This document discusses finding the extrema (maximum and minimum values) of functions on intervals using calculus. It defines extrema and relative extrema of functions, and explains how derivatives can be used to find them. Critical numbers are points where the derivative is zero or undefined, and may indicate relative extrema. The document provides examples of finding the critical numbers of functions and using them along with endpoint values to determine the absolute maximum and minimum values over a closed interval. While critical numbers sometimes identify relative extrema, the converse is not always true - not all critical numbers yield an extremum.
Differential Calculus, limits, slope of tangent line to the curve, the derivative. This slide accompanies my lecture in Differential calculus in LPU Batangas
In this chapter we shall study those points of the domain of a function where its graph changes its direction from upwards to downwards or from downwards to upwards. At such points the derivative of the function, if it exists, is necessarily zero.
The value of a function f (x) is said to be maximum at x = a, if there exists a very small positive number h, such that
f(x) < f(a) x (a – h,a + h) , x a
In this case the point x = a is called a point of maxima for the function f(x).
Simlarly, the value of f(x) is said to the minimum at x = b, If there exists a very small positive number, h, such that
f(x) > f(b), x (b – h,b + h), x b
In this case x = b is called the point of minima for the function f(x).
Hene we find that,
(i) x = a is a maximum point of f(x)
f(a) f(a h) 0
f(a) f(a h) 0
(ii) x = b is a minimum point of f(x)
Rf(b) f(b h) 0
f(b) f(b h) 0
(iii) x = c is neither a maximum point nor a minimum point
Note :
(i) The maximum and minimum points are also known as extreme points.
(ii) A function may have more than one maximum and minimum points.
(iii) A maximum value of a function f(x) in an interval [a,b] is not necessarily its greatest value in that interval. Similarly, a minimum value may not be the least value of the function. A minimum value may be greater than some maximum value for a function.
(iv) If a continuous function has only one maximum (minimum) point, then at this point function has its greatest (least) value.
(v) Monotonic functions do not have extreme points.
Ex. Function y = sin x, x (0, ) has a maximum point at x = /2 because the value of sin /2 is greatest in the given interval for sin x.
Clearly function y = sin x is increasing in the interval (0, /2) and decreasing in the interval ( /2, ) for that reason also it has maxima at x = /2. Similarly we can see from the graph of cos x which has a minimum point at x = .
Ex. f(x) = x2 , x (–1,1) has a minimum point at x = 0 because at x = 0, the value of x2 is 0, which is
less than the all the values of function at different points of the interval.
Clearly function y = x2 is decreasing in the interval
Rf(c) f(c h)
Sand
Tf(c) f(c h) 0
|V| have opposite signs.
(–1, 0) and increasing in the interval (0,1) So it has minima at x = 0.
Ex. f(x) = |x| has a minimum point at x = 0. It can be easily observed from its graph.
A. Necessary Condition : A point x = a is an extreme point of a function f(x) if f’(a) = 0, provided f’(a) exists. Thus if f’ (a) exists, then
x = a is an extreme point f’(a) = 0
or
f’ (a) 0 x = a is not an extreme point.
But its converse is not true i.e.
f’ (a) = 0 x = a is an extreme point.
For example if f(x) = x3 , then f’ (0) = 0 but x = 0 is not an extreme point.
B. Sufficient Condition :
(i) The value of the function f(x) at x = a is maximum, if f’ (a) = 0 and f” (a) < 0.
(ii) The value of
MAT-121 COLLEGE ALGEBRAWritten Assignment 32 points eac.docxjessiehampson
MAT-121: COLLEGE ALGEBRA
Written Assignment 3
2 points each except for 5, 6, 9, 15, 16, which are 4 points each as indicated.
SECTION 3.1
Algebraic
For the following exercise, determine whether the relationship represents y as a function of x. If the relationship represents a function then write the relationship as a function of
x
using
f
as the function.
x+y2=5
Consider the relationship 7n-5m=4.
Write the relationship as a function
n
=
k
(
m
).
Evaluate
k
(
5
).
Solve for
k
(
m
) = 7.
Graphical
Given the following graph
Evaluate
f
(4)
Solve for
f
(x) = 4
Numeric
For the following exercise, determine whether the relationship represents a function.
{(0, 5), (-5, 8), (0, -8)}
For the following exercise, use the function
f
represented in table below. (4 points)
x
-18
-12
-6
0
6
12
18
f(x)
24
17
10
3
-4
-11
-18
Answer the following:
Evaluate
f
(-6).
Solve
f
(
x
) = -11
Evaluate
f
(12)
Solve
f
(
x
) = -18
For the following exercise, evaluate the expressions, given functions
f
,
g
, and
h
:
f(x)=4x+2
; g(x)=7-6x; h(x)=7x2-3x+6
f(-1)g(1)h(0) (4 points)
Real-world applications
The number of cubic yards of compost,
C
, needed to cover a garden with an area of
A
square feet is given by
C
=
h
(
A
).
