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Integration 
Copyright © Cengage Learning. All rights reserved.
Antiderivatives and 
Indefinite Integration 
Copyright © Cengage Learning. All rights reserved.
3 
Objectives 
 Write the general solution of a differential equation and 
use indefinite integral notation for antiderivatives. 
 Use basic integration rules to find antiderivatives. 
 Find a particular solution of a differential equation.
4 
Antiderivatives
5 
Antiderivatives 
To find a function F whose derivative is f(x) = 3x2, you 
might use your knowledge of derivatives to conclude that 
The function F is an antiderivative of f .
6 
Antiderivatives 
Note that F is called an antiderivative of f, rather than the 
antiderivative of f. To see why, observe that 
are all derivatives of f (x) = 3x2. In fact, for any constant C, 
the function F(x)= x3 + C is an antiderivative of f.
Antiderivatives 
Using Theorem 4.1, you can represent the entire family of 
antiderivatives of a function by adding a constant to a known 
antiderivative. 
For example, knowing that Dx [x2] = 2x, you can represent the 
family of all antiderivatives of f(x) = 2x by 
7 
G(x) = x2 + C Family of all antiderivatives of f(x) = 2x 
where C is a constant. The constant C is called the constant 
of integration.
8 
Antiderivatives 
The family of functions represented by G is the general 
antiderivative of f, and G(x) = x2 + C is the general 
solution of the differential equation 
G'(x) = 2x. Differential equation 
A differential equation in x and y is an equation that 
involves x, y, and derivatives of y. 
For instance, y' = 3x and y' = x2 + 1 are examples of 
differential equations.
9 
Example 1 – Solving a Differential Equation 
Find the general solution of the differential equation y' = 2. 
Solution: 
To begin, you need to find a function whose derivative is 2. 
One such function is 
y = 2x. 2x is an antiderivative of 2. 
Now, you can use Theorem 4.1 to conclude that the 
general solution of the differential equation is 
y = 2x + C. General solution
10 
Example 1 – Solution 
The graphs of several functions of the form y = 2x + C 
are shown in Figure 4.1. 
Figure 4.1 
cont’d
11 
Notation for Antiderivatives
12 
Notation for Antiderivatives 
When solving a differential equation of the form 
it is convenient to write it in the equivalent differential form 
The operation of finding all solutions of this equation is 
called antidifferentiation (or indefinite integration) and is 
denoted by an integral sign ∫.
13 
Notation for Antiderivatives 
The general solution is denoted by 
The expression ∫f(x)dx is read as the antiderivative of f with 
respect to x. So, the differential dx serves to identify x as 
the variable of integration. The term indefinite integral is a 
synonym for antiderivative.
14 
Basic Integration Rules
15 
Basic Integration Rules 
The inverse nature of integration and differentiation can be 
verified by substituting F'(x) for f(x) in the indefinite 
integration definition to obtain 
Moreover, if ∫f(x)dx = F(x) + C, then
16 
Basic Integration Rules 
These two equations allow you to obtain integration 
formulas directly from differentiation formulas, as shown in 
the following summary.
17 
Basic Integration Rules 
cont’d
18 
Example 2 – Applying the Basic Integration Rules 
Describe the antiderivatives of 3x. 
Solution: 
So, the antiderivatives of 3x are of the form where 
C is any constant.
19 
Basic Integration Rules 
In Example 2, note that the general pattern of integration is 
similar to that of differentiation.
20 
Initial Conditions and Particular 
Solutions
21 
Initial Conditions and Particular Solutions 
You have already seen that the equation y = ∫f(x)dx has 
many solutions (each differing from the others by a 
constant). 
This means that the graphs of any two antiderivatives of f 
are vertical translations of each other.
22 
Initial Conditions and Particular Solutions 
For example, Figure 4.2 shows the 
graphs of several antiderivatives 
of the form 
for various integer values of C. 
Each of these antiderivatives is a solution 
of the differential equation 
Figure 4.2
23 
Initial Conditions and Particular Solutions 
In many applications of integration, you are given enough 
information to determine a particular solution. To do this, 
you need only know the value of y = F(x) for one value of x. 
This information is called an initial condition. 
For example, in Figure 4.2, only one curve passes through 
the point (2, 4). 
To find this curve, you can use the general solution 
F(x) = x3 – x + C General solution 
and the initial condition 
F(2) = 4 Initial condition
24 
Initial Conditions and Particular Solutions 
By using the initial condition in the general solution, you 
can determine that 
F(2) = 8 – 2 + C = 4 
which implies that C = –2. 
So, you obtain 
F(x) = x3 – x – 2. Particular solution
25 
Example 8 – Finding a Particular Solution 
Find the general solution of 
and find the particular solution that satisfies the initial 
condition F(1) = 0. 
Solution: 
To find the general solution, integrate to obtain
26 
Example 8 – Solution 
Using the initial condition F(1) = 0, you 
can solve for C as follows. 
