1) The document discusses calculating the normal force (N) on an object with a mass (m) of 4kg that is at an angle (θ) from the horizontal. It determines that the normal force is equal to N = mgcosθ, or 40 Newtons in this case. 2) It then considers calculating the tensions (T1 and T2) in two ropes attached at angles, determining that T2 = T1√3. Using the forces in the y-direction, it calculates the individual tensions as T1 = 40N and T2 = 40√3 N.

1. Gaya Normal (N)
N
N 4kg
Berapa besar
4kg mg sin θ gaya normal
pada gambar
mg cos θ
mg θ disamping ?
w Penyelesaian :
∑ F = 0 ⇔ N − w cosθ = 0
∑ F = 0⇔ N−w= 0 N = w cos θ = mg cos θ
N = w = mg ∴ N = m.g cos θ , maka :
∴ N = m.g = 4 x10 = 40 N N = m.g cos θ = 40 cos θ ( N )
By : mhharismansur

2. Tegangan Tali (T) Diagram vektor
0 0
y
60 30 T2 T2 sin 60 T1 sin 30
Hitunglah : T1
T1 T2 a. Besar T1
b. Besar T2 600 300
T3 Pada sumbu x T2 cos 60 T1 cos 30
4kg ∑F x =0 x
T1 cos 30 − T2 cos 60 = 0
Penyelesaian T3
T( 1
1 2 3) = T ( )
1
2 2
∴ T2 = T1 3 Kesimpulan :
Pada sumbu y
∴ T2 = T1 3 ⇔ T1 + T2 3 = 2W
∑ Fy = 0(ingat T3 = W )
T1 + 3T1 = 2.40 = 80 N
T1 sin 30 + T2 sin 60 − T3 = 0
1.∴ T1 = 40 N
T ( )+T (
1
1 2
1
2 2 3) = W
2.∴ T2 = 40 3 N
∴ T1 + T2 3 = 2W
By : mhharismansur