NUMERICAL METHOD
REPORTED BY:
Angel Grace Adem
MEAN( 𝑥 )
FORMULA:
Ungrouped Data :
𝑥 =
𝑥1+𝑥2+⋯ 𝑥 𝑛
𝑛
Group Data:
𝑥 =
𝑓𝑥
𝑛
where: f = frequency in each class
x= midpoint of each class
n= total number of scores
MEAN( 𝑥 )
EXAMPLES (ungrouped Data):
1. Find the mean of 5, 7, 11, 20 and 18.
SOLUTION:
𝑥 =
5 + 7 + 11 + 20 + 18
5
=
61
5
= 12.2
MEAN( 𝑥 )
2. Find the Weighted Arithmetic mean of the
numbers 12, 15, 16,12, 15, 18, 18, 20, 12 and
18.
SOLUTION:
𝑥 =
12 3 +15 2 +18 3 +16+20
3+2+3+1+1
=
36+30+54+36
10
=
156
10
= 15.6
MEAN( 𝑥 )
3. The class standing of a student is 84,
while the preliminary examination is 75.
Compute the preliminary grade if the weighted
of the class standing is 2 and the preliminary
examination is 1.
MEAN( 𝑥 )
SOLUTION:
𝑥 =
2
3
84 +
1
3
79
=
168
3
+
79
3
=
247
3
= 82.33
MEAN( 𝑥 )
Example (grouped data):
1. SOLUTION:
𝑥 =
𝑓𝑥
𝑛
𝑥 =
186
33
𝑥 = 5.636 or
5.64
Interv
al
Midpoint Frequen
cy
(𝒇𝒙)
1-3 2 7 14
4-6 5 12 60
7-9 8 14 112
n=33 𝑓𝑥 = 186
MEAN( 𝑥 )
2. On arriving in the Beach of Boracay, a sample of 60 vacationers is asked
about their ages by the Tourist Bureau. The Sample information is organized
into the following frequency distribution. Compute the mean age.
SOLUTION:
𝑥 =
𝑓𝑥
𝑛
𝑥 =
2540
60
𝑥 =42.33
Age
No. of
Vacatione
r (𝒇)
Midpoint
(x) (𝒇𝒙)
11-20 5 15.5 77.5
21-30 7 25.5 178.5
31-40 12 35.5 426
41-50 22 45.5 1001
51-60 8 55.5 444
61-70 4 65.5 262
71-80 2 75.5 151
n=60 𝑓𝑥 = 2540
MEAN( 𝑥 )
3. Compute the new salary of the 20 employees in the ABC Company
organized in the frequency distribution as follows:
SOLUTION:
𝑥 =
𝑓𝑥
𝑛
𝑥 =
5910
20
𝑥 =295.5
Salary of
Employees
𝒇
x
(𝒇𝒙)
101-200 4 150.
5
602
201-300 9 250.
5
2254.5
301-400 3 350.
5
1051.5
401-500 2 450.
5
901
501-600 2 550.
5
1101
n=20 𝑓𝑥 = 5910
MEDIAN 𝑥
FORMULA
Grouped Data :
𝑥 = 𝐿 𝑏 +
𝑛
2
−𝐶𝐹<
𝑓 𝑚
∙ 𝑐
Where: 𝐿 𝑏 =lower class containing the median
𝐶𝐹< = less than cumulative frequency
𝑓𝑚 = frequency of the class containing median
c = width of the class
n = number of sample
MEDIAN 𝑥
FORMULA (ungrouped data):
𝑥 =
𝑛+1
2
Where:
n= number of sample
MEDIAN 𝑥
EXAMPLE 1.
Following distribution of Mathematics scores of 20 students:
𝒙 = 𝑳 𝒃 +
𝒏
𝟐
−𝑪𝑭<
𝒇 𝒎
∙ 𝑐
𝒙 = 4.5 +
𝟐𝟎
𝟐
−𝟒
𝟖
∙ 𝑐
𝒙 = 4.5 +
10−4
8
⋅ 2
𝒙 = 6
Scores
Number
of
Students
CF
1-2 1 1
3-4 3 4 𝐶𝐹< =
4
5-6 8 12 𝐿 𝑏 =
4.5
7-8 6 18
9-10 2 20

numerical method in statistics (MEAN AND MEDIAN)

  • 1.
