1
Analog TransmissionAnalog Transmission
of Digital Data:of Digital Data:
ASK, FSK, PSK, QAMASK, FSK, PSK, QAM
CSE 3213, Fall 2010
Instructor: N. Vlajic
Required reading:
Garcia 3.7
2
Why Do We Need Digital-to-Analog Conversion?!
1) The medium/channel is band pass, and/or
2) Multiple users need to share the medium.
3
Modulation of Digital Data
ModulationModulation – process of converting digital data or a low-pass
analog to band-pass (higher-frequency) analog signal
Digital-to-analog modulation.
Analog-to-analog modulation.
Carrier SignalCarrier Signal – aka carrier freq. or modulated signal - high freq.
signal that acts as a basis for the information signal
• information signal is called modulating signal
freq
bandpass channel
4
Modulation of Digital Data (cont.)
DigitalDigital--toto--AnalogAnalog
ModulationModulation
– process of changing one of the characteristic
of an analog signal (typically a sinewave) based
on the information in a digital signal
• sinewave is defined by 3 characteristics (amplitude,
frequency, and phase) ⇒ digital data (binary 0 & 1)
can be represented by varying any of the three
• application: transmission of digital data over
telephone wire (modem)
Types of DigitalTypes of Digital--toto--AnalogAnalog
ModulationModulation
5
Modulation of Digital Data: ASK
ASKASK – strength of carrier signal is varied to represent binary 1 or 0
• both frequency & phase remain constant while amplitude changes
• commonly, one of the amplitudes is zero
• demodulation: only the presence or absence of a sinusoid in a
given time interval needs to be determined
• advantage: simplicity
• disadvantage: ASK is very susceptible to noise interference –
noise usually (only) affects the amplitude, therefore ASK is the
modulation technique most affected by noise
• application: ASK is used to transmit digital data over optical fiber
⎩
⎨
⎧
=
⎩
⎨
⎧
=
1binaryt),fAcos(2
0binary0,
1binaryt),fcos(2A
0binaryt),fcos(2A
s(t)
cc1
c0
ππ
π
Is this picture,
from the textbook,
entirely correct?!
+A
-A
6
Modulation of Digital Data: ASK (cont.)
Example [ ASK ]
vd(t)
vc(t)
vASK(t)
How does the frequency spectrum of vASK(t) look like!?
fvd(f) vc(f)
7
Modulation of Digital Data: ASK (cont.)
ASKASK--Modulated Signal: Frequency SpectrumModulated Signal: Frequency Spectrum
t)cos(ωt)fcos(2(t)v ccc == π
⎥
⎦
⎤
⎢
⎣
⎡
−+−+⋅= ...tcos5ω
5π
2
tcos3ω
3π
2
tcosω
π
2
2
1
A(t)v 000d
Carrier signal: , where 2πfc=ωc
Digital signal:
(unipolar!!!)
ωc ωωd_max
Modulated signal:
( ) ( )[ ]
( ) ( )[ ] ...t3ωωcost3ωωcos
3π
1
-tωωcostωωcos
π
1
tcosω
2
1
...tcos3ωtcosω
3π
2
-tcosωtcosω
π
2
tcosω
2
1
...tcos5ω
5π
2
tcos3ω
3π
2
tcosω
π
2
2
1
tcosω
(t)v(t)v(t)v
0c0c
0c0cc
0c0cc
000c
dcASK
+++−−
++−+=
=+⋅⋅+=
=⎥
⎦
⎤
⎢
⎣
⎡
−+−+⋅=
=⋅=
( )B)cos(AB)-cos(A
2
1
cosBcosA ++=⋅
ωc ωωc+ωd_maxωc-ωd_max
8
Modulation of Digital Data: FSK
FSKFSK – frequency of carrier signal is varied to represent binary 1 or 0
• peak amplitude & phase remain constant during each bit interval
• demodulation: demodulator must be able to determine which of
two possible frequencies is present at a given time
• advantage: FSK is less susceptible to errors than ASK – receiver
looks for specific frequency changes over a number
of intervals, so voltage (noise) spikes can be ignored
• disadvantage: FSK spectrum is 2 x ASK spectrum
• application: over voice lines, in high-freq. radio transmission, etc.
⎩
⎨
⎧
=
1binaryt),fAcos(2
0binaryt),fAcos(2
s(t)
2
1
π
π
f1<f2
+A
-A
9
Modulation of Digital Data: FSK (cont.)
