Rational Expressions
Simplifying
Section 11.3
Simplifying Rational Expressions
 The objective is to be able to simplify a
rational expression
5
2x +
3
92
x
x −
 Polynomial – The sum or difference of monomials.
 Rational expression – A fraction whose numerator
and denominator are polynomials.
 Reduced form – a rational expression in which the
numerator and denominator have no factors in
common.
 Divide out the
common factors
 Factor the
numerator and
denominator and
then divide the
common factors
Dividing Out Common Factors
Step 1 – Identify any factors which are common to both the
numerator and the denominator.
5
5 7
x
x( )−
The numerator and denominator have
a common factor.
The common factor is the five.
Dividing Out Common Factors
Step 2 – Divide out the common factors.
The fives can be divided since 5/5 = 1
The x remains in the numerator.
The (x-7) remains in the denominator
5
5 7
x
x( )−
=
x
x − 7
Factoring the Numerator
and Denominator
Factor the numerator.
Factor the denominator.
Divide out the common factors.
Write in simplified form.
3 9
1 2
2
3
x x
x
+
Factoring
Step 1: Look for common factors
to both terms in the numerator.
3 9
1 2
2
3
x x
x
+ ♦3 is a factor of both 3 and 9.
♦X is a factor of both x2
and x.
Step 2: Factor the numerator.
3 9
1 2
2
3
x x
x
+ 3 3
12 3
x x
x
( )+
Factoring
Step 3: Look for common factors to the
terms in the denominator and factor.
3 9
1 2
2
3
x x
x
+
The denominator only has one term.
The 12 and x3
can be factored.
The 12 can be factored into 3 x 4.
The x3
can be written as x • x2
.
3 9
1 2
2
3
x x
x
+ 3 3
3 4 2
x x
x x
( )+
• • •
Divide and Simplify
Step 4: Divide out the common factors. In this
case, the common factors divide to become 1.
3 3
3 4 2
x x
x x
( )+
• • •
Step 5: Write in simplified form.
x
x
+ 3
4 2
You Try It
Simplify the following rational expressions.
1
9
2 4
2
2
.
x y z
x y z
2
3
4 32
.
a
a a
+
+ +
3
3 1 5
7 1 02
.
x
x x
−
− +
4
2 1 5
1 2
2
2
.
x x
x x
− −
− −
5
1 4 3 5 2 1
1 2 3 0 1 8
2
2
.
x x
x x
+ +
+ +
Problem 1
9
2 4
2
2
x y z
x y z
= 3 3
3 8
• • • • •
• • • • •
x x y z
x y z z
3
3
• • •
• • •
x y z
x y z
•
3
8
•
•
x
z
1 •
3
8
x
z
=
3
8
x
z
Factor the numerator
and denominator
Divide out the
common factors.
Write in simplified
form.
Problem 2
a
a a
+
+ +
3
4 32 = a
a a
+
+ +
3
3 1( ) ( )
Factor the numerator
and denominator
a
a
+
+
3
3
•
1
1a +
1 •
1
1a +
= 1
1a +
Divide out the
common factors.
Write in simplified
form.
You Try It
Problem 3
3 1 5
7 1 02
x
x x
−
− +
= 3 5
5 2
( )
( ) ( )
x
x x
−
− −
x
x
−
−
5
5
•
3
2x −
1 •
3
2x −
=
3
2x −
Factor the numerator
and denominator
Divide out the
common factors.
Write in simplified
form.
You Try It
Problem 4
You Try It
x x
x x
2
2
2 1 5
1 2
− −
− −
=
( ) ( )
( ) ( )
x x
x x
− +
− +
5 3
4 3
x
x
+
+
3
3
•
x
x
−
−
5
4
1 •
x
x
−
−
5
4
=
x
x
−
−
5
4
Factor the numerator
and denominator
Divide out the
common factors.
Write in simplified
form.
Problem 5
1 4 3 5 2 1
1 2 3 0 1 8
2
2
x x
x x
+ +
+ +
=
7 2 5 3
6 2 6 3
2
2
( )
( )
x x
x x
+ +
+ +
( )
( )
2 5 3
2 6 3
2
2
x x
x x
+ +
+ +
•
7
6
1 •
7
6
=
7
6
You Try It
Factor the numerator
and denominator
Divide out the
common factors.