  • 2.
    MEAN( 𝑥 ) FORMULA: UngroupedData : 𝑥 = 𝑥1+𝑥2+⋯ 𝑥 𝑛 𝑛 Group Data: 𝑥 = 𝑓𝑥 𝑛 where: f = frequency in each class x= midpoint of each class n= total number of scores
  • 3.
    MEAN( 𝑥 ) EXAMPLES(ungrouped Data): 1. Find the mean of 5, 7, 11, 20 and 18. SOLUTION: 𝑥 = 5 + 7 + 11 + 20 + 18 5 = 61 5 = 12.2
  • 4.
    MEAN( 𝑥 ) 2.Find the Weighted Arithmetic mean of the numbers 12, 15, 16,12, 15, 18, 18, 20, 12 and 18. SOLUTION: 𝑥 = 12 3 +15 2 +18 3 +16+20 3+2+3+1+1 = 36+30+54+36 10 = 156 10 = 15.6
  • 5.
    MEAN( 𝑥 ) 3.The class standing of a student is 84, while the preliminary examination is 75. Compute the preliminary grade if the weighted of the class standing is 2 and the preliminary examination is 1.
  • 6.
    MEAN( 𝑥 ) SOLUTION: 𝑥= 2 3 84 + 1 3 79 = 168 3 + 79 3 = 247 3 = 82.33
  • 7.
    MEAN( 𝑥 ) Example(grouped data): 1. SOLUTION: 𝑥 = 𝑓𝑥 𝑛 𝑥 = 186 33 𝑥 = 5.636 or 5.64 Interv al Midpoint Frequen cy (𝒇𝒙) 1-3 2 7 14 4-6 5 12 60 7-9 8 14 112 n=33 𝑓𝑥 = 186
  • 8.
    MEAN( 𝑥 ) 2.On arriving in the Beach of Boracay, a sample of 60 vacationers is asked about their ages by the Tourist Bureau. The Sample information is organized into the following frequency distribution. Compute the mean age. SOLUTION: 𝑥 = 𝑓𝑥 𝑛 𝑥 = 2540 60 𝑥 =42.33 Age No. of Vacatione r (𝒇) Midpoint (x) (𝒇𝒙) 11-20 5 15.5 77.5 21-30 7 25.5 178.5 31-40 12 35.5 426 41-50 22 45.5 1001 51-60 8 55.5 444 61-70 4 65.5 262 71-80 2 75.5 151 n=60 𝑓𝑥 = 2540
  • 9.
    MEAN( 𝑥 ) 3.Compute the new salary of the 20 employees in the ABC Company organized in the frequency distribution as follows: SOLUTION: 𝑥 = 𝑓𝑥 𝑛 𝑥 = 5910 20 𝑥 =295.5 Salary of Employees 𝒇 x (𝒇𝒙) 101-200 4 150. 5 602 201-300 9 250. 5 2254.5 301-400 3 350. 5 1051.5 401-500 2 450. 5 901 501-600 2 550. 5 1101 n=20 𝑓𝑥 = 5910
  • 10.
    MEDIAN 𝑥 FORMULA Grouped Data: 𝑥 = 𝐿 𝑏 + 𝑛 2 −𝐶𝐹< 𝑓 𝑚 ∙ 𝑐 Where: 𝐿 𝑏 =lower class containing the median 𝐶𝐹< = less than cumulative frequency 𝑓𝑚 = frequency of the class containing median c = width of the class n = number of sample
  • 11.
    MEDIAN 𝑥 FORMULA (ungroupeddata): 𝑥 = 𝑛+1 2 Where: n= number of sample
  • 12.
    MEDIAN 𝑥 EXAMPLE 1. Followingdistribution of Mathematics scores of 20 students: 𝒙 = 𝑳 𝒃 + 𝒏 𝟐 −𝑪𝑭< 𝒇 𝒎 ∙ 𝑐 𝒙 = 4.5 + 𝟐𝟎 𝟐 −𝟒 𝟖 ∙ 𝑐 𝒙 = 4.5 + 10−4 8 ⋅ 2 𝒙 = 6 Scores Number of Students CF 1-2 1 1 3-4 3 4 𝐶𝐹< = 4 5-6 8 12 𝐿 𝑏 = 4.5 7-8 6 18 9-10 2 20