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SEQUENCE
and SERIES
What is a SEQUENCE?
ο‚› In mathematics, a sequence is an ordered list.
Like a set, it contains members (also
called elements, or terms). The number of
ordered elements (possibly infinite) is called
the length of the sequence. Unlike a set, order
matters, and exactly the same elements can
appear multiple times at different positions in
the sequence. Most precisely, a sequence
can be defined as a function whose domain
is a countable totally ordered set, such as
the natural numbers.
Source:
Wikipedia:http://en.wikipedia.org/wiki/Sequence
INFINITE SEQUENCE
ο‚› An infinite sequence is a function with domain the set of
natural numbers 𝑁 = 1, 2, 3, … … … .
ο‚› For example, consider the function "π‘Žβ€œ defined by
π‘Ž 𝑛 = 𝑛2 𝑛 = 1, 2, 3, … …
Instead of the usual functional notation π‘Ž 𝑛 , for
sequences we usually write
π‘Ž 𝑛 = 𝑛2
That is, a letter with a subscript, such as π‘Ž 𝑛, is used to
represent numbers in the range of a sequence. For the
sequence defined by π‘Ž 𝑛 = 𝑛2,
π‘Ž1 = 12
= 1
π‘Ž2 = 22
= 4
π‘Ž3 = 32
= 9
π‘Ž4 = 42
= 16
General or nth Term
ο‚› A sequence is frequently defined by giving its
range. The sequence on the given example
can be written as
1, 4, 9, 16, … … … , 𝑛2
, … …
Each number in the range of a sequence
is a term of the sequence, with π‘Ž 𝑛 the nth term
or general term of the sequence. The formula
for the nth term generates the terms of a
sequence by repeated substitution of counting
numbers for 𝑛.
FINITE SEQUENCE
ο‚› A finite sequence with π‘š terms is a
function with domain the set of natural
numbers 1, 2,3, … … , π‘š
ο‚› For example, 2, 4, 6, 8, 10 is a finite
sequence with 5 terms where π‘Ž 𝑛 = 2𝑛, for
𝑛 = 1,2,3,4,5. In contrast, 2,4,6,8,10, … … is an
infinite sequence where π‘Ž 𝑛 = 2𝑛, for 𝑛 =
1,2,3,4,5 … ….
Sample Problems
1. Write the first five terms of the infinite sequence
with general term π‘Ž 𝑛 = 2𝑛 βˆ’ 1.
Answer:
π‘Ž1 = 2 1 βˆ’ 1 = 1
π‘Ž2 = 2 2 βˆ’ 1 = 3
π‘Ž3 = 2 3 βˆ’ 1 = 5
π‘Ž4 = 2 4 βˆ’ 1 = 7
π‘Ž5 = 2 5 βˆ’ 1 = 9
Thus, the first five terms are 1,3,5,7,9 and the
sequence is
1, 3, 5, 7, 9, … … 2𝑛 βˆ’ 1, … …
2. A finite sequence has four terms, and the formula for the
nth term is π‘₯ 𝑛 = βˆ’1 𝑛 1
2 π‘›βˆ’1. What is the sequence?
Answer:
π‘₯1 = βˆ’1 1 1
21βˆ’1 = βˆ’1
π‘₯2 = βˆ’1 2 1
22βˆ’1 =
1
2
π‘₯3 = βˆ’1 3 1
23βˆ’1 = βˆ’
1
4
π‘₯4 = βˆ’1 4 1
24βˆ’1 =
1
8
Thus the sequence is
βˆ’1,
1
2
, βˆ’
1
4
,
1
8
3. Find a formula for π‘Ž 𝑛 given the first few terms
of the sequence.
a.) 2, 3, 4, 5, …
Answer: Each term is one larger than the
corresponding natural number. Thus, we have,
π‘Ž1 = 2 = 1 + 1
π‘Ž2 = 3 = 2 + 1
π‘Ž3 = 4 = 3 + 1
π‘Ž4 = 5 = 4 + 1
Hence, π‘Ž 𝑛 = 𝑛 + 1
b.) 3, 6, 9, 12, ……
Answer:
π‘Ž1 = 3 = 3 βˆ™ 1
π‘Ž2 = 6 = 3 βˆ™ 2
π‘Ž3 = 9 = 3 βˆ™ 3
π‘Ž4 = 12 = 3 βˆ™ 4
Thus, π‘Ž 𝑛 = 3𝑛
SERIES
ο‚› Associated with every sequence, is a
SERIES, the indicated sum of the
sequence.
ο‚› For example, associated with the
sequence 2, 4, 6, 8, 10, is the series
2+4+6+8+10 and associated with the
sequence -1, Β½, -1/4, 1/8, is the series
(-1)+(1/2)+(-1/4)+(1/8).
Sigma Summation Notation
ο‚› The Greek letter βˆ‘ (sigma) is often used as a
summation symbol to abbreviate a series.
