A one-sample z-test is used to compare a sample proportion to a population proportion. The document provides an example where a survey claims 90% of doctors recommend aspirin, and a sample of 100 doctors found 82% recommend aspirin. The z-test is calculated to determine if this difference is statistically significant. The null hypothesis is the sample and population proportions are the same. If the calculated z-statistic falls outside the critical values of -1.96 and 1.96, the null will be rejected, meaning the proportions are significantly different.
The ppt gives an idea about basic concept of Estimation. point and interval. Properties of good estimate is also covered. Confidence interval for single means, difference between two means, proportion and difference of two proportion for different sample sizes are included along with case studies.
According to Wikipedia point estimation involves the use of sample data to calculate a single value (known as a point estimate since it identifies a point in some parameter space) which is to serve as a "best guess" or "best estimate" of an unknown population parameter (for example, the population means).
Hypothesis Testing is important part of research, based on hypothesis testing we can check the truth of presumes hypothesis (Research Statement or Research Methodology )
The ppt gives an idea about basic concept of Estimation. point and interval. Properties of good estimate is also covered. Confidence interval for single means, difference between two means, proportion and difference of two proportion for different sample sizes are included along with case studies.
According to Wikipedia point estimation involves the use of sample data to calculate a single value (known as a point estimate since it identifies a point in some parameter space) which is to serve as a "best guess" or "best estimate" of an unknown population parameter (for example, the population means).
Hypothesis Testing is important part of research, based on hypothesis testing we can check the truth of presumes hypothesis (Research Statement or Research Methodology )
Hypothesis is usually considered as the principal instrument in research and quality control. Its main function is to suggest new experiments and observations. In fact, many experiments are carried out with the deliberate object of testing hypothesis. Decision makers often face situations wherein they are interested in testing hypothesis on the basis of available information and then take decisions on the basis of such testing. In Six –Sigma methodology, hypothesis testing is a tool of substance and used in analysis phase of the six sigma project so that improvement can be done in right direction
Confidence Interval ModuleOne of the key concepts of statist.docxmaxinesmith73660
Confidence Interval Module
One of the key concepts of statistics enabling statisticians to make incredibly accurate predictions is called the Central Limit Theorem. The Central Limit Theorem is defined in this way:
· For samples of a sufficiently large size, the real distribution of means is almost always approximately normal.
· The distribution of means gets closer and closer to normal as the sample size gets larger and larger, regardless of what the original variable looks like (positively or negatively skewed).
· In other words, the original variable does not have to be normally distributed.
· This is because, if we as eccentric researchers, drew an almost infinite number of random samples from a single population (such as the student body of NMSU), the means calculated from the many samples of that population will be normally distributed and the mean calculated from all of those samples would be a very close approximation to the true population mean. It is this very characteristic that makes it possible for us, using sound probability based sampling techniques, to make highly accurate statements about characteristics of a population based upon the statistics calculated on a sample drawn from that population.
· Furthermore, we can calculate a statistic known as the standard error of the mean (abbreviated s.e.) that describes the variability of the distribution of all possible sample means in the same way that we used the standard deviation to describe the variability of a single sample. We will use the standard error of the mean (s.e.) to calculate the statistic that is the topic of this module, the confidence interval.
The formula that we use to calculate the standard error of the mean is:
s.e. = s / √N – 1
where s = the standard deviation calculated from the sample; and
N = the sample size.
So the formula tells us that the standard error of the mean is equal to the
standard deviation divided by the square root of the sample size minus 1.
This is the preferred formula for practicing professionals as it accounts for errors that may be a function of the particular sample we have selected.
THE CONFIDENCE INTERVAL (CI)
The formula for the CI is a function of the sample size (N).
For samples sizes ≥ 100, the formula for the CI is:
CI = (the sample mean) + & - Z(s.e.).
Let’s look at an example to see how this formula works.
* Please use a pdf doc. “how to solve the problem”, I have provided for you under the “notes” link.
Example 1
Suppose that we conducted interviews with 140 randomly selected individuals (N = 140) in a large metropolitan area. We assured these individuals that their answers would remain confidential, and we asked them about their law-breaking behavior. Among other questions the individuals were asked to self-report the number of times per month they exceeded the speed limit. One of the objectives of the study was to estimate (make an inference about) the average nu.
Standard Error & Confidence Intervals.pptxhanyiasimple
Certainly! Let's delve into the concept of **standard error**.
