46. We denote the tension in the upper left string (bc) as T and the tension in the lower right string (ab)
    as T . The supported weight is M g = 19.6 N. The force equilibrium conditions lead to

                               T cos 60◦ =      T cos 20◦        horizontal forces
                                       ◦                    ◦
                               T sin 60 = W + T sin 20           vertical forces .

     (a) We solve the above simultaneous equations and find

                                                        W
                                      T =                              = 15 N .
                                             tan 60◦ cos 20◦ − sin 20◦

    (b) Also, we obtain T = T cos 20◦ / cos 60◦ = 29 N.

P13 046

  • 1.
    46. We denotethe tension in the upper left string (bc) as T and the tension in the lower right string (ab) as T . The supported weight is M g = 19.6 N. The force equilibrium conditions lead to T cos 60◦ = T cos 20◦ horizontal forces ◦ ◦ T sin 60 = W + T sin 20 vertical forces . (a) We solve the above simultaneous equations and find W T = = 15 N . tan 60◦ cos 20◦ − sin 20◦ (b) Also, we obtain T = T cos 20◦ / cos 60◦ = 29 N.