Use of NMR in Structure 
Elucidation 
Presented By: 
Anuradha Verma 
Research Scholar
Overview 
• NMR is a sensitive, non-destructive method 
for elucidating the structure of organic 
molecules 
• Information can be gained from the hydrogens 
(proton NMR, the most common), carbons 
(13C NMR) or other elements like 31P, 15N, 19F.
Making NMR work 
• Not all protons absorb at the same field values 
• Either magnetic field strength or radio 
frequency must be varied 
• Frequency/field strength at which the proton 
aďsorďs tells soŵethiŶg aďout the protoŶ’s 
surroundings
In a magnetic field the states have different energies 
Alignment with the magnetic field (called ) is 
lower energy than against the magnetic field 
(called ). How much lower it is, depends on the 
strength of the magnetic field
• Energy difference linearly depends on field 
strength 
E 
 proton spin state 
(higher energy) 
E = h x 300 MHz E = h x 500 MHz 
7.05 T 11.75 T 
Bo 
proton spin state 
(lower energy) 
Graphical relationship between 
magnetic field (B o) and frequency (   
for 1H NMR absorptions 
at no magnetic field, 
there is no difference beteen 
- and - states. 
0 T
NMR Signals 
• The number of signals shows how many different 
kinds of protons are present. 
• The location of the signals shows how shielded or 
deshielded the proton is. 
• The intensity of the signal shows the number of 
protons of that type. 
• Signal splitting shows the number of protons on 
adjacent atoms.
Chemical shift 
• Protons in different environments absorb at 
different field strengths (for the same frequency) 
• Different environment = different electron density 
around the H
Location of Signals 
• More electronegative atoms 
deshield more and give larger 
shift values. 
• Effect decreases with distance. 
• Additional electronegative 
atoms cause increase in 
chemical shift.
Typical Values 
Chapter 13
Aromatic Protons, 7-8
Vinyl Protons, 5-6
Acetylenic Protons, 2.5
O-H and N-H Signals 
• Chemical shift depends on concentration. 
• Hydrogen bonding in concentrated solutions deshield 
the protons, so signal is around 3.5 for N-H and 4.5 
for O-H. 
• Proton exchange between the molecules broaden the 
peak.
Hydroxyl Proton 
• Ultrapure samples of 
ethanol show splitting. 
• Ethanol with a small 
amount of acidic or basic 
impurities will not show 
splitting.
N-H Proton 
• Moderate rate of exchange. 
• Peak may be broad.
Identifying the O-H or N-H Peak 
• Chemical shift will depend on concentration and 
solvent. 
• To verify that a particular peak is due to O-H or N-H, 
shake the sample with D2O. 
• Deuterium will exchange with the O-H or N-H 
protons. 
• On a second NMR spectrum the peak will be absent, 
or much less intense.
Carboxylic Acid Proton, 10+
Intensity of Signals 
• The area under each peak is proportional to 
the number of protons. 
• Shown by integral trace.
Spin-Spin Splitting 
• Nonequivalent protons on adjacent carbons have 
magnetic fields that may align with or oppose the 
external field. 
• This magnetic coupling causes the proton to absorb 
slightly downfield when the external field is reinforced 
and slightly upfield when the external field is opposed.
The N + 1 Rule 
If a signal is split by N equivalent protons, 
it is split into N + 1 peaks. 
=>
Doublet: 1 Adjacent Proton 
Chapter 13 
=>
Triplet: 2 Adjacent Protons 
Chapter 13 
=>
Range of Magnetic Coupling 
• Equivalent protons do not split each other. 
• Protons bonded to the same carbon will split 
each other only if they are not equivalent. 
• Protons on adjacent carbons normally will 
couple. 
• Protons separated by four or more bonds will not 
couple.
Coupling Constants 
• Distance between the peaks of multiplet 
• Measured in Hz 
• Not dependent on strength of the external field 
• Multiplets with the same coupling constants may 
come from adjacent groups of protons that split each 
other.
Values for Coupling Constants
Complex Splitting 
• Signals may be split by adjacent protons, different 
from each other, with different coupling constants. 
