Solving
Quadratic Equations
by Graphing
Quadratic Equation
y = ax2 + bx + c
2 is the quadratic term.
ax
bx is the linear term.
c is the constant term.
The highest exponent is two;
therefore, the degree is two.
Identifying Terms
2-7x+1
Example f(x)=5x
Quadratic term 5x2
Linear term
-7x
Constant term 1
Identifying Terms
2-3
Example f(x) = 4x
2
4x

Quadratic term
Linear term
0
Constant term -3
Identifying Terms
Now you try this
problem.
2 - 2x + 3
f(x) = 5x
quadratic term
linear term
constant term

5x2
-2x
3
Quadratic Solutions
The number of real solutions is at
most two.
6

f x  =

x 2 -2

 x +5

6

2
4

4

-5

2

5

2

-2

5
5

-4
-2
-2

No solutions

One solution

Two solutions
Quadratic Function

y = ax2 + bx +
c
Quadratic Term

Linear Term

Constant Term

2 – 3? 0x
What is the linear term of y = 4x
2- 5x ? -5x
What is the linear term of y = x
2 – 5x?
What is the constant term of y = x
0
Can the quadratic term be zero? No!
Solving Equations
When we talk about solving these
equations, we want to find the value
of x when y = 0. These values,
where the graph crosses the x-axis,
are called the x-intercepts.
These values are also referred to as
solutions, zeros, or roots.
Identifying Solutions
2-4
Example f(x) = x

4

2

-5

-2

-4

Solutions are -2 and 2.
Identifying Solutions
Now you try this
problem.
2
f(x) = 2x - x

4

2

5

-2

Solutions are 0 and 2.

-4
Quadratic Functions
The graph of a quadratic function is parabola
a:
y

A parabola can open
up or down.
If the parabola opens
up, the lowest point is
called the vertex
(minimum).
If the parabola opens
down, the vertex is the
highest point
(maximum).

Vertex

x

Vertex

NOTE: if the parabola opens left or right it is not a

function!
Standard Form
The standard form of a quadratic function is:
y = ax2 + bx + c
y

The parabola will
open up when the
a value is
positive.
The parabola will
open down when
the a value is
negative.

a0

a>0

x

a<0
Axis of Symmetry
Parabolas are symmetric.
If we drew a line down
the middle of the
parabola, we could fold
the parabola in half.

y
Axis of
Symmetr
y

We call this line the
Axis of symmetry.
x

If we graph one side of
the parabola, we could
REFLECT it over the
Axis of symmetry to
graph the other side.

The Axis of
symmetry ALWAYS
Finding the Axis of Symmetry
When a quadratic function is in standard
form
2

y = ax + bx + c,

the equation of the Axis of
symmetry is
This is best read as …

x

b
2a

‘the opposite of b divided by the quantity of 2
times a.’
2

Find the Axis of symmetry for y = 3x – 18x
a=3
b = -18+ 7
The Axis

18
18
x

2 3 
6

3

of
symmetry
is x = 3.
Finding the Vertex
The Axis of symmetry always goes through the

Vertex
_______. Thus, the Axis of symmetry
X-coordinate
gives us the ____________ of the vertex.
Find the vertex of

y = -2x2 + 8x - 3

STEP 1: Find the Axis of symmetry

x

b

a = -2

b=8

2a

x 

8
2( 2)



8
4

 2

The xcoordinate
of the
vertex is 2
Finding the Vertex
Find the vertex of

y = -2x2 + 8x - 3

STEP 1: Find the Axis of symmetry

x

b



2a

8
2(  2)



8
4

2

STEP 2: Substitute the x – value into the original
equation to find the y –coordinate of the vertex.

y  2
 2

2

2 

8

 4   16

  8  16  3
 5

2  3
 3

The
vertex
is (2 , 5)
Graphing a Quadratic Function
There are 3 steps to graphing a parabola in
standard form.
x
STEP 1: Find the Axis of symmetry using:

b
2a

STEP 2: Find the vertex
STEP 3: Find two other points and reflect them
across the Axis of symmetry. Then connect the
five points with a smooth curve.
MAKE A TABLE
using x – values close to
the Axis of symmetry.
Graphing a Quadratic Function

Graph : y  2 x

2

 4x 1

y

x 1

STEP 1: Find the Axis
of symmetry
x=

- b
2a

=

4
2 (2 )

= 1



STEP 2: Find the
vertex
Substitute in x = 1 to
find the y – value of
the vertex.
2

y = 2 (1) - 4 (1) - 1 = - 3

x

Vertex : 1 ,  3 
Graphing Quadratic
Equations
The graph of a quadratic equation is a
parabola.
The roots or zeros are the x-intercepts.
The vertex is the maximum or
minimum point.
All parabolas have an axis of
symmetry.
Graphing Quadratic
Equations
One method of graphing uses a table with arbitrary
x-values.
Graph y = x2 - 4x

