This document discusses the topic of electrostatics and dielectrics in the Electromagnetic Theory course. It defines a dielectric as a material where charge displacement occurs in an external electric field rather than free motion of charges. Dielectrics are classified as polar or nonpolar depending on whether they have a permanent dipole moment. The types of polarization in dielectrics are electronic, orientation, and ionic polarization. Key concepts discussed include polarization density, polarization charge density, the relationship between polarization and electric field through susceptibility and relative permittivity, atomic polarizability, and the relationship between polarization and electric displacement. An example problem calculates the polarization given the electric displacement.
#include <iostream>
using namespace std;
const int N = 40;
void sum(int*p, int n, int d[]){
int i;
*p = 0;
for(i = 0; i < n; ++i)
{
*p = *p + d[i];
}
}
int main(void){
int i;
int accum = 0;
int data[N];
for(i = 0; i < N; ++i)
{
data[i] = i;
}
sum(&accum, N, data);
cout<<"sum is " << accum << endl;
return 0;
}#include <iostream>
using namespace std;
const int N = 40;
void sum(int*p, int n, int d[]){
int i;
*p = 0;
for(i = 0; i < n; ++i)
{
*p = *p + d[i];
}
}
int main(void){
int i;
int accum = 0;
int data[N];
for(i = 0; i < N; ++i)
{
data[i] = i;
}
sum(&accum, N, data);
cout<<"sum is " << accum << endl;
return 0;
}#include <iostream>
using namespace std;
const int N = 40;
void sum(int*p, int n, int d[]){
int i;
*p = 0;
for(i = 0; i < n; ++i)
{
*p = *p + d[i];
}
}
int main(void){
int i;
int accum = 0;
int data[N];
for(i = 0; i < N; ++i)
{
data[i] = i;
}
sum(&accum, N, data);
cout<<"sum is " << accum << endl;
return 0;
}#include <iostream>
using namespace std;
const int N = 40;
void sum(int*p, int n, int d[]){
int i;
*p = 0;
for(i = 0; i < n; ++i)
{
*p = *p + d[i];
}
}
int main(void){
int i;
int accum = 0;
int data[N];
for(i = 0; i < N; ++i)
{
data[i] = i;
}
sum(&accum, N, data);
cout<<"sum is " << accum << endl;
return 0;
}#include <iostream>
using namespace std;
const int N = 40;
void sum(int*p, int n, int d[]){
int i;
*p = 0;
for(i = 0; i < n; ++i)
{
*p = *p + d[i];
}
}
int main(void){
int i;
int accum = 0;
int data[N];
for(i = 0; i < N; ++i)
{
data[i] = i;
}
sum(&accum, N, data);
cout<<"sum is " << accum << endl;
return 0;
}#include <iostream>
using namespace std;
const int N = 40;
void sum(int*p, int n, int d[]){
int i;
*p = 0;
for(i = 0; i < n; ++i)
{
*p = *p + d[i];
}
}
int main(void){
int i;
int accum = 0;
int data[N];
for(i = 0; i < N; ++i)
{
data[i] = i;
}
sum(&accum, N, data);
cout<<"sum is " << accum << endl;
return 0;
}#include <iostream>
using namespace std;
const int N = 40;
void sum(int*p, int n, int d[]){
int i;
*p = 0;
for(i = 0; i < n; ++i)
{
*p = *p + d[i];
}
}
int main(void){
int i;
int accum = 0;
int data[N];
for(i = 0; i < N; ++i)
{
data[i] = i;
}
sum(&accum, N, data);
cout<<"sum is " << accum << endl;
return 0;
}#include <iostream>
using namespace std;
const int N = 40;
void sum(int*p, int n, int d[]){
int i;
*p = 0;
for(i = 0; i < n; ++i)
{
*p = *p + d[i];
}
}
int main(void){
int i;
int accum = 0;
int data[N];
for(i = 0; i < N; ++i)
{
data[i] = i;
}
sum(&accum, N, data);
cout<<"sum is " << accum << endl;
return 0;
}#include <iostream>
