The document discusses explicit and implicit functions. An explicit function expresses the dependent variable in terms of the independent variable, while an implicit function does not. Implicit differentiation is used when the variables in an applied problem are related through an implicit formula rather than an explicit one. The process of implicit differentiation involves taking the derivative of both sides of the implicit equation with respect to the independent variable and solving for the derivative of the dependent variable. The total derivative describes the derivative of a function that depends on variables that are themselves functions of other variables, and can be calculated using a chain rule formula involving the partial derivatives.

1. IMPLICIT FUNCTION
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2. WHAT IS EXPLICIT/IMPLICIT FUNCTION?
 The explicit function is a function in which the
dependent variable has been given “explicitly” in terms of
the independent variable. Or it is a function in which the
dependent variable is expressed in terms of some
independent variables.
 The Implicit function is a function in which the
dependent variable has not been given “explicitly” in
terms of the independent variable. Or it is a function in
which the dependent variable is not expressed in terms
of some independent variables.
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3. EXPLICIT/IMPLICIT FUNCTION
 Examples of explicit function
 Explicit functions:
y = 3x – 2
y = x2 + 5
 Examples of implicit function
 Implicit functions:
y2 + 2yx 4x2 = 0
y5 - 3y2x2 + 2 = 0
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4. WHY IMPLICIT DIFFERENTIATION?
 When an applied problem involves an equation not
in explicit form, implicit differentiation is used to
locate extrema or to find rates of change.
 Implicit Differentiation. In many examples,
especially the ones derived from differential
equations, the variables involved are not linked to
each other in an explicit way. Most of the time, they
are linked through an implicit formula, like F(x,y)
=0. Once x is fixed, we may find y through
numerical computations.
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5. PROCESS FOR IMPLICIT DIFFERENTIATION
 To find dy/dx
 Differentiate both sides with respect to x (y is
assumed to be a function of x, so d/dx)
 Collect like terms (all dy/dx on the same side,
everything else on the other side)
 Factor out the dy/dx and solve for dy/dx
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6. EXAMPLE
 Find dy/dx if 3xy + 4y2 = 10
 Differentiate both sides with respect to x:
 Use the product rule for (3x)(y)
 (The derivative of y is dy/dx)
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7.  Since y is assumed to be some function of x, use the
chain rule for 4y2
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8.  Combine like terms
 Factor and solve
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9. TOTAL DERIVATIVE
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10. WHAT IS TOTAL DERIVATIVE?
 he total derivative is the derivative with respect to
of the function that depends on the variable not only
directly but also via the intermediate variables . It
can be calculated using the formula.
 This rule is called the chain rule for the partial
derivatives of functions of functions.
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11. TOTAL DERIVATIVE
 If w = f(x, y, z, ...) is a continuous function of n
variables x, y, z, ..., with continuous partial
derivatives ∂w/∂x, ∂w/∂y, ∂w/∂z, ... and if x, y, z, ...
are differentiable functions x = x(t), y = y(t) , z = z(t),
etc. of a variable t, then the total derivative of w
with respect to t is given by
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12.  Similarly, if w = f(x, y, z, ...) is a continuous function of n
variables x, y, z, ..., with continuous partial derivatives
∂w/∂x, ∂w/∂y, ∂w/∂z, ... and if x, y, z, ... are differentiable
functions of m independent variables r, s, t ... , then
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13.  Note the similarity between total differentials and total
derivatives. The total derivative above can be obtained
by dividing the total differential by dt,dr,ds
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14.  As a special application of the chain rule let us consider
the relation defined by the two equations
z = f(x, y); y = g(x)
 Here, z is a function of x and y while y in turn is a function
of x. Thus z is really a function of the single variable x. If
we apply the chain rule we get
 which is the total derivative of z with respect to x.
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15. THANK YOU
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