Example [ FSK ]
vd(t)
vc1(t)
vc2(t)
vFSK(t)
ω1 ωωd_max ω2
ω1 ωω1-ωd_max
ω2 ω2+ωd_max
10
Modulation of Digital Data: FSK (cont.)
FSKFSK--Modulated Signal: Frequency SpectrumModulated Signal: Frequency Spectrum
(t)vd
Digital signal: - modulated with ω1 , and
- modulated with ω2
Modulated signal:
( ) ( )[ ]
( ) ( )[ ]
( ) ( )[ ]
( ) ( )[ ] ++++−+
++−−
++++−−
++−+=
=
=⎥⎦
⎤
⎢⎣
⎡
−−+−⋅+
+⎥
⎦
⎤
⎢
⎣
⎡
−+−+⋅=
=−⋅+⋅=
...t3ωωcost3ωωcos
3π
1
-tωωcostωωcos
π
1
tcosω
2
1
...t3ωωcost3ωωcos
3π
1
-tωωcostωωcos
π
1
tcosω
2
1
...tcos5ω
5π
2
tcos3ω
3π
2
tcosω
π
2
2
1
tcosω
...tcos5ω
5π
2
tcos3ω
3π
2
tcosω
π
2
2
1
tcosω
(t))vtcosω(t)vtcosω(t)v
0202
02022
0101
01011
0002
0001
d2d1FSK
...
1(
(t)v1-(t)'v dd =
11
PSKPSK – phase of carrier signal is varied to represent binary 1 or 0
• peak amplitude & freq. remain constant during each bit interval
• example: binary 1 = 0º phase, binary 0 = 180º (πrad) phase
⇒ PSK is equivalent to multiplying carrier signal by +1 when the
information is 1, and by -1 when the information is 0
• demodulation: demodulator must determine the phase of received
sinusoid with respect to some reference phase
• advantage: PSK is less susceptible to errors than ASK, while it
requires/occupies the same bandwidth as ASK
more efficient use of bandwidth (higher data-rate)
are possible, compared to FSK !!!
• disadvantage: more complex signal detection / recovery process,
than in ASK and FSK
⎩
⎨
⎧
+
=
0binary),tfAcos(2
1binaryt),fAcos(2
s(t)
c
c
ππ
π
Modulation of Digital Data: PSK
2-PSK, or
Binary PSK,
since only 2
different phases
are used.
+A
-A
⎩
⎨
⎧
=
0binaryt),fAcos(2-
1binaryt),fAcos(2
s(t)
c
c
π
π
12
Modulation of Digital Data: PSK (cont.)
Example [ PSK ]
vd(t)
vc(t)
vPSK(t)
ωc ωωd_max ωc ωωc+ωd_maxωc-ωd_max
13
Modulation of Digital Data: PSK (cont.)
PSK DetectionPSK Detection – multiply the received / modulated signal
by 2*cos(2πfct)
• resulting signal
• by removing the oscillatory part with a
low-pass filter, the original baseband signal
(i.e. the original binary sequence) can be
easily determined
[ ] 1binary,t)fcos(41At)f(22Acos cc
2
ππ +=
[ ] 0binary,t)fcos(41At)f(22Acos- cc
2
ππ +−=
t)fAcos(2 cπ±
( )2Acos1
2
1
Acos2
+=
14
Modulation of Digital Data: PSK (cont.)
1 1 1 10 01 1 1 10 0Information
Baseband
Signal
+A
-A
0 T 2T 3T 4T 5T 6T
+A
-A
0 T 2T 3T 4T 5T 6T
+A
-A
0 T 2T 3T 4T 5T 6T
+A
-A
0 T 2T 3T 4T 5T 6T
Modulated
Signal
x(t)
A cos(2πft) -A cos(2πft)
After multiplication
at receiver
x(t) cos(2πfct)
+A
-A
0 T 2T 3T 4T 5T 6T
+A
-A
0 T 2T 3T 4T 5T 6T
A {1 + cos(4πft)} -A {1 + cos(4πft)}
Baseband
signal discernable
after smoothing
+A
-A
0 T 2T 3T 4T 5T 6T
sender
receiver
Signal shifted above / below zero level.
15
Modulation of Digital Data: PSK (cont.)
