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Unit Circle
Getting circles, trig, triangles
and radians all together for
over 100 years
Solving Equations
 To find zeroes:
 y = sinx = 0
 Solve sin x = 0
 Take inverse sine of both sides to
solve for x
 So x = 0 and π
 T
The Unit Circle
Unit Circle
 Initial side: the right half of the x
axis, equal to the unit circle radius, is
considered the starting point for any
angles in the unit circle.
 Terminal side: the side, equal in
length to the initial side, after a
rotation of angle Θ.
Unit Circle Quadrant Table
Arc
Measure
Quad Sign
Sin Θ
Sign
Cos Θ
Sign
Tan Θ
0< Θ < π/2
π/2 < Θ < π
π < Θ < 3π/2
3π/2 < Θ < 2π
Pythagoras
 Pythagoras can help determine some
of the values on a unit circle.
 E.g. At P(Θ) = P(30˚) or P(π/6)
 The hypotenuse is 1, the opposite is 0.5
by the 30˚ rule, so what is the adjacent
side’s length?
 Use Pythagoras’ Theorem to solve.
Unit Circle Trig
 P(Θ) is the trigonometric point on the unit
circle after rotation of angle Θ
 sin Θ = the y coordinate of P(Θ)
 cos Θ = the x coordinate of P(Θ)
 tan Θ = sinΘ = y coordinate of P(Θ)
cosΘ x coordinate of P(Θ)
Activities
 P. 238, Q. 1,2,5, 6, 7, 8
Sine Function: y = sin x
Terms
 Amplitude = how much the y
increases and decreases from the
midpoint.
 Amplitude = (max-min)/2
 Amplitude is always positive = A
 In the equation amplitude is “a”
which can be positive or negative
 So A = |a|
Terms
 Period, p, describes the length of one
full cycle or the wavelength of the
function.
 Period is determined from the term
“b”.
 p = 2π/|b|, p is positive
 The longer the period, the lower the
frequency.
 Period = 1/frequency = 1/2π for sine fn
Rule for Basic Sine Function
Property Basic Function Transformed Function
Rule y = sin x y = a sin b(x-h) + k
Graph Sinusoidal
a = 1
Period =2π
Sinusoidal
a = amplitude
p = 2π/p p = period
h = horizontal translation
k = vertical translation
Domain ¶R ¶R
Range [-1,1] [k + A, k – A]
Rule for Basic Sine Function
Property Basic
Function
Transformed Function
Extremes Max 1
Min -1
Max k+ A
Min k - A
Variation Periodically
Inc or dec
Periodically increase or
decrease
Sign Depends Depends
Inverse Not a fn Not a fn
Exam QuestionThe population growth P of the native people of Northern Quebec is represented by the graph of
the sinusoidal function with equation
    6004
4
sin400 

 ttP
where t is the number of years elapsed since 1984.
Which one of the graphs below corresponds to this situation?
A)
1 000
600
200
2 4 6 8 t
E(t) C)
1 000
600
200
2 4 6 8 t
E(t)
B)
1 000
600
200
2 4 6 8 t
E(t) D)
1 000
600
200
2 4 6 8 t
E(t)
BIM : Information
Origin : BIM National Committee - Montérégie Region
Activities
 Page 253, Q. 6,9,13
 N.B. Many answers are periodic, i.e.
repetitive , (like me). So an answer
of 1 with a period of π, would give a
set {1, 1+ π, 1+2 π, 1+3 π….}
1 + n π, n Є Z, where n is an integer
Cosine Function: y = cos x
Rule for Basic Cosine Function
Property Basic Function Transformed Function
Rule y = cos x y = a cos b(x-h) + k
Graph Sinusoidal
a = 1
Period = 2π
Sinusoidal
a = amplitude
b = 2π/p p = period
h = horizontal translation
k = vertical translation
π/2 out of phase of sine
Domain ¶R ¶R
Range [-1,1] [k + A, k – A]
Rule for Basic Cosine Function
Property Basic
Function
Transformed Function
Extremes Max -1
Min 1
Max k + A
Min k - A
Variation Periodically
inc or dec
Periodically inc or dec
Sign Depends Depends
Inverse Not a fn Not a fn
Exam Question
If the value of x varies from  to 2, the function f(x) = cos x
A) increases in [, 2].
B) decreases in [, 2].
C) increases in 


 

2
3
, and decreases in .2,
2
3






D) decreases in 


 

