The document discusses concepts related to curves, tangents, normals, and curvature. It provides formulas for calculating the equation of the tangent and normal to a curve at a given point, as well as the length of the subtangent and subnormal. It also discusses how to find the radius of curvature and center of curvature at a point on a curve. An example is worked out to find the center of curvature of the curve xy=16 at the point (4,4).
Slope and Deflection Method ,The Moment Distribution Method ,Strain Energy Me...Aayushi5
An introduction to Different method is given here. The strain energy method actually solves these equations by the method of successive approximations.
Problems are solved to illustrate the Strain energy method as applied element.
Slope and Deflection Method ,The Moment Distribution Method ,Strain Energy Me...Aayushi5
An introduction to Different method is given here. The strain energy method actually solves these equations by the method of successive approximations.
Problems are solved to illustrate the Strain energy method as applied element.
Basic mechanical engineering (BMET-101/102) unit 4- part1 (force system and a...Varun Pratap Singh
Download Link: https://sites.google.com/view/varunpratapsingh/teaching-engagements
Unit-4 Part -1
Force system and Analysis
Basic concept: Review of laws of motion, transfer of force to parallel position, resultant of planer force system, Free-Body Diagrams, Equilibrium. Friction: Introduction, Laws of Coulomb friction, Equilibrium of bodies involving dry fiction.
Asignatura: Educacion fisica. Esto sirve para que puedas o hacer un buen saque y como pegarle al balon y sepas todos los saque que existen en el voleibol. Dada la importancia del saque en el momento actual del juego, llamase el Vóley, esta investigación esboza el análisis del mismo considerándolo como una habilidad compleja con diferentes componentes conductuales, que se desarrolla en su práctica como deporte y afición.
Experimental and numerical stress analysis of a rectangular wing structureLahiru Dilshan
Structures of an aircraft can be categorised as primary structural components and secondary structure components. Primary structure components are the components which lead to failure of the aircraft if such component is failed during the flight cycle. Secondary components are load sharing components in an aircraft but will not pave the way to catastrophic failure.
Designing aircraft structures should follow several strategies to assure safety. For that, there are three main methods used in designing and maintenance procedures. First one is the safe flight, which an aircraft component has a lifetime. That component is not used beyond that limit and should replace though it is not failed. The fail-safe method is another one that redundant systems or components are there to ensure there is another way to carry the load or do necessary control. The final one is the damage tolerance which measures the current damages are within acceptable limit and carry out the main functions until the next main maintenance process.
To determine the safety of a structure component load distribution, stress and strain variation, deflection can be used as parameters to make sure that component can withstand maximum allowable load with safety factor. There are several techniques used to get accurate results as numerical methods, Finite Element Method (FEM) and experimental methods. In the design process, those three steps are followed in an orderly manner to ensure the safety of an aircraft.
Learn Online Courses of Subject Engineering Mechanics of First Year Engineering. Clear the Concepts of Engineering Mechanics Through Video Lectures and PDF Notes. Visit us: https://ekeeda.com/streamdetails/subject/Engineering-Mechanics
Compactness and homogeneous maps on Banach function spacesesasancpe
The aim of this talk is to show how compact operators between Banach function spaces can be approximated by means of homogeneous maps. After explaining the special characterizations of compact and weakly compact sets that are known for Banach function spaces, we develop a factorization method for describing lattice and topological properties of homogeneous maps by approximating with “simple” homogeneous maps. No approximation properties for the spaces involved are needed. A canonical homogeneous map that is defined as φp(f ) := |f |1/p · ∥f ∥1/p′ from a Banach function space X into its p-th power X[p] plays a meaningful role.
This work has its roots in some classical descriptions of weakly compact subsets of Banach spaces (Grothendieck, Fremlin,...), but particular Banach lattice tools (p-convexification, Maurey-Rosenthal type theorems) are also required.
