CBSE - 10                                        Chemical Reactions and Equations
Chemistry                                           Representing a Chemical Reaction

  Balancing Chemical Equations                           In step-1, we need to write the
                                                         word equation. Methane
                                                         gives carbon dioxide and
     Step-1                                              water on combustion in air.

     Methane + Oxygen  Carbon dioxide + Water




Subtopic ID: 01.02.03
CBSE - 10                                        Chemical Reactions and Equations
Chemistry                                           Representing a Chemical Reaction

  Balancing Chemical Equations                           Let us represent the word
                                                         equation by the respective
                                                         molecular formula.
     Step-2
     CH4      + O2       CO2         + H2O
     Methane + Oxygen  Carbon dioxide + Water




Subtopic ID: 01.02.03
CBSE - 10                                         Chemical Reactions and Equations
Chemistry                                               Representing a Chemical Reaction

  Balancing Chemical Equations                               Write down the number of
                                                             atoms present on each side of
    Step-3                                                   the arrow. On the right hand
                                                             side we have one carbon, four
                                                             hydrogen and 2 oxygen
     CH4 + O2  CO2 + H2O                                    atoms. On the right hand side
                                                             we have 1 carbon, 2 hydrogen
                                                             and 3 oxygen atoms.
                    No. of atoms in   No. of atoms in
       Element           LHS               RHS
            C               1               1
            H               4               2
            O               2               3




Subtopic ID: 01.02.03
Chemical Reactions and Equations
                                                      Representing a Chemical Reaction

  Balancing Chemical Equations                             The atoms are not balanced in
                                                           this equation. Start balancing
  Step-4                                                   from the element with the
                                                           greater number of atoms. Do
                                                           not give priority to the atom
     CH4 + O2  CO2 + H2O                                  found in more than one
                                                           compound on either side of
                  No. of atoms in   No. of atoms           the arrow. For example, since
                                                           oxygen is present in two
     Element           LHS            in RHS               compounds on the right hand
                                                           side we should not give
           C            1                1                 priority to the oxygen atom
           H            4                2                 when balancing.

           O            2                3




Subtopic ID: 01.02.03
CBSE - 10                                         Chemical Reactions and Equations
Chemistry                                               Representing a Chemical Reaction

  Balancing Chemical Equations                               Balance the hydrogen atoms
                                                             by multiplying by 2 on the right
  Step-5                                                     hand side.


     CH4 + O2  CO2 + H2O

                    No. of atoms in   No. of atoms in
       Element           LHS               RHS
            C               1               1
            H               4              2x2
            O               2               3




Subtopic ID: 01.02.03
CBSE - 10                                         Chemical Reactions and Equations
Chemistry                                               Representing a Chemical Reaction

  Balancing Chemical Equations                               Write out the partially
                                                             balanced equation.

       Step-6
       CH4 + O2  CO2 + 2H2O
                    No. of atoms in   No. of atoms in
       Element           LHS               RHS
            C             1                 1
            H             4                2x2
            O             2                 3




Subtopic ID: 01.02.03
CBSE - 10                                          Chemical Reactions and Equations
Chemistry                                             Representing a Chemical Reaction

  Balancing Chemical Equations                             Write down the number of
                                                           atoms present on both sides
  Step-7                                                   of the arrow of the revised
                                                           equation. Again check
                                                           whether all the atoms are
                                                           balanced.
     CH4 + O2  CO2 + 2H2O
                        Step-7
                 No. of atoms    No. of atoms in
     Element       in LHS             RHS
           C            1              1
           H            4              4
           O            2              4




Subtopic ID: 01.02.03
Chemical Reactions and Equations
                                                      Representing a Chemical Reaction

  Balancing Chemical Equations                             Balance the atoms of the
                                                           remaining elements, here
  Step-8                                                   oxygen.



     CH4 + O2  CO2 + 2H2O
                        Step-7
                 No. of atoms    No. of atoms in
     Element       in LHS             RHS
           C             1             1
           H             4             4
           O            2x2             4




Subtopic ID: 01.02.03
Chemical Reactions and Equations
                                                      Representing a Chemical Reaction

  Balancing Chemical Equations                             Write down the balanced
                                                           equation.

