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STOICHIOMETRY AND MOLE CONCEPT 
1. Use of molar mass to predict reacting masses 
A balanced chemical equation is a way of describing the relative quantities of reactants 
and products that are involved in a reaction. The coefficients may be read to indicate 
the relative numbers of atoms, ions, or molecules involved in the reaction. 
The following equation, for magnesium metal burning in oxygen, can be read "two 
atoms of magnesium combine with one molecule of oxygen to form two 'molecules' 
(actually ions Mg 2+ and O2-) of magnesium oxide." 
2Mg(s) + O2(g) → 2MgO(s) 
A better way to read it is "two moles of magnesium metal combine with one 
mole of oxygen gas to form two moles of magnesium oxide". 
From this, the relative masses of the reactants and products can be predicted: 
2Mg(s) + O2(g) → 2MgO(s) 
2×24.3g 32g 2×40g 
If the relative masses of reactants and products in a reaction can be predicted from a 
balanced equation and knowledge of molar masses, then the actual mass of any 
reactant or product can be calculated by the use of ratios. 
Method 1 
Example one: 
What mass of sodium carbonate will be obtained if 3.36 g of pure sodium hydrogen 
carbonate is heated? (The other products of the reaction are carbon dioxide and water.) 
Stoichiometry and mole concept Page1
Method 2 
Example two: 
What mass of carbon will be converted to carbon monoxide in reducing 1000 g of 
iron(III) oxide to iron metal? What masses of iron and carbon monoxide should be 
formed? 
Note that with three "unknowns" in this problem, three algbraic symbols, x, y, z, are 
used. The values of x, y, and z are calculated by simple ratio: 
Mass of carbon converted = x = 226 g 
Mass of iron formed = y = 700 g 
Mass of carbon monoxide formed = z = 526 g 
The total mass of reactants should equal the total mass of products: 
1000 g + 226 g = 700 g + 526 g 
Stoichiometry and mole concept Page2
Example three: 
What mass of lead can be extracted by heating 120 g of solid lead sulfide in air, forming 
lead oxide and sulfur dioxide, and then heating the lead oxide with carbon, to form 
metallic lead and carbon monoxide? 
This problem can be solved as above, by writing the equations and carrying out all ratio 
calculations. An alternative method uses percentage composition: the problem can be 
summed up as "how much lead can be separated from 120 g of lead sulfide?" 
86.6% of 120 g = 104 g = mass of lead that can be extracted from 120 g of lead sulfide. 
2. Reacting volumes 
For 1 mole of any gas at room temperature is 24dm3 
1dm3 = 1000cm3 
Example 
Calculate the volume of oxygen at r.t.p necessary to burn 1.4 g of butane. 
Stoichiometry and mole concept Page3
3 Mole and concentration of solution 
Most of the practical work and information in questions gives volumes in cm3. You will 
have to change from cm3 into dm3 (1dm3 = 1000cm3) 
Example 
Calculate the volume of sodium hydroxide, concentration 0.16mol/dm3, needed to 
neutralize 20 cm3 of sulphuric acid, concentration 0.2 mol/dm3. 
Stoichiometry and mole concept Page4
4 Moles % yield and % purity 
Percentage yield 
Excess of magnesium carbonate was added 25cm3 of sulphuric acid, concentration 2.0 
mol/dm3. The untreated magnesium carbonate was removed by filtration. The solution 
of magnesium sulphate was evaporated to give 6.7 g of hydrated magnesium sulphate 
crystals. Calculate the percentage yield. 
Stoichiometry and mole concept Page5
Percentage purity 
Example 
7.0 g of impure calcium carbonate was heated and 2.42g of carbon dioxide is was 
collected. Calculate the percentage purity of the calcium carbonate. 
Stoichiometry and mole concept Page6
Exercises: 
1. What mass of copper can be extracted from 5.0 g of copper(II) sulfate by dissolving 
the copper sulfate in water and adding zinc metal? (The other product is zinc sulfate). 
Zn + CuSO4 + H2O → ZnSO4 + Cu 
2. What mass of potassium iodide is needed to react exactly with 8.0 g of lead nitrate, to 
form lead iodide? (The other product is potassium nitrate). 
