This document discusses interference patterns produced by double slit diffraction of laser light with a wavelength of 400 nm. It provides calculations to determine: 1) the angular separation between the m=0 and m=1 bright fringes is 1.15 degrees, 2) the distance between the m=0 and m=1 fringes on the screen is 0.015 m, and 3) the distance between the m=1 bright fringe and the dark fringe between m=1 and m=2 is 0.0075 m.

1. Bright and Dark Fringe Spacing
Relevant equation for the following scenarios: d sin θ = m λ and d sin θ = (m + ½) λ
Scenario: You shoot a laser beam
with a wavelength of 400 nm to
illuminate a double slit, with a
spacing of 0.002 cm, and produce
an interference pattern on a
screen 75.0 cm away.
Q1) What is the angle θ
between the m = 0 fringe and
the m = 1 fringe?
Q2) What is the distance y
between the m = 0 fringe and
the m = 1 fringe?
Q3) What is the distance between the m = 1 bright fringe and the dark fringe between m
=1 and m = 2?

2. Solutions:
Q1) Using equation dsin θ = m λ , we know:
d = 0.002 cm = 0.002 x 10-2
m
λ = 400 nm= 400 x 10-9
m
Rearrangingthe equation, θ= arcsin(λ/d) =arcsin(400 x 10-9
m/0.002 x 10-2
m) = 1.15°
Q2) To obtaina value fory, we can use trigonometry.
tan θ = y/D => y = D*tan θ = (75 x 10-2
m)*tan (1.15°) = 0.015 m
Q3) First we have to solve forthe angle betweenthe m= 0 fringe andthe dark fringe betweenm= 1
and m = 2, thenfindthe difference betweenyfoundinQ2 andthe positionof the darkfringe.
Usingequation d sin θ = (m+ ½) λ , we know:
d = 0.002 cm = 0.002 x 10-2
m
λ = 400 nm= 400 x 10-9
m
(m+ ½) = 1.5
Rearrangingthe equation, θ1/2 = arcsin(((m+½)λ)/d)
= arcsin(1.5*400 x 10-9
m/0.002 x 10-2
m) = 1.72°
Positionof the darkfringe: y1/2 = D*tan θ1/2 = 0.0225 m
The dark fringe andthe adjacentbrightfringe are 0.0075m apart.