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UNIT 12.3/12.5 GEOMETRICUNIT 12.3/12.5 GEOMETRIC
SEQUENCES AND SERIESSEQUENCES AND SERIES
Warm Up
Simplify.
1. 2.
3. (–2)8
4.
Solve for x.
5.
Evaluate.
96
256
Find terms of a geometric sequence,
including geometric means.
Find the sums of geometric series.
Objectives
geometric sequence
geometric mean
geometric series
Vocabulary
Serena Williams was the winner out of 128 players
who began the 2003 Wimbledon Ladies’ Singles
Championship. After each match, the winner
continues to the next round and the loser is
eliminated from the tournament. This means that
after each round only half of the players remain.
The number of players remaining after each round
can be modeled by a geometric sequence. In a
geometric sequence, the ratio of successive
terms is a constant called the common ratio
r (r ≠ 1) . For the players remaining, r is .
Recall that exponential
functions have a common
ratio. When you graph the
ordered pairs (n, an) of a
geometric sequence, the
points lie on an exponential
curve as shown. Thus, you
can think of a geometric
sequence as an exponential
function with sequential
natural numbers as the
domain.
Check It Out! Example 1a
Determine whether the sequence could be
geometric or arithmetic. If possible, find the
common ratio or difference.
Differences
It could be geometric with
Ratios
1.7, 1.3, 0.9, 0.5, . . .
Check It Out! Example 1b
Determine whether the sequence could be
geometric or arithmetic. If possible, find the
common ratio or difference.
1.7 1.3 0.9 0.5
Differences –0.4 –0.4 –0.4
It could be arithmetic, with r = –0.4.
Ratio
Check It Out! Example 1c
Determine whether each sequence could be
geometric or arithmetic. If possible, find the
common ratio or difference.
–50, –32, –18, –8, . . .
–50, –32, –18, –8, . . .
Differences 18 14 10
It is neither.
Ratios
Each term in a geometric sequence is the product of
the previous term and the common ratio, giving the
recursive rule for a geometric sequence.
an = an–1rnth term
Common
ratio
First term
You can also use an explicit rule to find the nth term
of a geometric sequence. Each term is the product
of the first term and a power of the common ratio as
shown in the table.
This pattern can be generalized into a rule for all
geometric sequences.
Check It Out! Example 2a
Find the 9th term of the geometric sequence.
Step 1 Find the common ratio.
Check It Out! Example 2a Continued
Step 2 Write a rule, and evaluate for n = 9.
an = a1 r n–1
General rule
The 9th term is .
Substitute for a1, 9 for
n, and for r.
Check It Out! Example 2a Continued
Check Extend the sequence.
Given
a6 =
a7 =
a8 =
a9 =
0.001, 0.01, 0.1, 1, 10, . . .
Check It Out! Example 2b
Find the 9th term of the geometric sequence.
Step 1 Find the common ratio.
Check It Out! Example 2b Continued
Step 2 Write a rule, and evaluate for n = 9.
an = a1 r n–1
a9 = 0.001(10)9–1
= 0.001(100,000,000) = 100,000
The 7th term is 100,000.
General rule
Substitute 0.001 for a1,
9 for n, and 10 for r.
Check It Out! Example 2b Continued
Check Extend the sequence.
a6 = 10(10) = 100
a7 = 100(10) = 1,000
a8 = 1,000(10) = 10,000
a9 = 10,000(10) = 100,000
Givena5 = 10
When given two terms of a sequence, be
sure to consider positive and negative
values for r when necessary.
Caution!
Check It Out! Example 3a
Find the 7th term of the geometric sequence
with the given terms.
a4 = –8 and a5 = –40
Step 1 Find the common ratio.
a5 = a4 r(5 – 4)
a5 = a4 r
–40 = –8r
5 = r
Use the given terms.
Simplify.
Substitute –40 for a5 and –8 for a4.
Divide both sides by –8.
Check It Out! Example 3a Continued
Step 2 Find a1.
an = a1r n - 1
–8 = a1(5)4 - 1
–0.064 = a1
General rule
Use a5 = –8 and r = 5.
Check It Out! Example 3a Continued
Step 3 Write the rule and evaluate for a7.
an = a1r n - 1
Substitute for a1 and r.
The 7th term is –1,000.
an = –0.064(5)n - 1
a7 = –0.064(5)7 - 1
a7 = –1,000
Evaluate for n = 7.
a2 = 768 and a4 = 48
Check It Out! Example 3b
Find the 7th term of the geometric sequence
with the given terms.
Step 1 Find the common ratio.
a4 = a2 r(4 – 2)
a4 = a2 r2
48 = 768r2
0.0625 = r2
Use the given terms.
Simplify.
Substitute 48 for a4 and 768 for a2.
Divide both sides by 768.
±0.25 = r Take the square root.
