The document discusses the concept of approximating the area under a curve using rectangles. It shows that as the width of the rectangles decreases, the approximation becomes more accurate. The area under the curve between two points can be estimated as the difference in the area functions at those points. Ultimately, the derivative of the area function gives the exact equation of the curve, and the total area under the curve between two x-values can be calculated as the difference in the area function evaluated at those x-values.

1. Integration
Area Under Curve

2. Integration
Area Under Curve

3. Integration
Area Under Curve

4. Integration
Area Under Curve
Area  11  12 
3 3

5. Integration
Area Under Curve
Area  11  12 
3 3
Area  9

6. Integration
Area Under Curve
Area  11  12 
3 3
Area  9

7. Integration
Area Under Curve
10   11  Area  11  12 
3 3 3 3
Area  9

8. Integration
Area Under Curve
10   11  Area  11  12 
3 3 3 3
1  Area  9

9. Integration
Area Under Curve
10   11  Area  11  12 
3 3 3 3
1  Area  9
Estimate Area  5 unit 2

10. Integration
Area Under Curve
10   11  Area  11  12 
3 3 3 3
1  Area  9
Estimate Area  5 unit 2
Exact Area  4 unit 2

13. Area  0.40.43  0.83  1.23  1.63  23 

14. Area  0.40.43  0.83  1.23  1.63  23 
Area  5.76

15. Area  0.40.43  0.83  1.23  1.63  23 
Area  5.76

16. 0.403  0.43  0.83  1.23  1.63   Area  0.40.43  0.83  1.23  1.63  23 
Area  5.76

17. 0.403  0.43  0.83  1.23  1.63   Area  0.40.43  0.83  1.23  1.63  23 
2.56  Area  5.76

18. 0.403  0.43  0.83  1.23  1.63   Area  0.40.43  0.83  1.23  1.63  23 
2.56  Area  5.76
Estimate Area  4.16 unit 2

21. Area  0.20.23  0.43  0.63  0.83  13  1.23  1.43  1.63  1.83  23 

22. Area  0.20.23  0.43  0.63  0.83  13  1.23  1.43  1.63  1.83  23 
Area  4.84

23. Area  0.20.23  0.43  0.63  0.83  13  1.23  1.43  1.63  1.83  23 
Area  4.84

24. 0.203  0.23  0.43  0.63  0.83  13  1.23  1.43  1.63  1.83  
Area  0.20.23  0.43  0.63  0.83  13  1.23  1.43  1.63  1.83  23 
Area  4.84

25. 0.203  0.23  0.43  0.63  0.83  13  1.23  1.43  1.63  1.83  
Area  0.20.23  0.43  0.63  0.83  13  1.23  1.43  1.63  1.83  23 
3.24  Area  4.84

26. 0.203  0.23  0.43  0.63  0.83  13  1.23  1.43  1.63  1.83  
Area  0.20.23  0.43  0.63  0.83  13  1.23  1.43  1.63  1.83  23 
3.24  Area  4.84
Estimate Area  4.04 unit 2

27. As the widths decrease, the estimate becomes more accurate, lets
investigate one of these rectangles.
y
y = f(x)
x

28. As the widths decrease, the estimate becomes more accurate, lets
investigate one of these rectangles.
y
y = f(x)
x

29. As the widths decrease, the estimate becomes more accurate, lets
investigate one of these rectangles.
y
y = f(x)
c x
A(c) is the area from 0 to c

30. As the widths decrease, the estimate becomes more accurate, lets
investigate one of these rectangles.
y
y = f(x)
c x x
A(c) is the area from 0 to c
A(x) is the area from 0 to x

31. A(x) – A(c) denotes the area from c to x, and can be estimated by
the rectangle;

32. A(x) – A(c) denotes the area from c to x, and can be estimated by
the rectangle;
f(x)
x-c

33. A(x) – A(c) denotes the area from c to x, and can be estimated by
the rectangle;
f(x)
x-c
A x   Ac    x  c  f  x 

34. A(x) – A(c) denotes the area from c to x, and can be estimated by
the rectangle;
f(x)
x-c
A x   Ac    x  c  f  x 
A x   Ac 
f x 
xc

35. A(x) – A(c) denotes the area from c to x, and can be estimated by
the rectangle;
f(x)
x-c
A x   Ac    x  c  f  x 
A x   Ac 
f x 
xc
Ac  h   Ac 
 h = width of rectangle
h

36. A(x) – A(c) denotes the area from c to x, and can be estimated by
the rectangle;
f(x)
x-c
A x   Ac    x  c  f  x 
A x   Ac 
f x 
xc
Ac  h   Ac 
 h = width of rectangle
h
As the width of the rectangle decreases, the estimate becomes more
accurate.