B
fc+B
f
f
fc-B fc
• If bandpass channel has bandwidth Wc [Hz],
then baseband channel has Wc/2 [Hz] available, so
modulation system supports 2*(Wc/2) = Wc [pulses/second]
recall Nyqyist Law: baseband transmission system of bandwidth Wc [Hz]
can theoretically support 2 Wc pulses/sec
Facts from Modulation TheoryFacts from Modulation Theory
Wc
Wc/2
Baseband signal x(t) with
bandwidth Wc/2
If
then
Modulated signal
x(t)cos(2πfct) has
bandwidth Wc Hz
How can we recover the factor 2 in supported data-rate !?
Data rate = 2*Wc/2 = B [bps]
16
Modulation of Digital Data: PSK (cont.)
QPSK = 4QPSK = 4--PSKPSK – PSK that uses phase shifts of 90º=π/2 rad ⇒ 4
different signals generated, each representing 2 bits
• advantage: higher data rate than in PSK (2 bits per bit
interval), while bandwidth occupancy remains the same
• 4-PSK can easily be extended to 8-PSK, i.e. n-PSK
• however, higher rate PSK schemes are limited by the
ability of equipment to distinguish small differences in
phase
⎪
⎪
⎪
⎩
⎪
⎪
⎪
⎨
⎧
+
+
+
=
11binary),
2
3
tfAcos(2
10binary),tfAcos(2
01binary),
2
tfAcos(2
00binaryt),fAcos(2
s(t)
c
c
c
c
π
π
ππ
π
π
π
17
Modulation of Digital Data: QAM
QuadratureQuadrature
AmplitudeAmplitude
ModulationModulation
(QAM)(QAM)
– uses “two-dimensional” signalling
• original information stream is split into two sequences that
consist of odd and even symbols, e.g. Bk and Ak
• Ak sequence (in-phase comp.) is modulated by
Bk sequence (quadrature-phase comp.) is modulated by
• composite signal is sent
through the channel
• advantage: data rate = 2 bits per bit-interval!
B1 B2 B3A1 A2 A3 …
Ak x
cos(2πfct)
Yi(t) = Ak cos(2πfct)
Bk
x
sin(2πfct)
Yq(t) = Bk sin(2πfct)
+
Transmitted
Signal
Y(t) = Ak cos(2πfct) + Bk sin(2πfct)
t)fcos(2 cπ
t)fsin(2 cπ
t)fsin(2Bt)fcos(2A ckck ππ +
1 -1 1 1 -1 1 …
1 0 1 1 0 1 …
18
Modulation of Digital Data: QAM (cont.)
Example [ QAM ]
Bk
vd(t)
Ak
sin(ωct)
cos(ωct)
19
Modulation of Digital Data: QAM
QAMQAM DemodulationDemodulation • by multiplying Y(t) by and then low-
pass filtering the resultant signal, sequence Ak is
obtained
t)fcos(22 cπ⋅
• by multiplying Y(t) by and then low-
pass filtering the resultant signal, sequence Bk is
obtained
t)fsin(22 cπ⋅
=+ t)fsin(2Bt)fcos(2A ckck ππ
( )cos(2A)1
2
1
(A)cos2
+=
( )cos(2A)1
2
1
(A)sin2
−=
(A)2sin(A)cossin(2A) =
Y(t) x
2cos(2πfct)
2Akcos2(2πfct)+2Bk cos(2πfct)sin(2πfct)
= Ak {1 + cos(4πfct)}+Bk {0 + sin(4πfct)}
Lowpass
filter
(smoother)
Ak
2Bk sin2(2πfct)+2Ak cos(2πfct)sin(2πfct)
= Bk {1 - cos(4πfct)}+Ak {0 + sin(4πfct)}
x
2sin(2πfct)
Bk
Lowpass
filter
(smoother)
smoothed to zero
smoothed to zero
Y(t) x
2cos(2πfct)
2Akcos2(2πfct)+2Bk cos(2πfct)sin(2πfct)
= Ak {1 + cos(4πfct)}+Bk {0 + sin(4πfct)}
Lowpass
filter
(smoother)
Ak
x
2cos(2πfct)
2Akcos2(2πfct)+2Bk cos(2πfct)sin(2πfct)
= Ak {1 + cos(4πfct)}+Bk {0 + sin(4πfct)}
Lowpass
filter
(smoother)
Ak
2Bk sin2(2πfct)+2Ak cos(2πfct)sin(2πfct)
= Bk {1 - cos(4πfct)}+Ak {0 + sin(4πfct)}
x
2sin(2πfct)
Bk
Lowpass
filter
(smoother)
x
2sin(2πfct)
Bk
Lowpass
filter
(smoother)
smoothed to zero
smoothed to zero
20
Signal Constellation
Constellation DiagramConstellation Diagram – used to represents possible symbols that may
be selected by a given modulation scheme as
points in 2-D plane
• X-axis is related to in-phase carrier: cos(ωct)
the projection of the point on the X-axis defines
the peak amplitude of the in-phase component
• Y-axis is related to quadrature carrier: sin(ωct)