Write in simplified
form.
x
x
5
105
:Simplify
− ( )
x
x
5
25 −
=
Factor
( )
x
x 2−
=
x
x 2−
=
1
23
:Simplify 2
2
−
++
y
yy
( )( )
( )( )11
21
−+
++
yy
yy
1
2
−
+
=
y
y
y
y
48
2412
:Simplify
+
( )( )
( )( )y
y
412
212 +
y
y
4
2+
=
xx
xx
23
2
:Simplify 2
2
+
+
( ) ( )
( ) ( )
2 1
3 2
x x
x x
+
+
2 1
3 2
x
x
+
=
+
2
2
9
Simplify:
2 15
a
a a
−
+ −
( ) ( )
( ) ( )
3 3
5 3
a a
a a
+ −
+ −
12
1
+
+
=
a
a
x
x
−
−
4
4
:Simplify
( )
( )( )41
4
−−
−
x
x
1
1
1
−=
−
=
Simplifying
4 3
5 5
x x
x
+
+ 2
5
25
q
q
+
−
3
x
3
5
x
5q +
1
5q −
( )1x +
5 ( )1x + ( )5q + ( )5q −
12.1 – Simplifying Rational Expressions
Simplifying
2
2
11 18
2
x x
x x
+ +
+ −
( )2x +
( )
( )
9
1
x
x
+
−
( )9x +
( )2x + ( )1x −
12.1 – Simplifying Rational Expressions
Simplifying
4
4
x
x
−
−
4x −
4x −
=
4x− +
1− ( )4x −
1−
12.1 – Simplifying Rational Expressions
Restrictions on
Rational Expressions
For what value of x is undefined?x x
x
2
2 1 5
4 2 0
− −
−
It is undefined for any value of “x” which makes the
denominator zero.
4 2 0 0x − =
4 5 0( )x − =
x − =5 0
x − + = +5 5 0 5
x = 5
The restriction is
that x cannot
equal 5.
YOU TRY IT
What are the excluded values of the variables for
the following rational expressions?
1
4 2
1 4
3 2
2 3
.
y z
y z
2
3 6
2 1 2
2
.
x
x
−
−
3
4 1 2
2 8
2
2
.
c c
c c
+ −
+ −
Problem 1
Solution
y ≠ 0
z ≠ 0
Problem 2
Solution
2x - 12 = 0
2x - 12 + 12 = 0 + 12
2x = 12
2x ÷ 2 = 12 ÷ 2
x = 6
ANSWER
x ≠ 6
Problem 3
Solution
C2
+ 2C - 8 = 0
(C-2)(C+4) = 0
C-2 = 0 or C + 4 = 0
C-2+2 = 0 + 2 C + 4 - 4 = 0 - 4
C = 2 or C = -4
Answer
C ≠ 2
C ≠ -4

Rational expressions ppt

  • 1.
  • 2.
    Simplifying Rational Expressions The objective is to be able to simplify a rational expression 5 2x + 3 92 x x −
  • 3.
     Polynomial –The sum or difference of monomials.  Rational expression – A fraction whose numerator and denominator are polynomials.  Reduced form – a rational expression in which the numerator and denominator have no factors in common.
  • 4.
     Divide outthe common factors  Factor the numerator and denominator and then divide the common factors
  • 5.
    Dividing Out CommonFactors Step 1 – Identify any factors which are common to both the numerator and the denominator. 5 5 7 x x( )− The numerator and denominator have a common factor. The common factor is the five.
  • 6.
    Dividing Out CommonFactors Step 2 – Divide out the common factors. The fives can be divided since 5/5 = 1 The x remains in the numerator. The (x-7) remains in the denominator 5 5 7 x x( )− = x x − 7
  • 7.
    Factoring the Numerator andDenominator Factor the numerator. Factor the denominator. Divide out the common factors. Write in simplified form. 3 9 1 2 2 3 x x x +
  • 8.
    Factoring Step 1: Lookfor common factors to both terms in the numerator. 3 9 1 2 2 3 x x x + ♦3 is a factor of both 3 and 9. ♦X is a factor of both x2 and x. Step 2: Factor the numerator. 3 9 1 2 2 3 x x x + 3 3 12 3 x x x ( )+
  • 9.
    Factoring Step 3: Lookfor common factors to the terms in the denominator and factor. 3 9 1 2 2 3 x x x + The denominator only has one term. The 12 and x3 can be factored. The 12 can be factored into 3 x 4. The x3 can be written as x • x2 . 3 9 1 2 2 3 x x x + 3 3 3 4 2 x x x x ( )+ • • •
  • 10.
    Divide and Simplify Step4: Divide out the common factors. In this case, the common factors divide to become 1. 3 3 3 4 2 x x x x ( )+ • • • Step 5: Write in simplified form. x x + 3 4 2
  • 11.