Basic mechanical engineering (BMET-101/102) unit 4- part1 (force system and a...Varun Pratap Singh
Download Link: https://sites.google.com/view/varunpratapsingh/teaching-engagements
Unit-4 Part -1
Force system and Analysis
Basic concept: Review of laws of motion, transfer of force to parallel position, resultant of planer force system, Free-Body Diagrams, Equilibrium. Friction: Introduction, Laws of Coulomb friction, Equilibrium of bodies involving dry fiction.
Asignatura: Educacion fisica. Esto sirve para que puedas o hacer un buen saque y como pegarle al balon y sepas todos los saque que existen en el voleibol. Dada la importancia del saque en el momento actual del juego, llamase el Vóley, esta investigación esboza el análisis del mismo considerándolo como una habilidad compleja con diferentes componentes conductuales, que se desarrolla en su práctica como deporte y afición.
Experimental and numerical stress analysis of a rectangular wing structureLahiru Dilshan
Structures of an aircraft can be categorised as primary structural components and secondary structure components. Primary structure components are the components which lead to failure of the aircraft if such component is failed during the flight cycle. Secondary components are load sharing components in an aircraft but will not pave the way to catastrophic failure.
Designing aircraft structures should follow several strategies to assure safety. For that, there are three main methods used in designing and maintenance procedures. First one is the safe flight, which an aircraft component has a lifetime. That component is not used beyond that limit and should replace though it is not failed. The fail-safe method is another one that redundant systems or components are there to ensure there is another way to carry the load or do necessary control. The final one is the damage tolerance which measures the current damages are within acceptable limit and carry out the main functions until the next main maintenance process.
To determine the safety of a structure component load distribution, stress and strain variation, deflection can be used as parameters to make sure that component can withstand maximum allowable load with safety factor. There are several techniques used to get accurate results as numerical methods, Finite Element Method (FEM) and experimental methods. In the design process, those three steps are followed in an orderly manner to ensure the safety of an aircraft.
Learn Online Courses of Subject Engineering Mechanics of First Year Engineering. Clear the Concepts of Engineering Mechanics Through Video Lectures and PDF Notes. Visit us: https://ekeeda.com/streamdetails/subject/Engineering-Mechanics
Compactness and homogeneous maps on Banach function spacesesasancpe
The aim of this talk is to show how compact operators between Banach function spaces can be approximated by means of homogeneous maps. After explaining the special characterizations of compact and weakly compact sets that are known for Banach function spaces, we develop a factorization method for describing lattice and topological properties of homogeneous maps by approximating with “simple” homogeneous maps. No approximation properties for the spaces involved are needed. A canonical homogeneous map that is defined as φp(f ) := |f |1/p · ∥f ∥1/p′ from a Banach function space X into its p-th power X[p] plays a meaningful role.
This work has its roots in some classical descriptions of weakly compact subsets of Banach spaces (Grothendieck, Fremlin,...), but particular Banach lattice tools (p-convexification, Maurey-Rosenthal type theorems) are also required.
Mathematics (from Greek μάθημα máthēma, “knowledge, study, learning”) is the study of topics such as quantity (numbers), structure, space, and change. There is a range of views among mathematicians and philosophers as to the exact scope and definition of mathematics
Circle, Definition, Equation of circle whose center and radius is known, General equation of a circle, Equation of circle passing through three given points, Equation of circle whose diameters is line joining two points (x1, y1) & (x2,y2), Tangent and Normal to a given circle at given point.
Palestine last event orientationfvgnh .pptxRaedMohamed3
An EFL lesson about the current events in Palestine. It is intended to be for intermediate students who wish to increase their listening skills through a short lesson in power point.
The Indian economy is classified into different sectors to simplify the analysis and understanding of economic activities. For Class 10, it's essential to grasp the sectors of the Indian economy, understand their characteristics, and recognize their importance. This guide will provide detailed notes on the Sectors of the Indian Economy Class 10, using specific long-tail keywords to enhance comprehension.