the projection of the point on the Y-axis defines
the peak amplitude of the quadrature component
• the length of line that connects the point to
the origin is the peak amplitude of the signal
element (combination of X & Y components)
• the angle the line makes with the X-axis is the
phase of the signal element
21
Modulation of Digital Data: QAM
QAM cont.QAM cont. – QAM can also be seen as a combination of ASK & PSK
( ) )
A
B
tantfcos(2BAt)fsin(2Bt)fcos(2AY(t)
k
k1-
ckkckck ++=+= πππ 2
1
22
Ak
Bk
(A, A)
(A,-A)(-A,-A)
(-A,A)
Ak
Bk
Ak
Bk
(A, A)
(A,-A)(-A,-A)
(-A,A)
4-level QAM
22
Ak
Bk
Ak
Bk
Modulation of Digital Data: QAM
1616--level QAMlevel QAM – the number of bits transmitted per T [sec] interval
can be further increased by increasing the number
of levels used
• in case of 16-level QAM, Ak and Bk individually can
assume 4 different levels: -1, -1/3, 1/3, 1
• data rate: 4 bits/pulse ⇒ 4W bits/second
( ) )
A
B
tantfcos(2BAt)fsin(2Bt)fcos(2AY(t)
k
k1-
ckkckck ++=+= πππ 2
1
22
In QAM various combinations of amplitude and phase are employed
to achieve higher digital data rates.
Amplitude changes are susceptible to noise ⇒ the number of phase shifts used
by a QAM system is always greater than the number of amplitude shifts.
Ak and Bk individually
can take on 4 different values;
the resultant signal can take
on (only) 3 different values!!!

Digital modulation

  • 1.
    1 Analog TransmissionAnalog Transmission ofDigital Data:of Digital Data: ASK, FSK, PSK, QAMASK, FSK, PSK, QAM CSE 3213, Fall 2010 Instructor: N. Vlajic Required reading: Garcia 3.7
  • 2.
    2 Why Do WeNeed Digital-to-Analog Conversion?! 1) The medium/channel is band pass, and/or 2) Multiple users need to share the medium.
  • 3.
    3 Modulation of DigitalData ModulationModulation – process of converting digital data or a low-pass analog to band-pass (higher-frequency) analog signal Digital-to-analog modulation. Analog-to-analog modulation. Carrier SignalCarrier Signal – aka carrier freq. or modulated signal - high freq. signal that acts as a basis for the information signal • information signal is called modulating signal freq bandpass channel
  • 4.
    4 Modulation of DigitalData (cont.) DigitalDigital--toto--AnalogAnalog ModulationModulation – process of changing one of the characteristic of an analog signal (typically a sinewave) based on the information in a digital signal • sinewave is defined by 3 characteristics (amplitude, frequency, and phase) ⇒ digital data (binary 0 & 1) can be represented by varying any of the three • application: transmission of digital data over telephone wire (modem) Types of DigitalTypes of Digital--toto--AnalogAnalog ModulationModulation
  • 5.
    5 Modulation of DigitalData: ASK ASKASK – strength of carrier signal is varied to represent binary 1 or 0 • both frequency & phase remain constant while amplitude changes • commonly, one of the amplitudes is zero • demodulation: only the presence or absence of a sinusoid in a given time interval needs to be determined • advantage: simplicity • disadvantage: ASK is very susceptible to noise interference – noise usually (only) affects the amplitude, therefore ASK is the modulation technique most affected by noise • application: ASK is used to transmit digital data over optical fiber ⎩ ⎨ ⎧ = ⎩ ⎨ ⎧ = 1binaryt),fAcos(2 0binary0, 1binaryt),fcos(2A 0binaryt),fcos(2A s(t) cc1 c0 ππ π Is this picture, from the textbook, entirely correct?! +A -A
  • 6.
