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TELE4653 Digital Modulation &
          Coding
                  Digital Modulation
                          Wei Zhang
                     w.zhang@unsw.edu.au


    School of Electrical Engineering and Telecommunications
              The University of New South Wales
Outline

 PAM (ASK)
 PSK
 QAM
 FSK




             TELE4653 - Digital Modulation & Coding - Lecture 2. March 8, 2010. – p.1/2
Modulation

 Source information to be transmitted is usually in the form of
 a binary data stream.
 The transmission medium, i.e., communication channel
 suffers from noise, attenuation, distortion, fading, and
 interference.
 Digital Modulation - To generate a signal that represents the
 binary data stream and matches the characteristics of the
 channel
 Modulation with Memoryless or with Memory




                                      TELE4653 - Digital Modulation & Coding - Lecture 2. March 8, 2010. – p.2/2
Definitions
                                                                                           1
 Signaling Interval: Ts . Signaling (Symbol) Rate: Rs =                                    Ts .
                      Ts
 Bit Interval: Tb =   k    for a signal carrying k bits of
 information.
 Bit Rate: R = kRs = Rs logM .
                           2
                                         M
 Average signal energy: Eavg =           m=1 pm Em              with pm being
 the probability of the mth signal.
                                        Eavg         Eavg
 Average energy per bit: Ebavg =         k     =     logM
                                                          .
                                                        2




                                               TELE4653 - Digital Modulation & Coding - Lecture 2. March 8, 2010. – p.3/2
PAM

The signal waveform may be represented as

                sm (t) = Am p(t), 1 ≤ m ≤ M                                                     (1)

where p(t) is a pulse of duration T and Am denotes the
amplitude with the mth value, given by

              Am = 2m − 1 − M, 1 ≤ m ≤ M                                                        (2)

i.e., the amplitudes are ±1, ±3, ±5, · · · , ±(M − 1).
Digital amplitude modulation is usually called amplitude-shift
keying (ASK).



                                          TELE4653 - Digital Modulation & Coding - Lecture 2. March 8, 2010. – p.4/2
PAM

The energy of signal sm (t) is given by
                           ∞
                Em =           A2 p2 (t)dt = A2 Ep
                                m             m                                                          (3)
                       −∞

The average signal energy is
                               M                      M
                                              Ep
                Eavg =             p m Em =                   A2
                                                               m
                                              M
                           m=1                      m=1
                           (M 2    − 1)Ep
                       =                  .                                                              (4)
                                   3
and the average energy per bit is
                           (M 2 − 1)Ep
                   Ebavg =         M
                                       .                                                                 (5)
                              3 log2
                                                   TELE4653 - Digital Modulation & Coding - Lecture 2. March 8, 2010. – p.6/2
Bandpass PAM
The bandpass PAM signals are carrier-modulated bandpass
signals with lowpass equivalents of the form s ml (t) = Am g(t),
where Am and g(t) are real. The signal waveform is

        sm (t) =     sml (t)ej2πfc t = Am g(t) cos(2πfc t)                                            (6)


The energy of signal sm (t) is given by

                                A2
                          Em   = m Eg .                                                               (7)
                                 2
Moreover,
                     (M 2 −1)Eg               (M 2 −1)Eg
            Eavg =        6     ,   Ebavg =    6 logM
                                                         .                                            (8)
                                                    2




                                                TELE4653 - Digital Modulation & Coding - Lecture 2. March 8, 2010. – p.7/2
Bandpass PAM - Expansion

For basedband PAM, the expansion of sm (t) = Am p(t) is

                   sm (t) = Am      Ep φ(t)                                                         (9)

where                           p(t)
                         φ(t) =      .                                                            (10)
                                  Ep