2
3
, and increases in .2,
2
3






Activities
 Page 263, Q. 4,6,9, 14
Tangent Function y = tan x
Rule for Basic Tangent Function
Property Basic Function Transformed Function
Rule y = tan x y = a tan b(x-h) + k
Graph Sinusoidal
a = 1
asymptote
Sinusoidal
a = amplitude
b = π/p p = period
h = horizontal translation
k = vertical translation
Domain ¶R ¶R
Range [-1,1] [k + a, k – a]
Rule for Basic Tangent Function
Property Basic
Function
Transformed Function
Extremes None None
Variation Depends Depends
Sign Either inc or
dec per fn
Either inc or dec per fn
Inverse Not a fn Not a fn
Exam Question
Which one of the following graphs represents the tangent function for the interval [0, ]?
A) f(x)
x

2
C) f(x)
x

B) f(x)
x

2
D) f(x)
x

Activities
 Page 270, Q. 4,9,10
Solving Trig Equations
 To solve sine equations for zero or
any other number, take the following
steps:
 Y = sin x = 0
 Sin x = 0
 Take inverse sine on both sides to
solve for x
 Based on the unit circle that gives
two possible zeroes.
Unit Circle & Equations
 So, sin x = 0
 The inverse sine of (0) gives 2
results
 sin -1 (sin x) = sin -1 (0)
 So x = 0 and x = π (180˚)
 Why?
 Because sin 0˚ = 0 and sin 180˚ = 0.
Remember sin Θ = sin (180˚ – Θ)
Solving Sine Equations
 E.g sin (x-2) = √2/2
 sin -1 (sin (x-2) = sin -1 (√2/2)
 So (x-2) = 0.785 or (x-2) = 2.356
 x = 0.785 +2 cuz sin(x)=sin(π-x)
 x = 2.785 so x = 4.356
 So the answers are 2.785 and 4.356
 To allow for a periodic/repeating answer
 2.785 + 2πn, where n is an integer
 4.356 + 2πn, n Є Z

Cosine Equations
 For cosine, remember that
 cos (x) = cos (-x) = cos (2π-x)
 E.g. cos (x)= 0
 cos -1 (cos (x)) = cos -1 (0)
 x = π/2 or x = 3π/2
Solving Cosine Equations
 E.g cos (2x+3) = √3/2
 cos -1 (cos (2x+3) = cos -1 (0.866)
 So (2x+3) = 0.523 or (2x+3) = 5.757
 2x = 0.523 -3 cuz cos(x)=cos(2π-x)
 x =-2.477 so x = 1.3785
 So the answers are -2.477 and 1.3785
 To allow for a periodic/repeating answer
 -2.477 + 2πn, where n is an integer
 & 1.3785 + 2πn, n Є Z

