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MATEMATIKA
TRIGONOMETRI
Disusun oleh :
DINI H NUPUS
.
Kelas :
X IIS 3
MATERI PELAJARAN
TENTANG
TRIGONOMETRI
Konsep Umum : PHYTAGORAS
Sin โˆ =
๐‘‘๐‘’๐‘๐‘Ž๐‘›
๐‘š๐‘–๐‘Ÿ๐‘–๐‘›๐‘”
=
3
5
Cos โˆ =
๐‘ ๐‘Ž๐‘š๐‘๐‘–๐‘›๐‘”
๐‘š๐‘–๐‘Ÿ๐‘–๐‘›๐‘”
=
4
5
Tan โˆ =
๐‘‘๐‘’๐‘๐‘Ž๐‘›
๐‘ ๐‘Ž๐‘š๐‘๐‘–๐‘›๐‘”
=
3
4
Sec โˆ =
1
๐ถ๐‘œ๐‘  โˆ
=
1
4
5
=
5
4
Cosec โˆ =
1
๐‘†๐‘–๐‘› โˆ
=
1
3
5
=
5
3
Cot โˆ =
1
๐‘‡๐‘Ž๐‘› โˆ
=
1
3
4
=
4
3
KUNCI SUKSES MATERI
TRIGONOMETRI
WAJIB
DI HAFALKAN !!!
NILAI PERBANDINGAN
TRIGONOMETRI
RUMUS IDENTITAS
TRIGONOMETRI
RUMUS 1
PENJUMLAHAN
SUDUT (sinus/cosinus)
RUMUS 2
JUMLAH & SELISIH
SUDUT (sinus/cosinus)
RUMUS 3
PERKALIAN SUDUT
(sinus/cosinus)
RUMUS 4
TRIGONOMETRI
NILAI PERBANDINGAN
TRIGONOMETRI
Kuadran II
(180ยฐโˆ’ โˆ)
90ยฐ < ๐ฑ < 180ยฐ
Sin +
Kuadran I
(90ยฐโˆ’ โˆ)
< 90ยฐ
All +
Kuadran III
(180ยฐ+ โˆ)
180ยฐ < ๐ฑ < 360ยฐ
Tan +
Kuadran IV
(360ยฐโˆ’ โˆ)
Cos +
Contoh Soal
A.Sin 140ยฐ = โ€ฆ B.Cos 240ยฐ = โ€ฆ
Penyelesaian:
B. Cos 240ยฐ = Kuadran III
Cos (18๐ŸŽยฐ+ โˆ) = 240ยฐ
Cos (1๐Ÿ–๐ŸŽยฐ + ๐Ÿ”๐ŸŽยฐ) = 240ยฐ
โˆ = 6๐ŸŽยฐ
Cos 60ยฐ =
Penyelesaian:
A. Sin 135ยฐ = Kuadran II
Sin (180ยฐโˆ’ โˆ) = 135ยฐ
Sin (180ยฐ โˆ’ ๐Ÿ’๐Ÿ“ยฐ) = 135ยฐ
โˆ = ๐Ÿ’๐ŸŽยฐ
Sin ๐Ÿ’๐Ÿ“ยฐ =
RUMUS IDENTITAS
TRIGONOMETRI
1. ๐‘บ๐’Š๐’ ๐Ÿ
๐‘จ + ๐‘ช๐’๐’” ๐Ÿ
๐‘จ = ๐Ÿ
2. 1 + ๐‘ป๐’‚๐’ ๐Ÿ
๐‘จ =
๐Ÿ
๐‘ช๐’๐’” ๐Ÿ ๐‘จ
= ๐‘บ๐’†๐’„ ๐Ÿ
๐‘จ
3. 1 + ๐‘ช๐’๐’• ๐Ÿ
๐‘จ =
๐Ÿ
๐‘บ๐’†๐’„ ๐Ÿ ๐‘จ
= ๐‘ช๐’๐’”๐’†๐’„ ๐Ÿ
๐‘จ
Tidak ada contoh soal
RUMUS 1
PENJUMLAHAN SUDUT
(SINUS/COSINUS)
SINUS
1. ๐’๐ข๐ง ๐€ + ๐ = ๐’๐ข๐ง๐€. ๐‚๐จ๐ฌ๐ + ๐‚๐จ๐ฌ๐€. ๐’๐ข๐ง๐
2. ๐’๐ข๐ง ๐€ โˆ’ ๐ = ๐’๐ข๐ง๐€. ๐‚๐จ๐ฌ๐ โˆ’ ๐‚๐จ๐ฌ๐€. ๐’๐ข๐ง๐
COSINUS
1. Cos ๐€ + ๐ = ๐‚๐จ๐ฌ๐€. ๐‚๐จ๐ฌ๐ โˆ’ ๐’๐ข๐ง๐€. ๐’๐ข๐ง๐
2. Cos ๐€ โˆ’ ๐ = ๐‚๐จ๐ฌ๐€. ๐‚๐จ๐ฌ๐ + ๐’๐ข๐ง๐€. ๐’๐ข๐ง๐
Contoh Soal
Penyelesaian:
A. Sin (45ยฐ + 60ยฐ)
= Sin 45ยฐ. Cos 60ยฐ + Cos 45ยฐ. Sin 60ยฐ
= 1
2 2. 1
2+1
2 2.1
2 3
= 1
4 2+1
4 6
B. Sin 36ยฐ. Cos 24ยฐ + Cos 36ยฐ. Sin 24ยฐ
= Sin (36ยฐ + 24ยฐ)
= Sin 60ยฐ
= 1
2 3
Tentukan Nilai dari:
A.Sin (45ยฐ + ๐Ÿ”๐ŸŽยฐ) !