For bandpass PAM, the expansion of sm (t) =                        sml (t)ej2πfc t
is [Tutorial 1]
                              Eg
                sm (t) = Am      φ(t)                                                             (11)
                               2
where
                           2
                φ(t) =        g(t) cos(2πfc t).                                                   (12)
                           Eg
                                              TELE4653 - Digital Modulation & Coding - Lecture 2. March 8, 2010. – p.9/2
Bandpass PAM - dmin
The bandpass PAM can be represented as the one-dimensional
                    E
vector: sm = Am 2g , where Am = ±1, ±3, · · · , ±(M − 1).
The Euclidean distance between any pair of signal points is

                                   2
                                                               Eg
           dmn =        s m − sn       = |Am − An |                                                 (13)
                                                               2
For adjacent signal points |Am − An | = 2, it has

                                       12 log2 M
              dmin =      2Eg =                  E
                                           2 − 1 bavg
                                                                                                    (14)
                                        M
where in the last equality Eq. (8) is used.


                                               TELE4653 - Digital Modulation & Coding - Lecture 2. March 8, 2010. – p.10/2
Phase Modulation

The bandpass PM signal waveform may be represented as
                                       2π(m−1)
                                   j
        sm (t) =           g(t)e          M      ej2πfc t , 1 ≤ m ≤ M
                            2π(m − 1)
                 = g(t) cos           + 2πfc t                                                             (15)
                               M
           2π(m−1)
Let θm =      M    ,   m = 1, 2, · · · , M . Then,

    sm (t) = g(t) cos θm cos(2πfc t) − g(t) sin θm sin(2πfc t).                                            (16)

Digital phase modulation is usually called phase-shift keying
(PSK).
The PSK signals have equal energy, Eavg = Em = 1 Eg .
                                                  2

                                                      TELE4653 - Digital Modulation & Coding - Lecture 2. March 8, 2010. – p.11/2
Phase Modulation - Expansion
                                                    2π(m−1)
                                                j
The expansion of PM signal s(t) =       g(t)e          M            ej2πfc t is

                    Eg                  Eg         ˜
        sm (t) =       cos(θm )φ(t) +      sin(θm )φ(t)                                         (17)
                    2                   2
where [see Tutorial 1]

                              2
                   φ(t) =        g(t) cos(2πfc t)                                               (18)
                              Eg

                   ˜            2
                   φ(t) = −        g(t) sin(2πfc t)                                             (19)
                                Eg



                                           TELE4653 - Digital Modulation & Coding - Lecture 2. March 8, 2010. – p.13/2
Phase Modulation - dmin
The bandpass PM can be represented as the two-dimensional
                  Eg               Eg
vector: sm =       2   cos θm ,     2   sin θm , m = 1, 2, · · · , M . Note

θm = 2π(m−1) for m = 1, 2, · · · , M .
        M
The Euclidean distance between any pair of signal points is

                         2
                                  Eg
dmn =          sm − sn       =           | cos θm − cos θn |2 + | sin θm − sin θn |2
                                  2
     =      Eg [1 − cos(θm − θn )].                                                                                (20)




                                                 TELE4653 - Digital Modulation & Coding - Lecture 2. March 8, 2010. – p.14/2
Phase Modulation - dmin

For adjacent signal points |m − n| = 1, it has

                                        2π
             dmin =        Eg   1 − cos( )                                                        (21)
                                        M

                                     2   π
                    =      2Eg sin                                                                (22)
                                         M
                                                      2      π
                    = 2 Ebavg log2 M × sin                                                        (23)
                                                             M
                                         π        π
For large values of M , we have sin      M   ≈    M,      and then

                                         π2
                dmin   ≈ 2 Ebavg log2 M × 2                                                       (24)
                                         M

                                             TELE4653 - Digital Modulation & Coding - Lecture 2. March 8, 2010. – p.15/2
QAM

The quadrature amplitude modulation (QAM) signal waveform
may be expressed as

   sm (t) =       (Ami + jAmq )g(t)ej2πfc t , m = 1, 2, · · · , M
           = Ami g(t) cos(2πfc t) − Amq g(t) sin(2πfc t),                                      (25)

where Ami and Amq are the information-bearing signal
amplitudes of the quadrature carriers and g(t) is the signal pulse.