Pb(NO3)2 + 2KI → PbI2 + 2KNO3 
3. When calcium carbonate is heated strongly, it forms calcium oxide and carbon 
dioxide.What mass of calcium carbonate is needed to make 50.0 g of calcium oxide? 
CaCO3 → CaO +CO2 
Stoichiometry and mole concept Page7
4. Sodium carbonate reacts with hydrochloric acid to form sodium chloride, water, and 
carbon dioxide. Some hydrochloric acid was added to some sodium carbonate: 6.0 g of 
sodium chloride were formed. What mass of carbon dioxide was produced? 
Na2CO3 + 2HCl → 2NaCl + H2O + CO2 
5. What mass of lead oxide would need to be reacted with nitric acid to produce 10.0g 
of lead nitrate? 
PbO + 2HNO3→ 2Pb (NO3)2 + H2O 
6.Ammonium nitrate (NH4NO3), an important fertilizer, produces N2O gas and H2O when 
it decomposes. Determine the mass of water produced from the decomposition of 25.0 
g of solid Ammonium nitrate. 
NH4NO3 →N2O + 2H2O (ans: 11.2 g H2O) 
Stoichiometry and mole concept Page8
7. Calculate the mass of magnesium oxide formed when 3.0 g of magnesium reacts 
with excess oxygen. 
2Mg + O2→ 2MgO 
8. What volume of carbon dioxide is produced by the reaction when 1.4 g of butane is 
completely burnt in oxygen? 
C4H8 + 6O2→ 4CO2 + 4H2O 
9. What is the volume of oxygen needed to react with 20cm3 of ethane? 
2C2H6 + 7O2→ 4CO2 + 3SO3 
Stoichiometry and mole concept Page9
10. Calculate the volume of sulphur trioxide formed when 20.0 g of iron (III) sulphate is 
heated. 
Fe2(SO4)3→ Fe2O3 + 3SO3 
11. When aluminum was reacted with an excess of hydrochloric acid, 0.72dm3 of 
hydrogen at r.t.p was formed. Calculate the mass of aluminum used. 
2Al + 6HCl → 2AlCl3 + 3H2 
12.25 cm3 of sodium carbonate 0.10 mol/dm3 was neutralized by, was neutralized by 
31.0 cm3 of hydrochloric acid. Calculate the concentration of the acid in mol/dm3. 
Na2CO3 + 2HCl →2NaCl + CO2 + H2O 
Stoichiometry and mole concept Page10
13. 12.0 g of Ethanoic acid reacted with an excess of ethanol to form 7.2 g of ethyl 
ethanoate. Calculate the percentage yield. 
CH3COOH + C2H5OH→CH3COOC2H5+ H2O 
14. An excess of nickel oxide reacted with 50.0 cm3 hydrochloric acid, concentration 1.6 
mol/dm3, to form 6.1 g of hydrated nickel chloride crystals. Calculate the percentage 
yield. 
NiO + 2HCl → NiCl2 + H2O 
NiCl2 + 6H2O → NiCl2.6H2O 
15. 9.30 g of impure NaHCO3 was heated 2.24 g of carbon dioxide was formed. 
Calculate the percentage purity of the sodium hydrogen carbonate. 
2NaHCO3→ Na2CO3 + H2O 
Stoichiometry and mole concept Page11
16.Solid lithium hydroxide is used in space vehicles to remove exhaled carbon dioxide 
from the living environment by forming solid lithium carbonate and liquid water. What 
mass of gaseous carbon dioxide can be absorbed by 1.00 kg of lithium hydroxide? 
2LiOH + CO2 → Li2CO3 + H2O 
17. A solution of lead (II) nitrate is mixed with a solution of potassium bromide. 
a)Write balanced molecular, complete ionic, and net ionic equations for this reaction. 
……………………………………………………………………………………………………… 
……………………………………………………………………………………………………… 
……………………………………………………………………………………………………… 
……………………………………………………………………………………………………… 
……………………………………………………………………………………………………… 
b) How many moles of lead (II) bromide could be produced from 6 moles of potassium 
bromide? 
c) How many moles of lead (II) bromide could be produced from 0.846 moles of 
potassium bromide? 
