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Section 2.5
                    Limits at Infinity

                          Math 1a


                      October 10, 2007



Announcements
   Midterm I is coming: October 24, 7:00-9:00 in Halls A and C
Definition
Let f be a function defined on some interval (a, ∞). Then

                          lim f (x) = L
                          x→∞

means that the values of f (x) can be made as close to L as we
like, by taking x sufficiently large.
Definition
Let f be a function defined on some interval (a, ∞). Then

                             lim f (x) = L
                          x→∞

means that the values of f (x) can be made as close to L as we
like, by taking x sufficiently large.

Definition
The line y = L is a called a horizontal asymptote of the curve
y = f (x) if either

             lim f (x) = L      or       lim f (x) = L.
            x→∞                        x→−∞
Definition
Let f be a function defined on some interval (a, ∞). Then

                              lim f (x) = L
                              x→∞

means that the values of f (x) can be made as close to L as we
like, by taking x sufficiently large.

Definition
The line y = L is a called a horizontal asymptote of the curve
y = f (x) if either

              lim f (x) = L         or    lim f (x) = L.
             x→∞                         x→−∞



y = L is a horizontal line!
Theorem
Let n be a positive integer. Then
           1
      lim n = 0
     x→∞ x
             1
       lim     =0
     x→−∞ x n
Using the limit laws to compute limits at ∞



   Example
   Find
                          2x 3 + 3x + 1
                      lim
                      x→∞ 4x 3 + 5x 2 + 7

   if it exists.
   A does not exist
   B 1/2
   C0
   D∞
Using the limit laws to compute limits at ∞



   Example
   Find
                          2x 3 + 3x + 1
                      lim
                      x→∞ 4x 3 + 5x 2 + 7

   if it exists.
   A does not exist
   B 1/2
   C0
   D∞
Solution
Factor out the largest power of x from the numerator and
denominator. We have
                2x 3 + 3x + 1     x 3 (2 + 3/x 2 + 1/x 3 )
                                =3
                4x 3 + 5x 2 + 7    x (4 + 5/x + 7/x 3 )
                2x 3 + 3x + 1            2 + 3/x 2 + 1/x 3
            lim                 = lim
           x→∞ 4x 3 + 5x 2 + 7    x→∞ 4 + 5/x + 7/x 3
                                  2+0+0            1
                                =              =
                                  4+0+0            2
Solution
Factor out the largest power of x from the numerator and
denominator. We have
                 2x 3 + 3x + 1     x 3 (2 + 3/x 2 + 1/x 3 )
                                 =3
                 4x 3 + 5x 2 + 7    x (4 + 5/x + 7/x 3 )
                 2x 3 + 3x + 1            2 + 3/x 2 + 1/x 3
             lim                 = lim
            x→∞ 4x 3 + 5x 2 + 7    x→∞ 4 + 5/x + 7/x 3
                                   2+0+0            1
                                 =              =
                                   4+0+0            2


Upshot
When finding limits of algebraic expressions at infinitely, look at
the highest degree terms.
Another Example




  Example
  Find                  √
                        3x 4 + 7
                  lim
                        x2 + 3
                  x→∞
Another Example




  Example
  Find                          √
                                3x 4 + 7
                          lim
                                x2 + 3
                          x→∞


  Solution       √
  The limit is       3.
Example
                           x2
Make a conjecture about lim   .
                       x→∞ 2x
Example
                              x2
Make a conjecture about lim      .
                          x→∞ 2x

Solution
The limit is zero. Exponential growth is infinitely faster than
geometric growth
Rationalizing to get a limit




   Example
                   4x 2 + 17 − 2x .
   Compute lim
             x→∞
Rationalizing to get a limit




   Example
                    4x 2 + 17 − 2x .
   Compute lim
              x→∞

   Solution
   This limit is of the form ∞ − ∞, which we cannot use. So we
   rationalize the numerator (the denominator is 1) to get an
   expression that we can use the limit laws on.
Worksheet

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Lesson 7: Limits at Infinity

  • 1. Section 2.5 Limits at Infinity Math 1a October 10, 2007 Announcements Midterm I is coming: October 24, 7:00-9:00 in Halls A and C
  • 2.
  • 3. Definition Let f be a function defined on some interval (a, ∞). Then lim f (x) = L x→∞ means that the values of f (x) can be made as close to L as we like, by taking x sufficiently large.
  • 4. Definition Let f be a function defined on some interval (a, ∞). Then lim f (x) = L x→∞ means that the values of f (x) can be made as close to L as we like, by taking x sufficiently large. Definition The line y = L is a called a horizontal asymptote of the curve y = f (x) if either lim f (x) = L or lim f (x) = L. x→∞ x→−∞
  • 5. Definition Let f be a function defined on some interval (a, ∞). Then lim f (x) = L x→∞ means that the values of f (x) can be made as close to L as we like, by taking x sufficiently large. Definition The line y = L is a called a horizontal asymptote of the curve y = f (x) if either lim f (x) = L or lim f (x) = L. x→∞ x→−∞ y = L is a horizontal line!
  • 6. Theorem Let n be a positive integer. Then 1 lim n = 0 x→∞ x 1 lim =0 x→−∞ x n
  • 7.
  • 8. Using the limit laws to compute limits at ∞ Example Find 2x 3 + 3x + 1 lim x→∞ 4x 3 + 5x 2 + 7 if it exists. A does not exist B 1/2 C0 D∞
  • 9. Using the limit laws to compute limits at ∞ Example Find 2x 3 + 3x + 1 lim x→∞ 4x 3 + 5x 2 + 7 if it exists. A does not exist B 1/2 C0 D∞
  • 10. Solution Factor out the largest power of x from the numerator and denominator. We have 2x 3 + 3x + 1 x 3 (2 + 3/x 2 + 1/x 3 ) =3 4x 3 + 5x 2 + 7 x (4 + 5/x + 7/x 3 ) 2x 3 + 3x + 1 2 + 3/x 2 + 1/x 3 lim = lim x→∞ 4x 3 + 5x 2 + 7 x→∞ 4 + 5/x + 7/x 3 2+0+0 1 = = 4+0+0 2
  • 11. Solution Factor out the largest power of x from the numerator and denominator. We have 2x 3 + 3x + 1 x 3 (2 + 3/x 2 + 1/x 3 ) =3 4x 3 + 5x 2 + 7 x (4 + 5/x + 7/x 3 ) 2x 3 + 3x + 1 2 + 3/x 2 + 1/x 3 lim = lim x→∞ 4x 3 + 5x 2 + 7 x→∞ 4 + 5/x + 7/x 3 2+0+0 1 = = 4+0+0 2 Upshot When finding limits of algebraic expressions at infinitely, look at the highest degree terms.
  • 12. Another Example Example Find √ 3x 4 + 7 lim x2 + 3 x→∞
  • 13.
  • 14. Another Example Example Find √ 3x 4 + 7 lim x2 + 3 x→∞ Solution √ The limit is 3.
  • 15. Example x2 Make a conjecture about lim . x→∞ 2x
  • 16.
  • 17. Example x2 Make a conjecture about lim . x→∞ 2x Solution The limit is zero. Exponential growth is infinitely faster than geometric growth
  • 18. Rationalizing to get a limit Example 4x 2 + 17 − 2x . Compute lim x→∞
  • 19.
  • 20. Rationalizing to get a limit Example 4x 2 + 17 − 2x . Compute lim x→∞ Solution This limit is of the form ∞ − ∞, which we cannot use. So we rationalize the numerator (the denominator is 1) to get an expression that we can use the limit laws on.