    6 Modulation of DigitalData: ASK (cont.) Example [ ASK ] vd(t) vc(t) vASK(t) How does the frequency spectrum of vASK(t) look like!? fvd(f) vc(f)
  • 7.
    7 Modulation of DigitalData: ASK (cont.) ASKASK--Modulated Signal: Frequency SpectrumModulated Signal: Frequency Spectrum t)cos(ωt)fcos(2(t)v ccc == π ⎥ ⎦ ⎤ ⎢ ⎣ ⎡ −+−+⋅= ...tcos5ω 5π 2 tcos3ω 3π 2 tcosω π 2 2 1 A(t)v 000d Carrier signal: , where 2πfc=ωc Digital signal: (unipolar!!!) ωc ωωd_max Modulated signal: ( ) ( )[ ] ( ) ( )[ ] ...t3ωωcost3ωωcos 3π 1 -tωωcostωωcos π 1 tcosω 2 1 ...tcos3ωtcosω 3π 2 -tcosωtcosω π 2 tcosω 2 1 ...tcos5ω 5π 2 tcos3ω 3π 2 tcosω π 2 2 1 tcosω (t)v(t)v(t)v 0c0c 0c0cc 0c0cc 000c dcASK +++−− ++−+= =+⋅⋅+= =⎥ ⎦ ⎤ ⎢ ⎣ ⎡ −+−+⋅= =⋅= ( )B)cos(AB)-cos(A 2 1 cosBcosA ++=⋅ ωc ωωc+ωd_maxωc-ωd_max
  • 8.
    8 Modulation of DigitalData: FSK FSKFSK – frequency of carrier signal is varied to represent binary 1 or 0 • peak amplitude & phase remain constant during each bit interval • demodulation: demodulator must be able to determine which of two possible frequencies is present at a given time • advantage: FSK is less susceptible to errors than ASK – receiver looks for specific frequency changes over a number of intervals, so voltage (noise) spikes can be ignored • disadvantage: FSK spectrum is 2 x ASK spectrum • application: over voice lines, in high-freq. radio transmission, etc. ⎩ ⎨ ⎧ = 1binaryt),fAcos(2 0binaryt),fAcos(2 s(t) 2 1 π π f1<f2 +A -A
  • 9.
    9 Modulation of DigitalData: FSK (cont.) Example [ FSK ] vd(t) vc1(t) vc2(t) vFSK(t) ω1 ωωd_max ω2 ω1 ωω1-ωd_max ω2 ω2+ωd_max
  • 10.
    10 Modulation of DigitalData: FSK (cont.) FSKFSK--Modulated Signal: Frequency SpectrumModulated Signal: Frequency Spectrum (t)vd Digital signal: - modulated with ω1 , and - modulated with ω2 Modulated signal: ( ) ( )[ ] ( ) ( )[ ] ( ) ( )[ ] ( ) ( )[ ] ++++−+ ++−− ++++−− ++−+= = =⎥⎦ ⎤ ⎢⎣ ⎡ −−+−⋅+ +⎥ ⎦ ⎤ ⎢ ⎣ ⎡ −+−+⋅= =−⋅+⋅= ...t3ωωcost3ωωcos 3π 1 -tωωcostωωcos π 1 tcosω 2 1 ...t3ωωcost3ωωcos 3π 1 -tωωcostωωcos π 1 tcosω 2 1 ...tcos5ω 5π 2 tcos3ω 3π 2 tcosω π 2 2 1 tcosω ...tcos5ω 5π 2 tcos3ω 3π 2 tcosω π 2 2 1 tcosω (t))vtcosω(t)vtcosω(t)v 0202 02022 0101 01011 0002 0001 d2d1FSK ... 1( (t)v1-(t)'v dd =
  • 11.