4

2

x

y

0
1
2
3
4

0
-3
-4
-3
0

5

-2

-4

Roots 0 and 4 , Vertex (2, -4) ,
Axis of Symmetry x = 2
Graphing Quadratic
Equations
Try this problem y = x2 - 2x - 8.
4

x

y

-2
-1
1
3
4

2

5

-2

-4

Roots
Vertex
Axis of Symmetry

Graphing quadratic equations

  • 1.
  • 2.
    Quadratic Equation y =ax2 + bx + c 2 is the quadratic term. ax bx is the linear term. c is the constant term. The highest exponent is two; therefore, the degree is two.
  • 3.
    Identifying Terms 2-7x+1 Example f(x)=5x Quadraticterm 5x2 Linear term -7x Constant term 1
  • 4.
    Identifying Terms 2-3 Example f(x)= 4x 2 4x Quadratic term Linear term 0 Constant term -3
  • 5.
    Identifying Terms Now youtry this problem. 2 - 2x + 3 f(x) = 5x quadratic term linear term constant term 5x2 -2x 3
  • 6.
    Quadratic Solutions The numberof real solutions is at most two. 6 f x  = x 2 -2  x +5 6 2 4 4 -5 2 5 2 -2 5 5 -4 -2 -2 No solutions One solution Two solutions
  • 7.
    Quadratic Function y =ax2 + bx + c Quadratic Term Linear Term Constant Term 2 – 3? 0x What is the linear term of y = 4x 2- 5x ? -5x What is the linear term of y = x 2 – 5x? What is the constant term of y = x 0 Can the quadratic term be zero? No!
  • 8.
    Solving Equations When wetalk about solving these equations, we want to find the value of x when y = 0. These values, where the graph crosses the x-axis, are called the x-intercepts. These values are also referred to as solutions, zeros, or roots.
  • 9.
    Identifying Solutions 2-4 Example f(x)= x 4 2 -5 -2 -4 Solutions are -2 and 2.
  • 10.
    Identifying Solutions Now youtry this problem. 2 f(x) = 2x - x 4 2 5 -2 Solutions are 0 and 2. -4
  • 11.
    Quadratic Functions The graphof a quadratic function is parabola a: y A parabola can open up or down. If the parabola opens up, the lowest point is called the vertex (minimum). If the parabola opens down, the vertex is the highest point (maximum). Vertex x Vertex NOTE: if the parabola opens left or right it is not a function!
  • 12.
    Standard Form The standardform of a quadratic function is: y = ax2 + bx + c y The parabola will open up when the a value is positive. The parabola will open down when the a value is negative. a0 a>0 x a<0
  • 13.
    Axis of Symmetry Parabolasare symmetric. If we drew a line down the middle of the parabola, we could fold the parabola in half. y Axis of Symmetr y We call this line the Axis of symmetry. x If we graph one side of the parabola, we could REFLECT it over the Axis of symmetry to graph the other side. The Axis of symmetry ALWAYS
  • 14.
    Finding the Axisof Symmetry When a quadratic function is in standard form 2 y = ax + bx + c, the equation of the Axis of symmetry is This is best read as … x b 2a ‘the opposite of b divided by the quantity of 2 times a.’ 2 Find the Axis of symmetry for y = 3x – 18x a=3 b = -18+ 7 The Axis 18 18 x  2 3  6 3 of symmetry is x = 3.
  • 15.
    Finding the Vertex TheAxis of symmetry always goes through the Vertex _______. Thus, the Axis of symmetry X-coordinate gives us the ____________ of the vertex. Find the vertex of y = -2x2 + 8x - 3 STEP 1: Find the Axis of symmetry x b a = -2 b=8 2a x  8 2( 2)  8 4  2 The xcoordinate of the vertex is 2
  • 16.
    Finding the Vertex Findthe vertex of y = -2x2 + 8x - 3 STEP 1: Find the Axis of symmetry x b  2a 8 2(  2)  8 4 2 STEP 2: Substitute the x – value into the original equation to find the y –coordinate of the vertex. y  2  2 2 2  8  4   16   8  16  3  5 2  3  3 The vertex is (2 , 5)
  • 17.
    Graphing a QuadraticFunction There are 3 steps to graphing a parabola in standard form. x STEP 1: Find the Axis of symmetry using: b 2a STEP 2: Find the vertex STEP 3: Find two other points and reflect them across the Axis of symmetry. Then connect the five points with a smooth curve. MAKE A TABLE using x – values close to the Axis of symmetry.
  • 18.
    Graphing a QuadraticFunction Graph : y  2 x 2  4x 1 y x 1 STEP 1: Find the Axis of symmetry x= - b 2a = 4 2 (2 ) = 1  STEP 2: Find the vertex Substitute in x = 1 to find the y – value of the vertex. 2 y = 2 (1) - 4 (1) - 1 = - 3 x Vertex : 1 ,  3 
  • 19.
    Graphing Quadratic Equations The graphof a quadratic equation is a parabola. The roots or zeros are the x-intercepts. The vertex is the maximum or minimum point. All parabolas have an axis of symmetry.
  • 20.
    Graphing Quadratic Equations One methodof graphing uses a table with arbitrary x-values. Graph y = x2 - 4x 4 2 x y 0 1 2 3 4 0 -3 -4 -3 0 5 -2 -4 Roots 0 and 4 , Vertex (2, -4) , Axis of Symmetry x = 2
  • 21.
    Graphing Quadratic Equations Try thisproblem y = x2 - 2x - 8. 4 x y -2 -1 1 3 4 2 5 -2 -4 Roots Vertex Axis of Symmetry

Editor's Notes

  • #8 Ask students “Why is ‘a’ not allowed to be zero? Would the function still be quadratic?
  • #12 Let students know that in Algebra I we concentrate only on parabolas that are functions; In Algebra II, they will study parabolas that open left or right.
  • #13 Remind students that if ‘a’ = 0 you would not have a quadratic function.
  • #15 Discuss with the students that the line of symmetry of a quadratic function (parabola that opens up or down) is always a vertical line, therefore has the equation x =#. Ask “Does this parabola open up or down?