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Riemann Sums and the
Definite Integral
Why?
Why is the area of the yellow rectangle at the end (look
at the applet on this lesson)
 =
a bx∆
( )( ) ( )x f b f a∆ × −
Review
We partition the interval into n sub-intervals
Evaluate f(x) at right endpoints
of kth
sub-interval for k = 1, 2, 3, … n
a b
f(x)
b a
x
n
−
∆ =
a k x+ ×∆
Review
Sum
We expect Sn to improve
thus we define A, the area under the curve, to equal
the above limit.
a b
1
lim ( )
n
n
n
k
S f a k x x
→∞
=
= + ×∆ ×∆∑
f(x)
Look at
Goegebra demo
Look at
Goegebra demo
Riemann Sum
1. Partition the interval [a,b] into n subintervals
a = x0 < x1 … < xn-1< xn = b
1. Call this partition P
2. The kth
subinterval is ∆xk = xk-1 – xk
3. Largest ∆xk is called the norm, called ||P||
— Choose an arbitrary value from each
subinterval, call it
ic
Riemann Sum
3. Form the sum
4. This is the Riemann sum associated with
• the function f
• the given partition P
• the chosen subinterval representatives
 We will express a variety of quantities in terms of the
Riemann sum
1 1 2 2
1
( ) ( ) ... ( ) ( )
n
n n n i i
i
R f c x f c x f c x f c x
=
= ∆ + ∆ + + ∆ = ∆∑
ic
The Riemann Sum
Calculated
Consider the function
2x2
– 7x + 5
Use ∆x = 0.1
Let the = left edge
of each subinterval
Note the sum
x 2x^2-7x+5 dx * f(x)
4 9 0.9
4.1 9.92 0.992
4.2 10.88 1.088
4.3 11.88 1.188
4.4 12.92 1.292
4.5 14 1.4
4.6 15.12 1.512
4.7 16.28 1.628
4.8 17.48 1.748
4.9 18.72 1.872
5 20 2
5.1 21.32 2.132
5.2 22.68 2.268
5.3 24.08 2.408
5.4 25.52 2.552
5.5 27 2.7
5.6 28.52 2.852
5.7 30.08 3.008
5.8 31.68 3.168
5.9 33.32 3.332
Riemann sum = 40.04
ic
The Riemann Sum
We have summed a series of boxes
If the ∆x were smaller, we would have gotten a better
approximation
f(x) = 2x2
– 7x + 5
1
( ) 40.04
n
i i
i
f c x
=
∆ =∑
The Definite Integral
The definite integral is the limit of the Riemann sum
We say that f is integrable when
the number I can be approximated as accurate as needed by
making ||P|| sufficiently small
f must exist on [a,b] and the Riemann sum must exist
( )0
1
lim( )
b
a P
n
i i
k
f f c xI x dx
→
=
= ∆= ∫ ∑
If f is defined on the closed interval [a, b] and the limit of
a Riemann sum of f exists, then we say f is integrable on [a, b]
and we denote the limit by
∫∑ =∆
=
→∆
b
a
n
i
ii
x
dxxfxcf )()(lim
1
0
The limit is called the definite integral of f from a to b. The
number a is the lower limit of integration, and the number b
is the upper limit of integration.
Definition of the Definite
Integral
Example
Try
Use summation on calculator.
( )
3 4
2
4
11
use (1 )
k
x dx S f k x x
=
= + ⋅∆ ∆∑∫
b a
x
n
−
∆ =
Example
Note increased accuracy with smaller ∆x
Limit of the Riemann Sum
The definite integral is the
limit of the Riemann sum.