A garden with an area of 5,000 ft2 requires 25 yd3 of compost. Express this information in terms of the function
h
.
Explain the meaning of the statement
h
(2500) = 12.5.
SECTION 3.2
Algebraic
For the following exercise, find the domain and range of each function and state it using interval notation.
f(x)=9-2x5x+13
Numeric
For the following exercise, given each function
f
, evaluate
f
(3),
f
(-2),
f
(1), and f (0). (4 points)
Real-World Applications
The height,
h,
of a projectile is a function of the time,
t,
it is in the air. The height in meters for
t
seconds is given by the function h(t)= -9.8t2+19.6t. What is the domain of the function? What does the domain mean in the context of the problem?
SECTION 3.3
Algebraic
For the following exercise, find the average rate of change of each function on the interval specified in simplest form.
k(x)=23x+1
on [2, 2+h]
Graphical
For the following exercise, use the graph of each function to
estimate
the intervals on which the function is increasing or decreasing.
For the following exercise, find the average rate of change of each function on the interval specified.
g(x)=3x2-23x3 on [1, 3]
Real-World Applications
Near the surface of the moon, the distance that an object falls is a function of time. It is given by d(t)=1.6t2, where
t
is in seconds and d(t) is in meters. If an object is dropped from a certain height, find the average velocity of the object from t = 2 to t = 5.
SECTION 3.4
Algebraic
For the following exercise, determine the domain for each function in interval notation. (4 points)
f(x)=2x+5 and g(x)=4x+9, find f-g, f+g, fg, and fg
For.
Discuss and apply comprehensively the concepts, properties and theorems of functions, limits, continuity and the derivatives in determining the derivatives of algebraic functions
How to Make a Field invisible in Odoo 17Celine George
It is possible to hide or invisible some fields in odoo. Commonly using “invisible” attribute in the field definition to invisible the fields. This slide will show how to make a field invisible in odoo 17.
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Bills have a main role in point of sale procedure. It will help to track sales, handling payments and giving receipts to customers. Bill splitting also has an important role in POS. For example, If some friends come together for dinner and if they want to divide the bill then it is possible by POS bill splitting. This slide will show how to split bills in odoo 17 POS.
The French Revolution, which began in 1789, was a period of radical social and political upheaval in France. It marked the decline of absolute monarchies, the rise of secular and democratic republics, and the eventual rise of Napoleon Bonaparte. This revolutionary period is crucial in understanding the transition from feudalism to modernity in Europe.
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We all have good and bad thoughts from time to time and situation to situation. We are bombarded daily with spiraling thoughts(both negative and positive) creating all-consuming feel , making us difficult to manage with associated suffering. Good thoughts are like our Mob Signal (Positive thought) amidst noise(negative thought) in the atmosphere. Negative thoughts like noise outweigh positive thoughts. These thoughts often create unwanted confusion, trouble, stress and frustration in our mind as well as chaos in our physical world. Negative thoughts are also known as “distorted thinking”.
Model Attribute Check Company Auto PropertyCeline George
In Odoo, the multi-company feature allows you to manage multiple companies within a single Odoo database instance. Each company can have its own configurations while still sharing common resources such as products, customers, and suppliers.
Instructions for Submissions thorugh G- Classroom.pptxJheel Barad
This presentation provides a briefing on how to upload submissions and documents in Google Classroom. It was prepared as part of an orientation for new Sainik School in-service teacher trainees. As a training officer, my goal is to ensure that you are comfortable and proficient with this essential tool for managing assignments and fostering student engagement.
Operation “Blue Star” is the only event in the history of Independent India where the state went into war with its own people. Even after about 40 years it is not clear if it was culmination of states anger over people of the region, a political game of power or start of dictatorial chapter in the democratic setup.
The people of Punjab felt alienated from main stream due to denial of their just demands during a long democratic struggle since independence. As it happen all over the word, it led to militant struggle with great loss of lives of military, police and civilian personnel. Killing of Indira Gandhi and massacre of innocent Sikhs in Delhi and other India cities was also associated with this movement.
Welcome to TechSoup New Member Orientation and Q&A (May 2024).pdfTechSoup
In this webinar you will learn how your organization can access TechSoup's wide variety of product discount and donation programs. From hardware to software, we'll give you a tour of the tools available to help your nonprofit with productivity, collaboration, financial management, donor tracking, security, and more.
Ethnobotany and Ethnopharmacology:
Ethnobotany in herbal drug evaluation,
Impact of Ethnobotany in traditional medicine,
New development in herbals,
Bio-prospecting tools for drug discovery,
Role of Ethnopharmacology in drug evaluation,
Reverse Pharmacology.