B.Sin 36ยฐ. ๐‚๐จ๐ฌ ๐Ÿ๐Ÿ’ยฐ + ๐‚๐จ๐ฌ ๐Ÿ‘๐Ÿ”ยฐ. ๐’๐ข๐ง ๐Ÿ๐Ÿ’ยฐ !
RUMUS 2
JUMLAH & SELISIH SUDUT
(SINUS/COSINUS)
SINUS
1. ๐’๐ข๐ง๐€ + ๐’๐ข๐ง๐ = ๐Ÿ. ๐’๐ข๐ง ๐Ÿ
๐Ÿ ๐€ + ๐ . ๐‚๐จ๐ฌ ๐Ÿ
๐Ÿ ๐€ โˆ’ ๐
2. ๐’๐ข๐ง๐€ โˆ’ ๐’๐ข๐ง๐ = โˆ’๐Ÿ. ๐’๐ข๐ง ๐Ÿ
๐Ÿ ๐€ + ๐ . ๐‚๐จ๐ฌ ๐Ÿ
๐Ÿ ๐€ โˆ’ ๐
COSINUS
1. Cos๐€ + ๐‚๐จ๐ฌ๐ = ๐Ÿ. ๐‚๐จ๐ฌ ๐Ÿ
๐Ÿ ๐€ + ๐ . ๐‚๐จ๐ฌ ๐Ÿ
๐Ÿ ๐€ โˆ’ ๐
2. ๐‚๐จ๐ฌ๐€ โˆ’ ๐‚๐จ๐ฌ๐ = โˆ’๐Ÿ. ๐’๐ข๐ง ๐Ÿ
๐Ÿ ๐€ + ๐ . ๐’๐ข๐ง ๐Ÿ
๐Ÿ ๐€ โˆ’ ๐
Contoh Soal
Penyelesaian:
Cos 90ยฐ + ๐ถ๐‘œ๐‘  30ยฐ
= 2. ๐ถ๐‘œ๐‘  1
2 ๐ด + ๐ต . ๐ถ๐‘œ๐‘  1
2 ๐ด โˆ’ ๐ต
= 2. ๐ถ๐‘œ๐‘  1
2 90ยฐ + 30ยฐ . ๐ถ๐‘œ๐‘  1
2 90ยฐ โˆ’ 30ยฐ
= 2. ๐ถ๐‘œ๐‘  1
2 . 120ยฐ . ๐ถ๐‘œ๐‘  1
2 . 60ยฐ
= 2. ๐ถ๐‘œ๐‘  60ยฐ . ๐ถ๐‘œ๐‘  30ยฐ
= 2. 1
2 . 1
2 3
= 1 . 1
2 3
Tentukan Nilai dari :
Cos 90ยฐ + ๐‚๐จ๐ฌ ๐Ÿ‘๐ŸŽยฐ !