• Example: 
Ha of styrene which is split by an adjacent H trans to it 
(J = 17 Hz) and an adjacent H cis to it (J = 11 Hz). 
C C 
H 
H 
a 
H 
c 
b
General Regions of Chemical Shifts 
-Disubstitutid aliphatic 
Aromatic and heteroaromatic 
Aldehydic 
Olefinic 
Aliphatic alicyclic 
-Substituted aliphatic 
Acetylenic 
-Monosubstituted aliphatic 
10 9 8 7 6 5 4 3 2 1 0  = TMS 
CH3-CH2-CH2-CH2-CH2-CH=CH-CH2-CH=CH-CH2-CH2-CH2-CH2-CH2-CH2-CH2-COOCH2 
HOCH 
HOCH2
cyclohexane 
a singlet 12H
2,3-dimethyl-2-butene 
CH3 
C 
H3C 
C 
H3C 
CH3 
a singlet 12H
benzene 
a singlet 6H
p-xylene 
H3C CH3 
a a 
b 
a singlet 6H 
b singlet 4H
tert-butyl bromide 
CH3 a singlet 9H 
C CH3 H3C 
Br
ethyl bromide 
a b 
CH3CH2-Br 
a triplet 3H 
b quartet 2H
1-bromopropane 
a b c 
CH3CH2CH2-Br 
a triplet 3H 
b complex 2H 
c triplet 3H
isopropyl chloride 
a b a 
CH3CHCH3 
Cl 
a doublet 6H 
b septet 1H
2-bromobutane 
b d c a 
CH3CHCH2CH3 
Br 
a triplet 3H 
b doublet 3H 
c complex 2H 
d complex 1H
ethylbenzene 
CH2CH3 
c 
b a 
a triplet 3H 
b quartet 2H 
c ~singlet 5H
di-n-propylether 
a b c c b a 
CH3CH2CH2-O-CH2CH2CH3 
a triplet 6H 
b complex 4H 
c triplet 4H
1-propanol 
a b d c 
CH3CH2CH2-OH 
a triplet 3H 
b complex 2H 
c singlet 1H 
d triplet 2H
13C – NMR 
13C ~ 1.1% of carbons 
1) number of signals: how many different types of carbons 
2) chemical shift: hybridization of carbon sp, sp2, sp3
2-bromobutane 
a c d b 
CH3CH2CHCH3 
Br
Summary 
•The magnetic nucleus may assume any one of ( 2 I + 1) 
orientations with respect to the directions of the applied 
magnetic field. 
•Therefore, a proton (1/2) will be able to assume only one 
of two possible orientations that correspond to energy 
levels of + or -  H in an applied magnetic field, where H 
is the strength of the external magnetic field.
Summary 
•If proper v is introduced, the Wo will be resonance with 
the properly applied radio frequency and the proton will 
absorb the applied frequency and will be raised to the 
high energy spin state. 
•Even though the external magnetic field strength (Ho) 
applied to the molecule is the same, the actual magnetic 
field strength exerted to the protons of the molecule are 
different if the protons are in the different electronic 
chemical environment.
Structure Determination of Biological 
Molecules
Structure Determination by NMR 
• Biological molecules such as proteins and nucleic acids can be large 
and complex. They can easily exceed 2000 atoms. 
• Knowing their structure is critical in understanding the relationship 
between structure and function. 
• X-ray crystallography is an excellent method to determine detailed 3D 
structures of even some of the largest biological molecules. 
• However, it has some significant difficulties. Getting crystals and the 
obtained structure may not be biologically relevant. 
• NMR can be used to determine 3D structure and dynamics in solution! 
It’s liŵitatioŶ is ŵoleĐular size. Hoǁeǀer, this is ĐhaŶgiŶg.
• Large molecules with numerous atoms nuclear magnetic moment 
does not permit the determination of these fundamental parameters 
easily. 
• Some 1D spectra are far too complex for interpretation because 
signals overlap heavily. 
• e.g. cholesterols, protein spectra
How 2D NMR is useful? 