       Step-9
       CH4 + 2O2  CO2 + 2H2O


                 No. of atoms    No. of atoms in
     Element       in LHS             RHS
         C               1             1
         H               4             4
         O              2x2             4




Subtopic ID: 01.02.03

Balancing chemical equation

  • 1.
    CBSE - 10 Chemical Reactions and Equations Chemistry Representing a Chemical Reaction Balancing Chemical Equations In step-1, we need to write the word equation. Methane gives carbon dioxide and Step-1 water on combustion in air. Methane + Oxygen  Carbon dioxide + Water Subtopic ID: 01.02.03
  • 2.
    CBSE - 10 Chemical Reactions and Equations Chemistry Representing a Chemical Reaction Balancing Chemical Equations Let us represent the word equation by the respective molecular formula. Step-2 CH4 + O2  CO2 + H2O Methane + Oxygen  Carbon dioxide + Water Subtopic ID: 01.02.03
  • 3.
    CBSE - 10 Chemical Reactions and Equations Chemistry Representing a Chemical Reaction Balancing Chemical Equations Write down the number of atoms present on each side of Step-3 the arrow. On the right hand side we have one carbon, four hydrogen and 2 oxygen CH4 + O2  CO2 + H2O atoms. On the right hand side we have 1 carbon, 2 hydrogen and 3 oxygen atoms. No. of atoms in No. of atoms in Element LHS RHS C 1 1 H 4 2 O 2 3 Subtopic ID: 01.02.03
  • 4.
    Chemical Reactions andEquations Representing a Chemical Reaction Balancing Chemical Equations The atoms are not balanced in this equation. Start balancing Step-4 from the element with the greater number of atoms. Do not give priority to the atom CH4 + O2  CO2 + H2O found in more than one compound on either side of No. of atoms in No. of atoms the arrow. For example, since oxygen is present in two Element LHS in RHS compounds on the right hand side we should not give C 1 1 priority to the oxygen atom H 4 2 when balancing. O 2 3 Subtopic ID: 01.02.03
  • 5.
    CBSE - 10 Chemical Reactions and Equations Chemistry Representing a Chemical Reaction Balancing Chemical Equations Balance the hydrogen atoms by multiplying by 2 on the right Step-5 hand side. CH4 + O2  CO2 + H2O No. of atoms in No. of atoms in Element LHS RHS C 1 1 H 4 2x2 O 2 3 Subtopic ID: 01.02.03
  • 6.
    CBSE - 10 Chemical Reactions and Equations Chemistry Representing a Chemical Reaction Balancing Chemical Equations Write out the partially balanced equation. Step-6 CH4 + O2  CO2 + 2H2O No. of atoms in No. of atoms in Element LHS RHS C 1 1 H 4 2x2 O 2 3 Subtopic ID: 01.02.03
  • 7.
    CBSE - 10 Chemical Reactions and Equations Chemistry Representing a Chemical Reaction Balancing Chemical Equations Write down the number of atoms present on both sides Step-7 of the arrow of the revised equation. Again check whether all the atoms are balanced. CH4 + O2  CO2 + 2H2O Step-7 No. of atoms No. of atoms in Element in LHS RHS C 1 1 H 4 4 O 2 4 Subtopic ID: 01.02.03
  • 8.
    Chemical Reactions andEquations Representing a Chemical Reaction Balancing Chemical Equations Balance the atoms of the remaining elements, here Step-8 oxygen. CH4 + O2  CO2 + 2H2O Step-7 No. of atoms No. of atoms in Element in LHS RHS C 1 1 H 4 4 O 2x2 4 Subtopic ID: 01.02.03
  • 9.
    Chemical Reactions andEquations Representing a Chemical Reaction Balancing Chemical Equations Write down the balanced equation. Step-9 CH4 + 2O2  CO2 + 2H2O No. of atoms No. of atoms in Element in LHS RHS C 1 1 H 4 4 O 2x2 4 Subtopic ID: 01.02.03