RUMUS 3
PERKALIAN SUDUT
(SINUS/COSINUS)
1. ๐Ÿ. ๐’๐ข๐ง๐€. ๐‚๐จ๐ฌ๐ = ๐’๐ข๐ง ๐€ + ๐ + ๐’๐ข๐ง ๐€ โˆ’ ๐
2. ๐Ÿ. ๐‚๐จ๐ฌ๐€. ๐’๐ข๐ง๐ = ๐’๐ข๐ง ๐€ + ๐ โˆ’ ๐’๐ข๐ง ๐€ โˆ’ ๐
3. 2.Cos๐€. ๐‚๐จ๐ฌ๐ = ๐‚๐จ๐ฌ ๐€ + ๐ + ๐‚๐จ๐ฌ ๐€ โˆ’ ๐
4. โˆ’๐Ÿ. ๐‚๐จ๐ฌ๐€. ๐‚๐จ๐ฌ๐ = ๐‚๐จ๐ฌ ๐€ + ๐ โˆ’ ๐’๐ข๐ง ๐€ โˆ’ ๐
Contoh Soal
Penyelesaian:
2. Cos 60ยฐ. Sin 60ยฐ
= 2. Sin 60ยฐ + 30ยฐ โˆ’ Sin 60ยฐ โˆ’ 30ยฐ
= 2. Sin 90ยฐ โˆ’ Sin 30ยฐ
= 2. 1 - 1
2
= 2 - 1
2
๐“๐ž๐ง๐ญ๐ฎ๐ค๐š๐ง ๐๐ข๐ฅ๐š๐ข ๐๐š๐ซ๐ข โˆถ
๐Ÿ. ๐‚๐จ๐ฌ ๐Ÿ”๐ŸŽยฐ. ๐’๐ข๐ง ๐Ÿ‘๐ŸŽยฐ
RUMUS 4
TRIGONOMETRI
1. ๐‘บ๐’Š๐’ ๐Ÿ
โˆ = ๐Ÿ. ๐‘บ๐’Š๐’ โˆ. ๐‘ช๐’๐’” โˆ
2. ๐‘ช๐’๐’” ๐Ÿ
โˆ = ๐‘ช๐’๐’” ๐Ÿ
โˆ โˆ’๐‘บ๐’Š๐’ ๐Ÿ
โˆ
=2. ๐‘ช๐’๐’” ๐Ÿ
โˆ โˆ’1
3. ๐‘ป๐’‚๐’ ๐Ÿ
โˆ =
๐Ÿ.๐‘ป๐’‚๐’ โˆ
๐Ÿโˆ’๐‘ป๐’‚๐’ ๐Ÿโˆ
Contoh Soal
Penyelesaian:
๐‘†๐‘–๐‘›230ยฐ = ๐‘†๐‘–๐‘› 30ยฐ 2
= 1
2
2
= 1
4
Bentuk sederhana dari :
๐‘บ๐’Š๐’ ๐Ÿ
๐Ÿ‘๐ŸŽยฐ !
LATIHAN
SOAL
1. Cos (270ยฐ)
2. Sin (204ยฐ)
3. Tan (60ยฐ)
4. Sec (167ยฐ)
5. Sin260ยฐ+Cos260ยฐ
6. 2. ๐ถ๐‘œ๐‘ 260ยฐ+2. ๐‘†๐‘–๐‘›245+3. ๐‘‡๐‘Ž๐‘›245ยฐ
7. Sin 135ยฐ
8. Cos(90ยฐ-30ยฐ)
9. Cos 60ยฐ-Cos 30ยฐ
10.Jika f(x) = (Cos x + Sin x) . Tentukan nilai f(x),
jika x = 45ยฐ
PEMBAHASAN
SOAL
1. Cos (270ยฐ) = K III
Cos (180ยฐ+โˆ) = 270ยฐ
Cos (180ยฐ+๐Ÿ—๐ŸŽยฐ) = 270ยฐ
โˆ = ๐Ÿ—๐ŸŽยฐ
Cos ๐Ÿ—๐ŸŽยฐ = ๐ŸŽ
2. Sin (204ยฐ) = K III
Sin (180ยฐ+โˆ) = 204ยฐ
Sin (180ยฐ+๐Ÿ๐Ÿ’ยฐ) = 204ยฐ
โˆ = ๐Ÿ๐Ÿ’ยฐ (โˆ’)
3. Tan (60ยฐ) = K I
Tan (90ยฐโˆ’ โˆ) = 60ยฐ
Tan (90ยฐ โˆ’ ๐Ÿ‘๐ŸŽยฐ) = 60ยฐ
โˆ = ๐Ÿ‘๐ŸŽยฐ
Tan 3๐ŸŽยฐ = ๐Ÿ
๐Ÿ‘ ๐Ÿ‘
4. Sec (167ยฐ) = K II
Sec (180ยฐ โˆ’โˆ) = 167ยฐ
Sin (180ยฐ โˆ’ ๐Ÿ๐Ÿ‘ยฐ) = 167ยฐ
โˆ = ๐Ÿ๐Ÿ‘ยฐ (+)
5. ๐’๐ข๐ง ๐Ÿ60ยฐ+๐‚๐จ๐ฌ ๐Ÿ60ยฐ
= (Sin 60ยฐ) ๐Ÿ+(Cos 60ยฐ) ๐Ÿ
= ( ๐Ÿ
๐Ÿ ๐Ÿ‘) ๐Ÿ
+( ๐Ÿ
๐Ÿ) ๐Ÿ
= ๐Ÿ
๐Ÿ’ . ๐Ÿ‘ + ๐Ÿ
๐Ÿ’
= ๐Ÿ‘
๐Ÿ’ + ๐Ÿ
๐Ÿ’
= ๐Ÿ’
๐Ÿ’
= 1
6. 2. ๐‚๐จ๐ฌ ๐Ÿ60ยฐ+2. ๐’๐ข๐ง ๐Ÿ45+3. ๐“๐š๐ง ๐Ÿ45ยฐ