Check It Out! Example 3b Continued
Step 2 Find a1.
Consider both the positive and negative values for r.
an = a1r n - 1
768 = a1(0.25)2 - 1
3072 = a1
an = a1r n - 1
768 = a1(–0.25)2 - 1
–3072 = a1
General rule
Use a2= 768 and
r = ±0.25.
or
Check It Out! Example 3b Continued
Step 3 Write the rule and evaluate for a7.
Consider both the positive and negative values for r.
an = a1r n - 1
an = a1r n - 1
Substitute for
a1 and r.
an = 3072(0.25)n - 1
a7 = 3072(0.25)7 - 1
a7 = 0.75
an = 3072(–0.25)n - 1
a7 = 3072(–0.25)7 - 1
a7 = 0.75
Evaluate for
n = 7.
or
Check It Out! Example 3b Continued
an = a1r n - 1
an = a1r n - 1
Substitute for
a1 and r.
The 7th term is 0.75 or –0.75.
an = –3072(0.25)n - 1
a7 = –3072(0.25)7 - 1
a7 = –0.75
an = –3072(–0.25)n - 1
a7 = –3072(–0.25)7 - 1
a7 = –0.75
Evaluate for
n = 7.
or
Geometric means are the terms between any two
nonconsecutive terms of a geometric sequence.
Check It Out! Example 4
Find the geometric mean of 16 and 25.
Use the formula.
The indicated sum of the terms of a geometric
sequence is called a geometric series. You can
derive a formula for the partial sum of a geometric
series by subtracting the product of Sn and r from Sn
as shown.
Check It Out! Example 5a
Find the indicated sum for each geometric series.
Step 1 Find the common ratio.
S6 for
Check It Out! Example 5a Continued
Step 2 Find S6 with a1 = 2, r = , and n = 6.
Substitute.
Sum formula
Check It Out! Example 5b
Find the indicated sum for each geometric series.
Step 1 Find the first term.
Step 2 Find S6.
Check It Out! Example 5b Continued
Check It Out! Example 6
A 6-year lease states that the annual rent for
an office space is $84,000 the first year and
will increase by 8% each additional year of
the lease. What will the total rent expense be
for the 6-year lease?
≈ $616,218.04
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Algebra 2 unit 12.3.12.5

  • 1. UNIT 12.3/12.5 GEOMETRICUNIT 12.3/12.5 GEOMETRIC SEQUENCES AND SERIESSEQUENCES AND SERIES
  • 2. Warm Up Simplify. 1. 2. 3. (–2)8 4. Solve for x. 5. Evaluate. 96 256
  • 3. Find terms of a geometric sequence, including geometric means. Find the sums of geometric series. Objectives
  • 5. Serena Williams was the winner out of 128 players who began the 2003 Wimbledon Ladies’ Singles Championship. After each match, the winner continues to the next round and the loser is eliminated from the tournament. This means that after each round only half of the players remain.
  • 6. The number of players remaining after each round can be modeled by a geometric sequence. In a geometric sequence, the ratio of successive terms is a constant called the common ratio r (r ≠ 1) . For the players remaining, r is .
  • 7. Recall that exponential functions have a common ratio. When you graph the ordered pairs (n, an) of a geometric sequence, the points lie on an exponential curve as shown. Thus, you can think of a geometric sequence as an exponential function with sequential natural numbers as the domain.
  • 8. Check It Out! Example 1a Determine whether the sequence could be geometric or arithmetic. If possible, find the common ratio or difference. Differences It could be geometric with Ratios
  • 9. 1.7, 1.3, 0.9, 0.5, . . . Check It Out! Example 1b Determine whether the sequence could be geometric or arithmetic. If possible, find the common ratio or difference. 1.7 1.3 0.9 0.5 Differences –0.4 –0.4 –0.4 It could be arithmetic, with r = –0.4. Ratio
  • 10. Check It Out! Example 1c Determine whether each sequence could be geometric or arithmetic. If possible, find the common ratio or difference. –50, –32, –18, –8, . . . –50, –32, –18, –8, . . . Differences 18 14 10 It is neither. Ratios
  • 11. Each term in a geometric sequence is the product of the previous term and the common ratio, giving the recursive rule for a geometric sequence. an = an–1rnth term Common ratio First term
  • 12. You can also use an explicit rule to find the nth term of a geometric sequence. Each term is the product of the first term and a power of the common ratio as shown in the table. This pattern can be generalized into a rule for all geometric sequences.
  • 13.
  • 14. Check It Out! Example 2a Find the 9th term of the geometric sequence. Step 1 Find the common ratio.
  • 15. Check It Out! Example 2a Continued Step 2 Write a rule, and evaluate for n = 9. an = a1 r n–1 General rule The 9th term is . Substitute for a1, 9 for n, and for r.