3. 3
Objectives
Understand the definition of extrema of a function on an
interval.
Understand the definition of relative extrema of a
function on an open interval.
Find extrema on a closed interval.
5. 5
Extrema of a Function
In calculus, much effort is devoted to determining the
behavior of a function f on an interval I.
Does f have a maximum value on I? Does it have a
minimum value? Where is the function increasing? Where
is it decreasing?
In this chapter, you will learn how derivatives can be used
to answer these questions. You will also see why these
questions are important in real-life applications.
7. 7
Extrema of a Function
A function need not have a minimum or a maximum on an
interval. For instance, in Figure 3.1(a) and (b), you can see
that the function f(x) = x2 + 1 has both a minimum and a
maximum on the closed interval [–1, 2], but does not have
a maximum on the open interval (–1, 2).
Figure 3.1(a) Figure 3.1(b)
8. 8
Moreover, in Figure 3.1(c),
you can see that continuity
(or the lack of it) can affect the
existence of an extremum on
the interval.
This suggests the theorem below.
Figure 3.1(c)
Extrema of a Function
10. 10
Relative Extrema and Critical Numbers
In Figure 3.2, the graph of f(x) = x3 – 3x2 has a relative
maximum at the point (0, 0) and a relative minimum at
the point (2, –4).
Informally, for a continuous function,
you can think of a relative maximum
as occurring on a “hill” on the graph,
and a relative minimum as occurring
in a “valley” on the graph.
Figure 3.2
11. 11
Relative Extrema and Critical Numbers
Such a hill and valley can occur in two ways.
When the hill (or valley) is smooth and rounded, the graph
has a horizontal tangent line at the high point (or low point).
When the hill (or valley) is sharp and peaked, the graph
represents a function that is not differentiable at the high
point (or low point).
13. 13
Example 1 – The Value of the Derivative at Relative Extrema
Find the value of the derivative at each relative extremum
shown in Figure 3.3.
Figure 3.3
14. 14
Example 1(a) – Solution
The derivative of is
At the point (3, 2), the value of the derivative is f'(3) = 0
[see Figure 3.3(a)].
Figure 3.3(a)
15. 15
Example 1(b) – Solution
At x = 0, the derivative of f(x) = |x| does not exist because
the following one-sided limits differ [see Figure 3.3(b)].
cont’d
Figure 3.3(b)
16. 16
Example 1(c) – Solution
The derivative of f(x) = sin x is f'(x) = cos x.
At the point (π/2, 1), the value of the
derivative is f'(π/2) = cos(π/2) = 0.
At the point (3π/2, –1), the value of the
derivative is f'(3π/2) = cos(3π/2) = 0
[see Figure 3.3(c)].
cont’d
Figure 3.3(c)
17. 17
Relative Extrema and Critical Numbers
Note in Example 1 that at each relative extremum, the
derivative either is zero or does not exist. The x-values at
these special points are called critical numbers.
Figure 3.4 illustrates the two types of critical numbers.
Figure 3.4
18. 18
Relative Extrema and Critical Numbers
Notice in the definition above that the critical number c has
to be in the domain of f, but c does not have to been in the
domain of f'.
20. 20
Finding Extrema on a Closed Interval
Theorem 3.2 states that the relative extrema of a function
can occur only at the critical number of the function.
Knowing this, you can use the following guidelines to find
extrema on a closed interval.
21. 21
Example 2 – Finding Extrema on a Closed Interval
Find the extrema of f(x) = 3x4 – 4x3 on the interval [–1, 2].
Solution:
Begin by differentiating the function.
f(x) = 3x4 – 4x3 Write original function.
f'(x) = 12x3 – 12x2 Differentiate.
22. 22
Example 2 – Solution
To find the critical numbers on the interval (– 1,2), you must
find all x-values for which f'(x) = 0 and all x-values for which
f'(x) does not exist.
f'(x) = 12x3 – 12x2 = 0 Set f'(x) equal to 0.
12x2(x – 1) = 0 Factor.
x = 0, 1 Critical
numbers
Because f' is defined for all x, you can conclude that these
are the only critical numbers of f.
cont’d
23. Example 2 – Solution cont’d
23
By evaluating f at these two critical numbers and at the
endpoints of [–1, 2], you can determine that the maximum
is f(2) = 16 and the minimum is f(1) = –1, as shown in the
table.
24. Example 2 – Solution cont’d
24
The graph of f is shown in Figure 3.5.
Figure 3.5
25. cont’d
25
Example 2 – Solution
In Figure 3.5, note that the critical number x = 0 does not
yield a relative minimum or a relative maximum.
This tells you that the converse of Theorem 3.2 is not true.
In other words, the critical numbers of a function need not
produce relative extrema.