                                          TELE4653 - Digital Modulation & Coding - Lecture 2. March 8, 2010. – p.16/2
QAM

Alternatively, the QAM signal may be expressed as

              sm (t) =      rm g(t)ejθm ej2πfc t
                     = rm g(t) cos(θm + 2πfc t),                                              (26)


where rm =    A2 + A2 and θm = tan−1 (Amq /Ami ).
               mi   mq
It is apparent that QAM signal can be viewed as combined
amplitude rm and phase θm modulation.




                                         TELE4653 - Digital Modulation & Coding - Lecture 2. March 8, 2010. – p.17/2
QAM - Expansion
                                      ˜
Similar to PSK case, φ(t) in (18) and φ(t) in (19) can be used as
orthonormal basis for expansion of QAM signals [Tutorial 1]

                               Eg                  Eg ˜
            sm (t) = Ami          φ(t) + Amq          φ(t)                                          (27)
                               2                   2
which results in vector representation of the form

                                         Eg                   Eg
         sm = (sm1 , sm2 ) =       Ami      , Amq                                                   (28)
                                         2                    2

and
                           2       Eg
              Em = s m         =      A2 + A 2 .
                                       mi    mq                                                     (29)
                                   2

                                               TELE4653 - Digital Modulation & Coding - Lecture 2. March 8, 2010. – p.19/2
QAM - dmin

The Euclidean distance between any pair of signal vectors in
QAM is

         dmn =        s m − sn   2

                     Eg
               =        [(Ami − Ani )2 + (Amq − Anq )2 ].                                         (30)
                     2
In the case when the signal amplitude take values of
                  √
±1, ±3, · · · , ±( M − 1) on both Ami and Amq , the signal space
diagram is rectangular, as shown in Fig. on next page. In this
case,

                       dmin =        2Eg .                                                        (31)


                                             TELE4653 - Digital Modulation & Coding - Lecture 2. March 8, 2010. – p.20/2
Square QAM

In the case of square QAM (i,e., M = 4, 16, 64, 256, · · · ) with
                                √
amplitudes of ±1, ±3, · · · , ±( M − 1)
                               √ √
                                M M
                        1 Eg
            Eavg =                       (A2 + A2 )
                                           m    n
                        M 2
                               m=1 n=1
                         Eg   2M (M − 1)   M −1
                   =        ×            =      Eg                                                  (32)
                        2M        3          3
and
                                  M −1
                    Ebavg =               Eg                                                        (33)
                                 3 log2 M
                                   6 log2 M
                     dmin =                 Ebavg                                                   (34)
                                    M −1

                                               TELE4653 - Digital Modulation & Coding - Lecture 2. March 8, 2010. – p.22/2
PAM, PSK, QAM

For bandpass PAM, PSK, and QAM, the signaling schemes are
of the general form

       sm (t) =    Am g(t)ej2πfc t , m = 1, 2, · · · , M                                       (35)


    For PAM, Am is real, equal to ±1, ±3, · · · , ±(M − 1)
                                                 j 2π (m−1)
    For PSK, Am is complex and equal to e          M


    For QAM, Am = Ami + jAmq .
Therefore, PAM and PSK can be considered as special cases of
QAM.



                                          TELE4653 - Digital Modulation & Coding - Lecture 2. March 8, 2010. – p.23/2
FSK

The FSK signal waveform is

     sm (t) =       sml (t)ej2πfc t , 1 ≤ m ≤ M, 0 ≤ t ≤ T

                   2E
             =        cos (2πfc t + 2πm∆f t)                                                    (36)
                   T

                  2E j2πm∆f t
where sml (t) =   T e         ,   1 ≤ m ≤ M and 0 ≤ t ≤ T .