 Nonequivalent proton groups can have nearly the same chemical shift and/or 
complex splitting patterns making 1D NMR spectra complicated even for 
relatively simple molecules. 
 The introduction of additional spectral dimensions simplifies the spectra and 
provides more information. 
 Two-dimensional (2D) NMR techniques can be used to solve such sophisticated 
structural problems. 
 2-D spectra simplify the complexity arising from overlapping of peaks. 
 Simplification of NMR spectra makes their interpretation easier and sometimes 
the only way possible. 
 The interaction of nuclear spins (1H with 1H, 1H with 13C, etc.) are plotted in two 
dimensions
• In 2-D spectra the intensity is plotted as a 
function of two frequencies, usually represented 
as F1 and F2. F1 and F2 are Fourier transformed 
frequency axis from a time domain signal.
H-H Correlation Spectroscopy (COSY) 
• In a COSY experiment, the chemical shift range 
of the proton spectrum is plotted on both axis.
• COSY spectrum of a molecule containing just one 
type of protons HX. 
• COSY spectrum of a hypothetical molecule 
containing just two protons, HA and HX, which are 
not coupled
• COSY spectrum of a hypothetical molecule containing just two types 
of protons, HA and HX, which are coupled 
• Signals on the diagonal divides the spectrum in two equal halves. 
Signals symmetrical to the diagonal called cross signals (peaks). 
• The cross signals originate from nuclei that exchanged magnetization 
during the mixing time. They indicate an interaction of these two 
nuclei. The cross signals contain the information of 2D NMR spectra.
• If there had been no coupling, their 
magnetizations would not have given rise to off-diagonal 
peaks. 
• COSY spectrum shows which pairs in a molecule 
are Đoupled (thro’ ďond Đoupling, henĐe 
connectivity). 
• From a single COSY spectrum it is possible to 
trace out the whole coupling network in the 
molecule.
31P - NMR
• 31P-NMR allowed the measurement of the 
intracellular pH of the muscle, resting or 
fatigued, through the shift of the frequency of 
the Pi peak 
• The major phosphate metabolites of muscle are: 
ATP, PCr, Pi. ATP and PCr occur at high 
concentrations in normal resting muscle, 
whereas the appearance of Pi indicates fatigue.
31P-Spectroscopy of Heart Muscle 
• 31P spectrum of beating rat heart shows the 
Pi, PCr, and ATP resonances
Thank You

use of nmr in structure ellucidation

  • 1.
    Use of NMRin Structure Elucidation Presented By: Anuradha Verma Research Scholar
  • 2.
    Overview • NMRis a sensitive, non-destructive method for elucidating the structure of organic molecules • Information can be gained from the hydrogens (proton NMR, the most common), carbons (13C NMR) or other elements like 31P, 15N, 19F.
  • 3.
    Making NMR work • Not all protons absorb at the same field values • Either magnetic field strength or radio frequency must be varied • Frequency/field strength at which the proton aďsorďs tells soŵethiŶg aďout the protoŶ’s surroundings
  • 4.
    In a magneticfield the states have different energies Alignment with the magnetic field (called ) is lower energy than against the magnetic field (called ). How much lower it is, depends on the strength of the magnetic field
  • 5.
    • Energy differencelinearly depends on field strength E  proton spin state (higher energy) E = h x 300 MHz E = h x 500 MHz 7.05 T 11.75 T Bo proton spin state (lower energy) Graphical relationship between magnetic field (B o) and frequency (   for 1H NMR absorptions at no magnetic field, there is no difference beteen - and - states. 0 T
  • 6.
    NMR Signals •The number of signals shows how many different kinds of protons are present. • The location of the signals shows how shielded or deshielded the proton is. • The intensity of the signal shows the number of protons of that type. • Signal splitting shows the number of protons on adjacent atoms.
  • 7.
    Chemical shift •Protons in different environments absorb at different field strengths (for the same frequency) • Different environment = different electron density around the H
  • 8.
    Location of Signals • More electronegative atoms deshield more and give larger shift values. • Effect decreases with distance. • Additional electronegative atoms cause increase in chemical shift.
  • 9.
  • 10.