Stoichiometry and mole concept Page12

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Stoichiometry

  • 1. STOICHIOMETRY AND MOLE CONCEPT 1. Use of molar mass to predict reacting masses A balanced chemical equation is a way of describing the relative quantities of reactants and products that are involved in a reaction. The coefficients may be read to indicate the relative numbers of atoms, ions, or molecules involved in the reaction. The following equation, for magnesium metal burning in oxygen, can be read "two atoms of magnesium combine with one molecule of oxygen to form two 'molecules' (actually ions Mg 2+ and O2-) of magnesium oxide." 2Mg(s) + O2(g) → 2MgO(s) A better way to read it is "two moles of magnesium metal combine with one mole of oxygen gas to form two moles of magnesium oxide". From this, the relative masses of the reactants and products can be predicted: 2Mg(s) + O2(g) → 2MgO(s) 2×24.3g 32g 2×40g If the relative masses of reactants and products in a reaction can be predicted from a balanced equation and knowledge of molar masses, then the actual mass of any reactant or product can be calculated by the use of ratios. Method 1 Example one: What mass of sodium carbonate will be obtained if 3.36 g of pure sodium hydrogen carbonate is heated? (The other products of the reaction are carbon dioxide and water.) Stoichiometry and mole concept Page1
  • 2. Method 2 Example two: What mass of carbon will be converted to carbon monoxide in reducing 1000 g of iron(III) oxide to iron metal? What masses of iron and carbon monoxide should be formed? Note that with three "unknowns" in this problem, three algbraic symbols, x, y, z, are used. The values of x, y, and z are calculated by simple ratio: Mass of carbon converted = x = 226 g Mass of iron formed = y = 700 g Mass of carbon monoxide formed = z = 526 g The total mass of reactants should equal the total mass of products: 1000 g + 226 g = 700 g + 526 g Stoichiometry and mole concept Page2
  • 3. Example three: What mass of lead can be extracted by heating 120 g of solid lead sulfide in air, forming lead oxide and sulfur dioxide, and then heating the lead oxide with carbon, to form metallic lead and carbon monoxide? This problem can be solved as above, by writing the equations and carrying out all ratio calculations. An alternative method uses percentage composition: the problem can be summed up as "how much lead can be separated from 120 g of lead sulfide?" 86.6% of 120 g = 104 g = mass of lead that can be extracted from 120 g of lead sulfide. 2. Reacting volumes For 1 mole of any gas at room temperature is 24dm3 1dm3 = 1000cm3 Example Calculate the volume of oxygen at r.t.p necessary to burn 1.4 g of butane. Stoichiometry and mole concept Page3
  • 4. 3 Mole and concentration of solution Most of the practical work and information in questions gives volumes in cm3. You will have to change from cm3 into dm3 (1dm3 = 1000cm3) Example Calculate the volume of sodium hydroxide, concentration 0.16mol/dm3, needed to neutralize 20 cm3 of sulphuric acid, concentration 0.2 mol/dm3. Stoichiometry and mole concept Page4
  • 5. 4 Moles % yield and % purity Percentage yield Excess of magnesium carbonate was added 25cm3 of sulphuric acid, concentration 2.0 mol/dm3. The untreated magnesium carbonate was removed by filtration. The solution of magnesium sulphate was evaporated to give 6.7 g of hydrated magnesium sulphate crystals. Calculate the percentage yield. Stoichiometry and mole concept Page5
  • 6. Percentage purity Example 7.0 g of impure calcium carbonate was heated and 2.42g of carbon dioxide is was collected. Calculate the percentage purity of the calcium carbonate. Stoichiometry and mole concept Page6
