GAY- LUSSAC’S LAWNicole&Kassi.
The pressure of a fixed mass of gas, at constant volume, is directly proportional to the Kelvin temperature.P= kT
P1=  P2T1	 T2At a temperature of 40ºC an oxygen container is at a pressure of 21.5 atmospheres. If the temperature of the container is raised to 100ºC what will be the pressure of the Oxygen?
At a temperature of 40ºC an oxygen container is at a pressure of 21.5 atmospheres. If the temperature of the container is raised to 100ºC what will be the pressure of the Oxygen? Step1: convert C  FStep2: Multiply the original pressure by a ratio of Kelvin temperatures that will result in an increase pressure.

Gay Lussac’s Law

  • 1.
  • 2.
    The pressure ofa fixed mass of gas, at constant volume, is directly proportional to the Kelvin temperature.P= kT
  • 3.
    P1= P2T1 T2At a temperature of 40ºC an oxygen container is at a pressure of 21.5 atmospheres. If the temperature of the container is raised to 100ºC what will be the pressure of the Oxygen?
  • 4.
    At a temperatureof 40ºC an oxygen container is at a pressure of 21.5 atmospheres. If the temperature of the container is raised to 100ºC what will be the pressure of the Oxygen? Step1: convert C  FStep2: Multiply the original pressure by a ratio of Kelvin temperatures that will result in an increase pressure.