  • 11.
  • 12.
  • 13.
    O-H and N-HSignals • Chemical shift depends on concentration. • Hydrogen bonding in concentrated solutions deshield the protons, so signal is around 3.5 for N-H and 4.5 for O-H. • Proton exchange between the molecules broaden the peak.
  • 14.
    Hydroxyl Proton •Ultrapure samples of ethanol show splitting. • Ethanol with a small amount of acidic or basic impurities will not show splitting.
  • 15.
    N-H Proton •Moderate rate of exchange. • Peak may be broad.
  • 16.
    Identifying the O-Hor N-H Peak • Chemical shift will depend on concentration and solvent. • To verify that a particular peak is due to O-H or N-H, shake the sample with D2O. • Deuterium will exchange with the O-H or N-H protons. • On a second NMR spectrum the peak will be absent, or much less intense.
  • 17.
  • 18.
    Intensity of Signals • The area under each peak is proportional to the number of protons. • Shown by integral trace.
  • 19.
    Spin-Spin Splitting •Nonequivalent protons on adjacent carbons have magnetic fields that may align with or oppose the external field. • This magnetic coupling causes the proton to absorb slightly downfield when the external field is reinforced and slightly upfield when the external field is opposed.
  • 20.
    The N +1 Rule If a signal is split by N equivalent protons, it is split into N + 1 peaks. =>
  • 21.
    Doublet: 1 AdjacentProton Chapter 13 =>
  • 22.
    Triplet: 2 AdjacentProtons Chapter 13 =>
  • 23.
    Range of MagneticCoupling • Equivalent protons do not split each other. • Protons bonded to the same carbon will split each other only if they are not equivalent. • Protons on adjacent carbons normally will couple. • Protons separated by four or more bonds will not couple.
  • 24.
    Coupling Constants •Distance between the peaks of multiplet • Measured in Hz • Not dependent on strength of the external field • Multiplets with the same coupling constants may come from adjacent groups of protons that split each other.
  • 25.
  • 26.
    Complex Splitting •Signals may be split by adjacent protons, different from each other, with different coupling constants. • Example: Ha of styrene which is split by an adjacent H trans to it (J = 17 Hz) and an adjacent H cis to it (J = 11 Hz). C C H H a H c b
  • 27.
    General Regions ofChemical Shifts -Disubstitutid aliphatic Aromatic and heteroaromatic Aldehydic Olefinic Aliphatic alicyclic -Substituted aliphatic Acetylenic -Monosubstituted aliphatic 10 9 8 7 6 5 4 3 2 1 0  = TMS CH3-CH2-CH2-CH2-CH2-CH=CH-CH2-CH=CH-CH2-CH2-CH2-CH2-CH2-CH2-CH2-COOCH2 HOCH HOCH2
  • 28.
  • 29.
    2,3-dimethyl-2-butene CH3 C H3C C H3C CH3 a singlet 12H
  • 30.
  • 31.
    p-xylene H3C CH3 a a b a singlet 6H b singlet 4H
  • 32.
    tert-butyl bromide CH3a singlet 9H C CH3 H3C Br
  • 33.
    ethyl bromide ab CH3CH2-Br a triplet 3H b quartet 2H
  • 34.
    1-bromopropane a bc CH3CH2CH2-Br a triplet 3H b complex 2H c triplet 3H
  • 35.
    isopropyl chloride ab a CH3CHCH3 Cl a doublet 6H b septet 1H
  • 36.
    2-bromobutane b dc a CH3CHCH2CH3 Br a triplet 3H b doublet 3H c complex 2H d complex 1H
  • 37.
    ethylbenzene CH2CH3 c b a a triplet 3H b quartet 2H c ~singlet 5H
  • 38.
    di-n-propylether a bc c b a CH3CH2CH2-O-CH2CH2CH3 a triplet 6H b complex 4H c triplet 4H
  • 39.
    1-propanol a bd c CH3CH2CH2-OH a triplet 3H b complex 2H c singlet 1H d triplet 2H
  • 40.