ο‚› The series 2 + 4 +6 + 8 + 10 which has a general
term π‘₯ 𝑛 = 2𝑛, can be written as
𝑛=1
5
π‘₯ 𝑛 π‘œπ‘Ÿ
𝑛=1
5
2𝑛
and is read as β€œthe sum of the terms π‘₯ 𝑛 or 2𝑛 as 𝑛
varies from 1 to 5”. The letter 𝑛 is the index on the
summation while 1 and 5 are the lower and upper
limits of summation, respectively.
ο‚› In general, if π‘₯1, π‘₯2, π‘₯3, π‘₯4 … , π‘₯ 𝑛 is a
sequence associated with a series of
π‘˜=1
𝑛
π‘₯ π‘˜ = π‘₯1 + π‘₯2 + π‘₯3 + π‘₯4 + β‹― + π‘₯ 𝑛
Sample Problem
1. Write out the series
π‘˜=1
5
π‘˜2
+ 1
without using the sigma summation notation.
Answer:
π‘₯1 = 1 2
+ 1 = 1 + 1 = 2
π‘₯2 = 2 2
+ 1 = 4 + 1 = 5
π‘₯3 = 3 2
+ 1 = 9 + 1 = 10
π‘₯4 = 4 2
+ 1 = 16 + 1 = 17
π‘₯5 = 5 2
+ 1 = 25 + 1 = 26
Thus,
π‘˜=1
5
π‘˜2
+ 1 = 2 + 5 + 10 + 17 + 26 = 60
2. Express and write the series
π‘˜=2
4
βˆ’1 π‘˜
π‘˜ + 1
without using sigma notation.
Answer:
π‘₯2 = βˆ’1 2 2 + 1 = 3
π‘₯3 = βˆ’1 3
3 + 1 = βˆ’2
π‘₯4 = βˆ’1 4
4 + 1 = 5
Thus,
π‘˜=2
4
βˆ’1 π‘˜
π‘˜ + 1 = 3 βˆ’ 2 + 5
Break a leg!
1. Find the first four terms and the seventh
term 𝑛 = 1,2,3, 4 &7 if the general term
of the sequence is π‘₯ 𝑛 =
βˆ’1 𝑛
𝑛
.
2. Find a formula for π‘Ž 𝑛 given the few terms
of the sequence.
1
2
,
1
4
,
1
8
,
1
16
, …
THANK YOU VERY MUCH!!!
PROF. DENMAR ESTRADA MARASIGAN

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Sequence and series

  • 2. What is a SEQUENCE? ο‚› In mathematics, a sequence is an ordered list. Like a set, it contains members (also called elements, or terms). The number of ordered elements (possibly infinite) is called the length of the sequence. Unlike a set, order matters, and exactly the same elements can appear multiple times at different positions in the sequence. Most precisely, a sequence can be defined as a function whose domain is a countable totally ordered set, such as the natural numbers. Source: Wikipedia:http://en.wikipedia.org/wiki/Sequence
  • 3. INFINITE SEQUENCE ο‚› An infinite sequence is a function with domain the set of natural numbers 𝑁 = 1, 2, 3, … … … . ο‚› For example, consider the function "π‘Žβ€œ defined by π‘Ž 𝑛 = 𝑛2 𝑛 = 1, 2, 3, … … Instead of the usual functional notation π‘Ž 𝑛 , for sequences we usually write π‘Ž 𝑛 = 𝑛2 That is, a letter with a subscript, such as π‘Ž 𝑛, is used to represent numbers in the range of a sequence. For the sequence defined by π‘Ž 𝑛 = 𝑛2, π‘Ž1 = 12 = 1 π‘Ž2 = 22 = 4 π‘Ž3 = 32 = 9 π‘Ž4 = 42 = 16
  • 4. General or nth Term ο‚› A sequence is frequently defined by giving its range. The sequence on the given example can be written as 1, 4, 9, 16, … … … , 𝑛2 , … … Each number in the range of a sequence is a term of the sequence, with π‘Ž 𝑛 the nth term or general term of the sequence. The formula for the nth term generates the terms of a sequence by repeated substitution of counting numbers for 𝑛.
  • 5. FINITE SEQUENCE ο‚› A finite sequence with π‘š terms is a function with domain the set of natural numbers 1, 2,3, … … , π‘š ο‚› For example, 2, 4, 6, 8, 10 is a finite sequence with 5 terms where π‘Ž 𝑛 = 2𝑛, for 𝑛 = 1,2,3,4,5. In contrast, 2,4,6,8,10, … … is an infinite sequence where π‘Ž 𝑛 = 2𝑛, for 𝑛 = 1,2,3,4,5 … ….
