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Trig Identities
Relations in the Unit Circle
Solving Trigonometric Equations
Proving Trigonometric Statements
Basic Idenitities
Ratios
sin A = a/h
cos A = b/h
tan A = a/b
Inverse Ratios
csc A = 1/sinA = h/a
sec A = 1/cosA =h/b
cot A = 1/tanA =b/a
The Three Identities
1) sin2Θ + cos2Θ = 1
N.B. sin2Θ = (sinΘ)2 . That could be
confused with sinΘ2 .
2) 1 + tan2Θ = sec2Θ
N.B. sec2Θ = 1/sin2Θ
3) 1+ cot2Θ = csc2Θ
N.B. cot2Θ = 1/tan2Θ; csc2Θ = 1/sin2Θ
Proving Your Identity
 To prove an identity, identify the most complex
side and simplify it to express it in the same terms
as the other side. To do so, try the following:
 Substitute on or more basic identities to simplify
the expression.
 Perform operations or factor to find a basic
identity or a factor common to the numerator and
denominator.
 Multiply the numerator and the denominator by
the same trigonometric expression.
 Express the various functions using sine and
cosine functions.
Example of Proof: 1/sec2Θ + 1/csc2Θ = 1
 It helps to divide the equation into a
Left Hand Side (LHS) & a Right Hand Side RHS).
1/sec2Θ + 1/csc2Θ
cos2Θ + sin2Θ
1 (Trig Identity)
So 1
Proven/QED
Quad Erat Demonstratum
It has been shown.
1
= 1
Example of Proof: tan2x - sin2x = sin2xtan2x
tan2x - sin2x
sin2x/cos2x - sin2x
Factor sin2x out
Sin2x (1/cos2x -1)
Sin2x (sec2x -1)
Check identities
Sec2x = 1 + tan2x
So, sec2x – 1 = tan2x
Sin2x(tan2x)
sin2x tan2x
= sin2x tan2x
QED
Example of Proof: Last one
2cos2t-cost-1
cos t -1
Numerator: Quadratic expression
(2cos t + 1)(cos t -1)
(cos t -1)
Cancel out common factors
2 cos t + 1
Remember: sec t = 1/cos t
So cos t = 1/sec t
2 ( 1 ) + 1
(sec t)
Common Denominator
2 ( 1 ) + sec t = 2 + sec t 
(sec t) sec t sec t
sec t + 2
sec t
= sec t + 2 QED
sec t
Exam Question
Prove that,
   
  x
x
x
x
xx 2
2
2
2
22
tan
cos
cos1
1sec
1tansin





Show your work.
Exam Question
For all values of A (for which A is defined), the expression tan A + cot A is equal to
A) sin A cos A. C) sec A cosec A.
B) sec A cos A. D) sin A cosec A.
Activity
Page 284
Question 1, 11

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Trig identities

  • 1. Trig Identities Relations in the Unit Circle Solving Trigonometric Equations Proving Trigonometric Statements
  • 2. Basic Idenitities Ratios sin A = a/h cos A = b/h tan A = a/b Inverse Ratios csc A = 1/sinA = h/a sec A = 1/cosA =h/b cot A = 1/tanA =b/a
  • 3. The Three Identities 1) sin2Θ + cos2Θ = 1 N.B. sin2Θ = (sinΘ)2 . That could be confused with sinΘ2 . 2) 1 + tan2Θ = sec2Θ N.B. sec2Θ = 1/sin2Θ 3) 1+ cot2Θ = csc2Θ N.B. cot2Θ = 1/tan2Θ; csc2Θ = 1/sin2Θ
  • 4. Proving Your Identity  To prove an identity, identify the most complex side and simplify it to express it in the same terms as the other side. To do so, try the following:  Substitute on or more basic identities to simplify the expression.  Perform operations or factor to find a basic identity or a factor common to the numerator and denominator.  Multiply the numerator and the denominator by the same trigonometric expression.  Express the various functions using sine and cosine functions.
  • 5. Example of Proof: 1/sec2Θ + 1/csc2Θ = 1  It helps to divide the equation into a Left Hand Side (LHS) & a Right Hand Side RHS). 1/sec2Θ + 1/csc2Θ cos2Θ + sin2Θ 1 (Trig Identity) So 1 Proven/QED Quad Erat Demonstratum It has been shown. 1 = 1
  • 6. Example of Proof: tan2x - sin2x = sin2xtan2x tan2x - sin2x sin2x/cos2x - sin2x Factor sin2x out Sin2x (1/cos2x -1) Sin2x (sec2x -1) Check identities Sec2x = 1 + tan2x So, sec2x – 1 = tan2x Sin2x(tan2x) sin2x tan2x = sin2x tan2x QED
  • 7. Example of Proof: Last one 2cos2t-cost-1 cos t -1 Numerator: Quadratic expression (2cos t + 1)(cos t -1) (cos t -1) Cancel out common factors 2 cos t + 1 Remember: sec t = 1/cos t So cos t = 1/sec t 2 ( 1 ) + 1 (sec t) Common Denominator 2 ( 1 ) + sec t = 2 + sec t  (sec t) sec t sec t sec t + 2 sec t = sec t + 2 QED sec t
  • 8. Exam Question Prove that,       x x x x xx 2 2 2 2 22 tan cos cos1 1sec 1tansin      Show your work.
  • 9. Exam Question For all values of A (for which A is defined), the expression tan A + cot A is equal to A) sin A cos A. C) sec A cosec A. B) sec A cos A. D) sin A cosec A.