higher byte of
displacement.
OPCODE MOD REG R/M
D7 D0 D0D7 D6 D2D3D5
Lower Byte of
displacement
Higher Byte of
displacement
D7 D0 D0D7

14. (5). Immediate operand to register
 The instruction is 4-byte long in size.
 First byte of code denotes opcode.
 Second byte denotes opcode,R/M field.

15. (5). Immediate operand to register
 Third byte denotes lower byte of data.
 fourth byte denotes higher byte of data.
OPCODE W 11 REG R/M
D0
Lower Byte of
data
Higher Byte of
data
D7 D7 D6D5 D3 D0D2 D0D7 D0D7

16. (6). Immediate operand to memory with 16-
bit displacement
 The instruction is 5 or 6-byte long in size.
 First byte of code denotes opcode.
 Second byte denotes register mod,opcode & R/M
field.

17. (6). Immediate operand to memory with 16-
bit displacement
 The remaining 4 bytes of data contains 2 bytes of
displacement and 2 bytes of data.
OPCODE MOD OPCOD
E
R/M
D0
Lower Byte of
displacement
D7 D7 D6D5 D3 D2 D0D7D0
Higher Byte of
displacement
Lower Byte of
data
Higher Byte of
data
D7 D0D7D7 D0D0

18. Instruction Cycle
 Instruction is command which is given by the user
to computer.
 The time period during which one instruction is
fetched from memory and execute when a
computer given an instruction in machine language.
 Each instruction is further divided into sequence of
phases.
 After the execution the program counter is
incremented to point to the next instruction.

19. Phases
 Fetch an instruction from memory.
 Decode the instruction.
 Execute the instruction.

20. Fetch Cycle
 In this phase the sequence counter is
initialized to 0.
 The address of first instruction from PC is
loaded into address register during the
first clock cycle.

21. Fetch Cycle
0002
Mov AC,0
Mov AC, 0
0000
0001
0002
0003
IRDecode
unit
Execute
unit
PC
AC

22. Decode Cycle
 The instruction is decoded by the instruction
decoder of a processor.
 All the bits of the instruction under execution
stored in IR are analyzed and decode in third
clock cycle.

23. Decode Cycle
0002
Mov AC,0
0000
0001
0002
0003
PC
AC
IRDecode
unit
Execute
unit
Mov AC, 0

24. Execute Cycle
 In the last phase, the processor execute the
instruction.
 This involves setting the contents of the internal
register AC to constant value 0.

25. Execute Cycle
0003
AC 0
Mov AC,0
Mov AC, 0
0000
0001
0002
0003
IRDecode
unit
Execute
unit
PC
AC

26. Thank
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