  • 7. Exercises: 1. What mass of copper can be extracted from 5.0 g of copper(II) sulfate by dissolving the copper sulfate in water and adding zinc metal? (The other product is zinc sulfate). Zn + CuSO4 + H2O → ZnSO4 + Cu 2. What mass of potassium iodide is needed to react exactly with 8.0 g of lead nitrate, to form lead iodide? (The other product is potassium nitrate). Pb(NO3)2 + 2KI → PbI2 + 2KNO3 3. When calcium carbonate is heated strongly, it forms calcium oxide and carbon dioxide.What mass of calcium carbonate is needed to make 50.0 g of calcium oxide? CaCO3 → CaO +CO2 Stoichiometry and mole concept Page7
  • 8. 4. Sodium carbonate reacts with hydrochloric acid to form sodium chloride, water, and carbon dioxide. Some hydrochloric acid was added to some sodium carbonate: 6.0 g of sodium chloride were formed. What mass of carbon dioxide was produced? Na2CO3 + 2HCl → 2NaCl + H2O + CO2 5. What mass of lead oxide would need to be reacted with nitric acid to produce 10.0g of lead nitrate? PbO + 2HNO3→ 2Pb (NO3)2 + H2O 6.Ammonium nitrate (NH4NO3), an important fertilizer, produces N2O gas and H2O when it decomposes. Determine the mass of water produced from the decomposition of 25.0 g of solid Ammonium nitrate. NH4NO3 →N2O + 2H2O (ans: 11.2 g H2O) Stoichiometry and mole concept Page8
  • 9. 7. Calculate the mass of magnesium oxide formed when 3.0 g of magnesium reacts with excess oxygen. 2Mg + O2→ 2MgO 8. What volume of carbon dioxide is produced by the reaction when 1.4 g of butane is completely burnt in oxygen? C4H8 + 6O2→ 4CO2 + 4H2O 9. What is the volume of oxygen needed to react with 20cm3 of ethane? 2C2H6 + 7O2→ 4CO2 + 3SO3 Stoichiometry and mole concept Page9
  • 10. 10. Calculate the volume of sulphur trioxide formed when 20.0 g of iron (III) sulphate is heated. Fe2(SO4)3→ Fe2O3 + 3SO3 11. When aluminum was reacted with an excess of hydrochloric acid, 0.72dm3 of hydrogen at r.t.p was formed. Calculate the mass of aluminum used. 2Al + 6HCl → 2AlCl3 + 3H2 12.25 cm3 of sodium carbonate 0.10 mol/dm3 was neutralized by, was neutralized by 31.0 cm3 of hydrochloric acid. Calculate the concentration of the acid in mol/dm3. Na2CO3 + 2HCl →2NaCl + CO2 + H2O Stoichiometry and mole concept Page10
  • 11. 13. 12.0 g of Ethanoic acid reacted with an excess of ethanol to form 7.2 g of ethyl ethanoate. Calculate the percentage yield. CH3COOH + C2H5OH→CH3COOC2H5+ H2O 14. An excess of nickel oxide reacted with 50.0 cm3 hydrochloric acid, concentration 1.6 mol/dm3, to form 6.1 g of hydrated nickel chloride crystals. Calculate the percentage yield. NiO + 2HCl → NiCl2 + H2O NiCl2 + 6H2O → NiCl2.6H2O 15. 9.30 g of impure NaHCO3 was heated 2.24 g of carbon dioxide was formed. Calculate the percentage purity of the sodium hydrogen carbonate. 2NaHCO3→ Na2CO3 + H2O Stoichiometry and mole concept Page11
  • 12. 16.Solid lithium hydroxide is used in space vehicles to remove exhaled carbon dioxide from the living environment by forming solid lithium carbonate and liquid water. What mass of gaseous carbon dioxide can be absorbed by 1.00 kg of lithium hydroxide? 2LiOH + CO2 → Li2CO3 + H2O 17. A solution of lead (II) nitrate is mixed with a solution of potassium bromide. a)Write balanced molecular, complete ionic, and net ionic equations for this reaction. ……………………………………………………………………………………………………… ……………………………………………………………………………………………………… ……………………………………………………………………………………………………… ……………………………………………………………………………………………………… ……………………………………………………………………………………………………… b) How many moles of lead (II) bromide could be produced from 6 moles of potassium bromide? c) How many moles of lead (II) bromide could be produced from 0.846 moles of potassium bromide? Stoichiometry and mole concept Page12