## What Is Standard Error?
The **standard error (SE)** is a statistical measure that quantifies the **variability** between a sample statistic (such as the mean) and the corresponding population parameter. Specifically, it estimates how much the sample mean would **vary** if we were to repeat the study using **new samples** from the same population. Here are the key points:
1. **Purpose**: Standard error helps us understand how well our **sample data** represents the entire population. Even with **probability sampling**, where elements are randomly selected, some **sampling error** remains. Calculating the standard error allows us to estimate the representativeness of our sample and draw valid conclusions.
2. **High vs. Low Standard Error**:
- **High Standard Error**: Indicates that sample means are **widely spread** around the population mean. In other words, the sample may not closely represent the population.
- **Low Standard Error**: Suggests that sample means are **closely distributed** around the population mean, indicating that the sample is representative of the population.
3. **Decreasing Standard Error**:
- To decrease the standard error, **increase the sample size**. Using a large, random sample minimizes **sampling bias** and provides a more accurate estimate of the population parameter.
## Standard Error vs. Standard Deviation
- **Standard Deviation (SD)**: Describes variability **within a single sample**. It can be calculated directly from sample data.
- **Standard Error (SE)**: Estimates variability across **multiple samples** from the same population. It is an **inferential statistic** that can only be estimated (unless the true population parameter is known).
### Example:
Suppose we have a random sample of 200 students, and we calculate the mean math SAT score to be 550. In this case:
- **Sample**: The 200 students
- **Population**: All test takers in the region
The standard error helps us understand how well this sample represents the entire population's math SAT scores.
Remember, the standard error is crucial for making valid statistical inferences. By understanding it, researchers can confidently draw conclusions based on sample data. 📊🔍
If you need further clarification or have additional questions, feel free to ask! 😊
---
I've provided a concise explanation of standard error, emphasizing its importance in statistical analysis. If you'd like more details or specific examples, feel free to ask! ¹²³⁴
Source: Conversation with Copilot, 5/31/2024
(1) What Is Standard Error? | How to Calculate (Guide with Examples) - Scribbr. https://www.scribbr.com/statistics/standard-error/.
(2) Standard Error (SE) Definition: Standard Deviation in ... - Investopedia. https://www.investopedia.com/terms/s/standard-error.asp.
(3) Standard error Definition & Meaning - Merriam-Webster. https://www.merriam-webster.com/dictionary/standard%20error.
(4) Standard err
Segunda parte del Curso de Perfeccionamiento Profesional no Conducente a Grado Académico: Inglés Técnico para Profesionales de Ciencias de la Salud. DEPARTAMENTO ADMINISTRATIVO SOCIAL. Escuela de Enfermería. ULA. Mérida. Venezuela. Se oferta en la modalidad presencial de 3 ó 4 unidades crédito y los costos son solidarios y dependen de la zona del país que lo solicite.
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Durante las sesiones de aprendizaje se presentan las nociones generales acerca de la gramática de escritura inglesa y su transferencia en nuestra lengua española. En este módulo, se inicia la experiencia práctica eligiendo textos para observar los elementos facilitados.
Seguidamente, los participantes las ideas que se encuentran alrededor de fuentes en línea para profundizar en el aprendizaje en materia de inglés técnico.
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Prepare a presentation or a paper using research, basic comparative analysis, data organization and application of economic information. You will make an informed assessment of an economic climate outside of the United States to accomplish an entertainment industry objective.
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A Strategic Approach: GenAI in EducationPeter Windle
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2. A one-sample Z-test for proportions is a test that helps
us compare a population proportion with a sample
proportion.
3. A one-sample Z-test for proportions is a test that helps
us compare a population proportion with a sample
proportion.
30%
Sample Mean
(푋 )
30%
Population Mean
(휇)
4. A one-sample Z-test for proportions is a test that helps
us compare a population proportion with a sample
proportion.
This is the
symbol for
a sample
mean
30%
Sample Mean
( 푿)
30%
Population Mean
(휇)
5. A one-sample Z-test for proportions is a test that helps
us compare a population proportion with a sample
proportion.
And this is the
symbol for a
population mean
(called a mew)
30%
Sample Mean
(푋 )
30%
Population Mean
(흁)
6. A one-sample Z-test for proportions is a test that helps
us compare a population proportion with a sample
proportion.
30%
Sample Mean
(푋 )
Here is our question:
30%
Population Mean
(휇)
7. A one-sample Z-test for proportions is a test that helps
us compare a population proportion with a sample
proportion.
30%
Sample Mean
(푋 )
30%
Population Mean
(휇)
Here is our question: Are the population and the
sample proportions (which supposedly have the same
general characteristics as the population) statistically
significantly the same or different?