For more information, visit-www.vavaclasses.com
Instructions for Submissions thorugh G- Classroom.pptxJheel Barad
This presentation provides a briefing on how to upload submissions and documents in Google Classroom. It was prepared as part of an orientation for new Sainik School in-service teacher trainees. As a training officer, my goal is to ensure that you are comfortable and proficient with this essential tool for managing assignments and fostering student engagement.
The Roman Empire A Historical Colossus.pdfkaushalkr1407
The Roman Empire, a vast and enduring power, stands as one of history's most remarkable civilizations, leaving an indelible imprint on the world. It emerged from the Roman Republic, transitioning into an imperial powerhouse under the leadership of Augustus Caesar in 27 BCE. This transformation marked the beginning of an era defined by unprecedented territorial expansion, architectural marvels, and profound cultural influence.
The empire's roots lie in the city of Rome, founded, according to legend, by Romulus in 753 BCE. Over centuries, Rome evolved from a small settlement to a formidable republic, characterized by a complex political system with elected officials and checks on power. However, internal strife, class conflicts, and military ambitions paved the way for the end of the Republic. Julius Caesar’s dictatorship and subsequent assassination in 44 BCE created a power vacuum, leading to a civil war. Octavian, later Augustus, emerged victorious, heralding the Roman Empire’s birth.
Under Augustus, the empire experienced the Pax Romana, a 200-year period of relative peace and stability. Augustus reformed the military, established efficient administrative systems, and initiated grand construction projects. The empire's borders expanded, encompassing territories from Britain to Egypt and from Spain to the Euphrates. Roman legions, renowned for their discipline and engineering prowess, secured and maintained these vast territories, building roads, fortifications, and cities that facilitated control and integration.
The Roman Empire’s society was hierarchical, with a rigid class system. At the top were the patricians, wealthy elites who held significant political power. Below them were the plebeians, free citizens with limited political influence, and the vast numbers of slaves who formed the backbone of the economy. The family unit was central, governed by the paterfamilias, the male head who held absolute authority.
Culturally, the Romans were eclectic, absorbing and adapting elements from the civilizations they encountered, particularly the Greeks. Roman art, literature, and philosophy reflected this synthesis, creating a rich cultural tapestry. Latin, the Roman language, became the lingua franca of the Western world, influencing numerous modern languages.
Roman architecture and engineering achievements were monumental. They perfected the arch, vault, and dome, constructing enduring structures like the Colosseum, Pantheon, and aqueducts. These engineering marvels not only showcased Roman ingenuity but also served practical purposes, from public entertainment to water supply.
Unit 8 - Information and Communication Technology (Paper I).pdfThiyagu K
This slides describes the basic concepts of ICT, basics of Email, Emerging Technology and Digital Initiatives in Education. This presentations aligns with the UGC Paper I syllabus.
Synthetic Fiber Construction in lab .pptxPavel ( NSTU)
Synthetic fiber production is a fascinating and complex field that blends chemistry, engineering, and environmental science. By understanding these aspects, students can gain a comprehensive view of synthetic fiber production, its impact on society and the environment, and the potential for future innovations. Synthetic fibers play a crucial role in modern society, impacting various aspects of daily life, industry, and the environment. ynthetic fibers are integral to modern life, offering a range of benefits from cost-effectiveness and versatility to innovative applications and performance characteristics. While they pose environmental challenges, ongoing research and development aim to create more sustainable and eco-friendly alternatives. Understanding the importance of synthetic fibers helps in appreciating their role in the economy, industry, and daily life, while also emphasizing the need for sustainable practices and innovation.
How to Split Bills in the Odoo 17 POS ModuleCeline George
Bills have a main role in point of sale procedure. It will help to track sales, handling payments and giving receipts to customers. Bill splitting also has an important role in POS. For example, If some friends come together for dinner and if they want to divide the bill then it is possible by POS bill splitting. This slide will show how to split bills in odoo 17 POS.