using namespace std
#include <iostream>
using namespace std;
const int N = 40;
void sum(int*p, int n, int d[]){
int i;
*p = 0;
for(i = 0; i < n; ++i)
{
*p = *p + d[i];
}
}
int main(void){
int i;
int accum = 0;
int data[N];
for(i = 0; i < N; ++i)
{
data[i] = i;
}
sum(&accum, N, data);
cout<<"sum is " << accum << endl;
return 0;
}#include <iostream>
using namespace std;
const int N = 40;
void sum(int*p, int n, int d[]){
int i;
*p = 0;
for(i = 0; i < n; ++i)
{
*p = *p + d[i];
}
}
int main(void){
int i;
int accum = 0;
int data[N];
for(i = 0; i < N; ++i)
{
data[i] = i;
}
sum(&accum, N, data);
cout<<"sum is " << accum << endl;
return 0;
}#include <iostream>
using namespace std;
const int N = 40;
void sum(int*p, int n, int d[]){
int i;
*p = 0;
for(i = 0; i < n; ++i)
{
*p = *p + d[i];
}
}
int main(void){
int i;
int accum = 0;
int data[N];
for(i = 0; i < N; ++i)
{
data[i] = i;
}
sum(&accum, N, data);
cout<<"sum is " << accum << endl;
return 0;
}#include <iostream>
using namespace std;
const int N = 40;
void sum(int*p, int n, int d[]){
int i;
*p = 0;
for(i = 0; i < n; ++i)
{
*p = *p + d[i];
}
}
int main(void){
int i;
int accum = 0;
int data[N];
for(i = 0; i < N; ++i)
{
data[i] = i;
}
sum(&accum, N, data);
cout<<"sum is " << accum << endl;
return 0;
}#include <iostream>
using namespace std;
const int N = 40;
void sum(int*p, int n, int d[]){
int i;
*p = 0;
for(i = 0; i < n; ++i)
{
*p = *p + d[i];
}
}
int main(void){
int i;
int accum = 0;
int data[N];
for(i = 0; i < N; ++i)
{
data[i] = i;
}
sum(&accum, N, data);
cout<<"sum is " << accum << endl;
return 0;
}#include <iostream>
using namespace std;
const int N = 40;
void sum(int*p, int n, int d[]){
int i;
*p = 0;
for(i = 0; i < n; ++i)
{
*p = *p + d[i];
}
}
int main(void){
int i;
int accum = 0;
int data[N];
for(i = 0; i < N; ++i)
{
data[i] = i;
}
sum(&accum, N, data);
cout<<"sum is " << accum << endl;
return 0;
}#include <iostream>
using namespace std;
const int N = 40;
void sum(int*p, int n, int d[]){
int i;
*p = 0;
for(i = 0; i < n; ++i)
{
*p = *p + d[i];
}
}
int main(void){
int i;
int accum = 0;
int data[N];
for(i = 0; i < N; ++i)
{
data[i] = i;
}
sum(&accum, N, data);
cout<<"sum is " << accum << endl;
return 0;
}#include <iostream>
using namespace std;
const int N = 40;
void sum(int*p, int n, int d[]){
int i;
*p = 0;
for(i = 0; i < n; ++i)
{
*p = *p + d[i];
}
}
int main(void){
int i;
int accum = 0;
int data[N];
for(i = 0; i < N; ++i)
{
data[i] = i;
}
sum(&accum, N, data);
cout<<"sum is " << accum << endl;
return 0;
}#include <iostream>
using namespace std
The following presentation consists of introduction to dielectrics, and includes following topics - Basic terms, Polarization of Dielectric, Polarization method, Internal Field, Clausius-Mossotti Equation, Types of dielectric, Properties of good Dielectric, and Application of Dielectric.
This Presentation "Energy band theory of solids" will help you to Clarify your doubts and Enrich your Knowledge. Kindly use this presentation as a Reference and utilize this presentation
It covers all the Maxwell's Equation for Point form(differential form) and integral form. It also covers Gauss Law for Electric Field, Gauss law for magnetic field, Faraday's Law and Ampere Maxwell law. It also covers the reason why Gauss Laws are also known as Maxwell's Equation.