    11 PSKPSK – phaseof carrier signal is varied to represent binary 1 or 0 • peak amplitude & freq. remain constant during each bit interval • example: binary 1 = 0º phase, binary 0 = 180º (πrad) phase ⇒ PSK is equivalent to multiplying carrier signal by +1 when the information is 1, and by -1 when the information is 0 • demodulation: demodulator must determine the phase of received sinusoid with respect to some reference phase • advantage: PSK is less susceptible to errors than ASK, while it requires/occupies the same bandwidth as ASK more efficient use of bandwidth (higher data-rate) are possible, compared to FSK !!! • disadvantage: more complex signal detection / recovery process, than in ASK and FSK ⎩ ⎨ ⎧ + = 0binary),tfAcos(2 1binaryt),fAcos(2 s(t) c c ππ π Modulation of Digital Data: PSK 2-PSK, or Binary PSK, since only 2 different phases are used. +A -A ⎩ ⎨ ⎧ = 0binaryt),fAcos(2- 1binaryt),fAcos(2 s(t) c c π π
  • 12.
    12 Modulation of DigitalData: PSK (cont.) Example [ PSK ] vd(t) vc(t) vPSK(t) ωc ωωd_max ωc ωωc+ωd_maxωc-ωd_max
  • 13.
    13 Modulation of DigitalData: PSK (cont.) PSK DetectionPSK Detection – multiply the received / modulated signal by 2*cos(2πfct) • resulting signal • by removing the oscillatory part with a low-pass filter, the original baseband signal (i.e. the original binary sequence) can be easily determined [ ] 1binary,t)fcos(41At)f(22Acos cc 2 ππ += [ ] 0binary,t)fcos(41At)f(22Acos- cc 2 ππ +−= t)fAcos(2 cπ± ( )2Acos1 2 1 Acos2 +=
  • 14.
    14 Modulation of DigitalData: PSK (cont.) 1 1 1 10 01 1 1 10 0Information Baseband Signal +A -A 0 T 2T 3T 4T 5T 6T +A -A 0 T 2T 3T 4T 5T 6T +A -A 0 T 2T 3T 4T 5T 6T +A -A 0 T 2T 3T 4T 5T 6T Modulated Signal x(t) A cos(2πft) -A cos(2πft) After multiplication at receiver x(t) cos(2πfct) +A -A 0 T 2T 3T 4T 5T 6T +A -A 0 T 2T 3T 4T 5T 6T A {1 + cos(4πft)} -A {1 + cos(4πft)} Baseband signal discernable after smoothing +A -A 0 T 2T 3T 4T 5T 6T sender receiver Signal shifted above / below zero level.
  • 15.
    15 Modulation of DigitalData: PSK (cont.) B fc+B f f fc-B fc • If bandpass channel has bandwidth Wc [Hz], then baseband channel has Wc/2 [Hz] available, so modulation system supports 2*(Wc/2) = Wc [pulses/second] recall Nyqyist Law: baseband transmission system of bandwidth Wc [Hz] can theoretically support 2 Wc pulses/sec Facts from Modulation TheoryFacts from Modulation Theory Wc Wc/2 Baseband signal x(t) with bandwidth Wc/2 If then Modulated signal x(t)cos(2πfct) has bandwidth Wc Hz How can we recover the factor 2 in supported data-rate !? Data rate = 2*Wc/2 = B [bps]
  • 16.
    16 Modulation of DigitalData: PSK (cont.) QPSK = 4QPSK = 4--PSKPSK – PSK that uses phase shifts of 90º=π/2 rad ⇒ 4 different signals generated, each representing 2 bits • advantage: higher data rate than in PSK (2 bits per bit interval), while bandwidth occupancy remains the same • 4-PSK can easily be extended to 8-PSK, i.e. n-PSK • however, higher rate PSK schemes are limited by the ability of equipment to distinguish small differences in phase ⎪ ⎪ ⎪ ⎩ ⎪ ⎪ ⎪ ⎨ ⎧ + + + = 11binary), 2 3 tfAcos(2 10binary),tfAcos(2 01binary), 2 tfAcos(2 00binaryt),fAcos(2 s(t) c c c c π π ππ π π π
  • 17.
    17 Modulation of DigitalData: QAM QuadratureQuadrature AmplitudeAmplitude ModulationModulation (QAM)(QAM) – uses “two-dimensional” signalling • original information stream is split into two sequences that consist of odd and even symbols, e.g. Bk and Ak • Ak sequence (in-phase comp.) is modulated by Bk sequence (quadrature-phase comp.) is modulated by • composite signal is sent through the channel • advantage: data rate = 2 bits per bit-interval! B1 B2 B3A1 A2 A3 … Ak x cos(2πfct) Yi(t) = Ak cos(2πfct) Bk x sin(2πfct) Yq(t) = Bk sin(2πfct) + Transmitted Signal Y(t) = Ak cos(2πfct) + Bk sin(2πfct) t)fcos(2 cπ t)fsin(2 cπ t)fsin(2Bt)fcos(2A ckck ππ + 1 -1 1 1 -1 1 … 1 0 1 1 0 1 …
  • 18.