So, the particular solution, as shown 
in Figure 4.3, is 
cont’d 
Figure 4.3

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Lar calc10 ch04_sec1

  • 1. Integration Copyright © Cengage Learning. All rights reserved.
  • 2. Antiderivatives and Indefinite Integration Copyright © Cengage Learning. All rights reserved.
  • 3. 3 Objectives  Write the general solution of a differential equation and use indefinite integral notation for antiderivatives.  Use basic integration rules to find antiderivatives.  Find a particular solution of a differential equation.
  • 5. 5 Antiderivatives To find a function F whose derivative is f(x) = 3x2, you might use your knowledge of derivatives to conclude that The function F is an antiderivative of f .
  • 6. 6 Antiderivatives Note that F is called an antiderivative of f, rather than the antiderivative of f. To see why, observe that are all derivatives of f (x) = 3x2. In fact, for any constant C, the function F(x)= x3 + C is an antiderivative of f.
  • 7. Antiderivatives Using Theorem 4.1, you can represent the entire family of antiderivatives of a function by adding a constant to a known antiderivative. For example, knowing that Dx [x2] = 2x, you can represent the family of all antiderivatives of f(x) = 2x by 7 G(x) = x2 + C Family of all antiderivatives of f(x) = 2x where C is a constant. The constant C is called the constant of integration.
  • 8. 8 Antiderivatives The family of functions represented by G is the general antiderivative of f, and G(x) = x2 + C is the general solution of the differential equation G'(x) = 2x. Differential equation A differential equation in x and y is an equation that involves x, y, and derivatives of y. For instance, y' = 3x and y' = x2 + 1 are examples of differential equations.
  • 9. 9 Example 1 – Solving a Differential Equation Find the general solution of the differential equation y' = 2. Solution: To begin, you need to find a function whose derivative is 2. One such function is y = 2x. 2x is an antiderivative of 2. Now, you can use Theorem 4.1 to conclude that the general solution of the differential equation is y = 2x + C. General solution
  • 10. 10 Example 1 – Solution The graphs of several functions of the form y = 2x + C are shown in Figure 4.1. Figure 4.1 cont’d
  • 11. 11 Notation for Antiderivatives
  • 12. 12 Notation for Antiderivatives When solving a differential equation of the form it is convenient to write it in the equivalent differential form The operation of finding all solutions of this equation is called antidifferentiation (or indefinite integration) and is denoted by an integral sign ∫.
  • 13. 13 Notation for Antiderivatives The general solution is denoted by The expression ∫f(x)dx is read as the antiderivative of f with respect to x. So, the differential dx serves to identify x as the variable of integration. The term indefinite integral is a synonym for antiderivative.
  • 15. 15 Basic Integration Rules The inverse nature of integration and differentiation can be verified by substituting F'(x) for f(x) in the indefinite integration definition to obtain Moreover, if ∫f(x)dx = F(x) + C, then
  • 16. 16 Basic Integration Rules These two equations allow you to obtain integration formulas directly from differentiation formulas, as shown in the following summary.
  • 17. 17 Basic Integration Rules cont’d
  • 18. 18 Example 2 – Applying the Basic Integration Rules Describe the antiderivatives of 3x. Solution: So, the antiderivatives of 3x are of the form where C is any constant.
  • 19. 19 Basic Integration Rules In Example 2, note that the general pattern of integration is similar to that of differentiation.
  • 20. 20 Initial Conditions and Particular Solutions
  • 21. 21 Initial Conditions and Particular Solutions You have already seen that the equation y = ∫f(x)dx has many solutions (each differing from the others by a constant). This means that the graphs of any two antiderivatives of f are vertical translations of each other.
  • 22. 22 Initial Conditions and Particular Solutions For example, Figure 4.2 shows the graphs of several antiderivatives of the form for various integer values of C. Each of these antiderivatives is a solution of the differential equation Figure 4.2
  • 23. 23 Initial Conditions and Particular Solutions In many applications of integration, you are given enough information to determine a particular solution. To do this, you need only know the value of y = F(x) for one value of x. This information is called an initial condition. For example, in Figure 4.2, only one curve passes through the point (2, 4). To find this curve, you can use the general solution F(x) = x3 – x + C General solution and the initial condition F(2) = 4 Initial condition
  • 24. 24 Initial Conditions and Particular Solutions By using the initial condition in the general solution, you can determine that F(2) = 8 – 2 + C = 4 which implies that C = –2. So, you obtain F(x) = x3 – x – 2. Particular solution
  • 25. 25 Example 8 – Finding a Particular Solution Find the general solution of and find the particular solution that satisfies the initial condition F(1) = 0. Solution: To find the general solution, integrate to obtain
  • 26. 26 Example 8 – Solution Using the initial condition F(1) = 0, you can solve for C as follows. So, the particular solution, as shown in Figure 4.3, is cont’d Figure 4.3