    You Try It Simplifythe following rational expressions. 1 9 2 4 2 2 . x y z x y z 2 3 4 32 . a a a + + + 3 3 1 5 7 1 02 . x x x − − + 4 2 1 5 1 2 2 2 . x x x x − − − − 5 1 4 3 5 2 1 1 2 3 0 1 8 2 2 . x x x x + + + +
  • 12.
    Problem 1 9 2 4 2 2 xy z x y z = 3 3 3 8 • • • • • • • • • • x x y z x y z z 3 3 • • • • • • x y z x y z • 3 8 • • x z 1 • 3 8 x z = 3 8 x z Factor the numerator and denominator Divide out the common factors. Write in simplified form.
  • 13.
    Problem 2 a a a + ++ 3 4 32 = a a a + + + 3 3 1( ) ( ) Factor the numerator and denominator a a + + 3 3 • 1 1a + 1 • 1 1a + = 1 1a + Divide out the common factors. Write in simplified form. You Try It
  • 14.
    Problem 3 3 15 7 1 02 x x x − − + = 3 5 5 2 ( ) ( ) ( ) x x x − − − x x − − 5 5 • 3 2x − 1 • 3 2x − = 3 2x − Factor the numerator and denominator Divide out the common factors. Write in simplified form. You Try It
  • 15.
    Problem 4 You TryIt x x x x 2 2 2 1 5 1 2 − − − − = ( ) ( ) ( ) ( ) x x x x − + − + 5 3 4 3 x x + + 3 3 • x x − − 5 4 1 • x x − − 5 4 = x x − − 5 4 Factor the numerator and denominator Divide out the common factors. Write in simplified form.
  • 16.
    Problem 5 1 43 5 2 1 1 2 3 0 1 8 2 2 x x x x + + + + = 7 2 5 3 6 2 6 3 2 2 ( ) ( ) x x x x + + + + ( ) ( ) 2 5 3 2 6 3 2 2 x x x x + + + + • 7 6 1 • 7 6 = 7 6 You Try It Factor the numerator and denominator Divide out the common factors. Write in simplified form.
  • 17.
    x x 5 105 :Simplify − ( ) x x 5 25− = Factor ( ) x x 2− = x x 2− =
  • 18.
    1 23 :Simplify 2 2 − ++ y yy ( )() ( )( )11 21 −+ ++ yy yy 1 2 − + = y y
  • 19.
    y y 48 2412 :Simplify + ( )( ) ()( )y y 412 212 + y y 4 2+ =
  • 20.
    xx xx 23 2 :Simplify 2 2 + + ( )( ) ( ) ( ) 2 1 3 2 x x x x + + 2 1 3 2 x x + = +
  • 21.
    2 2 9 Simplify: 2 15 a a a − +− ( ) ( ) ( ) ( ) 3 3 5 3 a a a a + − + − 12 1 + + = a a
  • 22.
    x x − − 4 4 :Simplify ( ) ( )()41 4 −− − x x 1 1 1 −= − =
  • 23.
    Simplifying 4 3 5 5 xx x + + 2 5 25 q q + − 3 x 3 5 x 5q + 1 5q − ( )1x + 5 ( )1x + ( )5q + ( )5q − 12.1 – Simplifying Rational Expressions
  • 24.
    Simplifying 2 2 11 18 2 x x xx + + + − ( )2x + ( ) ( ) 9 1 x x + − ( )9x + ( )2x + ( )1x − 12.1 – Simplifying Rational Expressions
  • 25.
    Simplifying 4 4 x x − − 4x − 4x − = 4x−+ 1− ( )4x − 1− 12.1 – Simplifying Rational Expressions
  • 26.
    Restrictions on Rational Expressions Forwhat value of x is undefined?x x x 2 2 1 5 4 2 0 − − − It is undefined for any value of “x” which makes the denominator zero. 4 2 0 0x − = 4 5 0( )x − = x − =5 0 x − + = +5 5 0 5 x = 5 The restriction is that x cannot equal 5.
  • 27.
    YOU TRY IT Whatare the excluded values of the variables for the following rational expressions? 1 4 2 1 4 3 2 2 3 . y z y z 2 3 6 2 1 2 2 . x x − − 3 4 1 2 2 8 2 2 . c c c c + − + −
  • 28.
  • 29.
    Problem 2 Solution 2x -12 = 0 2x - 12 + 12 = 0 + 12 2x = 12 2x ÷ 2 = 12 ÷ 2 x = 6 ANSWER x ≠ 6
  • 30.
    Problem 3 Solution C2 + 2C- 8 = 0 (C-2)(C+4) = 0 C-2 = 0 or C + 4 = 0 C-2+2 = 0 + 2 C + 4 - 4 = 0 - 4 C = 2 or C = -4 Answer C ≠ 2 C ≠ -4