  • 16. Check It Out! Example 2a Continued Check Extend the sequence. Given a6 = a7 = a8 = a9 =
  • 17. 0.001, 0.01, 0.1, 1, 10, . . . Check It Out! Example 2b Find the 9th term of the geometric sequence. Step 1 Find the common ratio.
  • 18. Check It Out! Example 2b Continued Step 2 Write a rule, and evaluate for n = 9. an = a1 r n–1 a9 = 0.001(10)9–1 = 0.001(100,000,000) = 100,000 The 7th term is 100,000. General rule Substitute 0.001 for a1, 9 for n, and 10 for r.
  • 19. Check It Out! Example 2b Continued Check Extend the sequence. a6 = 10(10) = 100 a7 = 100(10) = 1,000 a8 = 1,000(10) = 10,000 a9 = 10,000(10) = 100,000 Givena5 = 10
  • 20. When given two terms of a sequence, be sure to consider positive and negative values for r when necessary. Caution!
  • 21. Check It Out! Example 3a Find the 7th term of the geometric sequence with the given terms. a4 = –8 and a5 = –40 Step 1 Find the common ratio. a5 = a4 r(5 – 4) a5 = a4 r –40 = –8r 5 = r Use the given terms. Simplify. Substitute –40 for a5 and –8 for a4. Divide both sides by –8.
  • 22. Check It Out! Example 3a Continued Step 2 Find a1. an = a1r n - 1 –8 = a1(5)4 - 1 –0.064 = a1 General rule Use a5 = –8 and r = 5.
  • 23. Check It Out! Example 3a Continued Step 3 Write the rule and evaluate for a7. an = a1r n - 1 Substitute for a1 and r. The 7th term is –1,000. an = –0.064(5)n - 1 a7 = –0.064(5)7 - 1 a7 = –1,000 Evaluate for n = 7.
  • 24. a2 = 768 and a4 = 48 Check It Out! Example 3b Find the 7th term of the geometric sequence with the given terms. Step 1 Find the common ratio. a4 = a2 r(4 – 2) a4 = a2 r2 48 = 768r2 0.0625 = r2 Use the given terms. Simplify. Substitute 48 for a4 and 768 for a2. Divide both sides by 768. ±0.25 = r Take the square root.
  • 25. Check It Out! Example 3b Continued Step 2 Find a1. Consider both the positive and negative values for r. an = a1r n - 1 768 = a1(0.25)2 - 1 3072 = a1 an = a1r n - 1 768 = a1(–0.25)2 - 1 –3072 = a1 General rule Use a2= 768 and r = ±0.25. or
  • 26. Check It Out! Example 3b Continued Step 3 Write the rule and evaluate for a7. Consider both the positive and negative values for r. an = a1r n - 1 an = a1r n - 1 Substitute for a1 and r. an = 3072(0.25)n - 1 a7 = 3072(0.25)7 - 1 a7 = 0.75 an = 3072(–0.25)n - 1 a7 = 3072(–0.25)7 - 1 a7 = 0.75 Evaluate for n = 7. or
  • 27. Check It Out! Example 3b Continued an = a1r n - 1 an = a1r n - 1 Substitute for a1 and r. The 7th term is 0.75 or –0.75. an = –3072(0.25)n - 1 a7 = –3072(0.25)7 - 1 a7 = –0.75 an = –3072(–0.25)n - 1 a7 = –3072(–0.25)7 - 1 a7 = –0.75 Evaluate for n = 7. or
  • 28. Geometric means are the terms between any two nonconsecutive terms of a geometric sequence.
  • 29. Check It Out! Example 4 Find the geometric mean of 16 and 25. Use the formula.
  • 30. The indicated sum of the terms of a geometric sequence is called a geometric series. You can derive a formula for the partial sum of a geometric series by subtracting the product of Sn and r from Sn as shown.
  • 31.
  • 32. Check It Out! Example 5a Find the indicated sum for each geometric series. Step 1 Find the common ratio. S6 for
  • 33. Check It Out! Example 5a Continued Step 2 Find S6 with a1 = 2, r = , and n = 6. Substitute. Sum formula
  • 34. Check It Out! Example 5b Find the indicated sum for each geometric series. Step 1 Find the first term.
  • 35. Step 2 Find S6. Check It Out! Example 5b Continued
  • 36. Check It Out! Example 6 A 6-year lease states that the annual rent for an office space is $84,000 the first year and will increase by 8% each additional year of the lease. What will the total rent expense be for the 6-year lease? ≈ $616,218.04
  • 37. All rights belong to their respective owners. Copyright Disclaimer Under Section 107 of the Copyright Act 1976, allowance is made for "fair use" for purposes such as criticism, comment, news reporting, TEACHING, scholarship, and research. Fair use is a use permitted by copyright statute that might otherwise be infringing. Non-profit, EDUCATIONAL or personal use tips the balance in favor of fair use.