The following presentation consists of introduction to dielectrics, and includes following topics - Basic terms, Polarization of Dielectric, Polarization method, Internal Field, Clausius-Mossotti Equation, Types of dielectric, Properties of good Dielectric, and Application of Dielectric.
This Presentation "Energy band theory of solids" will help you to Clarify your doubts and Enrich your Knowledge. Kindly use this presentation as a Reference and utilize this presentation
It covers all the Maxwell's Equation for Point form(differential form) and integral form. It also covers Gauss Law for Electric Field, Gauss law for magnetic field, Faraday's Law and Ampere Maxwell law. It also covers the reason why Gauss Laws are also known as Maxwell's Equation.
THE IMPORTANCE OF MARTIAN ATMOSPHERE SAMPLE RETURN.Sérgio Sacani
The return of a sample of near-surface atmosphere from Mars would facilitate answers to several first-order science questions surrounding the formation and evolution of the planet. One of the important aspects of terrestrial planet formation in general is the role that primary atmospheres played in influencing the chemistry and structure of the planets and their antecedents. Studies of the martian atmosphere can be used to investigate the role of a primary atmosphere in its history. Atmosphere samples would also inform our understanding of the near-surface chemistry of the planet, and ultimately the prospects for life. High-precision isotopic analyses of constituent gases are needed to address these questions, requiring that the analyses are made on returned samples rather than in situ.
Earliest Galaxies in the JADES Origins Field: Luminosity Function and Cosmic ...Sérgio Sacani
We characterize the earliest galaxy population in the JADES Origins Field (JOF), the deepest
imaging field observed with JWST. We make use of the ancillary Hubble optical images (5 filters
spanning 0.4−0.9µm) and novel JWST images with 14 filters spanning 0.8−5µm, including 7 mediumband filters, and reaching total exposure times of up to 46 hours per filter. We combine all our data
at > 2.3µm to construct an ultradeep image, reaching as deep as ≈ 31.4 AB mag in the stack and
30.3-31.0 AB mag (5σ, r = 0.1” circular aperture) in individual filters. We measure photometric
redshifts and use robust selection criteria to identify a sample of eight galaxy candidates at redshifts
z = 11.5 − 15. These objects show compact half-light radii of R1/2 ∼ 50 − 200pc, stellar masses of
M⋆ ∼ 107−108M⊙, and star-formation rates of SFR ∼ 0.1−1 M⊙ yr−1
. Our search finds no candidates
at 15 < z < 20, placing upper limits at these redshifts. We develop a forward modeling approach to
infer the properties of the evolving luminosity function without binning in redshift or luminosity that
marginalizes over the photometric redshift uncertainty of our candidate galaxies and incorporates the
impact of non-detections. We find a z = 12 luminosity function in good agreement with prior results,
and that the luminosity function normalization and UV luminosity density decline by a factor of ∼ 2.5
from z = 12 to z = 14. We discuss the possible implications of our results in the context of theoretical
models for evolution of the dark matter halo mass function.
Cancer cell metabolism: special Reference to Lactate PathwayAADYARAJPANDEY1
Normal Cell Metabolism:
Cellular respiration describes the series of steps that cells use to break down sugar and other chemicals to get the energy we need to function.
Energy is stored in the bonds of glucose and when glucose is broken down, much of that energy is released.
Cell utilize energy in the form of ATP.
The first step of respiration is called glycolysis. In a series of steps, glycolysis breaks glucose into two smaller molecules - a chemical called pyruvate. A small amount of ATP is formed during this process.
Most healthy cells continue the breakdown in a second process, called the Kreb's cycle. The Kreb's cycle allows cells to “burn” the pyruvates made in glycolysis to get more ATP.
The last step in the breakdown of glucose is called oxidative phosphorylation (Ox-Phos).
It takes place in specialized cell structures called mitochondria. This process produces a large amount of ATP. Importantly, cells need oxygen to complete oxidative phosphorylation.
