This document provides an overview of wave motion concepts including wave propagation, types of waves, wave terminology, speed of transverse waves, standing waves, and resonance. Key points covered include:
- Transverse waves have vibration perpendicular to propagation direction, while longitudinal waves have parallel vibration.
- Period, frequency, wavelength, speed, and phase are defined for waves.
- The speed of a transverse wave depends on the tension and linear mass density of the string.
- Standing waves occur at resonant frequencies when the string length is an integer multiple of half wavelengths.
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In this presentation, I explain what a standing wave on a string is, the difference between a standing wave and a travelling wave, and go over some practice problems.
WAVES
INTRODUCTION
A wave is a period disturbance which transfers energy from one place to another.
There are two types of waves:
1. Mechanical waves
2. Electromagnetic waves
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2. Week 13, Lesson 2 Wave Motion 2
Wave Motion
A wave has been generated on a string by sinusoidal vibration of the
hand at its end, as shown.
The wave that is now on the string furnishes a record of earlier vibrations at
the source.
Energy is carried by the wave from the source (the hand) to the right, along the string.
This direction, the direction of energy transport, is called the direction of
propagation of the wave.
3. Week 13, Lesson 2 Wave Motion 3
Each particle of the string vibrates up and down, perpendicular
to the line of propagation.
Any wave in which the vibration direction is perpendicular to
the direction of propagation is called a transverse wave.
Typical transverse waves besides those on a string include
electromagnetic waves – light and radio waves.
Sound waves are longitudinal (or compressional) waves since
the vibration direction is parallel to the direction of propagation.
4. Week 13, Lesson 2 Wave Motion 4
Wave Terminology
The period of vibration (T) is the time taken for a particle such as the one at A
to move through one complete cycle – down from point A and then back to A.
x
y
A
The frequency of vibration (f) is the number of such vibrations executed by
the particle each second.
f = 1/T unit is the Hz = 1s-1
B
C
D
E
Wave Crests
troughs
As time goes on, the crests and troughs move to the right with speed, v.
amplitude
yo
wavelength
The wavelength is the distance along the propagation between corresponding
points on the wave.
5. Week 13, Lesson 2 Wave Motion 5
In time T (the period), a crest moving with average speed v will
move a distance (one wavelength) to the right.
Using the formula for distance traveled from linear motion:
s = vt
We get:
= vT = v/f
This relation holds for all waves – not just waves on a string.
6. Week 13, Lesson 2 Wave Motion 6
In-Phase Vibrations
In-phase vibrations exist at two vibration points of a wave if the points
undergo vibration in the same direction together.
For example, the particles of the string at points A and C vibrate in phase,
since they move up and down together.
A
C
Vibrations are in phase if the points are a whole number of wave lengths apart.
B
The pieces of the string at A and B vibrate opposite to each other. These
vibrations are said to be 180, or half a cycle, out of phase.
7. Week 13, Lesson 2 Wave Motion 7
Speed of a Transverse Wave
The speed of a transverse wave on a stretched string or wire is:
v = tension in string/mass per unit length of string
8. Week 13, Lesson 2 Wave Motion 8
Standing Waves
At certain vibration frequencies, a string will resonate – that is, it will vibrate
with large amplitude in vibration patterns similar to those shown below and
will appear as a blur.
These and similar vibration patterns are called standing waves.
A
B
C
D
E
The stationary points, B,D,
are called nodes.
The points of greatest motion,
A, C, E, are called antinodes.
The distance between adjacent
nodes (or antinodes) is ½ , and
is called a segment.
9. Week 13, Lesson 2 Wave Motion 9
A
B
C
D
E
Conditions for Resonance
Looking at our figure, we see that the string always resonates in whole segments
– where a segment is the distance between adjacent nodes or antinodes.
The fixed ends are always nodes. Therefore the string will resonate only if it is
one segment long, or two
segments long, or so on.
Since the length of a segment
is ½ , the string can resonate
only if it is /2 long, or 2(/2)
or 3 (/2) long, and so on.
L = /2
L = 2(/2)
L = 3(/2)
L = 4(/2)
Fundamental
First Overtone
Second Overtone
Third Overtone
L = length of resonating string
10. Week 13, Lesson 2 Wave Motion 10
In general, for resonance of a string fastened at both ends,
L = nn /2
Where n = 1,2,3, ….
And L is the Length of the resonating string
And n is the wavelength when the string resonates in n segments.
Since wavelength is related to frequency by = v/f, it can be seen that a
string of fixed length resonates only to certain special frequencies.
These discrete values of resonance frequency are integer
multiples of the fundamental resonance frequency f1 .
fn = v/n =
v
2L/n
= nf1
11. Week 13, Lesson 2 Wave Motion 11
Often the resonance frequencies of a taut string are connected
with the production of music.
The fundamental frequency f1 is sometimes referred to as the
first harmonic, with f2 , f3 , f4 , and fn as the second, third, forth,
and nth harmonics.
Thus the term harmonic in general refers to a vibration of a
single sinusoidal wave frequency, and the term simple harmonic
motion refers to periodic motion that can be described by a sine
or cosine function with a single frequency.
Harmonics
12. Week 13, Lesson 2 Wave Motion 12
Harmonics example
The speed of a wave on a particular string is 24 m/s. If the string is 6.0 m
long, to what driving frequencies will it resonate?
Answer:
For resonance to occur, the length of the string must be an integral number
of half wavelengths. Or, n = 2L/n
Therefore, 1 = 12m/1 = 12.0 m; 2 = 12 m/2 = 6.0 m; 3 =12m/3 = 4.0 m
Now, fn = v/n
Therefore,
f1 = 24 m/s / 12 m = 2.0 Hz
f2 = 24 m/s / 6.0 m = 4.0 Hz
f3 = 24 m/s / 4.0 m = 6.0 Hz
13. Week 13, Lesson 2 Wave Motion 13
Worked example
A
C
B
Suppose that the following figure represents a 50 Hz wave on a string. Take
Distance yo to be 3 mm, and distance AE to be 40 cm. What is:
a)
The amplitude,
b)
The wavelength, and
c)
The speed of the wave.
D
E
(ans. 3.0 mm, 20 cm, 10 m/s)
14. Week 13, Lesson 2 Wave Motion 14
Worked example
A horizontal cord 5 m long has a mass of 1.45 g. What must be the tension
in the cord if the wavelength of a 129 Hz on it is to be 60 cm? How large a
mass must be hung from its end (say, over a pulley) to give it this tension?
(ans. 1.50 N, 0.153 kg)
15. Week 13, Lesson 2 Wave Motion 15
Worked example
A string vibrates in five segments to a frequency of 460 Hz.
a)
What is its fundamental frequency?
b)
What will cause it to vibrate in three segments?
16. Week 13, Lesson 2 Wave Motion 16
Longitudinal Waves
Longitudinal (Compressional Waves) occur as lengthwise vibrations of air
columns, solid bars, and the like.
At resonance, nodes exist at fixed points, such as the closed end of an air
column in a tube, or the location of a clamp on a bar.
The resonance diagrams shown earlier are used to display the resonance of
longitudinal waves as well as transverse waves. However, for longitudinal
waves, the diagrams are mainly schematic and are used simply to indicate
the locations of nodes and antinodes.
In analyzing these diagrams, we use th fact that the distance between node
and adjacent antinode is ¼ .
17. Week 13, Lesson 2 Wave Motion 17
Worked example
Compressional (sound) waves are sent down an air-filled tube 90 cm long
and closed at one end. The tube resonates at several frequencies, the
lowest of which is 95 Hz. Find the speed of sound waves in air.
(ans. 342 m/s)