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Standing Waves
By: Priya Suresh
Let’s Start With A Definition…
 What is a standing wave?
 A standing wave is composed of 2 harmonic waves with
EQUAL amplitude, wavelength, and frequency but the
waves move in OPPOSITE directions
*for simplicity we may assume that the phase constants are
0 for both waves
Some Other Key Terms…
 NODE: points on the wave that have zero amplitude
and remain at rest
 ANTINODE: points on the wave that have maximum
amplitude
*since nodes do not move, energy is conserved in a
standing wave
Amplitude Of A Standing Wave
 The amplitude of the wave at a specific point can be
described with the following equation
 A(x) = 2Asin(kx) = 2Asin(2π*x/λ)
 Antinodes have maximum amplitude at 2A
 Nodes have zero amplitude
 All other points have amplitude between 0 and 2A
Equation For Position Of Wave
As A Function of Time D(x,t)
D(x,t) = 2Asin(kx)cos(ωt)
Or another form is…
 D(x,t) = A(x)cos(ωt)
Nodes And Antinodes
 Nodes occur at x= …-λ,-λ/2, 0, λ/2, λ…
 Antinodes occur at x=…-3λ/4, -λ/4, λ/4, 3λ/4…
 The distance between 2 consecutive nodes/antinodes
is λ/2
 An antinode is λ/4 apart from a node
 Speed of a wave is greatest at antinodes
 Speed of a wave is zero at nodes
Now Lets Use What We
Know To A Solve A Problem
Two sinusoidal waves with wavelengths 0.80m, amplitudes 3.0m and
frequencies 95Hz are moving in opposite directions to produce a
standing wave. (Assume the phase constants are 0).
a) Determine the equation of the standing wave.
b) If the wave starts at x=0, at what values of x will there be nodes?
(Give the first 3 locations)
c) At what values of x will there be antinodes? (Give the first 3
locations)
d) Determine the equation to find the amplitude at a given x value
e) What is the amplitude at x=5
Solving The Problem Step by Step
a) The equation for a standing wave is D(x,t) =
2Asin(kx)cos(ωt)
 k = 2π/λ= 2π/0.80 = 7.85 rad/m
 ω = 2πf = 2π(95) = 596.90 rad/s
 A = 3  2A = 6m
Therefore the equation is…
D(x,t) = 6sin(7.85x)cos(596.9t)
b) The first 3 nodes occur at x=0, λ/2, λ
x=0m,
x=0.80/2=0.40m
x=0.80m
Therefore the nodes occur at: 0m, 0.40m, 0.80m
c) The first 3 antinodes occur at x= λ/4, 3λ/4, 5λ/4
x=0.80/4=0.20m
x=3(0.80)/4=0.60m
x=5(0.80)/4=1.0m
Therefore the antinodes occur at: 0.20m, 0.40m, 1.0m
d) The equation to determine the amplitude is:
A(x) = 2Asin(kx)
A= 3.0m
k= 7.85rad/m
Therefore the amplitude is given by…
A(x)= 6sin(7.85x)
e) At x=5 the amplitude is…
A(5)= 6sin(7.85*5) =5.99m
Thank You

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Physics lo6

  • 2. Let’s Start With A Definition…  What is a standing wave?  A standing wave is composed of 2 harmonic waves with EQUAL amplitude, wavelength, and frequency but the waves move in OPPOSITE directions *for simplicity we may assume that the phase constants are 0 for both waves
  • 3. Some Other Key Terms…  NODE: points on the wave that have zero amplitude and remain at rest  ANTINODE: points on the wave that have maximum amplitude *since nodes do not move, energy is conserved in a standing wave
  • 4. Amplitude Of A Standing Wave  The amplitude of the wave at a specific point can be described with the following equation  A(x) = 2Asin(kx) = 2Asin(2π*x/λ)  Antinodes have maximum amplitude at 2A  Nodes have zero amplitude  All other points have amplitude between 0 and 2A
  • 5. Equation For Position Of Wave As A Function of Time D(x,t) D(x,t) = 2Asin(kx)cos(ωt) Or another form is…  D(x,t) = A(x)cos(ωt)
  • 6. Nodes And Antinodes  Nodes occur at x= …-λ,-λ/2, 0, λ/2, λ…  Antinodes occur at x=…-3λ/4, -λ/4, λ/4, 3λ/4…  The distance between 2 consecutive nodes/antinodes is λ/2  An antinode is λ/4 apart from a node  Speed of a wave is greatest at antinodes  Speed of a wave is zero at nodes
  • 7. Now Lets Use What We Know To A Solve A Problem Two sinusoidal waves with wavelengths 0.80m, amplitudes 3.0m and frequencies 95Hz are moving in opposite directions to produce a standing wave. (Assume the phase constants are 0). a) Determine the equation of the standing wave. b) If the wave starts at x=0, at what values of x will there be nodes? (Give the first 3 locations) c) At what values of x will there be antinodes? (Give the first 3 locations) d) Determine the equation to find the amplitude at a given x value e) What is the amplitude at x=5
  • 8. Solving The Problem Step by Step a) The equation for a standing wave is D(x,t) = 2Asin(kx)cos(ωt)  k = 2π/λ= 2π/0.80 = 7.85 rad/m  ω = 2πf = 2π(95) = 596.90 rad/s  A = 3  2A = 6m Therefore the equation is… D(x,t) = 6sin(7.85x)cos(596.9t)
  • 9. b) The first 3 nodes occur at x=0, λ/2, λ x=0m, x=0.80/2=0.40m x=0.80m Therefore the nodes occur at: 0m, 0.40m, 0.80m c) The first 3 antinodes occur at x= λ/4, 3λ/4, 5λ/4 x=0.80/4=0.20m x=3(0.80)/4=0.60m x=5(0.80)/4=1.0m Therefore the antinodes occur at: 0.20m, 0.40m, 1.0m
  • 10. d) The equation to determine the amplitude is: A(x) = 2Asin(kx) A= 3.0m k= 7.85rad/m Therefore the amplitude is given by… A(x)= 6sin(7.85x) e) At x=5 the amplitude is… A(5)= 6sin(7.85*5) =5.99m