If a cell completes only glycolysis, only 2 molecules of ATP are made per glucose. However, if the cell completes the entire respiration process (glycolysis - Kreb's - oxidative phosphorylation), about 36 molecules of ATP are created, giving it much more energy to use.
IN CANCER CELL:
Unlike healthy cells that "burn" the entire molecule of sugar to capture a large amount of energy as ATP, cancer cells are wasteful.
Cancer cells only partially break down sugar molecules. They overuse the first step of respiration, glycolysis. They frequently do not complete the second step, oxidative phosphorylation.
This results in only 2 molecules of ATP per each glucose molecule instead of the 36 or so ATPs healthy cells gain. As a result, cancer cells need to use a lot more sugar molecules to get enough energy to survive.
Unlike healthy cells that "burn" the entire molecule of sugar to capture a large amount of energy as ATP, cancer cells are wasteful.
Cancer cells only partially break down sugar molecules. They overuse the first step of respiration, glycolysis. They frequently do not complete the second step, oxidative phosphorylation.
This results in only 2 molecules of ATP per each glucose molecule instead of the 36 or so ATPs healthy cells gain. As a result, cancer cells need to use a lot more sugar molecules to get enough energy to survive.
introduction to WARBERG PHENOMENA:
WARBURG EFFECT Usually, cancer cells are highly glycolytic (glucose addiction) and take up more glucose than do normal cells from outside.
Otto Heinrich Warburg (; 8 October 1883 – 1 August 1970) In 1931 was awarded the Nobel Prize in Physiology for his "discovery of the nature and mode of action of the respiratory enzyme.
WARNBURG EFFECT : cancer cells under aerobic (well-oxygenated) conditions to metabolize glucose to lactate (aerobic glycolysis) is known as the Warburg effect. Warburg made the observation that tumor slices consume glucose and secrete lactate at a higher rate than normal tissues.
Slide 1: Title Slide
Extrachromosomal Inheritance
Slide 2: Introduction to Extrachromosomal Inheritance
Definition: Extrachromosomal inheritance refers to the transmission of genetic material that is not found within the nucleus.
Key Components: Involves genes located in mitochondria, chloroplasts, and plasmids.
Slide 3: Mitochondrial Inheritance
Mitochondria: Organelles responsible for energy production.
Mitochondrial DNA (mtDNA): Circular DNA molecule found in mitochondria.
Inheritance Pattern: Maternally inherited, meaning it is passed from mothers to all their offspring.
Diseases: Examples include Leber’s hereditary optic neuropathy (LHON) and mitochondrial myopathy.
Slide 4: Chloroplast Inheritance
Chloroplasts: Organelles responsible for photosynthesis in plants.
Chloroplast DNA (cpDNA): Circular DNA molecule found in chloroplasts.
Inheritance Pattern: Often maternally inherited in most plants, but can vary in some species.
Examples: Variegation in plants, where leaf color patterns are determined by chloroplast DNA.
Slide 5: Plasmid Inheritance
Plasmids: Small, circular DNA molecules found in bacteria and some eukaryotes.
Features: Can carry antibiotic resistance genes and can be transferred between cells through processes like conjugation.
Significance: Important in biotechnology for gene cloning and genetic engineering.
Slide 6: Mechanisms of Extrachromosomal Inheritance
Non-Mendelian Patterns: Do not follow Mendel’s laws of inheritance.
Cytoplasmic Segregation: During cell division, organelles like mitochondria and chloroplasts are randomly distributed to daughter cells.
Heteroplasmy: Presence of more than one type of organellar genome within a cell, leading to variation in expression.
Slide 7: Examples of Extrachromosomal Inheritance
Four O’clock Plant (Mirabilis jalapa): Shows variegated leaves due to different cpDNA in leaf cells.
Petite Mutants in Yeast: Result from mutations in mitochondrial DNA affecting respiration.
Slide 8: Importance of Extrachromosomal Inheritance
Evolution: Provides insight into the evolution of eukaryotic cells.
Medicine: Understanding mitochondrial inheritance helps in diagnosing and treating mitochondrial diseases.
Agriculture: Chloroplast inheritance can be used in plant breeding and genetic modification.