    13C – NMR 13C ~ 1.1% of carbons 1) number of signals: how many different types of carbons 2) chemical shift: hybridization of carbon sp, sp2, sp3
  • 41.
    2-bromobutane a cd b CH3CH2CHCH3 Br
  • 42.
    Summary •The magneticnucleus may assume any one of ( 2 I + 1) orientations with respect to the directions of the applied magnetic field. •Therefore, a proton (1/2) will be able to assume only one of two possible orientations that correspond to energy levels of + or -  H in an applied magnetic field, where H is the strength of the external magnetic field.
  • 43.
    Summary •If properv is introduced, the Wo will be resonance with the properly applied radio frequency and the proton will absorb the applied frequency and will be raised to the high energy spin state. •Even though the external magnetic field strength (Ho) applied to the molecule is the same, the actual magnetic field strength exerted to the protons of the molecule are different if the protons are in the different electronic chemical environment.
  • 44.
    Structure Determination ofBiological Molecules
  • 45.
    Structure Determination byNMR • Biological molecules such as proteins and nucleic acids can be large and complex. They can easily exceed 2000 atoms. • Knowing their structure is critical in understanding the relationship between structure and function. • X-ray crystallography is an excellent method to determine detailed 3D structures of even some of the largest biological molecules. • However, it has some significant difficulties. Getting crystals and the obtained structure may not be biologically relevant. • NMR can be used to determine 3D structure and dynamics in solution! It’s liŵitatioŶ is ŵoleĐular size. Hoǁeǀer, this is ĐhaŶgiŶg.
  • 46.
    • Large moleculeswith numerous atoms nuclear magnetic moment does not permit the determination of these fundamental parameters easily. • Some 1D spectra are far too complex for interpretation because signals overlap heavily. • e.g. cholesterols, protein spectra
  • 47.
    How 2D NMRis useful?  Nonequivalent proton groups can have nearly the same chemical shift and/or complex splitting patterns making 1D NMR spectra complicated even for relatively simple molecules.  The introduction of additional spectral dimensions simplifies the spectra and provides more information.  Two-dimensional (2D) NMR techniques can be used to solve such sophisticated structural problems.  2-D spectra simplify the complexity arising from overlapping of peaks.  Simplification of NMR spectra makes their interpretation easier and sometimes the only way possible.  The interaction of nuclear spins (1H with 1H, 1H with 13C, etc.) are plotted in two dimensions
  • 48.
    • In 2-Dspectra the intensity is plotted as a function of two frequencies, usually represented as F1 and F2. F1 and F2 are Fourier transformed frequency axis from a time domain signal.
  • 49.
    H-H Correlation Spectroscopy(COSY) • In a COSY experiment, the chemical shift range of the proton spectrum is plotted on both axis.
  • 50.
    • COSY spectrumof a molecule containing just one type of protons HX. • COSY spectrum of a hypothetical molecule containing just two protons, HA and HX, which are not coupled
  • 51.
    • COSY spectrumof a hypothetical molecule containing just two types of protons, HA and HX, which are coupled • Signals on the diagonal divides the spectrum in two equal halves. Signals symmetrical to the diagonal called cross signals (peaks). • The cross signals originate from nuclei that exchanged magnetization during the mixing time. They indicate an interaction of these two nuclei. The cross signals contain the information of 2D NMR spectra.
  • 52.
    • If therehad been no coupling, their magnetizations would not have given rise to off-diagonal peaks. • COSY spectrum shows which pairs in a molecule are Đoupled (thro’ ďond Đoupling, henĐe connectivity). • From a single COSY spectrum it is possible to trace out the whole coupling network in the molecule.
  • 53.
  • 54.
    • 31P-NMR allowedthe measurement of the intracellular pH of the muscle, resting or fatigued, through the shift of the frequency of the Pi peak • The major phosphate metabolites of muscle are: ATP, PCr, Pi. ATP and PCr occur at high concentrations in normal resting muscle, whereas the appearance of Pi indicates fatigue.
  • 55.
    31P-Spectroscopy of HeartMuscle • 31P spectrum of beating rat heart shows the Pi, PCr, and ATP resonances
  • 56.