FSK signaling is a nonlinear modulation scheme, whereas ASK,
PSK, and QAM are linear modulation schemes.




                                           TELE4653 - Digital Modulation & Coding - Lecture 2. March 8, 2010. – p.24/2
FSK

FSK is an orthogonal signaling if           [ sml (t), snl (t) ] = 0, m = n.
                                        T
                              2E
           sml (t), snl (t) =               ej2π(m−n)∆f t dt                                           (37)
                              T     0

and

           [ sml (t), snl (t) ] = 2Esinc(2T (m − n)∆f )                                                (38)

FSK is an orthogonal signaling when ∆f = k/2T . The minimum
frequency separation ∆f that guarantees orthogonality is
       1
∆f = 2T .



                                                  TELE4653 - Digital Modulation & Coding - Lecture 2. March 8, 2010. – p.25/2

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Tele4653 l2

  • 1. TELE4653 Digital Modulation & Coding Digital Modulation Wei Zhang w.zhang@unsw.edu.au School of Electrical Engineering and Telecommunications The University of New South Wales
  • 2. Outline PAM (ASK) PSK QAM FSK TELE4653 - Digital Modulation & Coding - Lecture 2. March 8, 2010. – p.1/2
  • 3. Modulation Source information to be transmitted is usually in the form of a binary data stream. The transmission medium, i.e., communication channel suffers from noise, attenuation, distortion, fading, and interference. Digital Modulation - To generate a signal that represents the binary data stream and matches the characteristics of the channel Modulation with Memoryless or with Memory TELE4653 - Digital Modulation & Coding - Lecture 2. March 8, 2010. – p.2/2
  • 4. Definitions 1 Signaling Interval: Ts . Signaling (Symbol) Rate: Rs = Ts . Ts Bit Interval: Tb = k for a signal carrying k bits of information. Bit Rate: R = kRs = Rs logM . 2 M Average signal energy: Eavg = m=1 pm Em with pm being the probability of the mth signal. Eavg Eavg Average energy per bit: Ebavg = k = logM . 2 TELE4653 - Digital Modulation & Coding - Lecture 2. March 8, 2010. – p.3/2
  • 5. PAM The signal waveform may be represented as sm (t) = Am p(t), 1 ≤ m ≤ M (1) where p(t) is a pulse of duration T and Am denotes the amplitude with the mth value, given by Am = 2m − 1 − M, 1 ≤ m ≤ M (2) i.e., the amplitudes are ±1, ±3, ±5, · · · , ±(M − 1). Digital amplitude modulation is usually called amplitude-shift keying (ASK). TELE4653 - Digital Modulation & Coding - Lecture 2. March 8, 2010. – p.4/2
  • 6.
  • 7. PAM The energy of signal sm (t) is given by ∞ Em = A2 p2 (t)dt = A2 Ep m m (3) −∞ The average signal energy is M M Ep Eavg = p m Em = A2 m M m=1 m=1 (M 2 − 1)Ep = . (4) 3 and the average energy per bit is (M 2 − 1)Ep Ebavg = M . (5) 3 log2 TELE4653 - Digital Modulation & Coding - Lecture 2. March 8, 2010. – p.6/2