= 2(Cos 60ยฐ) ๐Ÿ
+ 2(Sin 60ยฐ) ๐Ÿ
+3(Tan ๐Ÿ’๐Ÿ“ยฐ) ๐Ÿ
= 2( ๐Ÿ
๐Ÿ) ๐Ÿ + ๐Ÿ( ๐Ÿ
๐Ÿ ๐Ÿ) ๐Ÿ+๐Ÿ‘(๐Ÿ) ๐Ÿ
= 2( ๐Ÿ
๐Ÿ’) +2( ๐Ÿ
๐Ÿ’.2)+3.1
= ๐Ÿ
๐Ÿ’+ ๐Ÿ
๐Ÿ’.4+3
= ๐Ÿ
๐Ÿ’+2+3
= ๐Ÿ
๐Ÿ’ + ๐Ÿ“
7. Sin 135ยฐ = (Sin 90+45)
= ๐’๐ข๐ง ๐€ + ๐ = ๐’๐ข๐ง๐€. ๐‚๐จ๐ฌ๐ + ๐‚๐จ๐ฌ๐€. ๐’๐ข๐ง๐
= Sin 90ยฐ.Cos 45ยฐ+Cos 90ยฐ.Sin 45ยฐ
= 1. ๐Ÿ
๐Ÿ ๐Ÿ+0. ๐Ÿ
๐Ÿ ๐Ÿ
= ๐Ÿ
๐Ÿ ๐Ÿ
8. Cos(90ยฐ-30ยฐ)
= Cos ๐€ โˆ’ ๐ = ๐‚๐จ๐ฌ๐€. ๐‚๐จ๐ฌ๐ + ๐’๐ข๐ง๐€. ๐’๐ข๐ง๐
= Cos 90ยฐ.Cos 45ยฐ+Sin 90ยฐ.Sin 45ยฐ
= ๐Ÿ
๐Ÿ ๐Ÿ.0+ ๐Ÿ
๐Ÿ ๐Ÿ‘. ๐Ÿ
= ๐Ÿ
๐Ÿ ๐Ÿ‘
9. Cos 60ยฐ-Cos 30ยฐ
= ๐‚๐จ๐ฌ๐€ โˆ’ ๐‚๐จ๐ฌ๐ = โˆ’๐Ÿ. ๐’๐ข๐ง ๐Ÿ
๐Ÿ ๐€ + ๐ . ๐’๐ข๐ง ๐Ÿ
๐Ÿ ๐€ โˆ’ ๐
= โˆ’๐Ÿ. ๐’๐ข๐ง ๐Ÿ
๐Ÿ ๐Ÿ”๐ŸŽยฐ + ๐Ÿ‘๐ŸŽยฐ . ๐’๐ข๐ง ๐Ÿ
๐Ÿ ๐Ÿ”๐ŸŽยฐ โˆ’ ๐Ÿ‘๐ŸŽยฐ
= โˆ’๐Ÿ. ๐’๐ข๐ง ๐Ÿ
๐Ÿ ๐Ÿ—๐ŸŽยฐ . ๐’๐ข๐ง ๐Ÿ
๐Ÿ ๐Ÿ‘๐ŸŽยฐ
= โˆ’๐Ÿ. ๐’๐ข๐ง ๐Ÿ’๐Ÿ“ยฐ. ๐’๐ข๐ง ๐Ÿ‘๐ŸŽยฐ
= โˆ’๐Ÿ. ๐Ÿ
๐Ÿ ๐Ÿ. ๐’๐ข๐ง ๐Ÿ๐Ÿ“ยฐ
= โˆ’ ๐Ÿ
๐Ÿ . โˆ’๐Ÿ. ๐’๐ข๐ง ๐Ÿ๐Ÿ“ยฐ
= โˆ’๐Ÿ. โˆ’๐Ÿ. ๐’๐ข๐ง ๐Ÿ๐Ÿ“ยฐ
= ๐Ÿ. ๐’๐ข๐ง ๐Ÿ๐Ÿ“ยฐ
10. Jika f(x) = (Cos x + Sin x) . Tentukan nilai f(x),
jika x = 45ยฐ
F (x) = (Cos x + Sin x) ( Cos x + Sin x)
= ๐‘ช๐’๐’” ๐Ÿ ๐’™ + ๐‘บ๐’Š๐’ ๐’™. ๐‚๐จ๐ฌ ๐’™+ ๐‘บ๐’Š๐’ ๐’™. ๐‚๐จ๐ฌ ๐’™+ ๐‘บ๐’Š๐’ ๐Ÿ ๐’™
= ๐‘ช๐’๐’” ๐Ÿ ๐’™ + ๐‘บ๐’Š๐’ ๐Ÿ ๐’™ + ๐‘บ๐’Š๐’ ๐’™. ๐‚๐จ๐ฌ ๐’™+ ๐‘บ๐’Š๐’ ๐’™. ๐‚๐จ๐ฌ ๐’™
= 1 + ๐‘บ๐’Š๐’ ๐’™. ๐‚๐จ๐ฌ ๐’™+ ๐‘บ๐’Š๐’ ๐’™. ๐‚๐จ๐ฌ ๐’™
= 1 + (Sin (A+B)+Sin (A-B))
= 1 + (Sin (45ยฐ+45ยฐ)+Sin (45ยฐ-45ยฐ))
= 1 + (Sin 90ยฐ +Sin90ยฐ)
= 1 + 1 + 0
= 2

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Matematika Trigonometri Rangkuman

  • 1. MATEMATIKA TRIGONOMETRI Disusun oleh : DINI H NUPUS . Kelas : X IIS 3 MATERI PELAJARAN TENTANG
  • 2. TRIGONOMETRI Konsep Umum : PHYTAGORAS Sin โˆ = ๐‘‘๐‘’๐‘๐‘Ž๐‘› ๐‘š๐‘–๐‘Ÿ๐‘–๐‘›๐‘” = 3 5 Cos โˆ = ๐‘ ๐‘Ž๐‘š๐‘๐‘–๐‘›๐‘” ๐‘š๐‘–๐‘Ÿ๐‘–๐‘›๐‘” = 4 5 Tan โˆ = ๐‘‘๐‘’๐‘๐‘Ž๐‘› ๐‘ ๐‘Ž๐‘š๐‘๐‘–๐‘›๐‘” = 3 4 Sec โˆ = 1 ๐ถ๐‘œ๐‘  โˆ = 1 4 5 = 5 4 Cosec โˆ = 1 ๐‘†๐‘–๐‘› โˆ = 1 3 5 = 5 3 Cot โˆ = 1 ๐‘‡๐‘Ž๐‘› โˆ = 1 3 4 = 4 3