Read| The latest issue of The Challenger is here! We are thrilled to announce that our school paper has qualified for the NATIONAL SCHOOLS PRESS CONFERENCE (NSPC) 2024. Thank you for your unwavering support and trust. Dive into the stories that made us stand out!
2024.06.01 Introducing a competency framework for languag learning materials ...Sandy Millin
http://sandymillin.wordpress.com/iateflwebinar2024
Published classroom materials form the basis of syllabuses, drive teacher professional development, and have a potentially huge influence on learners, teachers and education systems. All teachers also create their own materials, whether a few sentences on a blackboard, a highly-structured fully-realised online course, or anything in between. Despite this, the knowledge and skills needed to create effective language learning materials are rarely part of teacher training, and are mostly learnt by trial and error.
Knowledge and skills frameworks, generally called competency frameworks, for ELT teachers, trainers and managers have existed for a few years now. However, until I created one for my MA dissertation, there wasn’t one drawing together what we need to know and do to be able to effectively produce language learning materials.
This webinar will introduce you to my framework, highlighting the key competencies I identified from my research. It will also show how anybody involved in language teaching (any language, not just English!), teacher training, managing schools or developing language learning materials can benefit from using the framework.
We all have good and bad thoughts from time to time and situation to situation. We are bombarded daily with spiraling thoughts(both negative and positive) creating all-consuming feel , making us difficult to manage with associated suffering. Good thoughts are like our Mob Signal (Positive thought) amidst noise(negative thought) in the atmosphere. Negative thoughts like noise outweigh positive thoughts. These thoughts often create unwanted confusion, trouble, stress and frustration in our mind as well as chaos in our physical world. Negative thoughts are also known as “distorted thinking”.
How to Create Map Views in the Odoo 17 ERPCeline George
The map views are useful for providing a geographical representation of data. They allow users to visualize and analyze the data in a more intuitive manner.
3. Let P be a given point on a curve y = f(x) and Q be another point on it
and let the point Q moves along the curve nearer and nearer to the point
P then the limiting position of the secant PQ provided limit exists, when
Q moves up to and ultimately coincide with P, is called the tangent to
the curve at the point P. The line through the point P perpendicular to
the tangent is called the normal to the curve at the point P.
The equation of the tangent at P(x,y) on the curve, y=f(x) is,
)( xX
dx
dy
yY −=−
( , ) ( )
dy
at P Y X
dx
α β β α⇒ − = −
Or,
The equation of the normal at P(x,y) on the curve, y=f(x) is
)(
1
xX
dx
dy
yY −
−
=− Or,
1
( , ) ( )at P y x
dy
dx
α β β α
−
⇒ − = −
4. Now draw PM perpendicular on x-axis. The projection TM of the
tangent PT on the x-axis, called the sub tangent.
While the projection, MN of the normal PN on the x-axis is called
sub normal.
Formula:
(i) Length of the sub tangent,
1
cot
1
tan
1
/
TM MP
y
y
dy dx
y
y
ψ
ψ
=
= ×
= ×
=
5. (ii) Length of the sub-normal,
1
tanMN PM
dy
y
dx
yy
ψ=
= ×
=
(iii) Length of the tangent,
)1(
2
1
1
y
y
y
PT +=
(iv) Length of the normal,
)1(
2
1yyPN +=
6. Find the equation of the tangent and normal to the curve of
at the point Hence calculate the length of the sub-
tangent and sub-normal.
6)( 2
−+= xxxf
.1=x
Solution:
Given,
At
We have to find the length of the tangent and also normal at the point (1, -4).