    18 Modulation of DigitalData: QAM (cont.) Example [ QAM ] Bk vd(t) Ak sin(ωct) cos(ωct)
  • 19.
    19 Modulation of DigitalData: QAM QAMQAM DemodulationDemodulation • by multiplying Y(t) by and then low- pass filtering the resultant signal, sequence Ak is obtained t)fcos(22 cπ⋅ • by multiplying Y(t) by and then low- pass filtering the resultant signal, sequence Bk is obtained t)fsin(22 cπ⋅ =+ t)fsin(2Bt)fcos(2A ckck ππ ( )cos(2A)1 2 1 (A)cos2 += ( )cos(2A)1 2 1 (A)sin2 −= (A)2sin(A)cossin(2A) = Y(t) x 2cos(2πfct) 2Akcos2(2πfct)+2Bk cos(2πfct)sin(2πfct) = Ak {1 + cos(4πfct)}+Bk {0 + sin(4πfct)} Lowpass filter (smoother) Ak 2Bk sin2(2πfct)+2Ak cos(2πfct)sin(2πfct) = Bk {1 - cos(4πfct)}+Ak {0 + sin(4πfct)} x 2sin(2πfct) Bk Lowpass filter (smoother) smoothed to zero smoothed to zero Y(t) x 2cos(2πfct) 2Akcos2(2πfct)+2Bk cos(2πfct)sin(2πfct) = Ak {1 + cos(4πfct)}+Bk {0 + sin(4πfct)} Lowpass filter (smoother) Ak x 2cos(2πfct) 2Akcos2(2πfct)+2Bk cos(2πfct)sin(2πfct) = Ak {1 + cos(4πfct)}+Bk {0 + sin(4πfct)} Lowpass filter (smoother) Ak 2Bk sin2(2πfct)+2Ak cos(2πfct)sin(2πfct) = Bk {1 - cos(4πfct)}+Ak {0 + sin(4πfct)} x 2sin(2πfct) Bk Lowpass filter (smoother) x 2sin(2πfct) Bk Lowpass filter (smoother) smoothed to zero smoothed to zero
  • 20.
    20 Signal Constellation Constellation DiagramConstellationDiagram – used to represents possible symbols that may be selected by a given modulation scheme as points in 2-D plane • X-axis is related to in-phase carrier: cos(ωct) the projection of the point on the X-axis defines the peak amplitude of the in-phase component • Y-axis is related to quadrature carrier: sin(ωct) the projection of the point on the Y-axis defines the peak amplitude of the quadrature component • the length of line that connects the point to the origin is the peak amplitude of the signal element (combination of X & Y components) • the angle the line makes with the X-axis is the phase of the signal element
  • 21.
    21 Modulation of DigitalData: QAM QAM cont.QAM cont. – QAM can also be seen as a combination of ASK & PSK ( ) ) A B tantfcos(2BAt)fsin(2Bt)fcos(2AY(t) k k1- ckkckck ++=+= πππ 2 1 22 Ak Bk (A, A) (A,-A)(-A,-A) (-A,A) Ak Bk Ak Bk (A, A) (A,-A)(-A,-A) (-A,A) 4-level QAM
  • 22.
    22 Ak Bk Ak Bk Modulation of DigitalData: QAM 1616--level QAMlevel QAM – the number of bits transmitted per T [sec] interval can be further increased by increasing the number of levels used • in case of 16-level QAM, Ak and Bk individually can assume 4 different levels: -1, -1/3, 1/3, 1 • data rate: 4 bits/pulse ⇒ 4W bits/second ( ) ) A B tantfcos(2BAt)fsin(2Bt)fcos(2AY(t) k k1- ckkckck ++=+= πππ 2 1 22 In QAM various combinations of amplitude and phase are employed to achieve higher digital data rates. Amplitude changes are susceptible to noise ⇒ the number of phase shifts used by a QAM system is always greater than the number of amplitude shifts. Ak and Bk individually can take on 4 different values; the resultant signal can take on (only) 3 different values!!!