A physics problem analyzes the tension forces in three connected strings. String 1 has a tension of 49N. This tension splits into components that give string 2 a tension of 28N. Analyzing string 2 and 3, string 3 has tensions of 28N horizontally and 50N vertically, giving it an overall tension of 57N at an angle of 29 degrees from vertical.

1. 16. (a) Analyzing vertical forces where string 1 and string 2 meet, we find
40 N
T1 = = 49 N .
cos 35◦
(b) Looking at the horizontal forces at that point leads to
T2 = T1 sin 35◦ = (49 N) sin 35◦ = 28 N .
(c) We denote the components of T3 as Tx (rightward) and Ty (upward). Analyzing horizontal forces
where string 2 and string 3 meet, we find Tx = T2 = 28 N. From the vertical forces there, we
conclude Ty = 50 N. Therefore,
T3 = 2 2
Tx + Ty = 57 N .
(d) The angle of string 3 (measured from vertical) is
Tx 28
θ = tan−1 = tan−1 = 29◦ .
Ty 50