  • 4. NILAI PERBANDINGAN TRIGONOMETRI RUMUS IDENTITAS TRIGONOMETRI RUMUS 1 PENJUMLAHAN SUDUT (sinus/cosinus) RUMUS 2 JUMLAH & SELISIH SUDUT (sinus/cosinus) RUMUS 3 PERKALIAN SUDUT (sinus/cosinus) RUMUS 4 TRIGONOMETRI
  • 5. NILAI PERBANDINGAN TRIGONOMETRI Kuadran II (180ยฐโˆ’ โˆ) 90ยฐ < ๐ฑ < 180ยฐ Sin + Kuadran I (90ยฐโˆ’ โˆ) < 90ยฐ All + Kuadran III (180ยฐ+ โˆ) 180ยฐ < ๐ฑ < 360ยฐ Tan + Kuadran IV (360ยฐโˆ’ โˆ) Cos +
  • 6. Contoh Soal A.Sin 140ยฐ = โ€ฆ B.Cos 240ยฐ = โ€ฆ Penyelesaian: B. Cos 240ยฐ = Kuadran III Cos (18๐ŸŽยฐ+ โˆ) = 240ยฐ Cos (1๐Ÿ–๐ŸŽยฐ + ๐Ÿ”๐ŸŽยฐ) = 240ยฐ โˆ = 6๐ŸŽยฐ Cos 60ยฐ = Penyelesaian: A. Sin 135ยฐ = Kuadran II Sin (180ยฐโˆ’ โˆ) = 135ยฐ Sin (180ยฐ โˆ’ ๐Ÿ’๐Ÿ“ยฐ) = 135ยฐ โˆ = ๐Ÿ’๐ŸŽยฐ Sin ๐Ÿ’๐Ÿ“ยฐ =
  • 7. RUMUS IDENTITAS TRIGONOMETRI 1. ๐‘บ๐’Š๐’ ๐Ÿ ๐‘จ + ๐‘ช๐’๐’” ๐Ÿ ๐‘จ = ๐Ÿ 2. 1 + ๐‘ป๐’‚๐’ ๐Ÿ ๐‘จ = ๐Ÿ ๐‘ช๐’๐’” ๐Ÿ ๐‘จ = ๐‘บ๐’†๐’„ ๐Ÿ ๐‘จ 3. 1 + ๐‘ช๐’๐’• ๐Ÿ ๐‘จ = ๐Ÿ ๐‘บ๐’†๐’„ ๐Ÿ ๐‘จ = ๐‘ช๐’๐’”๐’†๐’„ ๐Ÿ ๐‘จ Tidak ada contoh soal
  • 8. RUMUS 1 PENJUMLAHAN SUDUT (SINUS/COSINUS) SINUS 1. ๐’๐ข๐ง ๐€ + ๐ = ๐’๐ข๐ง๐€. ๐‚๐จ๐ฌ๐ + ๐‚๐จ๐ฌ๐€. ๐’๐ข๐ง๐ 2. ๐’๐ข๐ง ๐€ โˆ’ ๐ = ๐’๐ข๐ง๐€. ๐‚๐จ๐ฌ๐ โˆ’ ๐‚๐จ๐ฌ๐€. ๐’๐ข๐ง๐ COSINUS 1. Cos ๐€ + ๐ = ๐‚๐จ๐ฌ๐€. ๐‚๐จ๐ฌ๐ โˆ’ ๐’๐ข๐ง๐€. ๐’๐ข๐ง๐ 2. Cos ๐€ โˆ’ ๐ = ๐‚๐จ๐ฌ๐€. ๐‚๐จ๐ฌ๐ + ๐’๐ข๐ง๐€. ๐’๐ข๐ง๐
  • 9. Contoh Soal Penyelesaian: A. Sin (45ยฐ + 60ยฐ) = Sin 45ยฐ. Cos 60ยฐ + Cos 45ยฐ. Sin 60ยฐ = 1 2 2. 1 2+1 2 2.1 2 3 = 1 4 2+1 4 6 B. Sin 36ยฐ. Cos 24ยฐ + Cos 36ยฐ. Sin 24ยฐ = Sin (36ยฐ + 24ยฐ) = Sin 60ยฐ = 1 2 3 Tentukan Nilai dari: A.Sin (45ยฐ + ๐Ÿ”๐ŸŽยฐ) ! B.Sin 36ยฐ. ๐‚๐จ๐ฌ ๐Ÿ๐Ÿ’ยฐ + ๐‚๐จ๐ฌ ๐Ÿ‘๐Ÿ”ยฐ. ๐’๐ข๐ง ๐Ÿ๐Ÿ’ยฐ !