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Unit circle

  • 1. Unit Circle Getting circles, trig, triangles and radians all together for over 100 years
  • 2. Solving Equations  To find zeroes:  y = sinx = 0  Solve sin x = 0  Take inverse sine of both sides to solve for x  So x = 0 and π  T
  • 4. Unit Circle  Initial side: the right half of the x axis, equal to the unit circle radius, is considered the starting point for any angles in the unit circle.  Terminal side: the side, equal in length to the initial side, after a rotation of angle Θ.
  • 5. Unit Circle Quadrant Table Arc Measure Quad Sign Sin Θ Sign Cos Θ Sign Tan Θ 0< Θ < π/2 π/2 < Θ < π π < Θ < 3π/2 3π/2 < Θ < 2π
  • 6. Pythagoras  Pythagoras can help determine some of the values on a unit circle.  E.g. At P(Θ) = P(30˚) or P(π/6)  The hypotenuse is 1, the opposite is 0.5 by the 30˚ rule, so what is the adjacent side’s length?  Use Pythagoras’ Theorem to solve.
  • 7. Unit Circle Trig  P(Θ) is the trigonometric point on the unit circle after rotation of angle Θ  sin Θ = the y coordinate of P(Θ)  cos Θ = the x coordinate of P(Θ)  tan Θ = sinΘ = y coordinate of P(Θ) cosΘ x coordinate of P(Θ)
  • 8.
  • 9. Activities  P. 238, Q. 1,2,5, 6, 7, 8
  • 10. Sine Function: y = sin x
  • 11. Terms  Amplitude = how much the y increases and decreases from the midpoint.  Amplitude = (max-min)/2  Amplitude is always positive = A  In the equation amplitude is “a” which can be positive or negative  So A = |a|
  • 12. Terms  Period, p, describes the length of one full cycle or the wavelength of the function.  Period is determined from the term “b”.  p = 2π/|b|, p is positive  The longer the period, the lower the frequency.  Period = 1/frequency = 1/2π for sine fn
  • 13. Rule for Basic Sine Function Property Basic Function Transformed Function Rule y = sin x y = a sin b(x-h) + k Graph Sinusoidal a = 1 Period =2π Sinusoidal a = amplitude p = 2π/p p = period h = horizontal translation k = vertical translation Domain ¶R ¶R Range [-1,1] [k + A, k – A]
  • 14. Rule for Basic Sine Function Property Basic Function Transformed Function Extremes Max 1 Min -1 Max k+ A Min k - A Variation Periodically Inc or dec Periodically increase or decrease Sign Depends Depends Inverse Not a fn Not a fn
  • 15. Exam QuestionThe population growth P of the native people of Northern Quebec is represented by the graph of the sinusoidal function with equation     6004 4 sin400    ttP where t is the number of years elapsed since 1984. Which one of the graphs below corresponds to this situation? A) 1 000 600 200 2 4 6 8 t E(t) C) 1 000 600 200 2 4 6 8 t E(t) B) 1 000 600 200 2 4 6 8 t E(t) D) 1 000 600 200 2 4 6 8 t E(t) BIM : Information Origin : BIM National Committee - Montérégie Region
  • 16. Activities  Page 253, Q. 6,9,13  N.B. Many answers are periodic, i.e. repetitive , (like me). So an answer of 1 with a period of π, would give a set {1, 1+ π, 1+2 π, 1+3 π….} 1 + n π, n Є Z, where n is an integer
  • 18. Rule for Basic Cosine Function Property Basic Function Transformed Function Rule y = cos x y = a cos b(x-h) + k Graph Sinusoidal a = 1 Period = 2π Sinusoidal a = amplitude b = 2π/p p = period h = horizontal translation k = vertical translation π/2 out of phase of sine Domain ¶R ¶R Range [-1,1] [k + A, k – A]
  • 19. Rule for Basic Cosine Function Property Basic Function Transformed Function Extremes Max -1 Min 1 Max k + A Min k - A Variation Periodically inc or dec Periodically inc or dec Sign Depends Depends Inverse Not a fn Not a fn
  • 20. Exam Question If the value of x varies from  to 2, the function f(x) = cos x A) increases in [, 2]. B) decreases in [, 2]. C) increases in       2 3 , and decreases in .2, 2 3       D) decreases in       2 3 , and increases in .2, 2 3      
  • 21. Activities  Page 263, Q. 4,6,9, 14
  • 23. Rule for Basic Tangent Function Property Basic Function Transformed Function Rule y = tan x y = a tan b(x-h) + k Graph Sinusoidal a = 1 asymptote Sinusoidal a = amplitude b = π/p p = period h = horizontal translation k = vertical translation Domain ¶R ¶R Range [-1,1] [k + a, k – a]
  • 24. Rule for Basic Tangent Function Property Basic Function Transformed Function Extremes None None Variation Depends Depends Sign Either inc or dec per fn Either inc or dec per fn Inverse Not a fn Not a fn
  • 25. Exam Question Which one of the following graphs represents the tangent function for the interval [0, ]? A) f(x) x  2 C) f(x) x  B) f(x) x  2 D) f(x) x 
  • 27. Solving Trig Equations  To solve sine equations for zero or any other number, take the following steps:  Y = sin x = 0  Sin x = 0  Take inverse sine on both sides to solve for x  Based on the unit circle that gives two possible zeroes.
  • 28. Unit Circle & Equations  So, sin x = 0  The inverse sine of (0) gives 2 results  sin -1 (sin x) = sin -1 (0)  So x = 0 and x = π (180˚)  Why?  Because sin 0˚ = 0 and sin 180˚ = 0. Remember sin Θ = sin (180˚ – Θ)
  • 29. Solving Sine Equations  E.g sin (x-2) = √2/2  sin -1 (sin (x-2) = sin -1 (√2/2)  So (x-2) = 0.785 or (x-2) = 2.356  x = 0.785 +2 cuz sin(x)=sin(π-x)  x = 2.785 so x = 4.356  So the answers are 2.785 and 4.356  To allow for a periodic/repeating answer  2.785 + 2πn, where n is an integer  4.356 + 2πn, n Є Z 
  • 30. Cosine Equations  For cosine, remember that  cos (x) = cos (-x) = cos (2π-x)  E.g. cos (x)= 0  cos -1 (cos (x)) = cos -1 (0)  x = π/2 or x = 3π/2
  • 31. Solving Cosine Equations  E.g cos (2x+3) = √3/2  cos -1 (cos (2x+3) = cos -1 (0.866)  So (2x+3) = 0.523 or (2x+3) = 5.757  2x = 0.523 -3 cuz cos(x)=cos(2π-x)  x =-2.477 so x = 1.3785  So the answers are -2.477 and 1.3785  To allow for a periodic/repeating answer  -2.477 + 2πn, where n is an integer  & 1.3785 + 2πn, n Є Z