Slide 9: Recent Research and Advances
Gene Editing: Techniques like CRISPR-Cas9 are being used to edit mitochondrial and chloroplast DNA.
Therapies: Development of mitochondrial replacement therapy (MRT) for preventing mitochondrial diseases.
Slide 10: Conclusion
Summary: Extrachromosomal inheritance involves the transmission of genetic material outside the nucleus and plays a crucial role in genetics, medicine, and biotechnology.
Future Directions: Continued research and technological advancements hold promise for new treatments and applications.
Slide 11: Questions and Discussion
Invite Audience: Open the floor for any questions or further discussion on the topic.
This pdf is about the Schizophrenia.
For more details visit on YouTube; @SELF-EXPLANATORY;
https://www.youtube.com/channel/UCAiarMZDNhe1A3Rnpr_WkzA/videos
Thanks...!
Observation of Io’s Resurfacing via Plume Deposition Using Ground-based Adapt...Sérgio Sacani
Since volcanic activity was first discovered on Io from Voyager images in 1979, changes
on Io’s surface have been monitored from both spacecraft and ground-based telescopes.
Here, we present the highest spatial resolution images of Io ever obtained from a groundbased telescope. These images, acquired by the SHARK-VIS instrument on the Large
Binocular Telescope, show evidence of a major resurfacing event on Io’s trailing hemisphere. When compared to the most recent spacecraft images, the SHARK-VIS images
show that a plume deposit from a powerful eruption at Pillan Patera has covered part
of the long-lived Pele plume deposit. Although this type of resurfacing event may be common on Io, few have been detected due to the rarity of spacecraft visits and the previously low spatial resolution available from Earth-based telescopes. The SHARK-VIS instrument ushers in a new era of high resolution imaging of Io’s surface using adaptive
optics at visible wavelengths.
Observation of Io’s Resurfacing via Plume Deposition Using Ground-based Adapt...
Dielectrics
1. Course: Electromagnetic Theory
paper code: EI 503
Course Coordinator: Arpan Deyasi
Department of Electronics and Communication Engineering
RCC Institute of Information Technology
Kolkata, India
Topic: Electrostatics – Dielectric
17-11-2021 Arpan Deyasi, EM Theory 1
Arpan Deyasi
Electromagnetic
Theory
2. Dielectric
It is a type of material in which electrons are bound to their parent nuclei/molecules and
only motion is possible in presence of external electric field is electric displacement of
positive and negative charges along opposite directions
Once the charge displacement has taken place, the material becomes polarized
Polarized material induces dipole moments
Dipole field and external field are comparable in magnitude
17-11-2021 Arpan Deyasi, EM Theory 2
Arpan Deyasi
Electromagnetic
Theory
3. Classification of Dielectric
[i] Polar dielectric
▪ Asymmetric arrangement of atoms, which means centers of gravity of positive
and negative charges don’t coincide, even in absence of external electric field
▪ Owing to net charge separation, material has permanent dipole moment
▪ Ex: Acetone, Water ammonia
17-11-2021 Arpan Deyasi, EM Theory 3
E=0 E≠0
Arpan Deyasi
Electromagnetic
Theory
4. Classification of Dielectric
[ii] Nonpolar dielectric
▪ Symmetric arrangement of atoms, which means centers of gravity of positive and negative
charges coincide in absence of external electric field
▪ Separation of c.g takes place when external field is present
▪ Owing to net charge separation in absence of field, materials do not have permanent dipole
moment
▪ Ex: Benzene, Methane
17-11-2021 Arpan Deyasi, EM Theory 4
E=0 E≠0
Arpan Deyasi
Electromagnetic
Theory
5. Types of Polarization
[i] Electronic Polarization
Bound, negative cloud subject to external electric field is displaced from
equilibrium position relative to positive nucleus
17-11-2021 Arpan Deyasi, EM Theory 5
E
Arpan Deyasi
Electromagnetic
Theory
6. Types of Polarization
[ii] Orientation Polarization
Electric dipoles are oriented parallel to applied electric field opposing thermal
agitation and mutual interacting forces, from their previous random
distribution
17-11-2021 Arpan Deyasi, EM Theory 6
E=0 E≠0
Arpan Deyasi
Electromagnetic
Theory
7. Types of Polarization
17-11-2021 Arpan Deyasi, EM Theory 7
E=0 E≠0
E
[iii] Ionic Polarization
Positive and negative ions of a molecule are displaced in presence of external
electric field
Arpan Deyasi
Electromagnetic
Theory
8. Polarization Density
Polarization density is the vector field that expresses the density of permanent
or induced electric dipole moments in a dielectric material
2
/
P Nqd C m
=
N: number of molecules per unit volume
q: magnitude of charge
d: separation distance between positive charge and negative charge centers
17-11-2021 Arpan Deyasi, EM Theory 8
Arpan Deyasi
Electromagnetic
Theory
9. Polarization Volume Charge Density
Consider a medium consisting of N such polarized
particles per unit volume, where net charge q
contained within an arbitrary volume V is
enclosed by a surface S
Net charge
.