  • 10. RUMUS 2 JUMLAH & SELISIH SUDUT (SINUS/COSINUS) SINUS 1. ๐’๐ข๐ง๐€ + ๐’๐ข๐ง๐ = ๐Ÿ. ๐’๐ข๐ง ๐Ÿ ๐Ÿ ๐€ + ๐ . ๐‚๐จ๐ฌ ๐Ÿ ๐Ÿ ๐€ โˆ’ ๐ 2. ๐’๐ข๐ง๐€ โˆ’ ๐’๐ข๐ง๐ = โˆ’๐Ÿ. ๐’๐ข๐ง ๐Ÿ ๐Ÿ ๐€ + ๐ . ๐‚๐จ๐ฌ ๐Ÿ ๐Ÿ ๐€ โˆ’ ๐ COSINUS 1. Cos๐€ + ๐‚๐จ๐ฌ๐ = ๐Ÿ. ๐‚๐จ๐ฌ ๐Ÿ ๐Ÿ ๐€ + ๐ . ๐‚๐จ๐ฌ ๐Ÿ ๐Ÿ ๐€ โˆ’ ๐ 2. ๐‚๐จ๐ฌ๐€ โˆ’ ๐‚๐จ๐ฌ๐ = โˆ’๐Ÿ. ๐’๐ข๐ง ๐Ÿ ๐Ÿ ๐€ + ๐ . ๐’๐ข๐ง ๐Ÿ ๐Ÿ ๐€ โˆ’ ๐
  • 11. Contoh Soal Penyelesaian: Cos 90ยฐ + ๐ถ๐‘œ๐‘  30ยฐ = 2. ๐ถ๐‘œ๐‘  1 2 ๐ด + ๐ต . ๐ถ๐‘œ๐‘  1 2 ๐ด โˆ’ ๐ต = 2. ๐ถ๐‘œ๐‘  1 2 90ยฐ + 30ยฐ . ๐ถ๐‘œ๐‘  1 2 90ยฐ โˆ’ 30ยฐ = 2. ๐ถ๐‘œ๐‘  1 2 . 120ยฐ . ๐ถ๐‘œ๐‘  1 2 . 60ยฐ = 2. ๐ถ๐‘œ๐‘  60ยฐ . ๐ถ๐‘œ๐‘  30ยฐ = 2. 1 2 . 1 2 3 = 1 . 1 2 3 Tentukan Nilai dari : Cos 90ยฐ + ๐‚๐จ๐ฌ ๐Ÿ‘๐ŸŽยฐ !
  • 12. RUMUS 3 PERKALIAN SUDUT (SINUS/COSINUS) 1. ๐Ÿ. ๐’๐ข๐ง๐€. ๐‚๐จ๐ฌ๐ = ๐’๐ข๐ง ๐€ + ๐ + ๐’๐ข๐ง ๐€ โˆ’ ๐ 2. ๐Ÿ. ๐‚๐จ๐ฌ๐€. ๐’๐ข๐ง๐ = ๐’๐ข๐ง ๐€ + ๐ โˆ’ ๐’๐ข๐ง ๐€ โˆ’ ๐ 3. 2.Cos๐€. ๐‚๐จ๐ฌ๐ = ๐‚๐จ๐ฌ ๐€ + ๐ + ๐‚๐จ๐ฌ ๐€ โˆ’ ๐ 4. โˆ’๐Ÿ. ๐‚๐จ๐ฌ๐€. ๐‚๐จ๐ฌ๐ = ๐‚๐จ๐ฌ ๐€ + ๐ โˆ’ ๐’๐ข๐ง ๐€ โˆ’ ๐
  • 13. Contoh Soal Penyelesaian: 2. Cos 60ยฐ. Sin 60ยฐ = 2. Sin 60ยฐ + 30ยฐ โˆ’ Sin 60ยฐ โˆ’ 30ยฐ = 2. Sin 90ยฐ โˆ’ Sin 30ยฐ = 2. 1 - 1 2 = 2 - 1 2 ๐“๐ž๐ง๐ญ๐ฎ๐ค๐š๐ง ๐๐ข๐ฅ๐š๐ข ๐๐š๐ซ๐ข โˆถ ๐Ÿ. ๐‚๐จ๐ฌ ๐Ÿ”๐ŸŽยฐ. ๐’๐ข๐ง ๐Ÿ‘๐ŸŽยฐ