( )
3
2
1
x dx∫
Properties of Definite Integral
Integral of a sum = sum of integrals
Factor out a constant
Dominance
( ) ( ) [ , ]
( ) ( )
b b
a a
f x g x on a b
f x dx g x dx
≤
≤∫ ∫
Properties of Definite Integral
Subdivision rule
( ) ( ) ( )
c b c
a a b
f x dx f x dx f x dx= +∫ ∫ ∫
a b c
f(x)
Area As An Integral
The area under
the curve on the
interval [a,b]
a c
f(x)
( )
b
a
A f x dx= ∫
A

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Riemann sumsdefiniteintegrals

  • 1. Riemann Sums and the Definite Integral
  • 2. Why? Why is the area of the yellow rectangle at the end (look at the applet on this lesson)  = a bx∆ ( )( ) ( )x f b f a∆ × −
  • 3. Review We partition the interval into n sub-intervals Evaluate f(x) at right endpoints of kth sub-interval for k = 1, 2, 3, … n a b f(x) b a x n − ∆ = a k x+ ×∆
  • 4. Review Sum We expect Sn to improve thus we define A, the area under the curve, to equal the above limit. a b 1 lim ( ) n n n k S f a k x x →∞ = = + ×∆ ×∆∑ f(x) Look at Goegebra demo Look at Goegebra demo
  • 5. Riemann Sum 1. Partition the interval [a,b] into n subintervals a = x0 < x1 … < xn-1< xn = b 1. Call this partition P 2. The kth subinterval is ∆xk = xk-1 – xk 3. Largest ∆xk is called the norm, called ||P|| — Choose an arbitrary value from each subinterval, call it ic
  • 6. Riemann Sum 3. Form the sum 4. This is the Riemann sum associated with • the function f • the given partition P • the chosen subinterval representatives  We will express a variety of quantities in terms of the Riemann sum 1 1 2 2 1 ( ) ( ) ... ( ) ( ) n n n n i i i R f c x f c x f c x f c x = = ∆ + ∆ + + ∆ = ∆∑ ic
  • 7. The Riemann Sum Calculated Consider the function 2x2 – 7x + 5 Use ∆x = 0.1 Let the = left edge of each subinterval Note the sum x 2x^2-7x+5 dx * f(x) 4 9 0.9 4.1 9.92 0.992 4.2 10.88 1.088 4.3 11.88 1.188 4.4 12.92 1.292 4.5 14 1.4 4.6 15.12 1.512 4.7 16.28 1.628 4.8 17.48 1.748 4.9 18.72 1.872 5 20 2 5.1 21.32 2.132 5.2 22.68 2.268 5.3 24.08 2.408 5.4 25.52 2.552 5.5 27 2.7 5.6 28.52 2.852 5.7 30.08 3.008 5.8 31.68 3.168 5.9 33.32 3.332 Riemann sum = 40.04 ic
  • 8. The Riemann Sum We have summed a series of boxes If the ∆x were smaller, we would have gotten a better approximation f(x) = 2x2 – 7x + 5 1 ( ) 40.04 n i i i f c x = ∆ =∑
  • 9. The Definite Integral The definite integral is the limit of the Riemann sum We say that f is integrable when the number I can be approximated as accurate as needed by making ||P|| sufficiently small f must exist on [a,b] and the Riemann sum must exist ( )0 1 lim( ) b a P n i i k f f c xI x dx → = = ∆= ∫ ∑
  • 10. If f is defined on the closed interval [a, b] and the limit of a Riemann sum of f exists, then we say f is integrable on [a, b] and we denote the limit by ∫∑ =∆ = →∆ b a n i ii x dxxfxcf )()(lim 1 0 The limit is called the definite integral of f from a to b. The number a is the lower limit of integration, and the number b is the upper limit of integration. Definition of the Definite Integral
  • 11. Example Try Use summation on calculator. ( ) 3 4 2 4 11 use (1 ) k x dx S f k x x = = + ⋅∆ ∆∑∫ b a x n − ∆ =
  • 13. Limit of the Riemann Sum The definite integral is the limit of the Riemann sum. ( ) 3 2 1 x dx∫
  • 14. Properties of Definite Integral Integral of a sum = sum of integrals Factor out a constant Dominance ( ) ( ) [ , ] ( ) ( ) b b a a f x g x on a b f x dx g x dx ≤ ≤∫ ∫
  • 15. Properties of Definite Integral Subdivision rule ( ) ( ) ( ) c b c a a b f x dx f x dx f x dx= +∫ ∫ ∫ a b c f(x)
  • 16. Area As An Integral The area under the curve on the interval [a,b] a c f(x) ( ) b a A f x dx= ∫ A