Differentiating (1) w.r. to x, we get
)(6)( 2
ixxxfy →−+==
1,x = .4612
−=−+= xy
1
2 1 0
1, 2 1 1 3x
dy
x
dx
dy
At x
dx
=
= + +
∴ = = × + =
7. The length of the tangent of (1, -4) is,
073
073
334
)1(3)4(
)(
=−−∴
=−−⇒
−=+⇒
−=−−⇒
−=−
YX
YX
XY
XY
xX
dx
dy
yY
And, the equation of normal is as follows:1
( )
1
( 4) ( 1)
3
3( 4) 1
3 11 0
3 11 0
Y y X x
dy
dx
Y X
Y X
X Y
X Y
− = − −
⇒ − − = − −
⇒ + = − +
⇒ + + =
∴ + + =
8. Length of the sub tangent is:
1y
y
=
3
4−
=
3
4
=
∴
Length of the sub normal 1y y=
34×−=
12−=
.12=
9. Formulae: (Polar System)
Length of the sub tangent :
Length of the sub normal :
Length of the Tangent :
Length of the Normal :
1
2
r
r
=
1r=
2
1
2
1
rr
r
r
+=
2
1
2
rr +=
10. Question # 03:Compute the length of the polar
sub tangent, sub normal, tangent and also
normal, of the curve at .θcos42
=r 6
π
θ =
)(cos42
ir →= θ
6
π
θ =
Solution: Given,
At,
32
32
2
3
4
6
cos4
2
2
2
=∴
=⇒
×=⇒
=
r
r
r
r
π
11. Differentiating (i) w. r. to
, we getθ 2 4( sin )
2
dr
r
d
dr
r Sin
d
θ
θ
θ
θ
= −
⇒ = −
At,
6
π
θ =
1
2 sin
6
1
2
2
1
1
1
2 3
dr
r
d
dr
r
d
dr
r
d
dr
d r
r
π
θ
θ
θ
θ
= − ×
⇒ = − ×
⇒ = −
⇒ = −
⇒ = −
12. Therefore, the length of the sub tangent is:
( )
2
1
1
2
4
2 3
1
2 3
2 3 2 3
2 6 3
r
r
=
=
= ×
=
Length of the subnormal , 1
1
2 3
r =
Length of the tangent ,
2 2
1
1
26 3
r
r r
r
+ =
Length of the normal, 2 2
1
13
2 3
r r+ =
13. Curvature:
Sδ
λ
The curvature at a given point P is the limit (if it exists) of the
average curvature (bending) of arc PQ when the length of this arc
approaches zero. The curvature at P is denoted by
The angle is called the angle of contingence of P .
.
δψ
14. The average curvature or average bending of the arc
Thus, Curvature at is:
S
PQ
δ
δψ
=
P 0sLim
S
d
ds
δ
δψ
λ
δ
ψ
→=
=
Therefore, the curvature is the rate at which the curve
curve's or how much the curve is curving.
Radius of curvature:
The reciprocal of the curvature is called the radius of
the curvature of the curve at P.
It is usually denoted by,
Thus,
λ
ρ
.
1
ψλ
ρ
d
ds
==
15. Question#01: Find the radius of curvature for y = f (x)
Solution:
We know, ψtan=
dx
dy
2
2
2
2
2
3
sec
sec
1
sec sec
1
sec
d y d
dxdx
d ds
ds dx
ψ
ψ
ψ
ψ
ψ ψ
ρ
ψ
ρ
⇒ =
=
=
=
ψ
ψ
ψ
sec
cos
1
cos
=
=
=
dx
ds
dx
ds
ds
dx
17. Question#02: Find the radius of curvature at (0, 0) of
the curve
Solution:
Given,
Differentiating w. r. to. x, we have
Again, differentiating w. r. to. x , we get
Now at (0, 0),
And,
xxxy 72 23
+−=
xxxy 72 23
+−=
2
1 3 4 7
dy
y x x
dx
= = − +
2
22
6 4
d y
y x
dx
== = −
( ) ( )2
1 3 0 4 0 7 7y = − + =
( )2 6 0 4 4y = − = −
19. Question#02: Find the curvature and radius of
curvature at (0, b) of the curve
Ans:
Question#03: Show that the curvature at of
the curve is
2 2
1.
x y
a b
+ =
2
a
b
−
3 3
,
2 2
a a
÷
3 3
3x y axy+ = 8 2
3a
−
20. Question#4: Find the radius of curvature at of
the curve
Solution: Given,
Differentiating w. r. to , we get
( ),r θ
θ2cos22
ar =
2 2
2 2
2
cos2
ln ln( cos2 )
2ln ln ln(cos2 )
r a
r a
r a
θ
θ
θ
=
⇒ =
⇒ = +
θ
)1(2tan
2tan.