  • 14. RUMUS 4 TRIGONOMETRI 1. ๐‘บ๐’Š๐’ ๐Ÿ โˆ = ๐Ÿ. ๐‘บ๐’Š๐’ โˆ. ๐‘ช๐’๐’” โˆ 2. ๐‘ช๐’๐’” ๐Ÿ โˆ = ๐‘ช๐’๐’” ๐Ÿ โˆ โˆ’๐‘บ๐’Š๐’ ๐Ÿ โˆ =2. ๐‘ช๐’๐’” ๐Ÿ โˆ โˆ’1 3. ๐‘ป๐’‚๐’ ๐Ÿ โˆ = ๐Ÿ.๐‘ป๐’‚๐’ โˆ ๐Ÿโˆ’๐‘ป๐’‚๐’ ๐Ÿโˆ
  • 15. Contoh Soal Penyelesaian: ๐‘†๐‘–๐‘›230ยฐ = ๐‘†๐‘–๐‘› 30ยฐ 2 = 1 2 2 = 1 4 Bentuk sederhana dari : ๐‘บ๐’Š๐’ ๐Ÿ ๐Ÿ‘๐ŸŽยฐ !
  • 16. LATIHAN SOAL 1. Cos (270ยฐ) 2. Sin (204ยฐ) 3. Tan (60ยฐ) 4. Sec (167ยฐ) 5. Sin260ยฐ+Cos260ยฐ 6. 2. ๐ถ๐‘œ๐‘ 260ยฐ+2. ๐‘†๐‘–๐‘›245+3. ๐‘‡๐‘Ž๐‘›245ยฐ 7. Sin 135ยฐ 8. Cos(90ยฐ-30ยฐ) 9. Cos 60ยฐ-Cos 30ยฐ 10.Jika f(x) = (Cos x + Sin x) . Tentukan nilai f(x), jika x = 45ยฐ
  • 17. PEMBAHASAN SOAL 1. Cos (270ยฐ) = K III Cos (180ยฐ+โˆ) = 270ยฐ Cos (180ยฐ+๐Ÿ—๐ŸŽยฐ) = 270ยฐ โˆ = ๐Ÿ—๐ŸŽยฐ Cos ๐Ÿ—๐ŸŽยฐ = ๐ŸŽ 2. Sin (204ยฐ) = K III Sin (180ยฐ+โˆ) = 204ยฐ Sin (180ยฐ+๐Ÿ๐Ÿ’ยฐ) = 204ยฐ โˆ = ๐Ÿ๐Ÿ’ยฐ (โˆ’) 3. Tan (60ยฐ) = K I Tan (90ยฐโˆ’ โˆ) = 60ยฐ Tan (90ยฐ โˆ’ ๐Ÿ‘๐ŸŽยฐ) = 60ยฐ โˆ = ๐Ÿ‘๐ŸŽยฐ Tan 3๐ŸŽยฐ = ๐Ÿ ๐Ÿ‘ ๐Ÿ‘ 4. Sec (167ยฐ) = K II Sec (180ยฐ โˆ’โˆ) = 167ยฐ Sin (180ยฐ โˆ’ ๐Ÿ๐Ÿ‘ยฐ) = 167ยฐ โˆ = ๐Ÿ๐Ÿ‘ยฐ (+)
  • 18. 5. ๐’๐ข๐ง ๐Ÿ60ยฐ+๐‚๐จ๐ฌ ๐Ÿ60ยฐ = (Sin 60ยฐ) ๐Ÿ+(Cos 60ยฐ) ๐Ÿ = ( ๐Ÿ ๐Ÿ ๐Ÿ‘) ๐Ÿ +( ๐Ÿ ๐Ÿ) ๐Ÿ = ๐Ÿ ๐Ÿ’ . ๐Ÿ‘ + ๐Ÿ ๐Ÿ’ = ๐Ÿ‘ ๐Ÿ’ + ๐Ÿ ๐Ÿ’ = ๐Ÿ’ ๐Ÿ’ = 1 6. 2. ๐‚๐จ๐ฌ ๐Ÿ60ยฐ+2. ๐’๐ข๐ง ๐Ÿ45+3. ๐“๐š๐ง ๐Ÿ45ยฐ = 2(Cos 60ยฐ) ๐Ÿ + 2(Sin 60ยฐ) ๐Ÿ +3(Tan ๐Ÿ’๐Ÿ“ยฐ) ๐Ÿ = 2( ๐Ÿ ๐Ÿ) ๐Ÿ + ๐Ÿ( ๐Ÿ ๐Ÿ ๐Ÿ) ๐Ÿ+๐Ÿ‘(๐Ÿ) ๐Ÿ = 2( ๐Ÿ ๐Ÿ’) +2( ๐Ÿ ๐Ÿ’.2)+3.1 = ๐Ÿ ๐Ÿ’+ ๐Ÿ ๐Ÿ’.4+3 = ๐Ÿ ๐Ÿ’+2+3 = ๐Ÿ ๐Ÿ’ + ๐Ÿ“