37. i.e. as h  0, the Area becomes exact

38. i.e. as h  0, the Area becomes exact
Ac  h   Ac 
f  x   lim
h 0 h

39. i.e. as h  0, the Area becomes exact
Ac  h   Ac 
f  x   lim
h 0 h
A x  h   A x 
 lim
h 0
 as h  0, c  x 
h

40. i.e. as h  0, the Area becomes exact
Ac  h   Ac 
f  x   lim
h 0 h
A x  h   A x 
 lim
h 0
 as h  0, c  x 
h
 A x 

41. i.e. as h  0, the Area becomes exact
Ac  h   Ac 
f  x   lim
h 0 h
A x  h   A x 
 lim
h 0
 as h  0, c  x 
h
 A x 
 the equation of the curve is the derivative of the Area function.

42. i.e. as h  0, the Area becomes exact
Ac  h   Ac 
f  x   lim
h 0 h
A x  h   A x 
 lim
h 0
 as h  0, c  x 
h
 A x 
 the equation of the curve is the derivative of the Area function.
The area under the curve y  f  x  between x  a and x  b is;

43. i.e. as h  0, the Area becomes exact
Ac  h   Ac 
f  x   lim
h 0 h
A x  h   A x 
 lim
h 0
 as h  0, c  x 
h
 A x 
 the equation of the curve is the derivative of the Area function.
The area under the curve y  f  x  between x  a and x  b is;
b
A   f  x dx
a

44. i.e. as h  0, the Area becomes exact
Ac  h   Ac 
f  x   lim
h 0 h
A x  h   A x 
 lim
h 0
 as h  0, c  x 
h
 A x 
 the equation of the curve is the derivative of the Area function.
The area under the curve y  f  x  between x  a and x  b is;
b
A   f  x dx
a
 F b   F a 

45. i.e. as h  0, the Area becomes exact
Ac  h   Ac 
f  x   lim
h 0 h
A x  h   A x 
 lim
h 0
 as h  0, c  x 
h
 A x 
 the equation of the curve is the derivative of the Area function.
The area under the curve y  f  x  between x  a and x  b is;
b
A   f  x dx
a
 F b   F a 
where F  x  is the primitive function of f  x 

46. e.g. (i) Find the area under the curve y  x 3 , between x = 0 and
x= 2

47. e.g. (i) Find the area under the curve y  x 3 , between x = 0 and
2
x= 2
A   x 3 dx
0

48. e.g. (i) Find the area under the curve y  x 3 , between x = 0 and
2
x= 2
A   x 3 dx
0
2
  x4 
1
4 0
 

49. e.g. (i) Find the area under the curve y  x 3 , between x = 0 and
2
x= 2
A   x 3 dx
0
2
  x4 
1
4 0
 
 2  04 
1 4
4

50. e.g. (i) Find the area under the curve y  x 3 , between x = 0 and
2
x= 2
A   x 3 dx
0
2
  x4 
1
4 0
 
 2  04 
1 4
4
 4 units 2

51. e.g. (i) Find the area under the curve y  x 3 , between x = 0 and
2
x= 2
A   x 3 dx
0
2
  x4 
1
4 0
 
 2  04 
1 4
4
 4 units 2
3
ii   x 2  1dx
2

52. e.g. (i) Find the area under the curve y  x 3 , between x = 0 and
2
x= 2
A   x 3 dx
0
2
  x4 
1
4 0
 
 2  04 
1 4
4
 4 units 2
3 3
ii   x  1dx  
2 1 x 3  x 
2
2 3 

53. e.g. (i) Find the area under the curve y  x 3 , between x = 0 and
2
x= 2
A   x 3 dx
0
2
  x4 
1
4 0
 
 2  04 
1 4
4
 4 units 2
3 3
ii   x  1dx  
2 1 x 3  x 
2
2 3 
1 33  3  1 2 3  2
  
 3   3 

54. e.g. (i) Find the area under the curve y  x 3 , between x = 0 and
2
x= 2
A   x 3 dx
0
2
  x4 
1
4 0
 
 2  04 
1 4
4
 4 units 2
3 3
ii   x  1dx  
2 1 x 3  x 
2
2 3 
1 33  3  1 2 3  2
  
 3   3 
22

3

55. 5
iii   x 3dx
4

56. 5 5
 1  2 
iii   x dx   x 
3
4  2 4

57. 5 5
 1  2 
iii   x dx   x 
3
4  2 4
11 1 
   2  2
2 5 4 
9

800

58. 5 5
 1  2 
iii   x dx   x 
3
4  2 4
   2  2
1 1 1
 
2 5 4 
9

800
Exercise 11A; 1
Exercise 11B; 1 aefhi, 2ab (i,ii), 3ace, 4b, 5a, 7*