1
2)2sin(
2cos
1
0
1
.2
1
1
→−=⇒
−=⇒
×−×+=
θ
θ
θ
θθ
rr
r
r
d
dr
r
θ2tan222
1 rr =∴
21. Again differentiating w. r. to , we haveθ
( )
( ) ( )
2
2
2
1
2
tan 2
tan 2 sec 2 .2.
tan 2 2 sec 2
tan 2 tan 2 2 sec 2
d
r r
d
dr
r
d
r r
r r
θ
θ
θ θ
θ
θ θ
θ θ θ
= −
= − −
= − −
= − − −
θθ 2sec22tan 22
2 rrr −=⇒
22. Therefore, radius of curvature at is,( ),r θ
( )
3
2 2 2
1
2 2
1 22
r r
r r r r
ρ
+
=
+ −
( )
( )
( ){ }
( )
3
2 2 2 2
2 2 2 2 2
3
22 2
2 2 2 2 2 2 2
3
3 2 2
2 2 2 2 2
3 3 3 3
2 2 2 2 2 2 2 2
3 3
2 2
tan 2
2 tan 2 tan 2 2 sec 2
1 tan 2
2 tan 2 tan 2 2 sec 2
sec 2
tan 2 2 sec 2
sec 2 sec 2
(1 tan 2 ) 2 sec 2 sec 2 2 sec 2
sec 2
33 sec 2
r r
r r r r r
r
r r r r
r
r r r
r r
r r r r
r r
r
θ
θ θ θ
θ
θ θ θ
θ
θ θ
θ θ
θ θ θ θ
θ
θ
+
=
+ − −
+
=
+ − +
=
+ +
= =
+ + +
= = ×
2
2
2 2 2
2 2
2 2
sec 2
3
1
cos 2 sec 2
3 cos 2
r a
r
a a a
r a
r r r
θ
ρ θ θ
θ
= ×
∴ = = ⇒ = ⇒ =
Q
1
2 2
2
tan 2
tan 2 2 sec 2
r r
r r r
θ
θ θ
= −
= −
Q
23. Question#5: Find the radius of curvature at of
the curve
Ans:
( ),r θ
cosm m
r a mθ=
1
( 1)
m
m
a
m r
ρ −
=
+
24. Centre of Curvature:
Let be the centre of curvature at P(x, y) of curve
y = f (x).
Then,
where
),( βαC
2
1 1
2
2
1
2
(1 )
,
1
y y
x
y
y
y
y
α
β
+
= −
+
= +
1
2
2 2
dy
y
dx
d y
y
dx
=
=
25. Question#06: Find the centre of curvature of
corresponding to the point (4, 4).
Solution: Given the equation of the curve is,
Differentiating w. r. to. x, we have,
At (4, 4),
16=xy
)(
16
16
i
x
y
xy
→=⇒
=
)(
16
21 ii
x
y →−=
1 2
16
1.
4
y = − = −
26. Again differentiating w.r.to. x we get,
At (4, 4),
If be the centre of curvature at P(x, y) of curve
y= f (x, y)
then,
Therefore, the centre of the curvature is (8, 8).
1 2
16
y
x
= −
Q
32
32
x
y =
2
1
4
32
32 ==y
),( βαC
8
2
1
)11)(1(
4
)1(
2
2
11
=
+−
−=
+
−=
y
yy
xα
( )
( )
1 4, 4
2 4, 4
1
1
2
y
y
= −
=
Q
8
2
1
11
4
1 2
2
2
1
=
+
+=
+
+=
y
y
yβ