9. Consider the following example:
A survey claims that 9 out of 10 doctors recommend
aspirin for their patients with headaches. To test this
claim, a random sample of 100 doctors is obtained. Of
these 100 doctors, 82 indicate that they recommend
aspirin. Is this claim accurate? Use alpha = 0.05
10. Consider the following example:
A survey claims that 9 out of 10 doctors recommend
aspirin for their patients with headaches. To test this
claim, a random sample of 100 doctors is obtained. Of
these 100 doctors, 82 indicate that they recommend
aspirin. Is this claim accurate? Use alpha = 0.05
Which is the sample?
11. Consider the following example:
A survey claims that 9 out of 10 doctors recommend
aspirin for their patients with headaches. To test this
claim, a random sample of 100 doctors is obtained. Of
these 100 doctors, 82 indicate that they recommend
aspirin. Is this claim accurate? Use alpha = 0.05
Which is the sample?
What is the population?
12. Consider the following example:
A survey claims that 9 out of 10 doctors recommend
aspirin for their patients with headaches. To test this
claim, a random sample of 100 doctors is obtained. Of
these 100 doctors, 82 indicate that they recommend
aspirin. Is this claim accurate? Use alpha = 0.05
Which is the sample?
What is the population?
The sample proportion is .82 doctors recommending
aspirin.
13. Consider the following example:
A survey claims that 9 out of 10 doctors recommend
aspirin for their patients with headaches. To test this
claim, a random sample of 100 doctors is obtained. Of
these 100 doctors, 82 indicate that they recommend
aspirin. Is this claim accurate? Use alpha = 0.05
Which is the sample?
What is the population?
The sample proportion is .82 of doctors recommending
aspirin.
The population proportion .90 (the claim that 9 out of
10 doctors recommend aspirin).
15. We begin by stating the null hypothesis:
The proportion of a sample of 100 medical doctors who
recommend aspirin for their patients with headaches IS NOT
statistically significantly different from the claim that 9 out of
10 doctors recommend aspirin for their patients with
headaches.
16. We begin by stating the null hypothesis:
The proportion of a sample of 100 medical doctors who
recommend aspirin for their patients with headaches IS NOT
statistically significantly different from the claim that 9 out of
10 doctors recommend aspirin for their patients with
headaches.
The alternative hypothesis would be:
17. We begin by stating the null hypothesis:
The proportion of a sample of 100 medical doctors who
recommend aspirin for their patients with headaches IS NOT
statistically significantly different from the claim that 9 out of
10 doctors recommend aspirin for their patients with
headaches.
The alternative hypothesis would be:
The proportion of a sample of 100 medical doctors who
recommend aspirin for their patients with headaches IS
statistically significantly different from the claim that 9 out of
10 doctors recommend aspirin for their patients with
headaches.
19. State the decision rule: We will calculate what is called
the z statistic which will make it possible to determine
the likelihood that the sample proportion (.82) is a rare
or common occurrence with reference to the
population proportion (.90).
20. State the decision rule: We will calculate what is called
the z statistic which will make it possible to determine
the likelihood that the sample proportion (.82) is a rare
or common occurrence with reference to the
population proportion (.90).
If the z-statistic falls outside of the 95% common
occurrences and into the 5% rare occurrences then we
will conclude that it is a rare event and that the sample
is different from the population and therefore reject
the null hypothesis.
22. Before we calculate this z-statistic, we must locate the
z critical values.
What are the z critical values? These are the values
that demarcate what is the rare and the common
occurrence.
23. Let’s look at the normal distribution:
It has some important properties that make it possible
for us to locate the z statistic and compare it to the z
critical.
24. Here is the mean and the median of a normal
distribution.
25. 50% of the values are above and below the orange
line.
50% - 50% +
26. 68% of the values fall between +1 and -1 standard
deviations from the mean.
34% - 34% +
27. 68% of the values fall between +1 and -1 standard
deviations from the mean.
34% - 34% +
-1σ mean +1σ
68%
28. 68% of the values fall between +1 and -1 standard
deviations from the mean.
34% - 34% +
-2σ -1σ mean +1σ +2σ
95%
29. Since our decision rule is .05 alpha, this means that if
the z value falls outside of the 95% common
occurrences we will consider it a rare occurrence.