  • 8. Bandpass PAM The bandpass PAM signals are carrier-modulated bandpass signals with lowpass equivalents of the form s ml (t) = Am g(t), where Am and g(t) are real. The signal waveform is sm (t) = sml (t)ej2πfc t = Am g(t) cos(2πfc t) (6) The energy of signal sm (t) is given by A2 Em = m Eg . (7) 2 Moreover, (M 2 −1)Eg (M 2 −1)Eg Eavg = 6 , Ebavg = 6 logM . (8) 2 TELE4653 - Digital Modulation & Coding - Lecture 2. March 8, 2010. – p.7/2
  • 9.
  • 10. Bandpass PAM - Expansion For basedband PAM, the expansion of sm (t) = Am p(t) is sm (t) = Am Ep φ(t) (9) where p(t) φ(t) = . (10) Ep For bandpass PAM, the expansion of sm (t) = sml (t)ej2πfc t is [Tutorial 1] Eg sm (t) = Am φ(t) (11) 2 where 2 φ(t) = g(t) cos(2πfc t). (12) Eg TELE4653 - Digital Modulation & Coding - Lecture 2. March 8, 2010. – p.9/2
  • 11. Bandpass PAM - dmin The bandpass PAM can be represented as the one-dimensional E vector: sm = Am 2g , where Am = ±1, ±3, · · · , ±(M − 1). The Euclidean distance between any pair of signal points is 2 Eg dmn = s m − sn = |Am − An | (13) 2 For adjacent signal points |Am − An | = 2, it has 12 log2 M dmin = 2Eg = E 2 − 1 bavg (14) M where in the last equality Eq. (8) is used. TELE4653 - Digital Modulation & Coding - Lecture 2. March 8, 2010. – p.10/2
  • 12. Phase Modulation The bandpass PM signal waveform may be represented as 2π(m−1) j sm (t) = g(t)e M ej2πfc t , 1 ≤ m ≤ M 2π(m − 1) = g(t) cos + 2πfc t (15) M 2π(m−1) Let θm = M , m = 1, 2, · · · , M . Then, sm (t) = g(t) cos θm cos(2πfc t) − g(t) sin θm sin(2πfc t). (16) Digital phase modulation is usually called phase-shift keying (PSK). The PSK signals have equal energy, Eavg = Em = 1 Eg . 2 TELE4653 - Digital Modulation & Coding - Lecture 2. March 8, 2010. – p.11/2
  • 13.
  • 14. Phase Modulation - Expansion 2π(m−1) j The expansion of PM signal s(t) = g(t)e M ej2πfc t is Eg Eg ˜ sm (t) = cos(θm )φ(t) + sin(θm )φ(t) (17) 2 2 where [see Tutorial 1] 2 φ(t) = g(t) cos(2πfc t) (18) Eg ˜ 2 φ(t) = − g(t) sin(2πfc t) (19) Eg TELE4653 - Digital Modulation & Coding - Lecture 2. March 8, 2010. – p.13/2
  • 15. Phase Modulation - dmin The bandpass PM can be represented as the two-dimensional Eg Eg vector: sm = 2 cos θm , 2 sin θm , m = 1, 2, · · · , M . Note θm = 2π(m−1) for m = 1, 2, · · · , M . M The Euclidean distance between any pair of signal points is 2 Eg dmn = sm − sn = | cos θm − cos θn |2 + | sin θm − sin θn |2 2 = Eg [1 − cos(θm − θn )]. (20) TELE4653 - Digital Modulation & Coding - Lecture 2. March 8, 2010. – p.14/2
  • 16. Phase Modulation - dmin For adjacent signal points |m − n| = 1, it has 2π dmin = Eg 1 − cos( ) (21) M 2 π = 2Eg sin (22) M 2 π = 2 Ebavg log2 M × sin (23) M π π For large values of M , we have sin M ≈ M, and then π2 dmin ≈ 2 Ebavg log2 M × 2 (24) M TELE4653 - Digital Modulation & Coding - Lecture 2. March 8, 2010. – p.15/2