  • 6. Sample Problems 1. Write the first five terms of the infinite sequence with general term π‘Ž 𝑛 = 2𝑛 βˆ’ 1. Answer: π‘Ž1 = 2 1 βˆ’ 1 = 1 π‘Ž2 = 2 2 βˆ’ 1 = 3 π‘Ž3 = 2 3 βˆ’ 1 = 5 π‘Ž4 = 2 4 βˆ’ 1 = 7 π‘Ž5 = 2 5 βˆ’ 1 = 9 Thus, the first five terms are 1,3,5,7,9 and the sequence is 1, 3, 5, 7, 9, … … 2𝑛 βˆ’ 1, … …
  • 7. 2. A finite sequence has four terms, and the formula for the nth term is π‘₯ 𝑛 = βˆ’1 𝑛 1 2 π‘›βˆ’1. What is the sequence? Answer: π‘₯1 = βˆ’1 1 1 21βˆ’1 = βˆ’1 π‘₯2 = βˆ’1 2 1 22βˆ’1 = 1 2 π‘₯3 = βˆ’1 3 1 23βˆ’1 = βˆ’ 1 4 π‘₯4 = βˆ’1 4 1 24βˆ’1 = 1 8 Thus the sequence is βˆ’1, 1 2 , βˆ’ 1 4 , 1 8
  • 8. 3. Find a formula for π‘Ž 𝑛 given the first few terms of the sequence. a.) 2, 3, 4, 5, … Answer: Each term is one larger than the corresponding natural number. Thus, we have, π‘Ž1 = 2 = 1 + 1 π‘Ž2 = 3 = 2 + 1 π‘Ž3 = 4 = 3 + 1 π‘Ž4 = 5 = 4 + 1 Hence, π‘Ž 𝑛 = 𝑛 + 1
  • 9. b.) 3, 6, 9, 12, …… Answer: π‘Ž1 = 3 = 3 βˆ™ 1 π‘Ž2 = 6 = 3 βˆ™ 2 π‘Ž3 = 9 = 3 βˆ™ 3 π‘Ž4 = 12 = 3 βˆ™ 4 Thus, π‘Ž 𝑛 = 3𝑛
  • 10. SERIES ο‚› Associated with every sequence, is a SERIES, the indicated sum of the sequence. ο‚› For example, associated with the sequence 2, 4, 6, 8, 10, is the series 2+4+6+8+10 and associated with the sequence -1, Β½, -1/4, 1/8, is the series (-1)+(1/2)+(-1/4)+(1/8).
  • 11. Sigma Summation Notation ο‚› The Greek letter βˆ‘ (sigma) is often used as a summation symbol to abbreviate a series. ο‚› The series 2 + 4 +6 + 8 + 10 which has a general term π‘₯ 𝑛 = 2𝑛, can be written as 𝑛=1 5 π‘₯ 𝑛 π‘œπ‘Ÿ 𝑛=1 5 2𝑛 and is read as β€œthe sum of the terms π‘₯ 𝑛 or 2𝑛 as 𝑛 varies from 1 to 5”. The letter 𝑛 is the index on the summation while 1 and 5 are the lower and upper limits of summation, respectively.
  • 12. ο‚› In general, if π‘₯1, π‘₯2, π‘₯3, π‘₯4 … , π‘₯ 𝑛 is a sequence associated with a series of π‘˜=1 𝑛 π‘₯ π‘˜ = π‘₯1 + π‘₯2 + π‘₯3 + π‘₯4 + β‹― + π‘₯ 𝑛
  • 13. Sample Problem 1. Write out the series π‘˜=1 5 π‘˜2 + 1 without using the sigma summation notation. Answer: π‘₯1 = 1 2 + 1 = 1 + 1 = 2 π‘₯2 = 2 2 + 1 = 4 + 1 = 5 π‘₯3 = 3 2 + 1 = 9 + 1 = 10 π‘₯4 = 4 2 + 1 = 16 + 1 = 17 π‘₯5 = 5 2 + 1 = 25 + 1 = 26 Thus, π‘˜=1 5 π‘˜2 + 1 = 2 + 5 + 10 + 17 + 26 = 60
  • 14. 2. Express and write the series π‘˜=2 4 βˆ’1 π‘˜ π‘˜ + 1 without using sigma notation. Answer: π‘₯2 = βˆ’1 2 2 + 1 = 3 π‘₯3 = βˆ’1 3 3 + 1 = βˆ’2 π‘₯4 = βˆ’1 4 4 + 1 = 5 Thus, π‘˜=2 4 βˆ’1 π‘˜ π‘˜ + 1 = 3 βˆ’ 2 + 5
  • 15. Break a leg! 1. Find the first four terms and the seventh term 𝑛 = 1,2,3, 4 &7 if the general term of the sequence is π‘₯ 𝑛 = βˆ’1 𝑛 𝑛 . 2. Find a formula for π‘Ž 𝑛 given the few terms of the sequence. 1 2 , 1 4 , 1 8 , 1 16 , …
  • 16. THANK YOU VERY MUCH!!! PROF. DENMAR ESTRADA MARASIGAN