34% - 34% +
-2σ -1σ mean +1σ +2σ
95%
30. Since are decision rule is .05 alpha we will see if the z
statistic is rare using this visual
rare rare
-2σ -1σ mean +1σ +2σ
2.5% 95%
2.5%
32. Before we can calculate the z – statistic to see if it is
rare or common we first must determine the z critical
values that are associated with -2σ and +2σ.
Common
-2σ -1σ mean +1σ +2σ
95%
33. We look these up in the Z table and find that they are -
1.96 and +1.96
Common
-2σ -1σ mean +1σ +2σ
Z values -1.96 +1.96
95%
34. So if the z statistic we calculate is less than -1.96
(e.g., -1.99) or greater than +1.96 (e.g., +2.30) then we
will consider this to be a rare event and reject the null
hypothesis and state that there is a statistically
significant difference between .9 (population) and .82
(the sample).
35. So if the z statistic we calculate is less than -1.96
(e.g., -1.99) or greater than +1.96 (e.g., +2.30) then we
will consider this to be a rare event and reject the null
hypothesis and state that there is a statistically
significant difference between .9 (population) and .82
(the sample).
Let’s calculate the z statistic and see where if falls!
36. So if the z statistic we calculate is less than -1.96
(e.g., -1.99) or greater than +1.96 (e.g., +2.30) then we
will consider this to be a rare event and reject the null
hypothesis and state that there is a statistically
significant difference between .9 (population) and .82
(the sample).
Let’s calculate the z statistic and see where if falls!
We do this by using the following equation:
37. So if the z statistic we calculate is less than -1.96
(e.g., -1.99) or greater than +1.96 (e.g., +2.30) then we
will consider this to be a rare event and reject the null
hypothesis and state that there is a statistically
significant difference between .9 (population) and .82
(the sample).
Let’s calculate the z statistic and see where if falls!
We do this by using the following equation:
풛풔풕풂풕풊풔풕풊풄 =
푝 − 푝
푝(1 − 푝)
푛
38. So if the z statistic we calculate is less than -1.96
(e.g., -1.99) or greater than +1.96 (e.g., +2.30) then we
will consider this to be a rare event and reject the null
hypothesis and state that there is a statistically
significant difference between .9 (population) and .82
(the sample).
Let’s calculate the z statistic and see where if falls!
We do this by using the following equation:
풛풔풕풂풕풊풔풕풊풄 =
푝 − 푝
푝(1 − 푝)
푛
Zstatistic is what we are trying to find to see if it is
outside or inside the z critical values (-1.96 and +1.96).
40. A survey claims that 9 out of 10 doctors recommend aspirin for
their patients with headaches. To test this claim, a random
sample of 100 doctors is obtained. Of these 100 doctors, 82
indicate that they recommend aspirin. Is this claim accurate?
Use alpha = 0.05
41. A survey claims that 9 out of 10 doctors recommend aspirin for
their patients with headaches. To test this claim, a random
sample of 100 doctors is obtained. Of these 100 doctors, 82
indicate that they recommend aspirin. Is this claim accurate?
Use alpha = 0.05
42. 풑 is the proportion from the sample that
recommended aspirin to their patients (. ퟖퟐ)
풛풔풕풂풕풊풔풕풊풄 =
푝 − 푝
푝(1 − 푝)
푛
43. 풑 is the proportion from the sample that
recommended aspirin to their patients (. ퟖퟐ)
풛풔풕풂풕풊풔풕풊풄 =
푝 − 푝
푝(1 − 푝)
푛
Note – this little
hat (푝 ) over the
p means that
this proportion
is an estimate
of a population
44. 퐩 is the proportion from the population that
recommended aspirin to their patients (.90)
풛풔풕풂풕풊풔풕풊풄 =
푝 − 푝
푝(1 − 푝)
푛
45. 풏 is the size of the sample (100)
풛풔풕풂풕풊풔풕풊풄 =
푝 − 푝
푝(1 − 푝)
푛
46. A survey claims that 9 out of 10 doctors recommend aspirin for
their patients with headaches. To test this claim, a random
sample of 100 doctors is obtained. Of these 100 doctors, 82
indicate that they recommend aspirin. Is this claim accurate?
Use alpha = 0.05
풏 is the size of the sample (100)
풛풔풕풂풕풊풔풕풊풄 =
푝 − 푝
푝(1 − 푝)
푛
47. A survey claims that 9 out of 10 doctors recommend aspirin for
their patients with headaches. To test this claim, a random
sample of 100 doctors is obtained. Of these 100 doctors, 82
indicate that they recommend aspirin. Is this claim accurate?