  • 17. QAM The quadrature amplitude modulation (QAM) signal waveform may be expressed as sm (t) = (Ami + jAmq )g(t)ej2πfc t , m = 1, 2, · · · , M = Ami g(t) cos(2πfc t) − Amq g(t) sin(2πfc t), (25) where Ami and Amq are the information-bearing signal amplitudes of the quadrature carriers and g(t) is the signal pulse. TELE4653 - Digital Modulation & Coding - Lecture 2. March 8, 2010. – p.16/2
  • 18. QAM Alternatively, the QAM signal may be expressed as sm (t) = rm g(t)ejθm ej2πfc t = rm g(t) cos(θm + 2πfc t), (26) where rm = A2 + A2 and θm = tan−1 (Amq /Ami ). mi mq It is apparent that QAM signal can be viewed as combined amplitude rm and phase θm modulation. TELE4653 - Digital Modulation & Coding - Lecture 2. March 8, 2010. – p.17/2
  • 19.
  • 20. QAM - Expansion ˜ Similar to PSK case, φ(t) in (18) and φ(t) in (19) can be used as orthonormal basis for expansion of QAM signals [Tutorial 1] Eg Eg ˜ sm (t) = Ami φ(t) + Amq φ(t) (27) 2 2 which results in vector representation of the form Eg Eg sm = (sm1 , sm2 ) = Ami , Amq (28) 2 2 and 2 Eg Em = s m = A2 + A 2 . mi mq (29) 2 TELE4653 - Digital Modulation & Coding - Lecture 2. March 8, 2010. – p.19/2
  • 21. QAM - dmin The Euclidean distance between any pair of signal vectors in QAM is dmn = s m − sn 2 Eg = [(Ami − Ani )2 + (Amq − Anq )2 ]. (30) 2 In the case when the signal amplitude take values of √ ±1, ±3, · · · , ±( M − 1) on both Ami and Amq , the signal space diagram is rectangular, as shown in Fig. on next page. In this case, dmin = 2Eg . (31) TELE4653 - Digital Modulation & Coding - Lecture 2. March 8, 2010. – p.20/2
  • 22.
  • 23. Square QAM In the case of square QAM (i,e., M = 4, 16, 64, 256, · · · ) with √ amplitudes of ±1, ±3, · · · , ±( M − 1) √ √ M M 1 Eg Eavg = (A2 + A2 ) m n M 2 m=1 n=1 Eg 2M (M − 1) M −1 = × = Eg (32) 2M 3 3 and M −1 Ebavg = Eg (33) 3 log2 M 6 log2 M dmin = Ebavg (34) M −1 TELE4653 - Digital Modulation & Coding - Lecture 2. March 8, 2010. – p.22/2
  • 24. PAM, PSK, QAM For bandpass PAM, PSK, and QAM, the signaling schemes are of the general form sm (t) = Am g(t)ej2πfc t , m = 1, 2, · · · , M (35) For PAM, Am is real, equal to ±1, ±3, · · · , ±(M − 1) j 2π (m−1) For PSK, Am is complex and equal to e M For QAM, Am = Ami + jAmq . Therefore, PAM and PSK can be considered as special cases of QAM. TELE4653 - Digital Modulation & Coding - Lecture 2. March 8, 2010. – p.23/2
  • 25. FSK The FSK signal waveform is sm (t) = sml (t)ej2πfc t , 1 ≤ m ≤ M, 0 ≤ t ≤ T 2E = cos (2πfc t + 2πm∆f t) (36) T 2E j2πm∆f t where sml (t) = T e , 1 ≤ m ≤ M and 0 ≤ t ≤ T . FSK signaling is a nonlinear modulation scheme, whereas ASK, PSK, and QAM are linear modulation schemes. TELE4653 - Digital Modulation & Coding - Lecture 2. March 8, 2010. – p.24/2
  • 26. FSK FSK is an orthogonal signaling if [ sml (t), snl (t) ] = 0, m = n. T 2E sml (t), snl (t) = ej2π(m−n)∆f t dt (37) T 0 and [ sml (t), snl (t) ] = 2Esinc(2T (m − n)∆f ) (38) FSK is an orthogonal signaling when ∆f = k/2T . The minimum frequency separation ∆f that guarantees orthogonality is 1 ∆f = 2T . TELE4653 - Digital Modulation & Coding - Lecture 2. March 8, 2010. – p.25/2