  • 19. 7. Sin 135ยฐ = (Sin 90+45) = ๐’๐ข๐ง ๐€ + ๐ = ๐’๐ข๐ง๐€. ๐‚๐จ๐ฌ๐ + ๐‚๐จ๐ฌ๐€. ๐’๐ข๐ง๐ = Sin 90ยฐ.Cos 45ยฐ+Cos 90ยฐ.Sin 45ยฐ = 1. ๐Ÿ ๐Ÿ ๐Ÿ+0. ๐Ÿ ๐Ÿ ๐Ÿ = ๐Ÿ ๐Ÿ ๐Ÿ 8. Cos(90ยฐ-30ยฐ) = Cos ๐€ โˆ’ ๐ = ๐‚๐จ๐ฌ๐€. ๐‚๐จ๐ฌ๐ + ๐’๐ข๐ง๐€. ๐’๐ข๐ง๐ = Cos 90ยฐ.Cos 45ยฐ+Sin 90ยฐ.Sin 45ยฐ = ๐Ÿ ๐Ÿ ๐Ÿ.0+ ๐Ÿ ๐Ÿ ๐Ÿ‘. ๐Ÿ = ๐Ÿ ๐Ÿ ๐Ÿ‘
  • 20. 9. Cos 60ยฐ-Cos 30ยฐ = ๐‚๐จ๐ฌ๐€ โˆ’ ๐‚๐จ๐ฌ๐ = โˆ’๐Ÿ. ๐’๐ข๐ง ๐Ÿ ๐Ÿ ๐€ + ๐ . ๐’๐ข๐ง ๐Ÿ ๐Ÿ ๐€ โˆ’ ๐ = โˆ’๐Ÿ. ๐’๐ข๐ง ๐Ÿ ๐Ÿ ๐Ÿ”๐ŸŽยฐ + ๐Ÿ‘๐ŸŽยฐ . ๐’๐ข๐ง ๐Ÿ ๐Ÿ ๐Ÿ”๐ŸŽยฐ โˆ’ ๐Ÿ‘๐ŸŽยฐ = โˆ’๐Ÿ. ๐’๐ข๐ง ๐Ÿ ๐Ÿ ๐Ÿ—๐ŸŽยฐ . ๐’๐ข๐ง ๐Ÿ ๐Ÿ ๐Ÿ‘๐ŸŽยฐ = โˆ’๐Ÿ. ๐’๐ข๐ง ๐Ÿ’๐Ÿ“ยฐ. ๐’๐ข๐ง ๐Ÿ‘๐ŸŽยฐ = โˆ’๐Ÿ. ๐Ÿ ๐Ÿ ๐Ÿ. ๐’๐ข๐ง ๐Ÿ๐Ÿ“ยฐ = โˆ’ ๐Ÿ ๐Ÿ . โˆ’๐Ÿ. ๐’๐ข๐ง ๐Ÿ๐Ÿ“ยฐ = โˆ’๐Ÿ. โˆ’๐Ÿ. ๐’๐ข๐ง ๐Ÿ๐Ÿ“ยฐ = ๐Ÿ. ๐’๐ข๐ง ๐Ÿ๐Ÿ“ยฐ
  • 21. 10. Jika f(x) = (Cos x + Sin x) . Tentukan nilai f(x), jika x = 45ยฐ F (x) = (Cos x + Sin x) ( Cos x + Sin x) = ๐‘ช๐’๐’” ๐Ÿ ๐’™ + ๐‘บ๐’Š๐’ ๐’™. ๐‚๐จ๐ฌ ๐’™+ ๐‘บ๐’Š๐’ ๐’™. ๐‚๐จ๐ฌ ๐’™+ ๐‘บ๐’Š๐’ ๐Ÿ ๐’™ = ๐‘ช๐’๐’” ๐Ÿ ๐’™ + ๐‘บ๐’Š๐’ ๐Ÿ ๐’™ + ๐‘บ๐’Š๐’ ๐’™. ๐‚๐จ๐ฌ ๐’™+ ๐‘บ๐’Š๐’ ๐’™. ๐‚๐จ๐ฌ ๐’™ = 1 + ๐‘บ๐’Š๐’ ๐’™. ๐‚๐จ๐ฌ ๐’™+ ๐‘บ๐’Š๐’ ๐’™. ๐‚๐จ๐ฌ ๐’™ = 1 + (Sin (A+B)+Sin (A-B)) = 1 + (Sin (45ยฐ+45ยฐ)+Sin (45ยฐ-45ยฐ)) = 1 + (Sin 90ยฐ +Sin90ยฐ) = 1 + 1 + 0 = 2