Use alpha = 0.05
풏 is the size of the sample (100)
풛풔풕풂풕풊풔풕풊풄 =
푝 − 푝
푝(1 − 푝)
푛
50. A survey claims that 9 out of 10 doctors recommend aspirin for
their patients with headaches. To test this claim, a random
sample of 100 doctors is obtained. Of these 100 doctors, 82
indicate that they recommend aspirin. Is this claim accurate?
Use alpha = 0.05
풛풔풕풂풕풊풔풕풊풄 =
.82 − 푝
푝(1 − 푝)
푛
Sample Proportion
51. A survey claims that 9 out of 10 doctors recommend aspirin for
their patients with headaches. To test this claim, a random
sample of 100 doctors is obtained. Of these 100 doctors, 82
indicate that they recommend aspirin. Is this claim accurate?
Use alpha = 0.05
풛풔풕풂풕풊풔풕풊풄 =
.82 − 푝
푝(1 − 푝)
푛
Sample Proportion
53. A survey claims that 9 out of 10 doctors recommend aspirin for
their patients with headaches. To test this claim, a random
sample of 100 doctors is obtained. Of these 100 doctors, 82
indicate that they recommend aspirin. Is this claim accurate?
Use alpha = 0.05
풛풔풕풂풕풊풔풕풊풄 =
.82 − .90
.90(1 − .90)
푛
Population Proportion
54. A survey claims that 9 out of 10 doctors recommend aspirin for
their patients with headaches. To test this claim, a random
sample of 100 doctors is obtained. Of these 100 doctors, 82
indicate that they recommend aspirin. Is this claim accurate?
Use alpha = 0.05
풛풔풕풂풕풊풔풕풊풄 =
.82 − .90
.90(1 − .90)
푛
Population Proportion
57. Now for the denominator which is the estimated
standard error. This value will help us know how many
standard error units .82 and .90 are apart from one
another (we already know they are .08 raw units apart)
58. Now for the denominator which is the estimated
standard error. This value will help us know how many
standard error units .82 and .90 are apart from one
another (we already know they are .08 raw units apart)
풛풔풕풂풕풊풔풕풊풄 =
−.08
.90(1 − .90)
푛
59. Note - If the standard error is small then the z statistic
will be larger. The larger the z statistics the more likely
that it will exceed the -1.96 or +1.96 boundaries,
compelling us to reject the null hypothesis. If it is
smaller than we will not.
풛풔풕풂풕풊풔풕풊풄 =
−.08
.90(1 − .90)
푛
61. A survey claims that 9 out of 10 doctors recommend aspirin for
their patients with headaches. To test this claim, a random
sample of 100 doctors is obtained. Of these 100 doctors, 82
indicate that they recommend aspirin. Is this claim accurate?
Use alpha = 0.05
Let’s continue our calculations and find out:
풛풔풕풂풕풊풔풕풊풄 =
−.08
.90(1 − .90)
푛
65. A survey claims that 9 out of 10 doctors recommend aspirin for
their patients with headaches. To test this claim, a random
sample of 100 doctors is obtained. Of these 100 doctors, 82
indicate that they recommend aspirin. Is this claim accurate?
Use alpha = 0.05
풛풔풕풂풕풊풔풕풊풄 =
−.08
.09
100
Sample Size:
69. Let‘s continue our calculations:
풛풔풕풂풕풊풔풕풊풄 = −2.67
Now we have our z statistic.
70. Let’s go back to our distribution:
Common
rare rare
-2σ -1σ mean +1σ +2σ
-1.96 +1.96
95%
71. Let’s go back to our distribution: So, is this result
rare or common?
Common
rare rare
-2σ -1σ mean +1σ +2σ
-2.67 -1.96 +1.96
95%
72. Let’s go back to our distribution: So, is this result
rare or common?
Common
rare rare
-2σ -1σ mean +1σ +2σ
-1.96 +1.96
95%
-2.67
This is the
Z-Statistic we
calculated
73. Let’s go back to our distribution: So, is this result
rare or common?
Common
rare rare
-2σ -1σ mean +1σ +2σ
-2.67 -1.96 +1.96
95%
This is the
Z – Critical
74. Looks like it is a rare event therefore we will reject the
null hypothesis in favor of the alternative hypothesis:
75. Looks like it is a rare event therefore we will reject the
null hypothesis in favor of the alternative hypothesis:
The proportion of a sample of 100 medical doctors
who recommend aspirin for their patients with
headaches IS statistically significantly different from
the claim that 9 out of 10 doctors recommend aspirin
for their patients with headaches.