S
Q P ds
= −
.
V
Q Pdv
= −
17-11-2021 Arpan Deyasi, EM Theory 9
dS
E
n̂
S
Arpan Deyasi
Electromagnetic
Theory
10. Polarization Volume Charge Density
Net charge in V can be determined by integrating the polarization charge density
over its volume
v
V
Q dv
=
.
v
V V
dv Pdv
= −
.
v P
= −
17-11-2021 Arpan Deyasi, EM Theory 10
Arpan Deyasi
Electromagnetic
Theory
11. Net charge
Polarization Surface Charge Density
.
S
Q P ds
= −
P
S
Q ds
=
Again
.
P
S S
ds P ds
= −
ˆ
.
P P n
= −
17-11-2021 Arpan Deyasi, EM Theory 11
Arpan Deyasi
Electromagnetic
Theory
12. Relation between Polarization Vector and Electric Field
In free space
0E
=
Polarization field is directly proportional with electric field
0
P
E
−
=
When polarization is present, corresponding field works against the external electric field
P E
17-11-2021 Arpan Deyasi, EM Theory 12
Arpan Deyasi
Electromagnetic
Theory
13. Relation between Polarization Vector and Electric Field
0 e
P E
=
0
0
eE
E
−
=
0 0 e
E E
= −
0 0 e
E E
= −
χe is called susceptibility of the material
17-11-2021 Arpan Deyasi, EM Theory 13
Arpan Deyasi
Electromagnetic
Theory
14. Relation between Polarization Vector and Electric Field
0
1
1 e
E
=
+
The term (1+ χe) is called relative permittivity of the material, defined as εr
17-11-2021 Arpan Deyasi, EM Theory 14
Arpan Deyasi
Electromagnetic
Theory
15. Atomic Polarizability
Polarization density is given by
P pN
=
induced dipole moment
:
p
N: number of atoms per unit volume
Induced dipole moment acquired by the atom 0 e
p E
=
αe: number of atoms per unit volume (atomic polarizability)
0 e
P N E
=
17-11-2021 Arpan Deyasi, EM Theory 15
Arpan Deyasi
Electromagnetic
Theory
16. 17-11-2021 Arpan Deyasi, EM Theory 16
Relation between Polarization and Displacement
0 e
P E
=
0 e
P
E
=
0 r
D E
=
0 r
D
E
=
0 0
e r
P D
=
Arpan Deyasi
Electromagnetic
Theory
17. 17-11-2021 Arpan Deyasi, EM Theory 17
Relation between Polarization and Displacement
0 0
( 1)
r r
P D
=
−
( 1)
r
r
P D
−
=
Arpan Deyasi
Electromagnetic
Theory
18. 17-11-2021 Arpan Deyasi, EM Theory 18
Problem 1
Calculate polarization in a dielectric material with εr = 2.8, if displacement
density is 3⨯10-7 C/m2.
Soln
( 1)
r
r
P D
−
=
7 2
(2.8 1)
3 10 /
2.8
P C m
−
−
=
2
0.1928 /
P C m
=
Arpan Deyasi
Electromagnetic
Theory